diff --git a/log/2023_06_21_zVp15/RunMpp.sh b/log/2023_06_21_zVp15/RunMpp.sh new file mode 100644 index 0000000000000000000000000000000000000000..578cdd0760e58fb0b2f4f0ab2f2802d178065c9e --- /dev/null +++ b/log/2023_06_21_zVp15/RunMpp.sh @@ -0,0 +1,29 @@ +#!/bin/sh +### Job name +#SBATCH --job-name=MppFWILennart + +### File for the output +##vorher#SBATCH --output=Mpp%A ??????? +#SBATCH --output=Mpp%A + +### Time your job needs to execute +#SBATCH --time=280:00:00 + +### Use more than one node for parallel jobs on distributed-memory systems +###CR Version war 2, 4 geht, sofern genug frei. +#SBATCH --nodes=8 +###SBATCH --nodes=1 + +### Number of CPUS per task +#SBATCH --cpus-per-task=1 + +### Disable hyperthreading by setting the tasks per core to 1 +#SBATCH --ntasks-per-core=1 + +#SBATCH --mail-type=ALL + +#SBATCH --mail-user=uuwyh@student.kit.edu + +### Number of processes per node, in our case +#SBATCH --ntasks-per-node=16 +mpirun M++ diff --git a/log/2023_06_21_zVp15/_3h50_horst b/log/2023_06_21_zVp15/_3h50_horst new file mode 100644 index 0000000000000000000000000000000000000000..e69de29bb2d1d6434b8b29ae775ad8c2e48c5391 diff --git a/log/2023_06_21_zVp15/logfile_zVp15Cutted.log b/log/2023_06_21_zVp15/logfile_zVp15Cutted.log new file mode 100644 index 0000000000000000000000000000000000000000..ed9bab63f0fe85e7e67642fba3bc1ccb2206dddf --- /dev/null +++ b/log/2023_06_21_zVp15/logfile_zVp15Cutted.log @@ -0,0 +1,6379 @@ +start program on 128 procs at Wed Jun 21 22:39:11 2023 +Running on: node01 + reading config: ConfigVerbose........................... 2 + reading default: enableFileLogging....................... 1 + reading default: enableScreenLogging..................... 1 + reading default: precision............................... 8 + reading default: TimeLevel............................... 0 + reading config: Model................................... FWIInverse_DGTS + reading default: testAAO................................. 0 + reading config: ForwardSolver........................... VADGTS + reading config: ReconstructionType...................... SO + reading config: Mesh.................................... SeismogramGrid_test + reading config: level................................... 3 + reading default: plevel.................................. 3 + reading default: clevel.................................. 3 + reading config: Distribution............................ RCB + reading config: Overlap................................. dG1 + reading default: Scales.................................. 0 + reading default: CommSplit............................... 0 + reading default: DistributionVerbose..................... 0 + reading default: ClearDistribution....................... 1 + reading default: MeshesVerbose........................... 1 + reading default: MeshVerbose............................. 1 + Overlap: reading default: OverlapVerbose.......................... 0 + reading default: t0...................................... 0 + reading config: dt...................................... 0.001 + reading config: T....................................... 0.6 + reading config: rkorder................................. -2 + reading config: SignalName.............................. RickerDerivative + reading default: FrequencyFiltering...................... 0 + reading config: SignalFreq.............................. 25 + reading default: f_source................................ 25 + reading default: SourceInversion......................... 0 + reading config: SignalCutoff............................ 0.8 + reading config: SignalDelay............................. 0 + reading default: SaveFilteredSeismogram.................. 0 + reading default: SaveObservedSeismogram.................. 0 + reading config: numL.................................... 0 + reading default: dim..................................... 2 + reading config: Problem................................. VAcousticWaveC2Benchmark + reading default: RealDataLevel........................... 3 + reading default: InitialIterateLevel..................... 3 + reading config: deg..................................... 1 + reading config: parametrization......................... taup + reading default: shots................................... -1 + reading default: SourceStartX............................ -1e+100 + reading default: SourceStartY............................ -1e+100 + reading default: SourceEndX.............................. -1e+100 + reading default: SourceEndY.............................. -1e+100 + reading default: numberOfSourcesPerShot.................. 1 + reading config: FWISourceWaypoints...................... 2 + reading default: FWISourceIncludeLastWaypoint............ 1 + FWISourceCount0 + reading config: FWISourceCount0......................... 6 + reading config: FWISourceWaypoint0...................... 600,370 + FWISourceCount1 + reading config: FWISourceWaypoint1...................... 600,1620 + SOURCE LOCATIONS: + 0: ( 600.00000000, 370.00000000) + + + 1: ( 600.00000000, 620.00000000) + + + 2: ( 600.00000000, 870.00000000) + + + 3: ( 600.00000000, 1120) + + + 4: ( 600.00000000, 1370) + + + 5: ( 600.00000000, 1620) + + + reading config: source_factor........................... 242574257420000.5742 + reading config: Monoparam............................... Vp + monoparam = + Vp + reading default: z_perturb_0............................. 600 + reading default: z_perturb_1............................. 900 + reading default: z_perturb_2............................. 1200 + reading default: z_perturb_0_value....................... 1.05 + reading default: z_perturb_1_value....................... 1.1 + reading default: z_perturb_2_value....................... 0.95 + reading default: x_perturb............................... 900 + reading default: size_perturb............................ 200 + reading default: rho_bg.................................. 2000 + reading default: v_bg.................................... 3500 + reading default: tau_p_bg................................ 0.02 + reading default: impedance_bg............................ 1 + reading config: Qfactor................................. 100 + alphaValue = + 0 + reading default: FWIPrecon............................... 0 + reading default: FWIPreconType........................... 0 + reading default: FWIPreconRegularization................. 1e-08 + reading config: allowPlotting_M......................... 1 + reading config: allowPlotting_WF........................ 0 + reading default: plotFactor.............................. 1 + reading config: FWIReconstructRho....................... 0 + reading config: FWIReconstructV_P....................... 1 + reading config: FWIReconstructTauP...................... 0 + Mesh Info: + Mesh Name: ............................... SeismogramGrid_test + Distribution: ............................ RCB + Overlap: ................................. dG1 + CommSplit: ............................... 0 + Level: ................................... [3, -1, 0] + pLevel: .................................. 3 + Dimension: ............................... 2 + Cells: ................................... 87040 + Overlap: ................................. 21472 + Vertices: ................................ 98560 + Edges: ................................... 174672 + Faces: ................................... 218056 + ProcSets: ................................ 31900 + Mesh width [min, max]: ................... [12.500000, 29.474346] + + reading default: MatrixGraphVerbose...................... 0 + reading default: PaddingPML.............................. 0 + reading config: plot_tStep.............................. -1 + reading default: plotV................................... 0 + reading default: plot_rho................................ 1 + reading default: plot_kappa_0............................ 1 + reading default: plot_kappa_l............................ 0 + reading default: plot_velocity........................... 0 + reading config: compMeasure............................. 0 + Measure overall pressure p = p_0 + ... + p_L + reading default: Specfile................................ + reading config: FWIReceiverWaypoints.................... 2 + reading config: FWIReceiverIncludeLastWaypoint.......... 1 + FWIReceiverCount0 + reading config: FWIReceiverCount0....................... 64 + reading config: FWIReceiverWaypoint0.................... 1350.0, 370.0 + FWIReceiverCount1 + reading config: FWIReceiverWaypoint1.................... 1350.0, 1630.0 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.001 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.001 + 0: ( 1350, 370.00000000) 1: ( 1350, 390.00000000) + 2: ( 1350, 410.00000000) 3: ( 1350, 430.00000000) + 4: ( 1350, 450.00000000) 5: ( 1350, 470.00000000) + 6: ( 1350, 490.00000000) 7: ( 1350, 510.00000000) + 8: ( 1350, 530.00000000) 9: ( 1350, 550.00000000) + 10: ( 1350, 570.00000000) 11: ( 1350, 590.00000000) + 12: ( 1350, 610.00000000) 13: ( 1350, 630.00000000) + 14: ( 1350, 650.00000000) 15: ( 1350, 670.00000000) + 16: ( 1350, 690.00000000) 17: ( 1350, 710.00000000) + 18: ( 1350, 730.00000000) 19: ( 1350, 750.00000000) + 20: ( 1350, 770.00000000) 21: ( 1350, 790.00000000) + 22: ( 1350, 810.00000000) 23: ( 1350, 830.00000000) + 24: ( 1350, 850.00000000) 25: ( 1350, 870.00000000) + 26: ( 1350, 890.00000000) 27: ( 1350, 910.00000000) + 28: ( 1350, 930.00000000) 29: ( 1350, 950.00000000) + 30: ( 1350, 970.00000000) 31: ( 1350, 990.00000000) + 32: ( 1350, 1010) 33: ( 1350, 1030) + 34: ( 1350, 1050) 35: ( 1350, 1070) + 36: ( 1350, 1090) 37: ( 1350, 1110) + 38: ( 1350, 1130) 39: ( 1350, 1150) + 40: ( 1350, 1170) 41: ( 1350, 1190) + 42: ( 1350, 1210) 43: ( 1350, 1230) + 44: ( 1350, 1250) 45: ( 1350, 1270) + 46: ( 1350, 1290) 47: ( 1350, 1310) + 48: ( 1350, 1330) 49: ( 1350, 1350) + 50: ( 1350, 1370) 51: ( 1350, 1390) + 52: ( 1350, 1410) 53: ( 1350, 1430) + 54: ( 1350, 1450) 55: ( 1350, 1470) + 56: ( 1350, 1490) 57: ( 1350, 1510) + 58: ( 1350, 1530) 59: ( 1350, 1550) + 60: ( 1350, 1570) 61: ( 1350, 1590) + 62: ( 1350, 1610) 63: ( 1350, 1630) + + reading default: UseGardener............................. 0 + reading default: MeasureComp............................. 0 + Measure overall pressure p = p_0 + ... + p_L + reading default: CountCellsOld........................... 0 + reading config: useTaper................................ 1 + reading default: TaperFromFile........................... + reading config: taperRadiusSource....................... 0 + reading default: taperBoxUpper........................... 1e+100 + reading default: taperBoxLower........................... -1e+100 + reading default: taperBoxLeft............................ -1e+100 + reading default: taperBoxRight........................... 1e+100 + reading config: taperRadiusReceiver..................... 0 + reading config: taperExponent........................... -0.1 + reading config: taperIgnoreSourceCells.................. 1 + reading config: taperIgnoreReceiverCells................ 1 + reading default: taperRhoMin............................. -1 + reading default: taperRhoMax............................. -1 + reading default: taperVpMin.............................. -1 + reading default: taperVpMax.............................. -1 + reading default: taperTaupMin............................ -1 + reading default: taperTaupMax............................ -1 + reading default: seismopath.............................. + reading default: PlotVerbose............................. 0 + reading default: PlotEnabled............................. 0 + reading default: PlotPrecision........................... 4 + Time before FWD->createRealData(real, obs); Wed Jun 21 22:39:16 2023 + Generating Real data for shot 0 + reading default: AssembleVerbose......................... 1 + reading default: startTime............................... 0 + reading default: endTime................................. 1 + reading default: maxStepSize............................. 1e+100 + reading default: stepSize................................ 0 + reading default: minStepSize............................. 0 + reading default: dt_min.................................. 0 + reading default: maxSteps................................ 0 + reading default: steps................................... 0 + reading default: K....................................... 0 + reading default: tEps.................................... 1e-15 + reading default: tTol.................................... 1e-06 + reading default: upwind.................................. 1 + reading config: dampingFlux............................. 1 + reading default: UseCollectTweak......................... 0 + reading default: Preconditioner_S........................ PointBlockJacobi + reading config: LinearSolver............................ LS + reading default: PreconditionerVerbose................... 0 + reading default: PreconditionerDamp...................... 1 + reading default: PointBlockJacobiLapack.................. 0 + reading config: LinearVerbose........................... -1 + reading config: LinearSteps............................. 100 + reading config: LinearEpsilon........................... 1e-12 + reading config: LinearReduction......................... 0.0001 + reading default: LinearMinimalStepNumber................. 0 + reading default: LinearPrintSteps........................ 800 + reading default: TimeIntegratorVerbose................... 1 + Initialization: 0.09 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.59 seconds + Generating Real data for shot 1 + Initialization: 0.08 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.54 seconds + Generating Real data for shot 2 + Initialization: 0.08 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.50 seconds + Generating Real data for shot 3 + Initialization: 0.08 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.48 seconds + Generating Real data for shot 4 + Initialization: 0.09 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.51 seconds + Generating Real data for shot 5 + Initialization: 0.08 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.60 seconds + Time after FWD->createRealData(real, obs); Wed Jun 21 22:40:01 2023 + FWISourceCount0 + FWISourceCount1 + SOURCE LOCATIONS: + 0: ( 600.00000000, 370.00000000) + + + 1: ( 600.00000000, 620.00000000) + + + 2: ( 600.00000000, 870.00000000) + + + 3: ( 600.00000000, 1120) + + + 4: ( 600.00000000, 1370) + + + 5: ( 600.00000000, 1620) + + + monoparam = + Vp + alphaValue = + 0 + Frequency Filter to: -1 + + + Mesh Info: + Mesh Name: ............................... SeismogramGrid_test + Distribution: ............................ RCB + Overlap: ................................. dG1 + CommSplit: ............................... 0 + Level: ................................... [3, -1, 0] + pLevel: .................................. 3 + Dimension: ............................... 2 + Cells: ................................... 87040 + Overlap: ................................. 21472 + Vertices: ................................ 98560 + Edges: ................................... 174672 + Faces: ................................... 218056 + ProcSets: ................................ 31900 + Mesh width [min, max]: ................... [12.500000, 29.474346] + + Measure overall pressure p = p_0 + ... + p_L + FWIReceiverCount0 + FWIReceiverCount1 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.001 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.001 + 0: ( 1350, 370.00000000) 1: ( 1350, 390.00000000) + 2: ( 1350, 410.00000000) 3: ( 1350, 430.00000000) + 4: ( 1350, 450.00000000) 5: ( 1350, 470.00000000) + 6: ( 1350, 490.00000000) 7: ( 1350, 510.00000000) + 8: ( 1350, 530.00000000) 9: ( 1350, 550.00000000) + 10: ( 1350, 570.00000000) 11: ( 1350, 590.00000000) + 12: ( 1350, 610.00000000) 13: ( 1350, 630.00000000) + 14: ( 1350, 650.00000000) 15: ( 1350, 670.00000000) + 16: ( 1350, 690.00000000) 17: ( 1350, 710.00000000) + 18: ( 1350, 730.00000000) 19: ( 1350, 750.00000000) + 20: ( 1350, 770.00000000) 21: ( 1350, 790.00000000) + 22: ( 1350, 810.00000000) 23: ( 1350, 830.00000000) + 24: ( 1350, 850.00000000) 25: ( 1350, 870.00000000) + 26: ( 1350, 890.00000000) 27: ( 1350, 910.00000000) + 28: ( 1350, 930.00000000) 29: ( 1350, 950.00000000) + 30: ( 1350, 970.00000000) 31: ( 1350, 990.00000000) + 32: ( 1350, 1010) 33: ( 1350, 1030) + 34: ( 1350, 1050) 35: ( 1350, 1070) + 36: ( 1350, 1090) 37: ( 1350, 1110) + 38: ( 1350, 1130) 39: ( 1350, 1150) + 40: ( 1350, 1170) 41: ( 1350, 1190) + 42: ( 1350, 1210) 43: ( 1350, 1230) + 44: ( 1350, 1250) 45: ( 1350, 1270) + 46: ( 1350, 1290) 47: ( 1350, 1310) + 48: ( 1350, 1330) 49: ( 1350, 1350) + 50: ( 1350, 1370) 51: ( 1350, 1390) + 52: ( 1350, 1410) 53: ( 1350, 1430) + 54: ( 1350, 1450) 55: ( 1350, 1470) + 56: ( 1350, 1490) 57: ( 1350, 1510) + 58: ( 1350, 1530) 59: ( 1350, 1550) + 60: ( 1350, 1570) 61: ( 1350, 1590) + 62: ( 1350, 1610) 63: ( 1350, 1630) + + Measure overall pressure p = p_0 + ... + p_L + reading default: loadInitialModelFromFile................ 0 + reading default: loadRealModelFromFile................... 0 + reading config: FWINonlinearSolver...................... FWISO + reading default: FWI_MaxInnerLoopSteps_FWISO............. 10 + reading default: FWI_Gamma_FWISO......................... 0.9 + reading default: FWI_Damping_FWISO....................... 1 + reading default: FWI_ThetaMax_FWISO...................... 1 + reading default: FWI_ThetaInitial_FWISO.................. 0.4 + reading default: FWI_RegularizationStrategy_FWISO........ 0 + reading default: FWISO_Verbose........................... 1 + reading config: FWISO_Steps............................. 15 + reading default: FWISO_LineSearchSteps................... 3 + reading default: FWISO_Epsilon........................... 1e-10 + reading default: FWISO_Reduction......................... 1e-05 + reading default: FWISO_MinimalStepNumber................. 0 + reading default: FWI_Precon.............................. 0 + reading default: FWI_HierarchyLevel...................... -1 + reading default: FWI_SaveAdjointWF....................... 0 + reading default: FWI_SaveSeis............................ 0 + reading config: FWI_DebugPlottingLevel.................. 1 + reading default: FWI_BacktrackingFactor.................. 0.5 + reading default: FWI_BacktrackingActivated............... 0 + Memory Usage at start10375 + reading default: WriteSeismoToFileEvery.................. 2147483647 + Initialize Subproblems 10380 + Starting the Loops with max_iter: 15 and num_problems 6 + + + Iteration Main Looop Counting Variable iter: 0 + + iteration: 0 PROBLEM Number: 0 + FWISO problem 0: d(0) + shot: 0: Solving forward problem... + Initialization: 0.09 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.62 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 10508 + state_comps = + 1 + Prä-Residuumnorm: 223163.4 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 223163.4 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.39 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.68 seconds + Inner Loop: : InnerCG resNorm : 106203.8 + Inner Loop: : Time needed for inner loop: 19.17 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 19.17 seconds + Residuumnorm 1: 106203.8 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.83 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.93 seconds + Intermezzo Residuum: 93113.706 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 223163.4 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.76 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.48 seconds + PhiAdjSO: : 18.93 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.86 seconds + Initialization: 0.08 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.06 seconds + Inner Loop: : InnerCG resNorm : 63844.515 + Inner Loop: : Time needed for inner loop: 58.65 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.65 seconds + FWISO Subproblem: 0: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 63844.515 + reading default: PlotFactorIterates...................... 1 + reading default: PlotShot................................ -1 + + iteration: 0 PROBLEM Number: 1 + FWISO problem 1: d(0) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.57 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 27713 + state_comps = + 1 + Prä-Residuumnorm: 157344.78 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 157344.78 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.35 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + Inner Loop: : InnerCG resNorm : 92061.622 + Inner Loop: : Time needed for inner loop: 19.02 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 19.02 seconds + Residuumnorm 1: 92061.622 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.80 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.92 seconds + Intermezzo Residuum: 85987.134 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 157344.78 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.72 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.95 seconds + Inner Loop: : InnerCG resNorm : 59620.641 + Inner Loop: : Time needed for inner loop: 58.27 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.27 seconds + FWISO Subproblem: 1: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 59620.641 + + iteration: 0 PROBLEM Number: 2 + FWISO problem 2: d(0) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.53 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 29351 + state_comps = + 1 + Prä-Residuumnorm: 177771.59 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 177771.59 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.33 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Inner Loop: : InnerCG resNorm : 106962.45 + Inner Loop: : Time needed for inner loop: 19.01 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 19.01 seconds + Residuumnorm 1: 106962.45 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.68 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.74 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.91 seconds + Intermezzo Residuum: 100352.99 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 177771.59 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.71 seconds + Initialization: 0.05 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.00 seconds + Inner Loop: : InnerCG resNorm : 63211.404 + Inner Loop: : Time needed for inner loop: 58.27 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.27 seconds + FWISO Subproblem: 2: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 63211.404 + + iteration: 0 PROBLEM Number: 3 + FWISO problem 3: d(0) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.56 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 29648 + state_comps = + 1 + Prä-Residuumnorm: 208269.18 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 208269.18 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.35 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Inner Loop: : InnerCG resNorm : 87316.381 + Inner Loop: : Time needed for inner loop: 19.06 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 19.06 seconds + Residuumnorm 1: 87316.381 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.67 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.04 seconds + Intermezzo Residuum: 86444.268 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 208269.18 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + PhiAdjSO: : 18.98 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.73 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.05 seconds + Inner Loop: : InnerCG resNorm : 58365.165 + Inner Loop: : Time needed for inner loop: 58.36 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.36 seconds + FWISO Subproblem: 3: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 58365.165 + + iteration: 0 PROBLEM Number: 4 + FWISO problem 4: d(0) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.56 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 30197 + state_comps = + 1 + Prä-Residuumnorm: 189591.52 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 189591.52 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.34 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + Inner Loop: : InnerCG resNorm : 85248.504 + Inner Loop: : Time needed for inner loop: 19.12 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 19.12 seconds + Residuumnorm 1: 85248.504 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.75 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.08 seconds + Intermezzo Residuum: 73509.834 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 189591.52 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.68 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.94 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.74 seconds + Initialization: 0.08 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.05 seconds + Inner Loop: : InnerCG resNorm : 50798.767 + Inner Loop: : Time needed for inner loop: 58.42 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.43 seconds + FWISO Subproblem: 4: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 50798.767 + + iteration: 0 PROBLEM Number: 5 + FWISO problem 5: d(0) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.72 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 30715 + state_comps = + 1 + Prä-Residuumnorm: 122569.1 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 122569.1 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.35 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.72 seconds + Inner Loop: : InnerCG resNorm : 54780.636 + Inner Loop: : Time needed for inner loop: 19.15 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 19.15 seconds + Residuumnorm 1: 54780.636 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.72 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.12 seconds + Intermezzo Residuum: 60250.964 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 122569.1 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.79 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : 19.00 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.71 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.07 seconds + Inner Loop: : InnerCG resNorm : 40852.39 + Inner Loop: : Time needed for inner loop: 58.61 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.61 seconds + FWISO Subproblem: 5: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 40852.39 + + + Iteration Main Looop Counting Variable iter: 1 + + iteration: 1 PROBLEM Number: 0 + FWISO problem 0: d(1) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.77 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 30793 + Prä-Residuumnorm: 69584.003 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 21696.809 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.38 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.71 seconds + Inner Loop: : InnerCG resNorm : 35396.843 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.31 seconds + Initialization: 0.05 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.71 seconds + Inner Loop: : InnerCG resNorm : 26613.829 + Inner Loop: : Time needed for inner loop: 38.26 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 38.26 seconds + Residuumnorm 1: 26613.829 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.77 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.76 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.07 seconds + Intermezzo Residuum: 27452.949 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 21696.809 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.74 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + PhiAdjSO: : 18.99 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.75 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + Initialization: 0.08 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.08 seconds + Inner Loop: : InnerCG resNorm : 22763.528 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.71 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : 19.00 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.74 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.11 seconds + Inner Loop: : InnerCG resNorm : 19168.672 + Inner Loop: : Time needed for inner loop: 1:57.22 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:57.22 minutes + FWISO Subproblem: 0: d(1): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 19168.672 + + iteration: 1 PROBLEM Number: 1 + FWISO problem 1: d(1) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.59 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 30838 + Prä-Residuumnorm: 54301.754 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 18740.25 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.35 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Inner Loop: : InnerCG resNorm : 30079.702 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.36 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Inner Loop: : InnerCG resNorm : 22465.999 + Inner Loop: : Time needed for inner loop: 38.06 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 38.06 seconds + Residuumnorm 1: 22465.999 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.95 seconds + Intermezzo Residuum: 22862.195 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 18740.25 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + PhiAdjSO: : 19.03 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.96 seconds + Inner Loop: : InnerCG resNorm : 18686.182 + Inner Loop: : Time needed for inner loop: 58.25 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.25 seconds + FWISO Subproblem: 1: d(1): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 18686.182 + + iteration: 1 PROBLEM Number: 2 + FWISO problem 2: d(1) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.56 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 30931 + Prä-Residuumnorm: 49539.969 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 13805.403 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.32 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Inner Loop: : InnerCG resNorm : 26947.75 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.32 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Inner Loop: : InnerCG resNorm : 20777.068 + Inner Loop: : Time needed for inner loop: 38.11 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 38.11 seconds + Residuumnorm 1: 20777.068 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.89 seconds + Intermezzo Residuum: 21501.775 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 13805.403 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.69 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + PhiAdjSO: : 19.00 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.93 seconds + Inner Loop: : InnerCG resNorm : 18189.382 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + PhiAdjSO: : 19.02 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.93 seconds + Inner Loop: : InnerCG resNorm : 13711.506 + Inner Loop: : Time needed for inner loop: 1:56.52 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:56.52 minutes + FWISO Subproblem: 2: d(1): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 13711.506 + + iteration: 1 PROBLEM Number: 3 + FWISO problem 3: d(1) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.57 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31043 + Prä-Residuumnorm: 33610.496 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 5424.0644 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.33 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + Inner Loop: : InnerCG resNorm : 22986.895 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.36 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.71 seconds + Inner Loop: : InnerCG resNorm : 16379.024 + Inner Loop: : Time needed for inner loop: 38.14 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 38.14 seconds + Residuumnorm 1: 16379.024 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.87 seconds + Intermezzo Residuum: 16415.946 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5424.0644 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + PhiAdjSO: : 19.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.77 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.00 seconds + Inner Loop: : InnerCG resNorm : 13894.469 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + PhiAdjSO: : 18.95 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.03 seconds + Inner Loop: : InnerCG resNorm : 10795.661 + Inner Loop: : Time needed for inner loop: 1:56.76 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:56.76 minutes + FWISO Subproblem: 3: d(1): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 10795.661 + + iteration: 1 PROBLEM Number: 4 + FWISO problem 4: d(1) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.50 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31077 + Prä-Residuumnorm: 35082.966 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 6491.9279 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.32 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Inner Loop: : InnerCG resNorm : 24951.603 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.31 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Inner Loop: : InnerCG resNorm : 16600.29 + Inner Loop: : Time needed for inner loop: 38.00 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 38.00 seconds + Residuumnorm 1: 16600.29 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.89 seconds + Intermezzo Residuum: 16472.706 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 6491.9279 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : 18.96 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.91 seconds + Inner Loop: : InnerCG resNorm : 13652.963 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + PhiAdjSO: : 18.99 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.93 seconds + Inner Loop: : InnerCG resNorm : 11222.948 + Inner Loop: : Time needed for inner loop: 1:56.29 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:56.29 minutes + FWISO Subproblem: 4: d(1): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 11222.948 + + iteration: 1 PROBLEM Number: 5 + FWISO problem 5: d(1) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.63 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31123 + Prä-Residuumnorm: 33538.085 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9176.8899 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.33 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + Inner Loop: : InnerCG resNorm : 22744.548 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.28 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.69 seconds + Inner Loop: : InnerCG resNorm : 16814.299 + Inner Loop: : Time needed for inner loop: 38.12 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 38.12 seconds + Residuumnorm 1: 16814.299 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.68 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.75 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.02 seconds + Intermezzo Residuum: 16507.874 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 9176.8899 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + PhiAdjSO: : 19.05 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Initialization: 0.05 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.04 seconds + Inner Loop: : InnerCG resNorm : 13096.053 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.71 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + PhiAdjSO: : 18.95 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.69 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.68 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.00 seconds + Inner Loop: : InnerCG resNorm : 11089.985 + Inner Loop: : Time needed for inner loop: 1:56.94 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:56.94 minutes + FWISO Subproblem: 5: d(1): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 11089.985 + + + Iteration Main Looop Counting Variable iter: 2 + + iteration: 2 PROBLEM Number: 0 + FWISO problem 0: d(2) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.67 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31242 + Prä-Residuumnorm: 18240 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 11963.683 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.31 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Inner Loop: : InnerCG resNorm : 14017.439 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.31 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Inner Loop: : InnerCG resNorm : 12021.187 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.29 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Inner Loop: : InnerCG resNorm : 9029.0285 + Inner Loop: : Time needed for inner loop: 57.06 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 57.06 seconds + Residuumnorm 1: 9029.0285 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.68 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.97 seconds + Intermezzo Residuum: 9031.6483 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 11963.683 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + PhiAdjSO: : 18.97 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.67 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.07 seconds + Inner Loop: : InnerCG resNorm : 8166.7252 + Inner Loop: : Time needed for inner loop: 58.39 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.39 seconds + FWISO Subproblem: 0: d(2): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 8166.7252 + + iteration: 2 PROBLEM Number: 1 + FWISO problem 1: d(2) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.57 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31322 + Prä-Residuumnorm: 23162.658 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 15578.198 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.30 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Inner Loop: : InnerCG resNorm : 12446.381 + Inner Loop: : Time needed for inner loop: 18.98 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.98 seconds + Residuumnorm 1: 12446.381 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.99 seconds + Intermezzo Residuum: 12436.811 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 7194.3641 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : 18.92 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.99 seconds + Inner Loop: : InnerCG resNorm : 9494.8404 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : 18.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.93 seconds + Inner Loop: : InnerCG resNorm : 8236.5279 + Inner Loop: : Time needed for inner loop: 1:55.95 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.95 minutes + FWISO Subproblem: 1: d(2): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 8236.5279 + + iteration: 2 PROBLEM Number: 2 + FWISO problem 2: d(2) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.57 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31384 + Prä-Residuumnorm: 21508.875 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 13751.398 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.29 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Inner Loop: : InnerCG resNorm : 10217.838 + Inner Loop: : Time needed for inner loop: 18.93 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.93 seconds + Residuumnorm 1: 10217.838 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.92 seconds + Intermezzo Residuum: 10257.277 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 13751.398 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + PhiAdjSO: : 18.94 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.88 seconds + Inner Loop: : InnerCG resNorm : 8526.4536 + Inner Loop: : Time needed for inner loop: 57.98 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.98 seconds + FWISO Subproblem: 2: d(2): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 8526.4536 + + iteration: 2 PROBLEM Number: 3 + FWISO problem 3: d(2) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.50 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31434 + Prä-Residuumnorm: 19765.424 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 11477.585 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.29 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + Inner Loop: : InnerCG resNorm : 10990.261 + Inner Loop: : Time needed for inner loop: 18.94 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.94 seconds + Residuumnorm 1: 10990.261 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.92 seconds + Intermezzo Residuum: 10956.324 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 11477.585 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : 18.91 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.88 seconds + Inner Loop: : InnerCG resNorm : 8428.0365 + Inner Loop: : Time needed for inner loop: 57.96 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.96 seconds + FWISO Subproblem: 3: d(2): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 8428.0365 + + iteration: 2 PROBLEM Number: 4 + FWISO problem 4: d(2) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.58 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31482 + Prä-Residuumnorm: 15522.719 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9197.5603 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + Inner Loop: : InnerCG resNorm : 10412.766 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Inner Loop: : InnerCG resNorm : 8581.988 + Inner Loop: : Time needed for inner loop: 37.80 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.80 seconds + Residuumnorm 1: 8581.988 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.93 seconds + Intermezzo Residuum: 8581.3412 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 9197.5603 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : 18.92 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.88 seconds + Inner Loop: : InnerCG resNorm : 7690.7945 + Inner Loop: : Time needed for inner loop: 57.76 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.76 seconds + FWISO Subproblem: 4: d(2): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 7690.7945 + + iteration: 2 PROBLEM Number: 5 + FWISO problem 5: d(2) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.72 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31539 + Prä-Residuumnorm: 14736.871 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9384.6306 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Inner Loop: : InnerCG resNorm : 10472.626 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Inner Loop: : InnerCG resNorm : 9177.9466 + Inner Loop: : Time needed for inner loop: 37.85 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.85 seconds + Residuumnorm 1: 9177.9466 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.96 seconds + Intermezzo Residuum: 9152.9288 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 9384.6306 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.03 seconds + Inner Loop: : InnerCG resNorm : 8388.1863 + Inner Loop: : Time needed for inner loop: 58.18 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.18 seconds + FWISO Subproblem: 5: d(2): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 8388.1863 + + + Iteration Main Looop Counting Variable iter: 3 + + iteration: 3 PROBLEM Number: 0 + FWISO problem 0: d(3) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.63 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31586 + Prä-Residuumnorm: 14577.709 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 11233.619 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.28 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Inner Loop: : InnerCG resNorm : 9865.1157 + Inner Loop: : Time needed for inner loop: 18.92 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.92 seconds + Residuumnorm 1: 9865.1157 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.93 seconds + Intermezzo Residuum: 9875.9463 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 8605.4161 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.49 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.03 seconds + Inner Loop: : InnerCG resNorm : 8753.0142 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : 18.91 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.96 seconds + Inner Loop: : InnerCG resNorm : 7650.7698 + Inner Loop: : Time needed for inner loop: 1:56.20 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:56.20 minutes + FWISO Subproblem: 0: d(3): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 7650.7698 + + iteration: 3 PROBLEM Number: 1 + FWISO problem 1: d(3) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.50 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31645 + Prä-Residuumnorm: 9781.5883 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 5920.8044 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Inner Loop: : InnerCG resNorm : 7895.9417 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Inner Loop: : InnerCG resNorm : 6805.4155 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + Inner Loop: : InnerCG resNorm : 5663.0931 + Inner Loop: : Time needed for inner loop: 56.57 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 56.57 seconds + Residuumnorm 1: 5663.0931 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.87 seconds + Intermezzo Residuum: 5664.075 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 6409.8838 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : 18.93 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.88 seconds + Inner Loop: : InnerCG resNorm : 5197.3261 + Inner Loop: : Time needed for inner loop: 57.74 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.74 seconds + FWISO Subproblem: 1: d(3): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 5197.3261 + + iteration: 3 PROBLEM Number: 2 + FWISO problem 2: d(3) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.49 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31684 + Prä-Residuumnorm: 11887.734 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 6840.2309 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + Inner Loop: : InnerCG resNorm : 7917.0707 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Inner Loop: : InnerCG resNorm : 6647.3349 + Inner Loop: : Time needed for inner loop: 37.88 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.88 seconds + Residuumnorm 1: 6647.3349 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.92 seconds + Intermezzo Residuum: 6664.5149 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 6840.2309 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.49 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.90 seconds + Inner Loop: : InnerCG resNorm : 5906.4071 + Inner Loop: : Time needed for inner loop: 57.83 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.83 seconds + FWISO Subproblem: 2: d(3): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 5906.4071 + + iteration: 3 PROBLEM Number: 3 + FWISO problem 3: d(3) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.51 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31737 + Prä-Residuumnorm: 14786.966 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 7727.9797 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 8630.2053 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + Inner Loop: : InnerCG resNorm : 6507.3319 + Inner Loop: : Time needed for inner loop: 37.79 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.79 seconds + Residuumnorm 1: 6507.3319 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.91 seconds + Intermezzo Residuum: 6497.1771 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 7727.9797 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 5836.9375 + Inner Loop: : Time needed for inner loop: 57.74 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.74 seconds + FWISO Subproblem: 3: d(3): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 5836.9375 + + iteration: 3 PROBLEM Number: 4 + FWISO problem 4: d(3) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.60 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31783 + Prä-Residuumnorm: 10610.632 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 5658.3346 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Inner Loop: : InnerCG resNorm : 8109.1074 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Inner Loop: : InnerCG resNorm : 6883.2652 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Inner Loop: : InnerCG resNorm : 5702.8906 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Inner Loop: : InnerCG resNorm : 4826.0858 + Inner Loop: : Time needed for inner loop: 1:15.50 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 1:15.50 minutes + Residuumnorm 1: 4826.0858 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.87 seconds + Intermezzo Residuum: 4846.8999 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5658.3346 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : 18.94 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.92 seconds + Inner Loop: : InnerCG resNorm : 4417.7552 + Inner Loop: : Time needed for inner loop: 57.92 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.92 seconds + FWISO Subproblem: 4: d(3): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 4417.7552 + + iteration: 3 PROBLEM Number: 5 + FWISO problem 5: d(3) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.61 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31843 + Prä-Residuumnorm: 10056.114 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 5763.4776 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Inner Loop: : InnerCG resNorm : 8618.3297 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Inner Loop: : InnerCG resNorm : 7363.3119 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Inner Loop: : InnerCG resNorm : 5909.338 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Inner Loop: : InnerCG resNorm : 5199.1829 + Inner Loop: : Time needed for inner loop: 1:15.85 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 1:15.85 minutes + Residuumnorm 1: 5199.1829 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.98 seconds + Intermezzo Residuum: 5160.2798 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5763.4776 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.99 seconds + Inner Loop: : InnerCG resNorm : 4799.1989 + Inner Loop: : Time needed for inner loop: 58.17 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.17 seconds + FWISO Subproblem: 5: d(3): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 4799.1989 + + + Iteration Main Looop Counting Variable iter: 4 + + iteration: 4 PROBLEM Number: 0 + FWISO problem 0: d(4) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.62 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31888 + Prä-Residuumnorm: 9392.8656 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 6514.3489 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Inner Loop: : InnerCG resNorm : 8380.0289 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Inner Loop: : InnerCG resNorm : 7209.0987 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Inner Loop: : InnerCG resNorm : 5864.8166 + Inner Loop: : Time needed for inner loop: 56.80 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 56.80 seconds + Residuumnorm 1: 5864.8166 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.96 seconds + Intermezzo Residuum: 5857.3048 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 7468.7997 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.99 seconds + Inner Loop: : InnerCG resNorm : 5381.3622 + Inner Loop: : Time needed for inner loop: 58.06 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.06 seconds + FWISO Subproblem: 0: d(4): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 5381.3622 + + iteration: 4 PROBLEM Number: 1 + FWISO problem 1: d(4) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.54 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31932 + Prä-Residuumnorm: 9735.5921 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 8454.7157 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + Inner Loop: : InnerCG resNorm : 6925.644 + Inner Loop: : Time needed for inner loop: 18.92 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.92 seconds + Residuumnorm 1: 6925.644 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.81 seconds + Intermezzo Residuum: 6926.2536 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5741.7682 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.86 seconds + Inner Loop: : InnerCG resNorm : 5803.3172 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.86 seconds + Inner Loop: : InnerCG resNorm : 4950.4859 + Inner Loop: : Time needed for inner loop: 1:55.41 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.41 minutes + FWISO Subproblem: 1: d(4): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 4950.4859 + + iteration: 4 PROBLEM Number: 2 + FWISO problem 2: d(4) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.51 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 31978 + Prä-Residuumnorm: 9725.717 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 7660.959 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Inner Loop: : InnerCG resNorm : 6695.9889 + Inner Loop: : Time needed for inner loop: 18.98 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.98 seconds + Residuumnorm 1: 6695.9889 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.82 seconds + Intermezzo Residuum: 6701.2232 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5036.5809 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.92 seconds + Inner Loop: : InnerCG resNorm : 5953.7717 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.82 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.91 seconds + Inner Loop: : InnerCG resNorm : 4977.2888 + Inner Loop: : Time needed for inner loop: 1:55.52 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.52 minutes + FWISO Subproblem: 2: d(4): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 4977.2888 + + iteration: 4 PROBLEM Number: 3 + FWISO problem 3: d(4) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.51 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32026 + Prä-Residuumnorm: 12688.774 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9660.0973 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 7231.6743 + Inner Loop: : Time needed for inner loop: 18.86 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.86 seconds + Residuumnorm 1: 7231.6743 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Intermezzo Residuum: 7218.7202 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5968.2783 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.92 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.91 seconds + Inner Loop: : InnerCG resNorm : 5916.7703 + Inner Loop: : Time needed for inner loop: 57.85 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.85 seconds + FWISO Subproblem: 3: d(4): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 5916.7703 + + iteration: 4 PROBLEM Number: 4 + FWISO problem 4: d(4) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.52 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32075 + Prä-Residuumnorm: 10644.251 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 8160.2566 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Inner Loop: : InnerCG resNorm : 5880.2383 + Inner Loop: : Time needed for inner loop: 18.90 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.90 seconds + Residuumnorm 1: 5880.2383 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Intermezzo Residuum: 5890.9618 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5108.6361 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : 18.92 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.91 seconds + Inner Loop: : InnerCG resNorm : 5092.5591 + Inner Loop: : Time needed for inner loop: 57.86 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.86 seconds + FWISO Subproblem: 4: d(4): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 5092.5591 + + iteration: 4 PROBLEM Number: 5 + FWISO problem 5: d(4) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.63 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32121 + Prä-Residuumnorm: 6737.7095 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 5299.6521 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.76 seconds + Inner Loop: : InnerCG resNorm : 5425.3847 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Inner Loop: : InnerCG resNorm : 4897.5326 + Inner Loop: : Time needed for inner loop: 38.07 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 38.07 seconds + Residuumnorm 1: 4897.5326 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.75 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.92 seconds + Intermezzo Residuum: 4896.4453 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3475.4353 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.01 seconds + Inner Loop: : InnerCG resNorm : 4660.4656 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + PhiAdjSO: : 18.95 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.01 seconds + Inner Loop: : InnerCG resNorm : 4182.1073 + Inner Loop: : Time needed for inner loop: 1:56.42 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:56.42 minutes + FWISO Subproblem: 5: d(4): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 4182.1073 + + + Iteration Main Looop Counting Variable iter: 5 + + iteration: 5 PROBLEM Number: 0 + FWISO problem 0: d(5) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.60 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32166 + Prä-Residuumnorm: 8947.2967 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 8033.3072 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.30 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Inner Loop: : InnerCG resNorm : 6470.3422 + Inner Loop: : Time needed for inner loop: 18.94 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.94 seconds + Residuumnorm 1: 6470.3422 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.93 seconds + Intermezzo Residuum: 6473.0478 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 6403.0524 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.01 seconds + Inner Loop: : InnerCG resNorm : 5882.8836 + Inner Loop: : Time needed for inner loop: 58.13 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.13 seconds + FWISO Subproblem: 0: d(5): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 5882.8836 + + iteration: 5 PROBLEM Number: 1 + FWISO problem 1: d(5) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.51 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32212 + Prä-Residuumnorm: 6764.7741 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 5287.2817 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Inner Loop: : InnerCG resNorm : 5424.7141 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + Inner Loop: : InnerCG resNorm : 4839.3708 + Inner Loop: : Time needed for inner loop: 37.71 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.71 seconds + Residuumnorm 1: 4839.3708 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.78 seconds + Intermezzo Residuum: 4838.6239 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5377.2203 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.49 seconds + PhiAdjSO: : 18.91 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.86 seconds + Inner Loop: : InnerCG resNorm : 4531.556 + Inner Loop: : Time needed for inner loop: 57.68 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.68 seconds + FWISO Subproblem: 1: d(5): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 4531.556 + + iteration: 5 PROBLEM Number: 2 + FWISO problem 2: d(5) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.52 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32256 + Prä-Residuumnorm: 5519.5215 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3912.9603 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Inner Loop: : InnerCG resNorm : 4852.1073 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Inner Loop: : InnerCG resNorm : 4286.3379 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 3694.2996 + Inner Loop: : Time needed for inner loop: 56.63 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 56.63 seconds + Residuumnorm 1: 3694.2996 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.80 seconds + Intermezzo Residuum: 3695.5077 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4188.9364 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + PhiAdjSO: : 18.98 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.82 seconds + Inner Loop: : InnerCG resNorm : 3455.8175 + Inner Loop: : Time needed for inner loop: 57.80 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.80 seconds + FWISO Subproblem: 2: d(5): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 3455.8175 + + iteration: 5 PROBLEM Number: 3 + FWISO problem 3: d(5) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.50 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32303 + Prä-Residuumnorm: 9044.5727 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 6197.1555 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Inner Loop: : InnerCG resNorm : 5991.9243 + Inner Loop: : Time needed for inner loop: 19.01 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 19.01 seconds + Residuumnorm 1: 5991.9243 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.79 seconds + Intermezzo Residuum: 5988.1155 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3828.776 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.87 seconds + Inner Loop: : InnerCG resNorm : 5109.8808 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.84 seconds + Inner Loop: : InnerCG resNorm : 4240.1774 + Inner Loop: : Time needed for inner loop: 1:55.35 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.35 minutes + FWISO Subproblem: 3: d(5): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 4240.1774 + + iteration: 5 PROBLEM Number: 4 + FWISO problem 4: d(5) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.59 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32395 + Prä-Residuumnorm: 8112.4678 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 5597.3725 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Inner Loop: : InnerCG resNorm : 5454.7264 + Inner Loop: : Time needed for inner loop: 18.88 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.88 seconds + Residuumnorm 1: 5454.7264 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Intermezzo Residuum: 5458.5336 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3504.1716 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 4835.7053 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : 18.91 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.88 seconds + Inner Loop: : InnerCG resNorm : 4209.8273 + Inner Loop: : Time needed for inner loop: 1:55.50 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.50 minutes + FWISO Subproblem: 4: d(5): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 4209.8273 + + iteration: 5 PROBLEM Number: 5 + FWISO problem 5: d(5) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.62 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32441 + Prä-Residuumnorm: 5888.2624 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4168.3554 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Inner Loop: : InnerCG resNorm : 4730.2508 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Inner Loop: : InnerCG resNorm : 4379.6309 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Inner Loop: : InnerCG resNorm : 3927.926 + Inner Loop: : Time needed for inner loop: 56.82 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 56.82 seconds + Residuumnorm 1: 3927.926 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.90 seconds + Intermezzo Residuum: 3924.4629 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4462.7685 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.99 seconds + Inner Loop: : InnerCG resNorm : 3662.5035 + Inner Loop: : Time needed for inner loop: 58.13 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.13 seconds + FWISO Subproblem: 5: d(5): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 3662.5035 + + + Iteration Main Looop Counting Variable iter: 6 + + iteration: 6 PROBLEM Number: 0 + FWISO problem 0: d(6) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.60 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32492 + Prä-Residuumnorm: 6894.6476 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 5571.3073 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + Inner Loop: : InnerCG resNorm : 6249.3076 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Inner Loop: : InnerCG resNorm : 5342.1217 + Inner Loop: : Time needed for inner loop: 37.83 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.83 seconds + Residuumnorm 1: 5342.1217 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.98 seconds + Intermezzo Residuum: 5340.709 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4440.6833 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.94 seconds + Inner Loop: : InnerCG resNorm : 4899.2412 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.89 seconds + Inner Loop: : InnerCG resNorm : 4527.4115 + Inner Loop: : Time needed for inner loop: 1:55.96 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.96 minutes + FWISO Subproblem: 0: d(6): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 4527.4115 + + iteration: 6 PROBLEM Number: 1 + FWISO problem 1: d(6) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.49 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32534 + Prä-Residuumnorm: 6796.3702 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 6054.1735 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Inner Loop: : InnerCG resNorm : 5299.5128 + Inner Loop: : Time needed for inner loop: 18.87 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.87 seconds + Residuumnorm 1: 5299.5128 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.81 seconds + Intermezzo Residuum: 5298.5645 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4862.102 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.88 seconds + Inner Loop: : InnerCG resNorm : 4823.9861 + Inner Loop: : Time needed for inner loop: 57.67 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.67 seconds + FWISO Subproblem: 1: d(6): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 4823.9861 + + iteration: 6 PROBLEM Number: 2 + FWISO problem 2: d(6) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.50 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32583 + Prä-Residuumnorm: 5254.0518 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4744.2881 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Inner Loop: : InnerCG resNorm : 4169.1652 + Inner Loop: : Time needed for inner loop: 18.86 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.86 seconds + Residuumnorm 1: 4169.1652 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.78 seconds + Intermezzo Residuum: 4169.7319 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3588.7169 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + PhiAdjSO: : 18.98 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.87 seconds + Inner Loop: : InnerCG resNorm : 3859.444 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 3338.9622 + Inner Loop: : Time needed for inner loop: 1:55.64 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.64 minutes + FWISO Subproblem: 2: d(6): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 3338.9622 + + iteration: 6 PROBLEM Number: 3 + FWISO problem 3: d(6) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.52 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32627 + Prä-Residuumnorm: 7051.7691 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4348.5546 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Inner Loop: : InnerCG resNorm : 4846.9616 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 4191.0706 + Inner Loop: : Time needed for inner loop: 37.73 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.73 seconds + Residuumnorm 1: 4191.0706 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.79 seconds + Intermezzo Residuum: 4190.4463 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5018.4727 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.49 seconds + PhiAdjSO: : 18.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.83 seconds + Inner Loop: : InnerCG resNorm : 3887.7369 + Inner Loop: : Time needed for inner loop: 57.67 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.67 seconds + FWISO Subproblem: 3: d(6): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 3887.7369 + + iteration: 6 PROBLEM Number: 4 + FWISO problem 4: d(6) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.49 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32674 + Prä-Residuumnorm: 5950.2928 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3694.9798 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Inner Loop: : InnerCG resNorm : 4484.2869 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + Inner Loop: : InnerCG resNorm : 4044.1971 + Inner Loop: : Time needed for inner loop: 37.72 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.72 seconds + Residuumnorm 1: 4044.1971 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.87 seconds + Intermezzo Residuum: 4045.1119 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4260.2577 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.48 seconds + PhiAdjSO: : 18.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.92 seconds + Inner Loop: : InnerCG resNorm : 3748.2234 + Inner Loop: : Time needed for inner loop: 57.78 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.78 seconds + FWISO Subproblem: 4: d(6): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 3748.2234 + + iteration: 6 PROBLEM Number: 5 + FWISO problem 5: d(6) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.67 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32736 + Prä-Residuumnorm: 4406.4943 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3548.4301 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Inner Loop: : InnerCG resNorm : 3952.7617 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Inner Loop: : InnerCG resNorm : 3691.0357 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.28 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Inner Loop: : InnerCG resNorm : 3231.1456 + Inner Loop: : Time needed for inner loop: 56.92 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 56.92 seconds + Residuumnorm 1: 3231.1456 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.96 seconds + Intermezzo Residuum: 3229.6462 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3005.7505 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.68 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.94 seconds + Inner Loop: : InnerCG resNorm : 2999.8766 + Inner Loop: : Time needed for inner loop: 58.11 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.11 seconds + FWISO Subproblem: 5: d(6): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 2999.8766 + + + Iteration Main Looop Counting Variable iter: 7 + + iteration: 7 PROBLEM Number: 0 + FWISO problem 0: d(7) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.66 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32775 + Prä-Residuumnorm: 6041.2687 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 5461.4962 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Inner Loop: : InnerCG resNorm : 5154.8191 + Inner Loop: : Time needed for inner loop: 18.93 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.93 seconds + Residuumnorm 1: 5154.8191 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.90 seconds + Intermezzo Residuum: 5155.0389 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4966.1552 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.71 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.97 seconds + Inner Loop: : InnerCG resNorm : 4823.8128 + Inner Loop: : Time needed for inner loop: 58.12 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.12 seconds + FWISO Subproblem: 0: d(7): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 4823.8128 + + iteration: 7 PROBLEM Number: 1 + FWISO problem 1: d(7) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.54 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32819 + Prä-Residuumnorm: 5850.4973 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4690.4351 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Inner Loop: : InnerCG resNorm : 4775.5667 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 4058.6383 + Inner Loop: : Time needed for inner loop: 37.71 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.71 seconds + Residuumnorm 1: 4058.6383 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.76 seconds + Intermezzo Residuum: 4058.3446 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3766.8847 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.82 seconds + Inner Loop: : InnerCG resNorm : 3805.2525 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.96 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.91 seconds + Inner Loop: : InnerCG resNorm : 3579.9484 + Inner Loop: : Time needed for inner loop: 1:55.50 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.50 minutes + FWISO Subproblem: 1: d(7): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 3579.9484 + + iteration: 7 PROBLEM Number: 2 + FWISO problem 2: d(7) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.50 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32859 + Prä-Residuumnorm: 4535.4219 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3685.8436 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + Inner Loop: : InnerCG resNorm : 3830.0799 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Inner Loop: : InnerCG resNorm : 3452.5864 + Inner Loop: : Time needed for inner loop: 37.76 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.76 seconds + Residuumnorm 1: 3452.5864 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.77 seconds + Intermezzo Residuum: 3453.227 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3816.6437 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.81 seconds + Inner Loop: : InnerCG resNorm : 3226.969 + Inner Loop: : Time needed for inner loop: 57.65 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.65 seconds + FWISO Subproblem: 2: d(7): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 3226.969 + + iteration: 7 PROBLEM Number: 3 + FWISO problem 3: d(7) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.52 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32905 + Prä-Residuumnorm: 6087.5886 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4920.7851 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Inner Loop: : InnerCG resNorm : 4326.5503 + Inner Loop: : Time needed for inner loop: 18.97 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.97 seconds + Residuumnorm 1: 4326.5503 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.79 seconds + Intermezzo Residuum: 4325.6698 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3899.0723 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.89 seconds + Inner Loop: : InnerCG resNorm : 3932.9352 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.89 seconds + Inner Loop: : InnerCG resNorm : 3289.3007 + Inner Loop: : Time needed for inner loop: 1:55.48 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.48 minutes + FWISO Subproblem: 3: d(7): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 3289.3007 + + iteration: 7 PROBLEM Number: 4 + FWISO problem 4: d(7) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.54 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32947 + Prä-Residuumnorm: 5925.1171 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4802.2317 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Inner Loop: : InnerCG resNorm : 4300.2485 + Inner Loop: : Time needed for inner loop: 18.87 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.87 seconds + Residuumnorm 1: 4300.2485 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.86 seconds + Intermezzo Residuum: 4301.7284 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3818.0092 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.48 seconds + PhiAdjSO: : 18.83 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.88 seconds + Inner Loop: : InnerCG resNorm : 3931.1769 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.48 seconds + PhiAdjSO: : 18.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.89 seconds + Inner Loop: : InnerCG resNorm : 3411.3587 + Inner Loop: : Time needed for inner loop: 1:55.44 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.44 minutes + FWISO Subproblem: 4: d(7): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 3411.3587 + + iteration: 7 PROBLEM Number: 5 + FWISO problem 5: d(7) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.62 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32994 + Prä-Residuumnorm: 3993.9954 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2894.6304 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + Inner Loop: : InnerCG resNorm : 3389.3676 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Inner Loop: : InnerCG resNorm : 3198.4999 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Inner Loop: : InnerCG resNorm : 2940.0796 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + Inner Loop: : InnerCG resNorm : 2623.6787 + Inner Loop: : Time needed for inner loop: 1:15.84 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 1:15.84 minutes + Residuumnorm 1: 2623.6787 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.69 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.91 seconds + Intermezzo Residuum: 2621.3949 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2451.9397 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : 18.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.95 seconds + Inner Loop: : InnerCG resNorm : 2515.5755 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.96 seconds + Inner Loop: : InnerCG resNorm : 2431.051 + Inner Loop: : Time needed for inner loop: 1:56.20 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:56.20 minutes + FWISO Subproblem: 5: d(7): Finished first / second inner loop ( 4, 2 steps ) + ************************************* + Residuumnorm 2: 2431.051 + + + Iteration Main Looop Counting Variable iter: 8 + + iteration: 8 PROBLEM Number: 0 + FWISO problem 0: d(8) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.65 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33039 + Prä-Residuumnorm: 6080.5514 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4947.3081 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Inner Loop: : InnerCG resNorm : 5341.4067 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Inner Loop: : InnerCG resNorm : 4739.5598 + Inner Loop: : Time needed for inner loop: 37.89 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.89 seconds + Residuumnorm 1: 4739.5598 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.92 seconds + Intermezzo Residuum: 4738.7478 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4498.6023 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : 18.94 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.91 seconds + Inner Loop: : InnerCG resNorm : 4415.4517 + Inner Loop: : Time needed for inner loop: 58.03 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.03 seconds + FWISO Subproblem: 0: d(8): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 4415.4517 + + iteration: 8 PROBLEM Number: 1 + FWISO problem 1: d(8) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.50 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33088 + Prä-Residuumnorm: 5410.6642 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4874.2391 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.28 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Inner Loop: : InnerCG resNorm : 4322.0876 + Inner Loop: : Time needed for inner loop: 18.88 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.88 seconds + Residuumnorm 1: 4322.0876 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.78 seconds + Intermezzo Residuum: 4321.8263 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4447.1796 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.90 seconds + Inner Loop: : InnerCG resNorm : 3995.5344 + Inner Loop: : Time needed for inner loop: 57.76 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.76 seconds + FWISO Subproblem: 1: d(8): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 3995.5344 + + iteration: 8 PROBLEM Number: 2 + FWISO problem 2: d(8) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.50 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33135 + Prä-Residuumnorm: 4786.5628 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4338.2517 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Inner Loop: : InnerCG resNorm : 3693.6398 + Inner Loop: : Time needed for inner loop: 18.94 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.94 seconds + Residuumnorm 1: 3693.6398 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.81 seconds + Intermezzo Residuum: 3694.0606 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3625.1852 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 3407.3533 + Inner Loop: : Time needed for inner loop: 57.68 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.68 seconds + FWISO Subproblem: 2: d(8): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 3407.3533 + + iteration: 8 PROBLEM Number: 3 + FWISO problem 3: d(8) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.49 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33181 + Prä-Residuumnorm: 5674.2644 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4128.0142 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Inner Loop: : InnerCG resNorm : 3707.8221 + Inner Loop: : Time needed for inner loop: 18.93 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.93 seconds + Residuumnorm 1: 3707.8221 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.76 seconds + Intermezzo Residuum: 3706.7802 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4654.3023 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 3411.4395 + Inner Loop: : Time needed for inner loop: 57.68 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.68 seconds + FWISO Subproblem: 3: d(8): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 3411.4395 + + iteration: 8 PROBLEM Number: 4 + FWISO problem 4: d(8) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.49 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33231 + Prä-Residuumnorm: 5447.8869 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3973.8985 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Inner Loop: : InnerCG resNorm : 3824.2616 + Inner Loop: : Time needed for inner loop: 18.88 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.88 seconds + Residuumnorm 1: 3824.2616 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.82 seconds + Intermezzo Residuum: 3825.0118 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4479.19 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.88 seconds + Inner Loop: : InnerCG resNorm : 3504.9817 + Inner Loop: : Time needed for inner loop: 57.69 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.69 seconds + FWISO Subproblem: 4: d(8): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 3504.9817 + + iteration: 8 PROBLEM Number: 5 + FWISO problem 5: d(8) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.64 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33277 + Prä-Residuumnorm: 3193.8002 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2534.4694 und m_max 7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Inner Loop: : InnerCG resNorm : 2858.3097 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Inner Loop: : InnerCG resNorm : 2575.9359 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Inner Loop: : InnerCG resNorm : 2440.795 + Inner Loop: : Time needed for inner loop: 56.92 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 56.92 seconds + Residuumnorm 1: 2440.795 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.82 seconds + Intermezzo Residuum: 2440.9739 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2577.2474 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.91 seconds + Inner Loop: : InnerCG resNorm : 2365.1086 + Inner Loop: : Time needed for inner loop: 58.12 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.12 seconds + FWISO Subproblem: 5: d(8): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 2365.1086 + + + Iteration Main Looop Counting Variable iter: 9 + + iteration: 9 PROBLEM Number: 0 + FWISO problem 0: d(9) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.60 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33320 + Prä-Residuumnorm: 5286.1784 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4793.5811 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Inner Loop: : InnerCG resNorm : 4719.672 + Inner Loop: : Time needed for inner loop: 18.97 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.97 seconds + Residuumnorm 1: 4719.672 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.88 seconds + Intermezzo Residuum: 4719.9683 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3519.808 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.04 seconds + Inner Loop: : InnerCG resNorm : 4506.7224 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : 18.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.95 seconds + Inner Loop: : InnerCG resNorm : 4007.4345 + Inner Loop: : Time needed for inner loop: 1:56.13 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:56.13 minutes + FWISO Subproblem: 0: d(9): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 4007.4345 + + iteration: 9 PROBLEM Number: 1 + FWISO problem 1: d(9) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.60 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33365 + Prä-Residuumnorm: 5470.9031 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4435.6552 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Inner Loop: : InnerCG resNorm : 4162.1189 + Inner Loop: : Time needed for inner loop: 18.87 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.87 seconds + Residuumnorm 1: 4162.1189 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.79 seconds + Intermezzo Residuum: 4161.5409 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4047.0225 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.84 seconds + Inner Loop: : InnerCG resNorm : 3848.6725 + Inner Loop: : Time needed for inner loop: 57.63 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.63 seconds + FWISO Subproblem: 1: d(9): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 3848.6725 + + iteration: 9 PROBLEM Number: 2 + FWISO problem 2: d(9) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.48 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33413 + Prä-Residuumnorm: 4084.6503 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3331.8725 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + Inner Loop: : InnerCG resNorm : 3506.1634 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Inner Loop: : InnerCG resNorm : 3072.6548 + Inner Loop: : Time needed for inner loop: 37.75 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.75 seconds + Residuumnorm 1: 3072.6548 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.77 seconds + Intermezzo Residuum: 3072.3388 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2784.2217 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.84 seconds + Inner Loop: : InnerCG resNorm : 2892.0865 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : 18.91 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.84 seconds + Inner Loop: : InnerCG resNorm : 2687.9467 + Inner Loop: : Time needed for inner loop: 1:55.36 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.36 minutes + FWISO Subproblem: 2: d(9): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 2687.9467 + + iteration: 9 PROBLEM Number: 3 + FWISO problem 3: d(9) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.51 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33456 + Prä-Residuumnorm: 4505.4355 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2949.9245 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Inner Loop: : InnerCG resNorm : 3558.4861 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Inner Loop: : InnerCG resNorm : 3192.4372 + Inner Loop: : Time needed for inner loop: 37.73 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.73 seconds + Residuumnorm 1: 3192.4372 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.82 seconds + Intermezzo Residuum: 3192.4287 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3326.0157 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.95 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.84 seconds + Inner Loop: : InnerCG resNorm : 3014.6405 + Inner Loop: : Time needed for inner loop: 57.68 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.68 seconds + FWISO Subproblem: 3: d(9): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 3014.6405 + + iteration: 9 PROBLEM Number: 4 + FWISO problem 4: d(9) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.52 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33505 + Prä-Residuumnorm: 4551.7557 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2988.2033 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + Inner Loop: : InnerCG resNorm : 3686.2218 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 3354.1728 + Inner Loop: : Time needed for inner loop: 37.79 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.79 seconds + Residuumnorm 1: 3354.1728 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.77 seconds + Intermezzo Residuum: 3354.5693 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3368.1611 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.87 seconds + Inner Loop: : InnerCG resNorm : 3131.8309 + Inner Loop: : Time needed for inner loop: 57.68 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.68 seconds + FWISO Subproblem: 4: d(9): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 3131.8309 + + iteration: 9 PROBLEM Number: 5 + FWISO problem 5: d(9) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.65 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33552 + Prä-Residuumnorm: 2894.8334 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2067.4994 und m_max 7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.68 seconds + Inner Loop: : InnerCG resNorm : 2603.8264 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Inner Loop: : InnerCG resNorm : 2440.9909 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Inner Loop: : InnerCG resNorm : 2317.2009 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Inner Loop: : InnerCG resNorm : 2110.228 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Inner Loop: : InnerCG resNorm : 1993.6958 + Inner Loop: : Time needed for inner loop: 1:34.84 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 1:34.84 minutes + Residuumnorm 1: 1993.6958 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.69 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.89 seconds + Intermezzo Residuum: 1992.343 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2102.3957 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.71 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.49 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.96 seconds + Inner Loop: : InnerCG resNorm : 1942.7023 + Inner Loop: : Time needed for inner loop: 58.20 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.20 seconds + FWISO Subproblem: 5: d(9): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 1942.7023 + + + Iteration Main Looop Counting Variable iter: 10 + + iteration: 10 PROBLEM Number: 0 + FWISO problem 0: d(10) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.60 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33596 + Prä-Residuumnorm: 4539.3204 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3704.6877 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Inner Loop: : InnerCG resNorm : 4282.5304 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + Inner Loop: : InnerCG resNorm : 3730.2772 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.28 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Inner Loop: : InnerCG resNorm : 3322.3507 + Inner Loop: : Time needed for inner loop: 56.85 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 56.85 seconds + Residuumnorm 1: 3322.3507 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.68 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.86 seconds + Intermezzo Residuum: 3321.2675 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3780.916 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.01 seconds + Inner Loop: : InnerCG resNorm : 3085.5337 + Inner Loop: : Time needed for inner loop: 58.05 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.05 seconds + FWISO Subproblem: 0: d(10): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 3085.5337 + + iteration: 10 PROBLEM Number: 1 + FWISO problem 1: d(10) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.55 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33645 + Prä-Residuumnorm: 6089.809 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4443.7021 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 4511.1137 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 4006.3528 + Inner Loop: : Time needed for inner loop: 37.71 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.71 seconds + Residuumnorm 1: 4006.3528 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.81 seconds + Intermezzo Residuum: 4006.0336 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4054.3644 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.91 seconds + Inner Loop: : InnerCG resNorm : 3706.4405 + Inner Loop: : Time needed for inner loop: 57.66 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.66 seconds + FWISO Subproblem: 1: d(10): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 3706.4405 + + iteration: 10 PROBLEM Number: 2 + FWISO problem 2: d(10) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.48 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33689 + Prä-Residuumnorm: 4300.0175 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3903.7832 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Inner Loop: : InnerCG resNorm : 3550.7289 + Inner Loop: : Time needed for inner loop: 18.88 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.88 seconds + Residuumnorm 1: 3550.7289 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.83 seconds + Intermezzo Residuum: 3551.1495 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3615.5201 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.97 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 3247.0795 + Inner Loop: : Time needed for inner loop: 57.73 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.73 seconds + FWISO Subproblem: 2: d(10): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 3247.0795 + + iteration: 10 PROBLEM Number: 3 + FWISO problem 3: d(10) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.50 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33736 + Prä-Residuumnorm: 4816.1284 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3984.7392 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Inner Loop: : InnerCG resNorm : 3539.3505 + Inner Loop: : Time needed for inner loop: 18.90 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.90 seconds + Residuumnorm 1: 3539.3505 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.79 seconds + Intermezzo Residuum: 3539.3459 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3199.8387 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.96 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 3274.1142 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 2726.3065 + Inner Loop: : Time needed for inner loop: 1:55.62 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.62 minutes + FWISO Subproblem: 3: d(10): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 2726.3065 + + iteration: 10 PROBLEM Number: 4 + FWISO problem 4: d(10) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.53 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33785 + Prä-Residuumnorm: 4823.3871 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3994.9575 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Inner Loop: : InnerCG resNorm : 3610.5268 + Inner Loop: : Time needed for inner loop: 18.91 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.91 seconds + Residuumnorm 1: 3610.5268 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.82 seconds + Intermezzo Residuum: 3611.2245 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3212.2441 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 3360.0343 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + PhiAdjSO: : 19.01 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.80 seconds + Inner Loop: : InnerCG resNorm : 2780.4666 + Inner Loop: : Time needed for inner loop: 1:55.55 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.55 minutes + FWISO Subproblem: 4: d(10): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 2780.4666 + + iteration: 10 PROBLEM Number: 5 + FWISO problem 5: d(10) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.63 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33830 + Prä-Residuumnorm: 2880.3346 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2386.4204 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Inner Loop: : InnerCG resNorm : 2282.621 + Inner Loop: : Time needed for inner loop: 18.94 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.94 seconds + Residuumnorm 1: 2282.621 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.92 seconds + Intermezzo Residuum: 2282.703 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1882.6792 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.95 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.74 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.01 seconds + Inner Loop: : InnerCG resNorm : 2188.1139 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.67 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.81 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.95 seconds + Inner Loop: : InnerCG resNorm : 2089.8421 + Inner Loop: : Time needed for inner loop: 1:56.58 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:56.58 minutes + FWISO Subproblem: 5: d(10): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 2089.8421 + + + Iteration Main Looop Counting Variable iter: 11 + + iteration: 11 PROBLEM Number: 0 + FWISO problem 0: d(11) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.64 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33876 + Prä-Residuumnorm: 4204.5353 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3946.8431 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Inner Loop: : InnerCG resNorm : 3733.4032 + Inner Loop: : Time needed for inner loop: 18.94 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.94 seconds + Residuumnorm 1: 3733.4032 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.83 seconds + Intermezzo Residuum: 3733.6459 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3151.8585 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : 18.92 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.97 seconds + Inner Loop: : InnerCG resNorm : 3556.62 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.68 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.87 seconds + Inner Loop: : InnerCG resNorm : 3269.0029 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : 18.95 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.89 seconds + Inner Loop: : InnerCG resNorm : 2899.6708 + Inner Loop: : Time needed for inner loop: 2:54.19 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 2:54.19 minutes + FWISO Subproblem: 0: d(11): Finished first / second inner loop ( 1, 3 steps ) + ************************************* + Residuumnorm 2: 2899.6708 + + iteration: 11 PROBLEM Number: 1 + FWISO problem 1: d(11) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.51 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33922 + Prä-Residuumnorm: 5562.6041 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4810.8037 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 4133.0552 + Inner Loop: : Time needed for inner loop: 18.88 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.88 seconds + Residuumnorm 1: 4133.0552 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.75 seconds + Intermezzo Residuum: 4132.8065 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3333.0342 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.86 seconds + Inner Loop: : InnerCG resNorm : 3677.277 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.82 seconds + Inner Loop: : InnerCG resNorm : 3332.1314 + Inner Loop: : Time needed for inner loop: 1:55.36 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.36 minutes + FWISO Subproblem: 1: d(11): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 3332.1314 + + iteration: 11 PROBLEM Number: 2 + FWISO problem 2: d(11) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.49 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 33964 + Prä-Residuumnorm: 4496.9587 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3674.3191 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Inner Loop: : InnerCG resNorm : 3723.9856 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Inner Loop: : InnerCG resNorm : 3124.3516 + Inner Loop: : Time needed for inner loop: 37.76 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.76 seconds + Residuumnorm 1: 3124.3516 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.79 seconds + Intermezzo Residuum: 3124.8703 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3403 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.84 seconds + Inner Loop: : InnerCG resNorm : 2828.5633 + Inner Loop: : Time needed for inner loop: 57.69 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.69 seconds + FWISO Subproblem: 2: d(11): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 2828.5633 + + iteration: 11 PROBLEM Number: 3 + FWISO problem 3: d(11) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.48 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34008 + Prä-Residuumnorm: 3972.1845 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2957.8338 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 3145.0498 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Inner Loop: : InnerCG resNorm : 2854.0659 + Inner Loop: : Time needed for inner loop: 37.71 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.71 seconds + Residuumnorm 1: 2854.0659 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.84 seconds + Intermezzo Residuum: 2854.0291 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3305.6532 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 2695.0684 + Inner Loop: : Time needed for inner loop: 57.66 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.66 seconds + FWISO Subproblem: 3: d(11): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 2695.0684 + + iteration: 11 PROBLEM Number: 4 + FWISO problem 4: d(11) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.49 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34054 + Prä-Residuumnorm: 3442.4617 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2566.0888 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Inner Loop: : InnerCG resNorm : 2979.8738 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Inner Loop: : InnerCG resNorm : 2771.7002 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Inner Loop: : InnerCG resNorm : 2375.319 + Inner Loop: : Time needed for inner loop: 56.68 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 56.68 seconds + Residuumnorm 1: 2375.319 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.76 seconds + Intermezzo Residuum: 2375.0895 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2867.5236 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.91 seconds + Inner Loop: : InnerCG resNorm : 2259.3495 + Inner Loop: : Time needed for inner loop: 57.82 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.82 seconds + FWISO Subproblem: 4: d(11): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 2259.3495 + + iteration: 11 PROBLEM Number: 5 + FWISO problem 5: d(11) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.61 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34087 + Prä-Residuumnorm: 2685.81 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2002.7273 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Inner Loop: : InnerCG resNorm : 2369.6105 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Inner Loop: : InnerCG resNorm : 2232.1852 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Inner Loop: : InnerCG resNorm : 2046.3381 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.69 seconds + Inner Loop: : InnerCG resNorm : 1897.4843 + Inner Loop: : Time needed for inner loop: 1:15.91 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 1:15.91 minutes + Residuumnorm 1: 1897.4843 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.90 seconds + Intermezzo Residuum: 1897.0847 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2220.6708 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : 18.91 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.00 seconds + Inner Loop: : InnerCG resNorm : 1836.4702 + Inner Loop: : Time needed for inner loop: 58.16 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.16 seconds + FWISO Subproblem: 5: d(11): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 1836.4702 + + + Iteration Main Looop Counting Variable iter: 12 + + iteration: 12 PROBLEM Number: 0 + FWISO problem 0: d(12) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.57 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34133 + Prä-Residuumnorm: 3755.927 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3173.1567 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Inner Loop: : InnerCG resNorm : 3397.6557 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Inner Loop: : InnerCG resNorm : 3123.6987 + Inner Loop: : Time needed for inner loop: 37.95 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.95 seconds + Residuumnorm 1: 3123.6987 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.80 seconds + Intermezzo Residuum: 3123.629 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3442.4736 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.93 seconds + Inner Loop: : InnerCG resNorm : 2975.0294 + Inner Loop: : Time needed for inner loop: 58.03 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.03 seconds + FWISO Subproblem: 0: d(12): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 2975.0294 + + iteration: 12 PROBLEM Number: 1 + FWISO problem 1: d(12) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.53 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34179 + Prä-Residuumnorm: 4513.4267 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3513.0829 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + Inner Loop: : InnerCG resNorm : 3669.0914 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.27 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Inner Loop: : InnerCG resNorm : 3243.1364 + Inner Loop: : Time needed for inner loop: 37.77 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.77 seconds + Residuumnorm 1: 3243.1364 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.71 seconds + Intermezzo Residuum: 3243.0045 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3608.9043 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.81 seconds + Inner Loop: : InnerCG resNorm : 3059.3188 + Inner Loop: : Time needed for inner loop: 57.64 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.64 seconds + FWISO Subproblem: 1: d(12): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 3059.3188 + + iteration: 12 PROBLEM Number: 2 + FWISO problem 2: d(12) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.46 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34224 + Prä-Residuumnorm: 3879.8443 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3524.9696 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Inner Loop: : InnerCG resNorm : 3252.8468 + Inner Loop: : Time needed for inner loop: 18.91 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.91 seconds + Residuumnorm 1: 3252.8468 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.58 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.76 seconds + Intermezzo Residuum: 3253.2534 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2642.4079 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.84 seconds + Inner Loop: : InnerCG resNorm : 3015.8536 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 2514.4618 + Inner Loop: : Time needed for inner loop: 1:55.59 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.59 minutes + FWISO Subproblem: 2: d(12): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 2514.4618 + + iteration: 12 PROBLEM Number: 3 + FWISO problem 3: d(12) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.48 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34270 + Prä-Residuumnorm: 4206.9275 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3669.7798 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Inner Loop: : InnerCG resNorm : 3127.5968 + Inner Loop: : Time needed for inner loop: 18.87 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.87 seconds + Residuumnorm 1: 3127.5968 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.76 seconds + Intermezzo Residuum: 3127.6739 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3150.9057 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.91 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.87 seconds + Inner Loop: : InnerCG resNorm : 2880.32 + Inner Loop: : Time needed for inner loop: 57.71 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.71 seconds + FWISO Subproblem: 3: d(12): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 2880.32 + + iteration: 12 PROBLEM Number: 4 + FWISO problem 4: d(12) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.54 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34318 + Prä-Residuumnorm: 3283.2996 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3004.6816 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Inner Loop: : InnerCG resNorm : 2705.9427 + Inner Loop: : Time needed for inner loop: 18.88 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.88 seconds + Residuumnorm 1: 2705.9427 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.79 seconds + Intermezzo Residuum: 2706.179 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2461.4494 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.49 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.86 seconds + Inner Loop: : InnerCG resNorm : 2566.2495 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.79 seconds + Inner Loop: : InnerCG resNorm : 2310.7246 + Inner Loop: : Time needed for inner loop: 1:55.52 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.52 minutes + FWISO Subproblem: 4: d(12): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 2310.7246 + + iteration: 12 PROBLEM Number: 5 + FWISO problem 5: d(12) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 8.03 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34362 + Prä-Residuumnorm: 2428.9281 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2274.4906 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Inner Loop: : InnerCG resNorm : 2165.4663 + Inner Loop: : Time needed for inner loop: 18.96 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.96 seconds + Residuumnorm 1: 2165.4663 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.73 seconds + Intermezzo Residuum: 2165.5973 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1807.4491 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : 18.94 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.89 seconds + Inner Loop: : InnerCG resNorm : 2085.6751 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.88 seconds + Inner Loop: : InnerCG resNorm : 1912.4139 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.67 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.49 seconds + PhiAdjSO: : 18.92 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.69 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.81 seconds + Inner Loop: : InnerCG resNorm : 1772.6428 + Inner Loop: : Time needed for inner loop: 2:54.02 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 2:54.02 minutes + FWISO Subproblem: 5: d(12): Finished first / second inner loop ( 1, 3 steps ) + ************************************* + Residuumnorm 2: 1772.6428 + + + Iteration Main Looop Counting Variable iter: 13 + + iteration: 13 PROBLEM Number: 0 + FWISO problem 0: d(13) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.62 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34409 + Prä-Residuumnorm: 3991.7754 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3682.0931 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Inner Loop: : InnerCG resNorm : 3598.4165 + Inner Loop: : Time needed for inner loop: 18.96 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.96 seconds + Residuumnorm 1: 3598.4165 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.74 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.90 seconds + Intermezzo Residuum: 3598.6224 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3292.7752 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.96 seconds + Inner Loop: : InnerCG resNorm : 3419.8704 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.49 seconds + PhiAdjSO: : 18.83 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.93 seconds + Inner Loop: : InnerCG resNorm : 3036.0451 + Inner Loop: : Time needed for inner loop: 1:56.09 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:56.09 minutes + FWISO Subproblem: 0: d(13): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 3036.0451 + + iteration: 13 PROBLEM Number: 1 + FWISO problem 1: d(13) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.52 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34454 + Prä-Residuumnorm: 4429.106 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3938.2784 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 3586.5051 + Inner Loop: : Time needed for inner loop: 18.86 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.86 seconds + Residuumnorm 1: 3586.5051 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.84 seconds + Intermezzo Residuum: 3586.2936 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3187.3339 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.82 seconds + Inner Loop: : InnerCG resNorm : 3362.6278 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.79 seconds + Inner Loop: : InnerCG resNorm : 2874.7695 + Inner Loop: : Time needed for inner loop: 1:55.26 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.26 minutes + FWISO Subproblem: 1: d(13): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 2874.7695 + + iteration: 13 PROBLEM Number: 2 + FWISO problem 2: d(13) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.49 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34501 + Prä-Residuumnorm: 3394.2284 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2775.3941 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 2972.1176 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Inner Loop: : InnerCG resNorm : 2646.0674 + Inner Loop: : Time needed for inner loop: 37.73 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.73 seconds + Residuumnorm 1: 2646.0674 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.77 seconds + Intermezzo Residuum: 2646.1923 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2852.9513 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.78 seconds + Inner Loop: : InnerCG resNorm : 2474.55 + Inner Loop: : Time needed for inner loop: 57.69 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.69 seconds + FWISO Subproblem: 2: d(13): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 2474.55 + + iteration: 13 PROBLEM Number: 3 + FWISO problem 3: d(13) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.48 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34549 + Prä-Residuumnorm: 4140.8281 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3250.908 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.23 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Inner Loop: : InnerCG resNorm : 3131.1822 + Inner Loop: : Time needed for inner loop: 18.83 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.83 seconds + Residuumnorm 1: 3131.1822 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.75 seconds + Intermezzo Residuum: 3131.2424 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2791.2587 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.49 seconds + PhiAdjSO: : 18.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.87 seconds + Inner Loop: : InnerCG resNorm : 2898.1788 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.88 seconds + Inner Loop: : InnerCG resNorm : 2437.2408 + Inner Loop: : Time needed for inner loop: 1:55.56 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.56 minutes + FWISO Subproblem: 3: d(13): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 2437.2408 + + iteration: 13 PROBLEM Number: 4 + FWISO problem 4: d(13) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.55 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34592 + Prä-Residuumnorm: 3262.5682 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2687.1385 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Inner Loop: : InnerCG resNorm : 2672.2058 + Inner Loop: : Time needed for inner loop: 18.88 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.88 seconds + Residuumnorm 1: 2672.2058 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.80 seconds + Intermezzo Residuum: 2672.5689 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2854.2377 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 2530.3046 + Inner Loop: : Time needed for inner loop: 57.66 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.66 seconds + FWISO Subproblem: 4: d(13): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 2530.3046 + + iteration: 13 PROBLEM Number: 5 + FWISO problem 5: d(13) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.64 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34640 + Prä-Residuumnorm: 2161.9865 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1822.0697 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.67 seconds + Inner Loop: : InnerCG resNorm : 2013.1001 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Inner Loop: : InnerCG resNorm : 1901.6898 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + Inner Loop: : InnerCG resNorm : 1761.5031 + Inner Loop: : Time needed for inner loop: 56.91 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 56.91 seconds + Residuumnorm 1: 1761.5031 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.67 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.90 seconds + Intermezzo Residuum: 1761.5541 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1977.5939 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.83 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.89 seconds + Inner Loop: : InnerCG resNorm : 1698.4184 + Inner Loop: : Time needed for inner loop: 57.94 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.94 seconds + FWISO Subproblem: 5: d(13): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 1698.4184 + + + Iteration Main Looop Counting Variable iter: 14 + + iteration: 14 PROBLEM Number: 0 + FWISO problem 0: d(14) + shot: 0: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.60 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34685 + Prä-Residuumnorm: 3693.2834 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3066.0823 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.82 seconds + Inner Loop: : InnerCG resNorm : 3497.0747 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Inner Loop: : InnerCG resNorm : 3006.3005 + Inner Loop: : Time needed for inner loop: 38.09 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 38.09 seconds + Residuumnorm 1: 3006.3005 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.92 seconds + Intermezzo Residuum: 3006.1055 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3369.9178 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.67 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.47 seconds + PhiAdjSO: : 18.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.90 seconds + Inner Loop: : InnerCG resNorm : 2800.2414 + Inner Loop: : Time needed for inner loop: 58.02 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 58.02 seconds + FWISO Subproblem: 0: d(14): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 2800.2414 + + iteration: 14 PROBLEM Number: 1 + FWISO problem 1: d(14) + shot: 1: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.58 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34733 + Prä-Residuumnorm: 4053.1655 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 3243.5992 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 3321.3446 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 3059.2348 + Inner Loop: : Time needed for inner loop: 37.70 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.70 seconds + Residuumnorm 1: 3059.2348 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.81 seconds + Intermezzo Residuum: 3059.2596 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3484.98 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.49 seconds + PhiAdjSO: : 18.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.82 seconds + Inner Loop: : InnerCG resNorm : 2901.9504 + Inner Loop: : Time needed for inner loop: 57.70 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.70 seconds + FWISO Subproblem: 1: d(14): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 2901.9504 + + iteration: 14 PROBLEM Number: 2 + FWISO problem 2: d(14) + shot: 2: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.53 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34778 + Prä-Residuumnorm: 3273.2878 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2974.8955 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.57 seconds + Inner Loop: : InnerCG resNorm : 2726.8642 + Inner Loop: : Time needed for inner loop: 18.90 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.90 seconds + Residuumnorm 1: 2726.8642 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.75 seconds + Intermezzo Residuum: 2726.8834 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2476.1674 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.83 seconds + Inner Loop: : InnerCG resNorm : 2544.747 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 2286.3363 + Inner Loop: : Time needed for inner loop: 1:55.55 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 1:55.55 minutes + FWISO Subproblem: 2: d(14): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 2286.3363 + + iteration: 14 PROBLEM Number: 3 + FWISO problem 3: d(14) + shot: 3: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.53 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34823 + Prä-Residuumnorm: 3095.8179 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2187.4362 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.24 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Inner Loop: : InnerCG resNorm : 2642.2842 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.53 seconds + Inner Loop: : InnerCG resNorm : 2441.4093 + Inner Loop: : Time needed for inner loop: 37.73 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.73 seconds + Residuumnorm 1: 2441.4093 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.73 seconds + Intermezzo Residuum: 2441.4949 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2591.3269 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.51 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : 18.93 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.85 seconds + Inner Loop: : InnerCG resNorm : 2312.7768 + Inner Loop: : Time needed for inner loop: 57.71 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.71 seconds + FWISO Subproblem: 3: d(14): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 2312.7768 + + iteration: 14 PROBLEM Number: 4 + FWISO problem 4: d(14) + shot: 4: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.55 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34871 + Prä-Residuumnorm: 3166.2636 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2347.0375 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.26 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + Inner Loop: : InnerCG resNorm : 2662.0526 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Inner Loop: : InnerCG resNorm : 2460.0397 + Inner Loop: : Time needed for inner loop: 37.82 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 37.82 seconds + Residuumnorm 1: 2460.0397 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.59 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.82 seconds + Intermezzo Residuum: 2460.1451 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2492.9876 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.79 seconds + Inner Loop: : InnerCG resNorm : 2331.0717 + Inner Loop: : Time needed for inner loop: 57.69 seconds + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 57.69 seconds + FWISO Subproblem: 4: d(14): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 2331.0717 + + iteration: 14 PROBLEM Number: 5 + FWISO problem 5: d(14) + shot: 5: Solving forward problem... + Initialization: 0.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 7.64 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34917 + Prä-Residuumnorm: 2010.2239 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1904.8719 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.25 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Inner Loop: : InnerCG resNorm : 1874.7586 + Inner Loop: : Time needed for inner loop: 18.96 seconds + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 18.96 seconds + Residuumnorm 1: 1874.7586 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.63 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.83 seconds + Intermezzo Residuum: 1874.843 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1654.8974 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.60 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.52 seconds + PhiAdjSO: : 18.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.61 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.93 seconds + Inner Loop: : InnerCG resNorm : 1827.9835 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.64 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.50 seconds + PhiAdjSO: : 18.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.66 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.96 seconds + Inner Loop: : InnerCG resNorm : 1729.8271 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.62 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.55 seconds + PhiAdjSO: : 18.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 9.67 seconds + Initialization: 0.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 10.03 seconds + Inner Loop: : InnerCG resNorm : 1569.7146 + Inner Loop: : Time needed for inner loop: 2:54.34 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 2:54.34 minutes + FWISO Subproblem: 5: d(14): Finished first / second inner loop ( 1, 3 steps ) + ************************************* + Residuumnorm 2: 1569.7146 + FWISO: d(15)= 0 + 223163.4 + 69584.003 + 18240 + 14577.709 + 9392.8656 + 8947.2967 + 6894.6476 + 6041.2687 + 6080.5514 + 5286.1784 + 4539.3204 + 4204.5353 + 3755.927 + 3991.7754 + 3693.2834 + + + 157344.78 + 54301.754 + 23162.658 + 9781.5883 + 9735.5921 + 6764.7741 + 6796.3702 + 5850.4973 + 5410.6642 + 5470.9031 + 6089.809 + 5562.6041 + 4513.4267 + 4429.106 + 4053.1655 + + + 177771.59 + 49539.969 + 21508.875 + 11887.734 + 9725.717 + 5519.5215 + 5254.0518 + 4535.4219 + 4786.5628 + 4084.6503 + 4300.0175 + 4496.9587 + 3879.8443 + 3394.2284 + 3273.2878 + + + 208269.18 + 33610.496 + 19765.424 + 14786.966 + 12688.774 + 9044.5727 + 7051.7691 + 6087.5886 + 5674.2644 + 4505.4355 + 4816.1284 + 3972.1845 + 4206.9275 + 4140.8281 + 3095.8179 + + + 189591.52 + 35082.966 + 15522.719 + 10610.632 + 10644.251 + 8112.4678 + 5950.2928 + 5925.1171 + 5447.8869 + 4551.7557 + 4823.3871 + 3442.4617 + 3283.2996 + 3262.5682 + 3166.2636 + + + 122569.1 + 33538.085 + 14736.871 + 10056.114 + 6737.7095 + 5888.2624 + 4406.4943 + 3993.9954 + 3193.8002 + 2894.8334 + 2880.3346 + 2685.81 + 2428.9281 + 2161.9865 + 2010.2239 + + +end program after 3:50:50.00 hours on 128 procs at Thu Jun 22 02:30:01 2023 diff --git a/log/2023_06_21_zVp15/testconf.conf b/log/2023_06_21_zVp15/testconf.conf new file mode 100644 index 0000000000000000000000000000000000000000..e7abbf2734b18fafe6a78145ccb337cb7c0a284e --- /dev/null +++ b/log/2023_06_21_zVp15/testconf.conf @@ -0,0 +1,102 @@ +# Regular Expression um aus Test_Config von Clion eine ... M++ Config zu machen +# \{"([A-Za-z0-9_ ]+)", +"([A-Za-z0-9_ ,\.\-]+)"}. + +#Durchlauf 2023Mai05 mit 4 Quellen, 8 Iterationen, Materialpunkt, level 1 (Ergebnisse ganz gut) +#Durchlauf 2023Mai05 mit 4 Quellen, 8 Iterationen, TwoMedium, level 1 +#Back to FastMode (2 Quellen, 2 Iterationen, Pkt.Material, level 0) +#21.06 Receiver wieder auf 64. Bei multi noch nicht, jetzt aber bei rho rekonstruktion + + #Problem= VAcousticWaveTwoMedium;//<----- Geometrie oder so Siehe: src/Problems/FWIInversionProblems.cpp + Problem= VAcousticWaveC2Benchmark; + FWISO_Steps = 15; #Anzahl Iterationen + Monoparam= Vp; #can be "multi"/empty or "Vp", "Tau_p", "Rho" + plot_tStep= -1; + level = 3; + T=0.6; + dt= 0.001; + FWISourceCount0=6; #Anzahl Quellen + + FWIReconstructRho= 0; + FWIReconstructV_P= 1; + FWIReconstructTauP= 0; + + #Schnelle Configuration + #Problem= VAcousticWaveTwoMedium;//<----- Geometrie oder so Siehe: src/Problems/FWIInversionProblems.cpp + #Problem= VAcousticWaveC2Benchmark; + #FWISO_Steps = 2;//scheint zu klappen! + #Monoparam= Rho; #can be "multi"/empty or "Vp", "Tau_p", "Rho" + #plot_tStep= -1; + #level = 2; + #T=0.6; + #dt= 0.002; + + + ConfigVerbose=2; + ForwardSolver= VADGTS; + Distribution= RCB; + Model = FWIInverse_DGTS; + Mesh= SeismogramGrid_test; + + useTaper=1; + taperRadiusSource=0; + taperRadiusReceiver=0; + taperExponent=-0.1; + taperIgnoreReceiverCells=1; + taperIgnoreSourceCells=1; + #Monoparam= Rho; #can be "multi"/empty or "Vp", "Tau_p", "Rho" + ReconstructionType=SO;#!!! + FWIReceiverWaypoints= 2; + FWIReceiverWaypoint0= 1350.0, 370.0; + FWIReceiverWaypoint1= 1350.0, 1630.0; + #FWIReceiverWaypoint0= 1600.0, 370.0;#Selbst weiter nach "rechts" geschoben + #FWIReceiverWaypoint1= 1600.0, 1630.0; + FWIReceiverIncludeLastWaypoint= 1; + FWIReceiverCount0= 64;//Anzahl Receiver + UseSparseMatrix=1; + Qfactor=100; + SignalName=RickerDerivative; + SignalDelay=0; + SignalCutoff=0.8; + SignalFreq=25; + numL=0;#!!! + FWISourceWaypoints=2; + FWISourceWaypoint0=600,370; + FWISourceWaypoint1=600,1620; + #FWISourceCount0=2; #Anzahl Quelle + #FWISourceCount0=2; + FWIReceiverIncludeLastWaypoint=1; + measurement_space= point; + measurement_time= point; + compMeasure= 0; + source_component= 2; + perturbation_comp= 2; + dampingFlux= 1; + allowPlotting_M=1; + allowPlotting_WF=0; + plotfactor= 10; + parametrization= taup;#!!!! + #T=0.6; + #dt= 0.002; + deg= 1; + #level = 0;#Feinheit des Gitters (1 mehr -> Halbierung)//Achtung: 3 Böse, <2 Gut + TimeVerbose= 1; + rkorder= -2; + #plot_tStep= -1; + #FWISO_Steps = 2;//scheint zu klappen! + Steps = 2;//scheint auch nichts zu bringen :( + + Kmax=150; + Keps= 1e-07; + Overlap= dG1; + debugAdjoint= 0; + debugFrechet= 1; + source_factor= 242574257420000.5742; + LinearSolver= LS; + LinearVerbose= -1; + LinearSteps=100; + LinearNthIterOutput= 1; + LinearEpsilon= 1e-12; + LinearReduction= 0.0001; + FWINonlinearSolver= FWISO;#!!! + FWI_DebugPlottingLevel= 1; + CGREGINNCanonic_Steps=3; diff --git a/log/2023_06_27_IC_RhoMono_HighResolution/0testconf.conf b/log/2023_06_27_IC_RhoMono_HighResolution/0testconf.conf new file mode 100644 index 0000000000000000000000000000000000000000..e23eda7e5a3c6b4ee4c9bcdab3969da067c64c62 --- /dev/null +++ b/log/2023_06_27_IC_RhoMono_HighResolution/0testconf.conf @@ -0,0 +1,105 @@ +# Regular Expression um aus Test_Config von Clion eine ... M++ Config zu machen +# \{"([A-Za-z0-9_ ]+)", +"([A-Za-z0-9_ ,\.\-]+)"}. + +#Durchlauf 2023Mai05 mit 4 Quellen, 8 Iterationen, Materialpunkt, level 1 (Ergebnisse ganz gut) +#Durchlauf 2023Mai05 mit 4 Quellen, 8 Iterationen, TwoMedium, level 1 +#Back to FastMode (2 Quellen, 2 Iterationen, Pkt.Material, level 0) +#21.06 Receiver wieder auf 64. Bei multi noch nicht, jetzt aber bei rho rekonstruktion +#Neuer größerer Durchlauf 26.Juni Ohne Inverse Crime für Vp + + #Problem= VAcousticWaveTwoMedium;//<----- Geometrie oder so Siehe: src/Problems/FWIInversionProblems.cpp + Problem= VAcousticWaveC2Benchmark; + FWISO_Steps = 15; #Anzahl Iterationen + Monoparam= Rho; #can be "multi"/empty or "Vp", "Tau_p", "Rho" + plot_tStep= -1; + level = 3; + T=0.6; + dt= 0.0005; + FWISourceCount0=6; #Anzahl Quellen, Empfänger default 64 + deg = 2; #In paper CRC deg = 2. Vor 26.Juni2023 wars 1 + FWIReconstructRho= 1; + FWIReconstructV_P= 0; + FWIReconstructTauP= 0; + numL=0;#!!! + + #seismopath = C2NoDampingT06dt0005/C2NoDampingT06dt0005;#im Build Ordner! + #seismopath = readmePlease;//klappt in der ersten Iteration mit ..Please0 + #seismopath = ../FWI/conf/C2NoDampingT06dt0005/C2NoDampingT06dt0005;//mal sehen obs klappt + #seismopath = /home/lionbart/fwi/FWI/conf/C2NoDampingT06dt0005/C2NoDampingT06dt0005;//OUT OF RANGE ERROR + + #ReadFormat = FWI;#IFOS ist falsches Format. + #SpecfileNrOfSamples = 6; + + SaveObservedSeismogram = 0;#Plottet "d_obs", das Vorwärtsgelöste Wellenfeld (mit echten Materialparam) + + SignalName=Ricker;#RickerDerivative vorher!!! Geändert 26.Juni.2023 + + + + ConfigVerbose=2; + ForwardSolver= VADGTS; + Distribution= RCB; + Model = FWIInverse_DGTS; + Mesh= SeismogramGrid_test; + + useTaper=1; + taperRadiusSource=0; + taperRadiusReceiver=0; + taperExponent=-0.1; + taperIgnoreReceiverCells=1; + taperIgnoreSourceCells=1; + #Monoparam= Rho; #can be "multi"/empty or "Vp", "Tau_p", "Rho" + ReconstructionType=SO;#!!! + FWIReceiverWaypoints= 2; + FWIReceiverWaypoint0= 1350.0, 370.0; + FWIReceiverWaypoint1= 1350.0, 1630.0; + FWIReceiverIncludeLastWaypoint= 1; + FWIReceiverCount0= 64;//Anzahl Receiver + UseSparseMatrix=1; + Qfactor=100; + #SignalName=Ricker;# RickerDerivative vorher!!! Geändert 26.Juni.2023 + SignalDelay=0; + SignalCutoff=0.8; + SignalFreq=25; + #numL=0;#!!! + FWISourceWaypoints=2; + FWISourceWaypoint0=600,370; + FWISourceWaypoint1=600,1620; + #FWISourceCount0=2; #Anzahl Quelle + #FWISourceCount0=2; + FWIReceiverIncludeLastWaypoint=1; + measurement_space= point; + measurement_time= point; + compMeasure= 0; + source_component= 2; + perturbation_comp= 2; + dampingFlux= 1; + allowPlotting_M=1; + allowPlotting_WF=0; + plotfactor= 10; + parametrization= taup;#!!!! + #T=0.6; + #dt= 0.002; + #deg= 1; + #level = 0;#Feinheit des Gitters (1 mehr -> Halbierung)//Achtung: 3 Böse, <2 Gut + TimeVerbose= 1; + rkorder= -2; + #plot_tStep= -1; + #FWISO_Steps = 2;//scheint zu klappen! + Steps = 2;//scheint auch nichts zu bringen :( + + Kmax=150; + Keps= 1e-07; + Overlap= dG1; + debugAdjoint= 0; + debugFrechet= 1; + source_factor= 242574257420000.5742; + LinearSolver= LS; + LinearVerbose= -1; + LinearSteps=100; + LinearNthIterOutput= 1; + LinearEpsilon= 1e-12; + LinearReduction= 0.0001; + FWINonlinearSolver= FWISO;#!!! + FWI_DebugPlottingLevel= 1; + CGREGINNCanonic_Steps=3; diff --git a/log/2023_06_27_IC_RhoMono_HighResolution/logfile.log b/log/2023_06_27_IC_RhoMono_HighResolution/logfile.log new file mode 100644 index 0000000000000000000000000000000000000000..f2d44b3e12a8c4d57b340f1bd911a97d138020cd --- /dev/null +++ b/log/2023_06_27_IC_RhoMono_HighResolution/logfile.log @@ -0,0 +1,7053 @@ +start program on 64 procs at Tue Jun 27 00:42:41 2023 +Running on: pde13 + reading config: ConfigVerbose........................... 2 + reading default: enableFileLogging....................... 1 + reading default: enableScreenLogging..................... 1 + reading default: precision............................... 8 + reading default: TimeLevel............................... 0 + reading config: Model................................... FWIInverse_DGTS + reading default: testAAO................................. 0 + reading config: ForwardSolver........................... VADGTS + reading config: ReconstructionType...................... SO + reading config: Mesh.................................... SeismogramGrid_test + reading config: level................................... 3 + reading default: plevel.................................. 3 + reading default: clevel.................................. 3 + reading config: Distribution............................ RCB + reading config: Overlap................................. dG1 + reading default: Scales.................................. 0 + reading default: CommSplit............................... 0 + reading default: DistributionVerbose..................... 0 + reading default: ClearDistribution....................... 1 + reading default: MeshesVerbose........................... 1 + reading default: MeshVerbose............................. 1 + Overlap: reading default: OverlapVerbose.......................... 0 + reading default: t0...................................... 0 + reading config: dt...................................... 0.0005 + reading config: T....................................... 0.6 + reading config: rkorder................................. -2 + reading config: SignalName.............................. Ricker + reading default: FrequencyFiltering...................... 0 + reading config: SignalFreq.............................. 25 + reading default: f_source................................ 25 + reading default: SourceInversion......................... 0 + reading config: SignalCutoff............................ 0.8 + reading config: SignalDelay............................. 0 + reading default: SaveFilteredSeismogram.................. 0 + reading config: SaveObservedSeismogram.................. 0 + reading config: numL.................................... 0 + reading default: dim..................................... 2 + reading config: Problem................................. VAcousticWaveC2Benchmark + reading default: RealDataLevel........................... 3 + reading default: InitialIterateLevel..................... 3 + reading config: deg..................................... 2 + reading config: parametrization......................... taup + reading default: shots................................... -1 + reading default: SourceStartX............................ -1e+100 + reading default: SourceStartY............................ -1e+100 + reading default: SourceEndX.............................. -1e+100 + reading default: SourceEndY.............................. -1e+100 + reading default: numberOfSourcesPerShot.................. 1 + reading config: FWISourceWaypoints...................... 2 + reading default: FWISourceIncludeLastWaypoint............ 1 + FWISourceCount0 + reading config: FWISourceCount0......................... 6 + reading config: FWISourceWaypoint0...................... 600,370 + FWISourceCount1 + reading config: FWISourceWaypoint1...................... 600,1620 + SOURCE LOCATIONS: + 0: ( 600.00000000, 370.00000000) + + + 1: ( 600.00000000, 620.00000000) + + + 2: ( 600.00000000, 870.00000000) + + + 3: ( 600.00000000, 1120) + + + 4: ( 600.00000000, 1370) + + + 5: ( 600.00000000, 1620) + + + reading config: source_factor........................... 242574257420000.5742 + reading config: Monoparam............................... Rho + monoparam = + Rho + reading default: z_perturb_0............................. 600 + reading default: z_perturb_1............................. 900 + reading default: z_perturb_2............................. 1200 + reading default: z_perturb_0_value....................... 1.05 + reading default: z_perturb_1_value....................... 1.1 + reading default: z_perturb_2_value....................... 0.95 + reading default: x_perturb............................... 900 + reading default: size_perturb............................ 200 + reading default: rho_bg.................................. 2000 + reading default: v_bg.................................... 3500 + reading default: tau_p_bg................................ 0.02 + reading default: impedance_bg............................ 1 + reading config: Qfactor................................. 100 + alphaValue = + 0 + reading default: FWIPrecon............................... 0 + reading default: FWIPreconType........................... 0 + reading default: FWIPreconRegularization................. 1e-08 + reading config: allowPlotting_M......................... 1 + reading config: allowPlotting_WF........................ 0 + reading default: plotFactor.............................. 1 + reading config: FWIReconstructRho....................... 1 + reading config: FWIReconstructV_P....................... 0 + reading config: FWIReconstructTauP...................... 0 + Mesh Info: + Mesh Name: ............................... SeismogramGrid_test + Distribution: ............................ RCB + Overlap: ................................. dG1 + CommSplit: ............................... 0 + Level: ................................... [3, -1, 0] + pLevel: .................................. 3 + Dimension: ............................... 2 + Cells: ................................... 87040 + Overlap: ................................. 11232 + Vertices: ................................ 93312 + Edges: ................................... 174672 + Faces: ................................... 197352 + ProcSets: ................................ 16668 + Mesh width [min, max]: ................... [12.500000, 29.474346] + + reading default: MatrixGraphVerbose...................... 0 + reading default: PaddingPML.............................. 0 + reading config: plot_tStep.............................. -1 + reading default: plotV................................... 0 + reading default: plot_rho................................ 1 + reading default: plot_kappa_0............................ 1 + reading default: plot_kappa_l............................ 0 + reading default: plot_velocity........................... 0 + reading config: compMeasure............................. 0 + Measure overall pressure p = p_0 + ... + p_L + reading default: Specfile................................ + reading config: FWIReceiverWaypoints.................... 2 + reading config: FWIReceiverIncludeLastWaypoint.......... 1 + FWIReceiverCount0 + reading config: FWIReceiverCount0....................... 64 + reading config: FWIReceiverWaypoint0.................... 1350.0, 370.0 + FWIReceiverCount1 + reading config: FWIReceiverWaypoint1.................... 1350.0, 1630.0 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + 0: ( 1350, 370.00000000) 1: ( 1350, 390.00000000) + 2: ( 1350, 410.00000000) 3: ( 1350, 430.00000000) + 4: ( 1350, 450.00000000) 5: ( 1350, 470.00000000) + 6: ( 1350, 490.00000000) 7: ( 1350, 510.00000000) + 8: ( 1350, 530.00000000) 9: ( 1350, 550.00000000) + 10: ( 1350, 570.00000000) 11: ( 1350, 590.00000000) + 12: ( 1350, 610.00000000) 13: ( 1350, 630.00000000) + 14: ( 1350, 650.00000000) 15: ( 1350, 670.00000000) + 16: ( 1350, 690.00000000) 17: ( 1350, 710.00000000) + 18: ( 1350, 730.00000000) 19: ( 1350, 750.00000000) + 20: ( 1350, 770.00000000) 21: ( 1350, 790.00000000) + 22: ( 1350, 810.00000000) 23: ( 1350, 830.00000000) + 24: ( 1350, 850.00000000) 25: ( 1350, 870.00000000) + 26: ( 1350, 890.00000000) 27: ( 1350, 910.00000000) + 28: ( 1350, 930.00000000) 29: ( 1350, 950.00000000) + 30: ( 1350, 970.00000000) 31: ( 1350, 990.00000000) + 32: ( 1350, 1010) 33: ( 1350, 1030) + 34: ( 1350, 1050) 35: ( 1350, 1070) + 36: ( 1350, 1090) 37: ( 1350, 1110) + 38: ( 1350, 1130) 39: ( 1350, 1150) + 40: ( 1350, 1170) 41: ( 1350, 1190) + 42: ( 1350, 1210) 43: ( 1350, 1230) + 44: ( 1350, 1250) 45: ( 1350, 1270) + 46: ( 1350, 1290) 47: ( 1350, 1310) + 48: ( 1350, 1330) 49: ( 1350, 1350) + 50: ( 1350, 1370) 51: ( 1350, 1390) + 52: ( 1350, 1410) 53: ( 1350, 1430) + 54: ( 1350, 1450) 55: ( 1350, 1470) + 56: ( 1350, 1490) 57: ( 1350, 1510) + 58: ( 1350, 1530) 59: ( 1350, 1550) + 60: ( 1350, 1570) 61: ( 1350, 1590) + 62: ( 1350, 1610) 63: ( 1350, 1630) + + reading default: UseGardener............................. 0 + reading default: MeasureComp............................. 0 + Measure overall pressure p = p_0 + ... + p_L + reading default: CountCellsOld........................... 0 + reading config: useTaper................................ 1 + reading default: TaperFromFile........................... + reading config: taperRadiusSource....................... 0 + reading default: taperBoxUpper........................... 1e+100 + reading default: taperBoxLower........................... -1e+100 + reading default: taperBoxLeft............................ -1e+100 + reading default: taperBoxRight........................... 1e+100 + reading config: taperRadiusReceiver..................... 0 + reading config: taperExponent........................... -0.1 + reading config: taperIgnoreSourceCells.................. 1 + reading config: taperIgnoreReceiverCells................ 1 + reading default: taperRhoMin............................. -1 + reading default: taperRhoMax............................. -1 + reading default: taperVpMin.............................. -1 + reading default: taperVpMax.............................. -1 + reading default: taperTaupMin............................ -1 + reading default: taperTaupMax............................ -1 + reading default: seismopath.............................. + reading default: PlotVerbose............................. 0 + reading default: PlotEnabled............................. 0 + reading default: PlotPrecision........................... 4 + Time before FWD->createRealData(real, obs); Tue Jun 27 00:42:46 2023 + Generating Real data for shot 0 + reading default: AssembleVerbose......................... 1 + reading default: startTime............................... 0 + reading default: endTime................................. 1 + reading default: maxStepSize............................. 1e+100 + reading default: stepSize................................ 0 + reading default: minStepSize............................. 0 + reading default: dt_min.................................. 0 + reading default: maxSteps................................ 0 + reading default: steps................................... 0 + reading default: K....................................... 0 + reading default: tEps.................................... 1e-15 + reading default: tTol.................................... 1e-06 + reading default: upwind.................................. 1 + reading config: dampingFlux............................. 1 + reading default: UseCollectTweak......................... 0 + reading default: Preconditioner_S........................ PointBlockJacobi + reading config: LinearSolver............................ LS + reading default: PreconditionerVerbose................... 0 + reading default: PreconditionerDamp...................... 1 + reading default: PointBlockJacobiLapack.................. 0 + reading config: LinearVerbose........................... -1 + reading config: LinearSteps............................. 100 + reading config: LinearEpsilon........................... 1e-12 + reading config: LinearReduction......................... 0.0001 + reading default: LinearMinimalStepNumber................. 0 + reading default: LinearPrintSteps........................ 800 + reading default: TimeIntegratorVerbose................... 1 + Initialization: 0.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 26.79 seconds + Generating Real data for shot 1 + Initialization: 0.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 26.32 seconds + Generating Real data for shot 2 + Initialization: 0.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 26.16 seconds + Generating Real data for shot 3 + Initialization: 0.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 26.15 seconds + Generating Real data for shot 4 + Initialization: 0.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 26.15 seconds + Generating Real data for shot 5 + Initialization: 0.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 26.18 seconds + Time after FWD->createRealData(real, obs); Tue Jun 27 00:45:24 2023 + FWISourceCount0 + FWISourceCount1 + SOURCE LOCATIONS: + 0: ( 600.00000000, 370.00000000) + + + 1: ( 600.00000000, 620.00000000) + + + 2: ( 600.00000000, 870.00000000) + + + 3: ( 600.00000000, 1120) + + + 4: ( 600.00000000, 1370) + + + 5: ( 600.00000000, 1620) + + + monoparam = + Rho + alphaValue = + 0 + Frequency Filter to: -1 + + + Mesh Info: + Mesh Name: ............................... SeismogramGrid_test + Distribution: ............................ RCB + Overlap: ................................. dG1 + CommSplit: ............................... 0 + Level: ................................... [3, -1, 0] + pLevel: .................................. 3 + Dimension: ............................... 2 + Cells: ................................... 87040 + Overlap: ................................. 11232 + Vertices: ................................ 93312 + Edges: ................................... 174672 + Faces: ................................... 197352 + ProcSets: ................................ 16668 + Mesh width [min, max]: ................... [12.500000, 29.474346] + + Measure overall pressure p = p_0 + ... + p_L + FWIReceiverCount0 + FWIReceiverCount1 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + 0: ( 1350, 370.00000000) 1: ( 1350, 390.00000000) + 2: ( 1350, 410.00000000) 3: ( 1350, 430.00000000) + 4: ( 1350, 450.00000000) 5: ( 1350, 470.00000000) + 6: ( 1350, 490.00000000) 7: ( 1350, 510.00000000) + 8: ( 1350, 530.00000000) 9: ( 1350, 550.00000000) + 10: ( 1350, 570.00000000) 11: ( 1350, 590.00000000) + 12: ( 1350, 610.00000000) 13: ( 1350, 630.00000000) + 14: ( 1350, 650.00000000) 15: ( 1350, 670.00000000) + 16: ( 1350, 690.00000000) 17: ( 1350, 710.00000000) + 18: ( 1350, 730.00000000) 19: ( 1350, 750.00000000) + 20: ( 1350, 770.00000000) 21: ( 1350, 790.00000000) + 22: ( 1350, 810.00000000) 23: ( 1350, 830.00000000) + 24: ( 1350, 850.00000000) 25: ( 1350, 870.00000000) + 26: ( 1350, 890.00000000) 27: ( 1350, 910.00000000) + 28: ( 1350, 930.00000000) 29: ( 1350, 950.00000000) + 30: ( 1350, 970.00000000) 31: ( 1350, 990.00000000) + 32: ( 1350, 1010) 33: ( 1350, 1030) + 34: ( 1350, 1050) 35: ( 1350, 1070) + 36: ( 1350, 1090) 37: ( 1350, 1110) + 38: ( 1350, 1130) 39: ( 1350, 1150) + 40: ( 1350, 1170) 41: ( 1350, 1190) + 42: ( 1350, 1210) 43: ( 1350, 1230) + 44: ( 1350, 1250) 45: ( 1350, 1270) + 46: ( 1350, 1290) 47: ( 1350, 1310) + 48: ( 1350, 1330) 49: ( 1350, 1350) + 50: ( 1350, 1370) 51: ( 1350, 1390) + 52: ( 1350, 1410) 53: ( 1350, 1430) + 54: ( 1350, 1450) 55: ( 1350, 1470) + 56: ( 1350, 1490) 57: ( 1350, 1510) + 58: ( 1350, 1530) 59: ( 1350, 1550) + 60: ( 1350, 1570) 61: ( 1350, 1590) + 62: ( 1350, 1610) 63: ( 1350, 1630) + + Measure overall pressure p = p_0 + ... + p_L + reading default: loadInitialModelFromFile................ 0 + reading default: loadRealModelFromFile................... 0 + reading config: FWINonlinearSolver...................... FWISO + reading default: FWI_MaxInnerLoopSteps_FWISO............. 10 + reading default: FWI_Gamma_FWISO......................... 0.9 + reading default: FWI_Damping_FWISO....................... 1 + reading default: FWI_ThetaMax_FWISO...................... 1 + reading default: FWI_ThetaInitial_FWISO.................. 0.4 + reading default: FWI_RegularizationStrategy_FWISO........ 0 + reading default: FWISO_Verbose........................... 1 + reading config: FWISO_Steps............................. 15 + reading default: FWISO_LineSearchSteps................... 3 + reading default: FWISO_Epsilon........................... 1e-10 + reading default: FWISO_Reduction......................... 1e-05 + reading default: FWISO_MinimalStepNumber................. 0 + reading default: FWI_Precon.............................. 0 + reading default: FWI_HierarchyLevel...................... -1 + reading default: FWI_SaveAdjointWF....................... 0 + reading default: FWI_SaveSeis............................ 0 + reading config: FWI_DebugPlottingLevel.................. 1 + reading default: FWI_BacktrackingFactor.................. 0.5 + reading default: FWI_BacktrackingActivated............... 0 + Memory Usage at start38711 + reading default: WriteSeismoToFileEvery.................. 2147483647 + Initialize Subproblems 38711 + Starting the Loops with max_iter: 15 and num_problems 6 + + + Iteration Main Looop Counting Variable iter: 0 + + iteration: 0 PROBLEM Number: 0 + FWISO problem 0: d(0) + shot: 0: Solving forward problem... + Initialization: 0.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 26.33 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 39185 + state_comps = + 1 + Prä-Residuumnorm: 2690118 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2690118 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.78 seconds + Inner Loop: : InnerCG resNorm : 1491165.7 + Inner Loop: : Time needed for inner loop: 1:01.38 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:01.38 minutes + Residuumnorm 1: 1491165.7 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.86 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.18 seconds + Intermezzo Residuum: 1491851.2 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2690118 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.92 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.89 seconds + PhiAdjSO: : 1:01.69 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.00 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.90 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Inner Loop: : InnerCG resNorm : 1325229.7 + Inner Loop: : Time needed for inner loop: 3:06.98 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:06.98 minutes + FWISO Subproblem: 0: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 1325229.7 + reading default: PlotFactorIterates...................... 1 + reading default: PlotShot................................ -1 + + iteration: 0 PROBLEM Number: 1 + FWISO problem 1: d(0) + shot: 1: Solving forward problem... + Initialization: 0.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.05 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 74045 + state_comps = + 1 + Prä-Residuumnorm: 2868113.2 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2868113.2 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.31 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.35 seconds + Inner Loop: : InnerCG resNorm : 1747713.1 + Inner Loop: : Time needed for inner loop: 1:02.63 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:02.63 minutes + Residuumnorm 1: 1747713.1 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.38 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.66 seconds + Intermezzo Residuum: 1749132.3 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2868113.2 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.38 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + PhiAdjSO: : 1:02.82 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.34 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.65 seconds + Inner Loop: : InnerCG resNorm : 1499137.6 + Inner Loop: : Time needed for inner loop: 3:09.57 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:09.57 minutes + FWISO Subproblem: 1: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 1499137.6 + + iteration: 0 PROBLEM Number: 2 + FWISO problem 2: d(0) + shot: 2: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.07 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 81856 + state_comps = + 1 + Prä-Residuumnorm: 2682703.5 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2682703.5 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.32 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.40 seconds + Inner Loop: : InnerCG resNorm : 1651217.6 + Inner Loop: : Time needed for inner loop: 1:02.67 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:02.67 minutes + Residuumnorm 1: 1651217.6 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.45 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.47 seconds + Initialization: 0.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.79 seconds + Intermezzo Residuum: 1652588.6 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2682703.5 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + PhiAdjSO: : 1:02.80 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + Inner Loop: : InnerCG resNorm : 1384614.8 + Inner Loop: : Time needed for inner loop: 3:10.75 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.75 minutes + FWISO Subproblem: 2: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 1384614.8 + + iteration: 0 PROBLEM Number: 3 + FWISO problem 3: d(0) + shot: 3: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.05 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 92691 + state_comps = + 1 + Prä-Residuumnorm: 2198808.8 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2198808.8 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.19 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Inner Loop: : InnerCG resNorm : 1399088.9 + Inner Loop: : Time needed for inner loop: 1:02.72 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:02.72 minutes + Residuumnorm 1: 1399088.9 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Intermezzo Residuum: 1399051.6 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2198808.8 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.49 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + PhiAdjSO: : 1:02.82 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Initialization: 0.46 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.75 seconds + Inner Loop: : InnerCG resNorm : 1230692 + Inner Loop: : Time needed for inner loop: 3:10.32 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.32 minutes + FWISO Subproblem: 3: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 1230692 + + iteration: 0 PROBLEM Number: 4 + FWISO problem 4: d(0) + shot: 4: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.04 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 95332 + state_comps = + 1 + Prä-Residuumnorm: 2149822.4 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 2149822.4 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.27 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + Inner Loop: : InnerCG resNorm : 1546143 + Inner Loop: : Time needed for inner loop: 1:02.71 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:02.71 minutes + Residuumnorm 1: 1546143 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Intermezzo Residuum: 1547397.6 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2149822.4 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + PhiAdjSO: : 1:02.82 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.94 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.72 seconds + Inner Loop: : InnerCG resNorm : 1327915.3 + Inner Loop: : Time needed for inner loop: 3:11.14 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.14 minutes + FWISO Subproblem: 4: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 1327915.3 + + iteration: 0 PROBLEM Number: 5 + FWISO problem 5: d(0) + shot: 5: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.25 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 98975 + state_comps = + 1 + Prä-Residuumnorm: 1686014.7 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1686014.7 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.37 seconds + Initialization: 0.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Inner Loop: : InnerCG resNorm : 1367378.9 + Inner Loop: : Time needed for inner loop: 1:02.93 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:02.93 minutes + Residuumnorm 1: 1367378.9 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.84 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.79 seconds + Intermezzo Residuum: 1368745.6 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1686014.7 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + PhiAdjSO: : 1:02.85 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.42 seconds + Initialization: 0.47 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.64 seconds + Inner Loop: : InnerCG resNorm : 1201323.7 + Inner Loop: : Time needed for inner loop: 3:10.39 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.39 minutes + FWISO Subproblem: 5: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 1201323.7 + + + Iteration Main Looop Counting Variable iter: 1 + + iteration: 1 PROBLEM Number: 0 + FWISO problem 0: d(1) + shot: 0: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.07 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 102619 + Prä-Residuumnorm: 1586895.4 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 936106.57 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.25 seconds + Initialization: 0.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.44 seconds + Inner Loop: : InnerCG resNorm : 1332615.9 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.46 seconds + Inner Loop: : InnerCG resNorm : 1001225 + Inner Loop: : Time needed for inner loop: 2:05.56 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.56 minutes + Residuumnorm 1: 1001225 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.48 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.72 seconds + Intermezzo Residuum: 1000982 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 936106.57 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + PhiAdjSO: : 1:02.76 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Inner Loop: : InnerCG resNorm : 859834.76 + Inner Loop: : Time needed for inner loop: 3:10.93 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.93 minutes + FWISO Subproblem: 0: d(1): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 859834.76 + + iteration: 1 PROBLEM Number: 1 + FWISO problem 1: d(1) + shot: 1: Solving forward problem... + Initialization: 0.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.34 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 102570 + Prä-Residuumnorm: 1583899.4 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 874699.55 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.49 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Inner Loop: : InnerCG resNorm : 1380369.9 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.55 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Inner Loop: : InnerCG resNorm : 1009984 + Inner Loop: : Time needed for inner loop: 2:06.18 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.18 minutes + Residuumnorm 1: 1009984 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.01 seconds + Intermezzo Residuum: 1009545.5 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 874699.55 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.93 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + PhiAdjSO: : 1:03.04 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.04 seconds + Inner Loop: : InnerCG resNorm : 862704.13 + Inner Loop: : Time needed for inner loop: 3:11.66 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.66 minutes + FWISO Subproblem: 1: d(1): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 862704.13 + + iteration: 1 PROBLEM Number: 2 + FWISO problem 2: d(1) + shot: 2: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.22 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 102701 + Prä-Residuumnorm: 1655011.6 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1021008.6 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.49 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Inner Loop: : InnerCG resNorm : 1354244.1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.72 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Inner Loop: : InnerCG resNorm : 1039578.1 + Inner Loop: : Time needed for inner loop: 2:06.49 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.49 minutes + Residuumnorm 1: 1039578.1 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + Initialization: 0.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Intermezzo Residuum: 1039599.3 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1021008.6 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + PhiAdjSO: : 1:02.97 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Inner Loop: : InnerCG resNorm : 920294.75 + Inner Loop: : Time needed for inner loop: 3:11.12 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.12 minutes + FWISO Subproblem: 2: d(1): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 920294.75 + + iteration: 1 PROBLEM Number: 3 + FWISO problem 3: d(1) + shot: 3: Solving forward problem... + Initialization: 0.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.18 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 102864 + Prä-Residuumnorm: 1454070.7 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 961575.97 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.54 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Inner Loop: : InnerCG resNorm : 1249817.2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.53 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + Inner Loop: : InnerCG resNorm : 1032750 + Inner Loop: : Time needed for inner loop: 2:06.34 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.34 minutes + Residuumnorm 1: 1032750 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.93 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Intermezzo Residuum: 1032682.4 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 961575.97 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + PhiAdjSO: : 1:02.88 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.03 seconds + Inner Loop: : InnerCG resNorm : 938585.92 + Inner Loop: : Time needed for inner loop: 3:11.26 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.26 minutes + FWISO Subproblem: 3: d(1): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 938585.92 + + iteration: 1 PROBLEM Number: 4 + FWISO problem 4: d(1) + shot: 4: Solving forward problem... + Initialization: 0.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.16 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 102915 + Prä-Residuumnorm: 1340290.9 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 835594.44 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.44 seconds + Initialization: 0.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.83 seconds + Inner Loop: : InnerCG resNorm : 1193002.3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Inner Loop: : InnerCG resNorm : 918757.76 + Inner Loop: : Time needed for inner loop: 2:06.37 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.37 minutes + Residuumnorm 1: 918757.76 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.70 seconds + Intermezzo Residuum: 918700.24 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 835594.44 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + PhiAdjSO: : 1:02.64 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.79 seconds + Inner Loop: : InnerCG resNorm : 812369.81 + Inner Loop: : Time needed for inner loop: 3:10.60 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.60 minutes + FWISO Subproblem: 4: d(1): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 812369.81 + + iteration: 1 PROBLEM Number: 5 + FWISO problem 5: d(1) + shot: 5: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.16 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 102970 + Prä-Residuumnorm: 1150971 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 785719.22 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.41 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Inner Loop: : InnerCG resNorm : 1025122.1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + Initialization: 0.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + Inner Loop: : InnerCG resNorm : 777230.81 + Inner Loop: : Time needed for inner loop: 2:06.21 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.21 minutes + Residuumnorm 1: 777230.81 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.73 seconds + Intermezzo Residuum: 777001.19 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 785719.22 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + PhiAdjSO: : 1:02.80 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.75 seconds + Inner Loop: : InnerCG resNorm : 702961.73 + Inner Loop: : Time needed for inner loop: 3:10.76 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.76 minutes + FWISO Subproblem: 5: d(1): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 702961.73 + + + Iteration Main Looop Counting Variable iter: 2 + + iteration: 2 PROBLEM Number: 0 + FWISO problem 0: d(2) + shot: 0: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.19 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 103169 + Prä-Residuumnorm: 1108691 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 881352.81 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.29 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + Inner Loop: : InnerCG resNorm : 901320.34 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + Inner Loop: : InnerCG resNorm : 765287.75 + Inner Loop: : Time needed for inner loop: 2:05.68 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.68 minutes + Residuumnorm 1: 765287.75 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Intermezzo Residuum: 765400.91 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 588613.2 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + PhiAdjSO: : 1:02.89 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Inner Loop: : InnerCG resNorm : 706325.91 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + PhiAdjSO: : 1:02.75 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.69 seconds + Inner Loop: : InnerCG resNorm : 641343.84 + Inner Loop: : Time needed for inner loop: 6:21.42 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:21.42 minutes + FWISO Subproblem: 0: d(2): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 641343.84 + + iteration: 2 PROBLEM Number: 1 + FWISO problem 1: d(2) + shot: 1: Solving forward problem... + Initialization: 0.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.23 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 107987 + Prä-Residuumnorm: 1059064.2 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 821963.25 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.32 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Inner Loop: : InnerCG resNorm : 913494.88 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.37 seconds + Initialization: 0.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.47 seconds + Inner Loop: : InnerCG resNorm : 784445.43 + Inner Loop: : Time needed for inner loop: 2:05.52 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.52 minutes + Residuumnorm 1: 784445.43 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.70 seconds + Intermezzo Residuum: 784433.41 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 526376.04 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + PhiAdjSO: : 1:02.68 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.66 seconds + Inner Loop: : InnerCG resNorm : 722887.16 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.48 seconds + PhiAdjSO: : 1:02.80 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Inner Loop: : InnerCG resNorm : 668185.7 + Inner Loop: : Time needed for inner loop: 6:20.74 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:20.74 minutes + FWISO Subproblem: 1: d(2): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 668185.7 + + iteration: 2 PROBLEM Number: 2 + FWISO problem 2: d(2) + shot: 2: Solving forward problem... + Initialization: 0.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.27 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 109274 + Prä-Residuumnorm: 1202482.9 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 972158.89 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.34 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + Inner Loop: : InnerCG resNorm : 1047911.8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.49 seconds + Inner Loop: : InnerCG resNorm : 914566.26 + Inner Loop: : Time needed for inner loop: 2:05.73 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.73 minutes + Residuumnorm 1: 914566.26 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Intermezzo Residuum: 914548.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 667651.42 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + PhiAdjSO: : 1:02.67 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.75 seconds + Inner Loop: : InnerCG resNorm : 855627.4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.95 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.48 seconds + PhiAdjSO: : 1:02.87 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Inner Loop: : InnerCG resNorm : 792437.14 + Inner Loop: : Time needed for inner loop: 6:21.83 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:21.83 minutes + FWISO Subproblem: 2: d(2): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 792437.14 + + iteration: 2 PROBLEM Number: 3 + FWISO problem 3: d(2) + shot: 3: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.27 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 111634 + Prä-Residuumnorm: 1154319.1 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 958834.78 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Inner Loop: : InnerCG resNorm : 1016321.2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.49 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Inner Loop: : InnerCG resNorm : 880493.52 + Inner Loop: : Time needed for inner loop: 2:06.01 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.01 minutes + Residuumnorm 1: 880493.52 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Intermezzo Residuum: 880552.91 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 687015.39 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.93 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.49 seconds + PhiAdjSO: : 1:02.68 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.01 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.89 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Inner Loop: : InnerCG resNorm : 817630.27 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.88 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + PhiAdjSO: : 1:02.86 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.92 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Inner Loop: : InnerCG resNorm : 764436.58 + Inner Loop: : Time needed for inner loop: 6:22.85 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:22.85 minutes + FWISO Subproblem: 3: d(2): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 764436.58 + + iteration: 2 PROBLEM Number: 4 + FWISO problem 4: d(2) + shot: 4: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.35 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 111720 + Prä-Residuumnorm: 986145.81 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 800475.57 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.44 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Inner Loop: : InnerCG resNorm : 879435.42 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.63 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + Inner Loop: : InnerCG resNorm : 769436.5 + Inner Loop: : Time needed for inner loop: 2:06.41 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.41 minutes + Residuumnorm 1: 769436.5 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Intermezzo Residuum: 769399.78 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 553324.79 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.48 seconds + PhiAdjSO: : 1:02.73 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.93 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Inner Loop: : InnerCG resNorm : 718879.79 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + PhiAdjSO: : 1:02.85 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + Inner Loop: : InnerCG resNorm : 677060.14 + Inner Loop: : Time needed for inner loop: 6:21.44 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:21.44 minutes + FWISO Subproblem: 4: d(2): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 677060.14 + + iteration: 2 PROBLEM Number: 5 + FWISO problem 5: d(2) + shot: 5: Solving forward problem... + Initialization: 0.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.29 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 112931 + Prä-Residuumnorm: 803977.79 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 676409.72 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.34 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + Inner Loop: : InnerCG resNorm : 745576.64 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + Inner Loop: : InnerCG resNorm : 660852.06 + Inner Loop: : Time needed for inner loop: 2:05.76 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.76 minutes + Residuumnorm 1: 660852.06 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Intermezzo Residuum: 660864.19 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 493957.49 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.90 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + PhiAdjSO: : 1:02.86 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.94 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Inner Loop: : InnerCG resNorm : 612683.8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.90 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + PhiAdjSO: : 1:02.98 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.97 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Inner Loop: : InnerCG resNorm : 587310.29 + Inner Loop: : Time needed for inner loop: 6:23.14 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:23.14 minutes + FWISO Subproblem: 5: d(2): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 587310.29 + + + Iteration Main Looop Counting Variable iter: 3 + + iteration: 3 PROBLEM Number: 0 + FWISO problem 0: d(3) + shot: 0: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.35 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 112076 + Prä-Residuumnorm: 849141.72 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 607521.96 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + Inner Loop: : InnerCG resNorm : 762650.55 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.51 seconds + Initialization: 0.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + Inner Loop: : InnerCG resNorm : 653773.65 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.44 seconds + Inner Loop: : InnerCG resNorm : 569725.75 + Inner Loop: : Time needed for inner loop: 3:08.80 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.80 minutes + Residuumnorm 1: 569725.75 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.70 seconds + Intermezzo Residuum: 569615.34 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 649979.04 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + PhiAdjSO: : 1:03.03 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.88 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.71 seconds + Inner Loop: : InnerCG resNorm : 536292.58 + Inner Loop: : Time needed for inner loop: 3:11.22 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.22 minutes + FWISO Subproblem: 0: d(3): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 536292.58 + + iteration: 3 PROBLEM Number: 1 + FWISO problem 1: d(3) + shot: 1: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.23 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 112062 + Prä-Residuumnorm: 882274.71 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 616277.69 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.31 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + Inner Loop: : InnerCG resNorm : 758570.34 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + Inner Loop: : InnerCG resNorm : 674416.65 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.50 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + Inner Loop: : InnerCG resNorm : 608666.58 + Inner Loop: : Time needed for inner loop: 3:08.74 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.74 minutes + Residuumnorm 1: 608666.58 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Intermezzo Residuum: 608680.91 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 660391.42 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.91 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.46 seconds + PhiAdjSO: : 1:02.80 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.89 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Inner Loop: : InnerCG resNorm : 571876.85 + Inner Loop: : Time needed for inner loop: 3:11.50 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.50 minutes + FWISO Subproblem: 1: d(3): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 571876.85 + + iteration: 3 PROBLEM Number: 2 + FWISO problem 2: d(3) + shot: 2: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.31 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 112037 + Prä-Residuumnorm: 1051337 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 764967.17 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.44 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.00 seconds + Inner Loop: : InnerCG resNorm : 899437.63 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.60 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Inner Loop: : InnerCG resNorm : 814916.11 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.63 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Inner Loop: : InnerCG resNorm : 755366.17 + Inner Loop: : Time needed for inner loop: 3:09.79 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:09.79 minutes + Residuumnorm 1: 755366.17 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Intermezzo Residuum: 755492.7 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 817534.02 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.98 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + PhiAdjSO: : 1:02.90 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.76 seconds + Inner Loop: : InnerCG resNorm : 716250.7 + Inner Loop: : Time needed for inner loop: 3:11.27 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.27 minutes + FWISO Subproblem: 2: d(3): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 716250.7 + + iteration: 3 PROBLEM Number: 3 + FWISO problem 3: d(3) + shot: 3: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.20 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 112102 + Prä-Residuumnorm: 983717.18 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 735411.9 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Inner Loop: : InnerCG resNorm : 870501.95 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.55 seconds + Initialization: 0.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Inner Loop: : InnerCG resNorm : 791447.63 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.53 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + Inner Loop: : InnerCG resNorm : 711062.41 + Inner Loop: : Time needed for inner loop: 3:09.14 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:09.14 minutes + Residuumnorm 1: 711062.41 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.91 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Intermezzo Residuum: 711178.6 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 784597.76 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.02 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + PhiAdjSO: : 1:02.87 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.22 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.12 seconds + Inner Loop: : InnerCG resNorm : 670423.34 + Inner Loop: : Time needed for inner loop: 3:12.19 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:12.19 minutes + FWISO Subproblem: 3: d(3): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 670423.34 + + iteration: 3 PROBLEM Number: 4 + FWISO problem 4: d(3) + shot: 4: Solving forward problem... + Initialization: 0.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.28 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 112313 + Prä-Residuumnorm: 825238.72 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 602877.46 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + Inner Loop: : InnerCG resNorm : 744656.76 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.65 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + Inner Loop: : InnerCG resNorm : 673590.1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.60 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Inner Loop: : InnerCG resNorm : 615253.46 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.59 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + Inner Loop: : InnerCG resNorm : 572968.82 + Inner Loop: : Time needed for inner loop: 4:12.68 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:12.68 minutes + Residuumnorm 1: 572968.82 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Intermezzo Residuum: 573009.35 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 644139.4 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.91 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + PhiAdjSO: : 1:02.69 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Inner Loop: : InnerCG resNorm : 547603.8 + Inner Loop: : Time needed for inner loop: 3:11.04 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.04 minutes + FWISO Subproblem: 4: d(3): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 547603.8 + + iteration: 3 PROBLEM Number: 5 + FWISO problem 5: d(3) + shot: 5: Solving forward problem... + Initialization: 0.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.16 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 112347 + Prä-Residuumnorm: 725433.9 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 549295.63 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.22 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.36 seconds + Inner Loop: : InnerCG resNorm : 675880.04 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Inner Loop: : InnerCG resNorm : 601550.51 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.43 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Inner Loop: : InnerCG resNorm : 527146.81 + Inner Loop: : Time needed for inner loop: 3:08.43 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.43 minutes + Residuumnorm 1: 527146.81 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Intermezzo Residuum: 527029.61 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 585567.32 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.98 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + PhiAdjSO: : 1:02.83 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Inner Loop: : InnerCG resNorm : 493144.27 + Inner Loop: : Time needed for inner loop: 3:11.34 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.34 minutes + FWISO Subproblem: 5: d(3): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 493144.27 + + + Iteration Main Looop Counting Variable iter: 4 + + iteration: 4 PROBLEM Number: 0 + FWISO problem 0: d(4) + shot: 0: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.22 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 112353 + Prä-Residuumnorm: 731349.55 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 592614.56 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.40 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.45 seconds + Inner Loop: : InnerCG resNorm : 664535.06 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.71 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + Inner Loop: : InnerCG resNorm : 560732.48 + Inner Loop: : Time needed for inner loop: 2:05.88 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.88 minutes + Residuumnorm 1: 560732.48 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Intermezzo Residuum: 560755.23 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 503833.09 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + PhiAdjSO: : 1:02.78 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.00 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Inner Loop: : InnerCG resNorm : 520575.67 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + PhiAdjSO: : 1:02.85 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.91 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.03 seconds + Inner Loop: : InnerCG resNorm : 499902.39 + Inner Loop: : Time needed for inner loop: 6:22.34 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:22.34 minutes + FWISO Subproblem: 0: d(4): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 499902.39 + + iteration: 4 PROBLEM Number: 1 + FWISO problem 1: d(4) + shot: 1: Solving forward problem... + Initialization: 0.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.37 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 112464 + Prä-Residuumnorm: 754686.86 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 602999.82 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.35 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + Inner Loop: : InnerCG resNorm : 667114.7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.47 seconds + Inner Loop: : InnerCG resNorm : 594031.64 + Inner Loop: : Time needed for inner loop: 2:05.73 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.73 minutes + Residuumnorm 1: 594031.64 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.74 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Intermezzo Residuum: 594023.65 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 508401.58 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.05 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + PhiAdjSO: : 1:02.76 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.84 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.09 seconds + Inner Loop: : InnerCG resNorm : 562039.03 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.90 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + PhiAdjSO: : 1:02.85 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.98 seconds + Inner Loop: : InnerCG resNorm : 528071.28 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + PhiAdjSO: : 1:02.94 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Inner Loop: : InnerCG resNorm : 459287.58 + Inner Loop: : Time needed for inner loop: 9:33.77 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 9:33.77 minutes + FWISO Subproblem: 1: d(4): Finished first / second inner loop ( 2, 3 steps ) + ************************************* + Residuumnorm 2: 459287.58 + + iteration: 4 PROBLEM Number: 2 + FWISO problem 2: d(4) + shot: 2: Solving forward problem... + Initialization: 0.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.19 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 113906 + Prä-Residuumnorm: 964502.76 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 789357.86 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.33 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + Inner Loop: : InnerCG resNorm : 840000.21 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + Inner Loop: : InnerCG resNorm : 770819.87 + Inner Loop: : Time needed for inner loop: 2:06.18 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.18 minutes + Residuumnorm 1: 770819.87 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Intermezzo Residuum: 770829.26 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 675009.5 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + PhiAdjSO: : 1:02.79 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Inner Loop: : InnerCG resNorm : 738450.06 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + PhiAdjSO: : 1:02.78 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.00 seconds + Inner Loop: : InnerCG resNorm : 684431.68 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + PhiAdjSO: : 1:02.99 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Inner Loop: : InnerCG resNorm : 605577.03 + Inner Loop: : Time needed for inner loop: 9:32.59 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 9:32.59 minutes + FWISO Subproblem: 2: d(4): Finished first / second inner loop ( 2, 3 steps ) + ************************************* + Residuumnorm 2: 605577.03 + + iteration: 4 PROBLEM Number: 3 + FWISO problem 3: d(4) + shot: 3: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.28 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 114989 + Prä-Residuumnorm: 932409.54 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 775506.58 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.55 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + Inner Loop: : InnerCG resNorm : 817433.38 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.63 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Inner Loop: : InnerCG resNorm : 753088.14 + Inner Loop: : Time needed for inner loop: 2:06.32 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.32 minutes + Residuumnorm 1: 753088.14 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.95 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Intermezzo Residuum: 753140.91 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 669308.02 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + PhiAdjSO: : 1:02.81 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Inner Loop: : InnerCG resNorm : 717633.9 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.87 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + PhiAdjSO: : 1:03.12 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Inner Loop: : InnerCG resNorm : 674454.35 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + PhiAdjSO: : 1:02.68 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Inner Loop: : InnerCG resNorm : 588741.13 + Inner Loop: : Time needed for inner loop: 9:33.30 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 9:33.30 minutes + FWISO Subproblem: 3: d(4): Finished first / second inner loop ( 2, 3 steps ) + ************************************* + Residuumnorm 2: 588741.13 + + iteration: 4 PROBLEM Number: 4 + FWISO problem 4: d(4) + shot: 4: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.29 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116237 + Prä-Residuumnorm: 751102.95 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 649910.3 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.40 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Inner Loop: : InnerCG resNorm : 677239.7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.53 seconds + Initialization: 0.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + Inner Loop: : InnerCG resNorm : 615401.83 + Inner Loop: : Time needed for inner loop: 2:06.01 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.01 minutes + Residuumnorm 1: 615401.83 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Intermezzo Residuum: 615385.44 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 527645.51 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.93 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.83 seconds + PhiAdjSO: : 1:03.17 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.97 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.94 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.10 seconds + Inner Loop: : InnerCG resNorm : 586179.54 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.14 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + PhiAdjSO: : 1:03.08 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.04 seconds + Inner Loop: : InnerCG resNorm : 559176.13 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.97 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.36 seconds + PhiAdjSO: : 1:02.77 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.74 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Inner Loop: : InnerCG resNorm : 510312.67 + Inner Loop: : Time needed for inner loop: 9:35.21 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 9:35.21 minutes + FWISO Subproblem: 4: d(4): Finished first / second inner loop ( 2, 3 steps ) + ************************************* + Residuumnorm 2: 510312.67 + + iteration: 4 PROBLEM Number: 5 + FWISO problem 5: d(4) + shot: 5: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.20 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116285 + Prä-Residuumnorm: 623748.27 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 522782.54 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.45 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Inner Loop: : InnerCG resNorm : 592357.11 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.54 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + Inner Loop: : InnerCG resNorm : 519274.8 + Inner Loop: : Time needed for inner loop: 2:06.22 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.22 minutes + Residuumnorm 1: 519274.8 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.68 seconds + Intermezzo Residuum: 519270.13 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 453138.38 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + PhiAdjSO: : 1:02.87 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + Initialization: 0.47 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.98 seconds + Inner Loop: : InnerCG resNorm : 488091.85 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.83 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + PhiAdjSO: : 1:03.16 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.01 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Inner Loop: : InnerCG resNorm : 472477.7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + PhiAdjSO: : 1:02.71 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.07 seconds + Inner Loop: : InnerCG resNorm : 432604.06 + Inner Loop: : Time needed for inner loop: 9:34.21 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 9:34.21 minutes + FWISO Subproblem: 5: d(4): Finished first / second inner loop ( 2, 3 steps ) + ************************************* + Residuumnorm 2: 432604.06 + + + Iteration Main Looop Counting Variable iter: 5 + + iteration: 5 PROBLEM Number: 0 + FWISO problem 0: d(5) + shot: 0: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.35 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116452 + Prä-Residuumnorm: 669310.88 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 488110 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.50 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + Inner Loop: : InnerCG resNorm : 587051.62 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.55 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + Inner Loop: : InnerCG resNorm : 527720.44 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Inner Loop: : InnerCG resNorm : 469887.03 + Inner Loop: : Time needed for inner loop: 3:09.38 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:09.38 minutes + Residuumnorm 1: 469887.03 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Intermezzo Residuum: 469872.87 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 565202.49 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.89 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + PhiAdjSO: : 1:02.85 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Inner Loop: : InnerCG resNorm : 448045.2 + Inner Loop: : Time needed for inner loop: 3:10.94 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.94 minutes + FWISO Subproblem: 0: d(5): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 448045.2 + + iteration: 5 PROBLEM Number: 1 + FWISO problem 1: d(5) + shot: 1: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.28 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116463 + Prä-Residuumnorm: 704104.55 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 506325.8 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Inner Loop: : InnerCG resNorm : 588879.66 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.48 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + Inner Loop: : InnerCG resNorm : 520440.01 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.50 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + Inner Loop: : InnerCG resNorm : 483934.71 + Inner Loop: : Time needed for inner loop: 3:08.90 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.90 minutes + Residuumnorm 1: 483934.71 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.97 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.92 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.00 seconds + Intermezzo Residuum: 483927.66 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 627511.82 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.10 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + PhiAdjSO: : 1:02.99 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.74 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.11 seconds + Inner Loop: : InnerCG resNorm : 464289.88 + Inner Loop: : Time needed for inner loop: 3:11.73 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.73 minutes + FWISO Subproblem: 1: d(5): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 464289.88 + + iteration: 5 PROBLEM Number: 2 + FWISO problem 2: d(5) + shot: 2: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.37 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116473 + Prä-Residuumnorm: 856932.94 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 631189.57 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.48 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + Inner Loop: : InnerCG resNorm : 712618.7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.55 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + Inner Loop: : InnerCG resNorm : 651252.95 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.61 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + Inner Loop: : InnerCG resNorm : 616582.72 + Inner Loop: : Time needed for inner loop: 3:09.37 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:09.37 minutes + Residuumnorm 1: 616582.72 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Intermezzo Residuum: 616621.07 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 771197.47 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.83 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + PhiAdjSO: : 1:03.00 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.95 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Inner Loop: : InnerCG resNorm : 594587.68 + Inner Loop: : Time needed for inner loop: 3:11.58 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.58 minutes + FWISO Subproblem: 2: d(5): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 594587.68 + + iteration: 5 PROBLEM Number: 3 + FWISO problem 3: d(5) + shot: 3: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.31 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116510 + Prä-Residuumnorm: 797072.47 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 596649.24 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.46 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.84 seconds + Inner Loop: : InnerCG resNorm : 688894.6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + Inner Loop: : InnerCG resNorm : 638217.86 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.56 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + Inner Loop: : InnerCG resNorm : 601750.32 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.55 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + Inner Loop: : InnerCG resNorm : 565978.02 + Inner Loop: : Time needed for inner loop: 4:12.24 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:12.24 minutes + Residuumnorm 1: 565978.02 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.98 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Intermezzo Residuum: 566019.61 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 722101.48 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.49 seconds + PhiAdjSO: : 1:02.68 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.67 seconds + Inner Loop: : InnerCG resNorm : 545963.54 + Inner Loop: : Time needed for inner loop: 3:10.68 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.68 minutes + FWISO Subproblem: 3: d(5): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 545963.54 + + iteration: 5 PROBLEM Number: 4 + FWISO problem 4: d(5) + shot: 4: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.25 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116556 + Prä-Residuumnorm: 623008.03 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 485165.71 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.33 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Inner Loop: : InnerCG resNorm : 566670.22 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + Inner Loop: : InnerCG resNorm : 509654.91 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.48 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.35 seconds + Inner Loop: : InnerCG resNorm : 476528.5 + Inner Loop: : Time needed for inner loop: 3:08.42 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.42 minutes + Residuumnorm 1: 476528.5 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.74 seconds + Intermezzo Residuum: 476532.36 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 561225.21 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + PhiAdjSO: : 1:02.76 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Inner Loop: : InnerCG resNorm : 462989.49 + Inner Loop: : Time needed for inner loop: 3:11.07 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.07 minutes + FWISO Subproblem: 4: d(5): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 462989.49 + + iteration: 5 PROBLEM Number: 5 + FWISO problem 5: d(5) + shot: 5: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.29 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116605 + Prä-Residuumnorm: 559482.92 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 422027.81 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.40 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + Inner Loop: : InnerCG resNorm : 517959.75 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.51 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Inner Loop: : InnerCG resNorm : 465239.18 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Inner Loop: : InnerCG resNorm : 428854.23 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.48 seconds + Initialization: 0.47 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.45 seconds + Inner Loop: : InnerCG resNorm : 393883.46 + Inner Loop: : Time needed for inner loop: 4:11.58 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:11.58 minutes + Residuumnorm 1: 393883.46 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.75 seconds + Intermezzo Residuum: 393851.07 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 508472.33 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + PhiAdjSO: : 1:02.75 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.92 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Inner Loop: : InnerCG resNorm : 377872.29 + Inner Loop: : Time needed for inner loop: 3:10.96 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.96 minutes + FWISO Subproblem: 5: d(5): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 377872.29 + + + Iteration Main Looop Counting Variable iter: 6 + + iteration: 6 PROBLEM Number: 0 + FWISO problem 0: d(6) + shot: 0: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.22 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116708 + Prä-Residuumnorm: 572036.23 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 468792.27 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + Inner Loop: : InnerCG resNorm : 532076.28 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Inner Loop: : InnerCG resNorm : 475368.43 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Inner Loop: : InnerCG resNorm : 433474.78 + Inner Loop: : Time needed for inner loop: 3:09.08 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:09.08 minutes + Residuumnorm 1: 433474.78 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Intermezzo Residuum: 433472.5 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 434752.64 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.92 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + PhiAdjSO: : 1:03.06 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.07 seconds + Inner Loop: : InnerCG resNorm : 418684.92 + Inner Loop: : Time needed for inner loop: 3:11.67 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.67 minutes + FWISO Subproblem: 0: d(6): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 418684.92 + + iteration: 6 PROBLEM Number: 1 + FWISO problem 1: d(6) + shot: 1: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.33 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116755 + Prä-Residuumnorm: 625060.96 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 508010.37 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.53 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.74 seconds + Inner Loop: : InnerCG resNorm : 543241.07 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Inner Loop: : InnerCG resNorm : 489104.31 + Inner Loop: : Time needed for inner loop: 2:06.20 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.20 minutes + Residuumnorm 1: 489104.31 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + Intermezzo Residuum: 489104.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 501359.95 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + PhiAdjSO: : 1:02.66 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Inner Loop: : InnerCG resNorm : 466567.91 + Inner Loop: : Time needed for inner loop: 3:10.64 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.64 minutes + FWISO Subproblem: 1: d(6): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 466567.91 + + iteration: 6 PROBLEM Number: 2 + FWISO problem 2: d(6) + shot: 2: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.17 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116844 + Prä-Residuumnorm: 759066.12 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 625758.03 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.23 seconds + Initialization: 0.46 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + Inner Loop: : InnerCG resNorm : 655974.36 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + Inner Loop: : InnerCG resNorm : 612572.88 + Inner Loop: : Time needed for inner loop: 2:05.67 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.67 minutes + Residuumnorm 1: 612572.88 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.71 seconds + Intermezzo Residuum: 612575.97 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 614809.93 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + PhiAdjSO: : 1:02.82 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Inner Loop: : InnerCG resNorm : 594441.88 + Inner Loop: : Time needed for inner loop: 3:11.01 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.01 minutes + FWISO Subproblem: 2: d(6): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 594441.88 + + iteration: 6 PROBLEM Number: 3 + FWISO problem 3: d(6) + shot: 3: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.25 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116936 + Prä-Residuumnorm: 737593.76 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 644860.09 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + Inner Loop: : InnerCG resNorm : 653050.01 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + Inner Loop: : InnerCG resNorm : 604291.66 + Inner Loop: : Time needed for inner loop: 2:05.90 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.90 minutes + Residuumnorm 1: 604291.66 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Initialization: 0.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Intermezzo Residuum: 604312.77 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 601395.5 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + PhiAdjSO: : 1:03.03 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Inner Loop: : InnerCG resNorm : 581830.8 + Inner Loop: : Time needed for inner loop: 3:11.26 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.26 minutes + FWISO Subproblem: 3: d(6): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 581830.8 + + iteration: 6 PROBLEM Number: 4 + FWISO problem 4: d(6) + shot: 4: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.34 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116943 + Prä-Residuumnorm: 542982.89 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 462891.87 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Inner Loop: : InnerCG resNorm : 500721.74 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.65 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + Inner Loop: : InnerCG resNorm : 469286.5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.71 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Inner Loop: : InnerCG resNorm : 448182.43 + Inner Loop: : Time needed for inner loop: 3:09.62 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:09.62 minutes + Residuumnorm 1: 448182.43 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Intermezzo Residuum: 448177.5 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 440222.44 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + PhiAdjSO: : 1:03.00 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.98 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.11 seconds + Inner Loop: : InnerCG resNorm : 436846.39 + Inner Loop: : Time needed for inner loop: 3:11.84 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.84 minutes + FWISO Subproblem: 4: d(6): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 436846.39 + + iteration: 6 PROBLEM Number: 5 + FWISO problem 5: d(6) + shot: 5: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.32 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 116979 + Prä-Residuumnorm: 463257.3 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 406350.21 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.60 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + Inner Loop: : InnerCG resNorm : 430556.01 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.70 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Inner Loop: : InnerCG resNorm : 399622.63 + Inner Loop: : Time needed for inner loop: 2:06.55 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.55 minutes + Residuumnorm 1: 399622.63 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Intermezzo Residuum: 399637.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 378918.03 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + PhiAdjSO: : 1:03.08 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.95 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Inner Loop: : InnerCG resNorm : 385343.17 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.86 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + PhiAdjSO: : 1:03.10 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.83 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Inner Loop: : InnerCG resNorm : 370292.1 + Inner Loop: : Time needed for inner loop: 6:22.74 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:22.74 minutes + FWISO Subproblem: 5: d(6): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 370292.1 + + + Iteration Main Looop Counting Variable iter: 7 + + iteration: 7 PROBLEM Number: 0 + FWISO problem 0: d(7) + shot: 0: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.30 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117090 + Prä-Residuumnorm: 478426.34 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 352869.8 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Inner Loop: : InnerCG resNorm : 447436.73 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Inner Loop: : InnerCG resNorm : 407791.57 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.64 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + Inner Loop: : InnerCG resNorm : 386089.74 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Inner Loop: : InnerCG resNorm : 359777.28 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.60 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + Inner Loop: : InnerCG resNorm : 335508.9 + Inner Loop: : Time needed for inner loop: 5:15.80 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:15.80 minutes + Residuumnorm 1: 335508.9 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + Intermezzo Residuum: 335505.24 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 327247.46 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.04 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + PhiAdjSO: : 1:03.02 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.04 seconds + Inner Loop: : InnerCG resNorm : 324395.81 + Inner Loop: : Time needed for inner loop: 3:11.48 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.48 minutes + FWISO Subproblem: 0: d(7): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 324395.81 + + iteration: 7 PROBLEM Number: 1 + FWISO problem 1: d(7) + shot: 1: Solving forward problem... + Initialization: 0.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.23 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117111 + Prä-Residuumnorm: 579000.3 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 423517.64 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Inner Loop: : InnerCG resNorm : 519304.5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Inner Loop: : InnerCG resNorm : 467039.96 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Inner Loop: : InnerCG resNorm : 430258.94 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.55 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Inner Loop: : InnerCG resNorm : 385948.41 + Inner Loop: : Time needed for inner loop: 4:12.42 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:12.42 minutes + Residuumnorm 1: 385948.41 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Intermezzo Residuum: 385926.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 417973.32 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.84 seconds + PhiAdjSO: : 1:02.92 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Inner Loop: : InnerCG resNorm : 368171.63 + Inner Loop: : Time needed for inner loop: 3:11.16 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.16 minutes + FWISO Subproblem: 1: d(7): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 368171.63 + + iteration: 7 PROBLEM Number: 2 + FWISO problem 2: d(7) + shot: 2: Solving forward problem... + Initialization: 0.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.26 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117158 + Prä-Residuumnorm: 779732.98 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 578515.81 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.37 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + Inner Loop: : InnerCG resNorm : 686345.81 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.50 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Inner Loop: : InnerCG resNorm : 628880.89 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.54 seconds + Initialization: 0.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Inner Loop: : InnerCG resNorm : 596528.67 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.48 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + Inner Loop: : InnerCG resNorm : 544221.23 + Inner Loop: : Time needed for inner loop: 4:12.09 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:12.09 minutes + Residuumnorm 1: 544221.23 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.08 seconds + Intermezzo Residuum: 544278.25 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 568394.25 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + PhiAdjSO: : 1:02.68 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Inner Loop: : InnerCG resNorm : 522436.55 + Inner Loop: : Time needed for inner loop: 3:10.99 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.99 minutes + FWISO Subproblem: 2: d(7): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 522436.55 + + iteration: 7 PROBLEM Number: 3 + FWISO problem 3: d(7) + shot: 3: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.19 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117204 + Prä-Residuumnorm: 728076.33 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 572885.3 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.28 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Inner Loop: : InnerCG resNorm : 642471 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.43 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + Inner Loop: : InnerCG resNorm : 602626.68 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.48 seconds + Inner Loop: : InnerCG resNorm : 564355.7 + Inner Loop: : Time needed for inner loop: 3:08.47 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.47 minutes + Residuumnorm 1: 564355.7 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + Intermezzo Residuum: 564395.39 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 534271.93 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + PhiAdjSO: : 1:02.99 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.84 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.05 seconds + Inner Loop: : InnerCG resNorm : 544506.23 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.87 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + PhiAdjSO: : 1:03.24 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Inner Loop: : InnerCG resNorm : 524747.44 + Inner Loop: : Time needed for inner loop: 6:23.01 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:23.01 minutes + FWISO Subproblem: 3: d(7): Finished first / second inner loop ( 3, 2 steps ) + ************************************* + Residuumnorm 2: 524747.44 + + iteration: 7 PROBLEM Number: 4 + FWISO problem 4: d(7) + shot: 4: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.29 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117250 + Prä-Residuumnorm: 526517.15 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 403969.38 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.32 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + Inner Loop: : InnerCG resNorm : 481855.66 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + Inner Loop: : InnerCG resNorm : 455103.72 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Inner Loop: : InnerCG resNorm : 432901.51 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.48 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + Inner Loop: : InnerCG resNorm : 405812.28 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Inner Loop: : InnerCG resNorm : 388405.8 + Inner Loop: : Time needed for inner loop: 5:14.63 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:14.63 minutes + Residuumnorm 1: 388405.8 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Intermezzo Residuum: 388410.17 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 384185.58 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.94 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + PhiAdjSO: : 1:02.78 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Inner Loop: : InnerCG resNorm : 377334.85 + Inner Loop: : Time needed for inner loop: 3:11.18 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.18 minutes + FWISO Subproblem: 4: d(7): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 377334.85 + + iteration: 7 PROBLEM Number: 5 + FWISO problem 5: d(7) + shot: 5: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.19 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117268 + Prä-Residuumnorm: 470459.25 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 371400.72 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.40 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + Inner Loop: : InnerCG resNorm : 438896.52 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.60 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Inner Loop: : InnerCG resNorm : 397705.41 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + Inner Loop: : InnerCG resNorm : 366216.12 + Inner Loop: : Time needed for inner loop: 3:09.25 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:09.25 minutes + Residuumnorm 1: 366216.12 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Intermezzo Residuum: 366196.07 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 427634.03 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + PhiAdjSO: : 1:02.64 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Inner Loop: : InnerCG resNorm : 351127.81 + Inner Loop: : Time needed for inner loop: 3:10.73 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.73 minutes + FWISO Subproblem: 5: d(7): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 351127.81 + + + Iteration Main Looop Counting Variable iter: 8 + + iteration: 8 PROBLEM Number: 0 + FWISO problem 0: d(8) + shot: 0: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.24 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117313 + Prä-Residuumnorm: 468376.76 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 394625.26 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.41 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Inner Loop: : InnerCG resNorm : 420855.23 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.53 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Inner Loop: : InnerCG resNorm : 386094.34 + Inner Loop: : Time needed for inner loop: 2:05.96 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.96 minutes + Residuumnorm 1: 386094.34 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.01 seconds + Intermezzo Residuum: 386103.44 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 288336.12 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.91 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + PhiAdjSO: : 1:02.82 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Inner Loop: : InnerCG resNorm : 369622.87 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.95 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + PhiAdjSO: : 1:02.96 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.84 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.76 seconds + Inner Loop: : InnerCG resNorm : 355545.05 + Inner Loop: : Time needed for inner loop: 6:22.26 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:22.26 minutes + FWISO Subproblem: 0: d(8): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 355545.05 + + iteration: 8 PROBLEM Number: 1 + FWISO problem 1: d(8) + shot: 1: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.20 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117458 + Prä-Residuumnorm: 512038.79 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 443288.26 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.22 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + Inner Loop: : InnerCG resNorm : 441383.56 + Inner Loop: : Time needed for inner loop: 1:02.66 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:02.66 minutes + Residuumnorm 1: 441383.56 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.49 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.70 seconds + Intermezzo Residuum: 441402.73 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 332671.15 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + PhiAdjSO: : 1:02.85 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.06 seconds + Inner Loop: : InnerCG resNorm : 415203.94 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + PhiAdjSO: : 1:03.00 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.86 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.74 seconds + Inner Loop: : InnerCG resNorm : 377973.87 + Inner Loop: : Time needed for inner loop: 6:22.21 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:22.21 minutes + FWISO Subproblem: 1: d(8): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 377973.87 + + iteration: 8 PROBLEM Number: 2 + FWISO problem 2: d(8) + shot: 2: Solving forward problem... + Initialization: 0.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.29 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117439 + Prä-Residuumnorm: 685509.87 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 597058.85 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.54 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Inner Loop: : InnerCG resNorm : 595474.86 + Inner Loop: : Time needed for inner loop: 1:03.17 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:03.17 minutes + Residuumnorm 1: 595474.86 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.76 seconds + Intermezzo Residuum: 595454.41 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 449738.42 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.84 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + PhiAdjSO: : 1:02.72 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Inner Loop: : InnerCG resNorm : 569443.22 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + PhiAdjSO: : 1:02.80 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Inner Loop: : InnerCG resNorm : 538643.77 + Inner Loop: : Time needed for inner loop: 6:21.37 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:21.38 minutes + FWISO Subproblem: 2: d(8): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 538643.77 + + iteration: 8 PROBLEM Number: 3 + FWISO problem 3: d(8) + shot: 3: Solving forward problem... + Initialization: 0.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.31 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117513 + Prä-Residuumnorm: 676033.66 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 579968.32 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.46 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Inner Loop: : InnerCG resNorm : 604269.01 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.61 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Inner Loop: : InnerCG resNorm : 562764.04 + Inner Loop: : Time needed for inner loop: 2:06.09 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.09 minutes + Residuumnorm 1: 562764.04 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.71 seconds + Intermezzo Residuum: 562783.23 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 586058 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + PhiAdjSO: : 1:02.90 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Inner Loop: : InnerCG resNorm : 543844 + Inner Loop: : Time needed for inner loop: 3:11.07 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.07 minutes + FWISO Subproblem: 3: d(8): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 543844 + + iteration: 8 PROBLEM Number: 4 + FWISO problem 4: d(8) + shot: 4: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.19 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117546 + Prä-Residuumnorm: 451843.1 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 388742.74 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.44 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Inner Loop: : InnerCG resNorm : 417055.55 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.43 seconds + Inner Loop: : InnerCG resNorm : 392896.17 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.38 seconds + Inner Loop: : InnerCG resNorm : 382190.45 + Inner Loop: : Time needed for inner loop: 3:08.41 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.41 minutes + Residuumnorm 1: 382190.45 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Intermezzo Residuum: 382178.97 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 296728.12 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + PhiAdjSO: : 1:02.83 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.84 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.14 seconds + Inner Loop: : InnerCG resNorm : 375908.01 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.90 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + PhiAdjSO: : 1:03.00 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Inner Loop: : InnerCG resNorm : 362405.75 + Inner Loop: : Time needed for inner loop: 6:22.83 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:22.83 minutes + FWISO Subproblem: 4: d(8): Finished first / second inner loop ( 3, 2 steps ) + ************************************* + Residuumnorm 2: 362405.75 + + iteration: 8 PROBLEM Number: 5 + FWISO problem 5: d(8) + shot: 5: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.36 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117615 + Prä-Residuumnorm: 399044.69 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 343030.23 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + Inner Loop: : InnerCG resNorm : 382854.2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.49 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + Inner Loop: : InnerCG resNorm : 354879.99 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + Inner Loop: : InnerCG resNorm : 331695.75 + Inner Loop: : Time needed for inner loop: 3:08.82 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.82 minutes + Residuumnorm 1: 331695.75 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.71 seconds + Intermezzo Residuum: 331691.97 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 326448.21 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + PhiAdjSO: : 1:02.77 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.70 seconds + Inner Loop: : InnerCG resNorm : 323189.3 + Inner Loop: : Time needed for inner loop: 3:10.33 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.33 minutes + FWISO Subproblem: 5: d(8): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 323189.3 + + + Iteration Main Looop Counting Variable iter: 9 + + iteration: 9 PROBLEM Number: 0 + FWISO problem 0: d(9) + shot: 0: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.20 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117627 + Prä-Residuumnorm: 422405.51 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 320303.46 und m_max 7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.36 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Inner Loop: : InnerCG resNorm : 390660.4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.55 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + Inner Loop: : InnerCG resNorm : 362041.15 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.49 seconds + Inner Loop: : InnerCG resNorm : 341054.44 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.50 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Inner Loop: : InnerCG resNorm : 322384.5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.50 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Inner Loop: : InnerCG resNorm : 305956.68 + Inner Loop: : Time needed for inner loop: 5:14.54 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:14.54 minutes + Residuumnorm 1: 305956.68 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.79 seconds + Intermezzo Residuum: 305943.97 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 341220.7 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + PhiAdjSO: : 1:02.91 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.02 seconds + Inner Loop: : InnerCG resNorm : 297457.8 + Inner Loop: : Time needed for inner loop: 3:11.18 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.18 minutes + FWISO Subproblem: 0: d(9): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 297457.8 + + iteration: 9 PROBLEM Number: 1 + FWISO problem 1: d(9) + shot: 1: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.29 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117707 + Prä-Residuumnorm: 472092.06 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 367834.59 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + Inner Loop: : InnerCG resNorm : 419248.53 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.48 seconds + Initialization: 0.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + Inner Loop: : InnerCG resNorm : 387048.41 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.46 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + Inner Loop: : InnerCG resNorm : 360101.68 + Inner Loop: : Time needed for inner loop: 3:08.64 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.64 minutes + Residuumnorm 1: 360101.68 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Intermezzo Residuum: 360084.49 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 389404.93 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + PhiAdjSO: : 1:02.92 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Inner Loop: : InnerCG resNorm : 344998.59 + Inner Loop: : Time needed for inner loop: 3:11.09 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.09 minutes + FWISO Subproblem: 1: d(9): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 344998.59 + + iteration: 9 PROBLEM Number: 2 + FWISO problem 2: d(9) + shot: 2: Solving forward problem... + Initialization: 0.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.22 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117779 + Prä-Residuumnorm: 677191.22 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 530832.19 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.43 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.48 seconds + Inner Loop: : InnerCG resNorm : 596858.51 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.49 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.45 seconds + Inner Loop: : InnerCG resNorm : 564297.03 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Inner Loop: : InnerCG resNorm : 533165.43 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.51 seconds + Initialization: 0.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.83 seconds + Inner Loop: : InnerCG resNorm : 493671.26 + Inner Loop: : Time needed for inner loop: 4:11.76 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:11.76 minutes + Residuumnorm 1: 493671.26 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.83 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Intermezzo Residuum: 493720.73 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 560736.04 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.93 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + PhiAdjSO: : 1:02.81 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Inner Loop: : InnerCG resNorm : 476103.68 + Inner Loop: : Time needed for inner loop: 3:11.16 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.16 minutes + FWISO Subproblem: 2: d(9): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 476103.68 + + iteration: 9 PROBLEM Number: 3 + FWISO problem 3: d(9) + shot: 3: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.22 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117791 + Prä-Residuumnorm: 666844.57 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 514876.51 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Inner Loop: : InnerCG resNorm : 593401.34 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.46 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.47 seconds + Inner Loop: : InnerCG resNorm : 556056.43 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.44 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + Inner Loop: : InnerCG resNorm : 523428.95 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + Inner Loop: : InnerCG resNorm : 495404.36 + Inner Loop: : Time needed for inner loop: 4:11.52 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:11.52 minutes + Residuumnorm 1: 495404.36 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.47 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Intermezzo Residuum: 495408.56 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 520282.73 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + PhiAdjSO: : 1:02.81 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.95 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Inner Loop: : InnerCG resNorm : 480041.53 + Inner Loop: : Time needed for inner loop: 3:11.01 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.01 minutes + FWISO Subproblem: 3: d(9): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 480041.53 + + iteration: 9 PROBLEM Number: 4 + FWISO problem 4: d(9) + shot: 4: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.32 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117838 + Prä-Residuumnorm: 478963.53 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 370868.2 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Inner Loop: : InnerCG resNorm : 423670.51 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + Inner Loop: : InnerCG resNorm : 398890.55 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.48 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Inner Loop: : InnerCG resNorm : 380394.89 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + Inner Loop: : InnerCG resNorm : 368086.65 + Inner Loop: : Time needed for inner loop: 4:11.95 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:11.95 minutes + Residuumnorm 1: 368086.65 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Intermezzo Residuum: 368088.01 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 396750.9 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.98 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + PhiAdjSO: : 1:02.81 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.74 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + Inner Loop: : InnerCG resNorm : 360101.57 + Inner Loop: : Time needed for inner loop: 3:11.33 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.33 minutes + FWISO Subproblem: 4: d(9): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 360101.57 + + iteration: 9 PROBLEM Number: 5 + FWISO problem 5: d(9) + shot: 5: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.30 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117885 + Prä-Residuumnorm: 399453.3 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 309043.34 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + Inner Loop: : InnerCG resNorm : 381168.4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.61 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Inner Loop: : InnerCG resNorm : 348735.47 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + Inner Loop: : InnerCG resNorm : 329400.9 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.49 seconds + Inner Loop: : InnerCG resNorm : 314456.28 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.55 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + Inner Loop: : InnerCG resNorm : 297516.57 + Inner Loop: : Time needed for inner loop: 5:15.21 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:15.21 minutes + Residuumnorm 1: 297516.57 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Intermezzo Residuum: 297508.69 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 294104.24 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.83 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + PhiAdjSO: : 1:02.88 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Inner Loop: : InnerCG resNorm : 287890.2 + Inner Loop: : Time needed for inner loop: 3:10.88 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.88 minutes + FWISO Subproblem: 5: d(9): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 287890.2 + + + Iteration Main Looop Counting Variable iter: 10 + + iteration: 10 PROBLEM Number: 0 + FWISO problem 0: d(10) + shot: 0: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.32 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117891 + Prä-Residuumnorm: 405591.27 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 366376.15 und m_max 7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.50 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.74 seconds + Inner Loop: : InnerCG resNorm : 371571.72 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.50 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + Inner Loop: : InnerCG resNorm : 347241.09 + Inner Loop: : Time needed for inner loop: 2:06.21 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:06.21 minutes + Residuumnorm 1: 347241.09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Intermezzo Residuum: 347239.45 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 294874.28 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + PhiAdjSO: : 1:02.84 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Inner Loop: : InnerCG resNorm : 335642.87 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.48 seconds + PhiAdjSO: : 1:02.81 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.74 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Inner Loop: : InnerCG resNorm : 324813.44 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + PhiAdjSO: : 1:03.14 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.94 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.17 seconds + Inner Loop: : InnerCG resNorm : 309421.43 + Inner Loop: : Time needed for inner loop: 9:33.73 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 9:33.73 minutes + FWISO Subproblem: 0: d(10): Finished first / second inner loop ( 2, 3 steps ) + ************************************* + Residuumnorm 2: 309421.43 + + iteration: 10 PROBLEM Number: 1 + FWISO problem 1: d(10) + shot: 1: Solving forward problem... + Initialization: 0.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.35 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118163 + Prä-Residuumnorm: 447010.86 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 414104.69 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Inner Loop: : InnerCG resNorm : 395029.15 + Inner Loop: : Time needed for inner loop: 1:03.09 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:03.09 minutes + Residuumnorm 1: 395029.15 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.07 seconds + Intermezzo Residuum: 395039.55 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 331845.04 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + PhiAdjSO: : 1:02.99 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.14 seconds + Inner Loop: : InnerCG resNorm : 374460.52 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + PhiAdjSO: : 1:02.95 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + Initialization: 0.47 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Inner Loop: : InnerCG resNorm : 341648.91 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.94 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + PhiAdjSO: : 1:03.15 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Inner Loop: : InnerCG resNorm : 324208.28 + Inner Loop: : Time needed for inner loop: 9:34.40 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 9:34.40 minutes + FWISO Subproblem: 1: d(10): Finished first / second inner loop ( 1, 3 steps ) + ************************************* + Residuumnorm 2: 324208.28 + + iteration: 10 PROBLEM Number: 2 + FWISO problem 2: d(10) + shot: 2: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.29 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118188 + Prä-Residuumnorm: 626059.4 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 592232.38 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Inner Loop: : InnerCG resNorm : 543997.56 + Inner Loop: : Time needed for inner loop: 1:02.87 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:02.87 minutes + Residuumnorm 1: 543997.56 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.46 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.46 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.71 seconds + Intermezzo Residuum: 543967.65 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 466557.53 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + PhiAdjSO: : 1:02.90 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.86 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Inner Loop: : InnerCG resNorm : 521136.6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + PhiAdjSO: : 1:02.83 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.83 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Inner Loop: : InnerCG resNorm : 490494.6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + PhiAdjSO: : 1:02.82 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.45 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.93 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.73 seconds + Inner Loop: : InnerCG resNorm : 465613.02 + Inner Loop: : Time needed for inner loop: 9:32.76 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 9:32.76 minutes + FWISO Subproblem: 2: d(10): Finished first / second inner loop ( 1, 3 steps ) + ************************************* + Residuumnorm 2: 465613.02 + + iteration: 10 PROBLEM Number: 3 + FWISO problem 3: d(10) + shot: 3: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.37 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118176 + Prä-Residuumnorm: 647876.81 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 574054.07 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.44 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + Inner Loop: : InnerCG resNorm : 579393.2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.44 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + Inner Loop: : InnerCG resNorm : 539027.48 + Inner Loop: : Time needed for inner loop: 2:05.83 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.83 minutes + Residuumnorm 1: 539027.48 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Intermezzo Residuum: 539039.89 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 454935.4 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.88 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + PhiAdjSO: : 1:02.79 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.94 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Inner Loop: : InnerCG resNorm : 520009.8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + PhiAdjSO: : 1:03.00 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Inner Loop: : InnerCG resNorm : 498245.51 + Inner Loop: : Time needed for inner loop: 6:22.18 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:22.18 minutes + FWISO Subproblem: 3: d(10): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 498245.51 + + iteration: 10 PROBLEM Number: 4 + FWISO problem 4: d(10) + shot: 4: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.31 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118243 + Prä-Residuumnorm: 430015.15 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 357228.88 und m_max 7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + Inner Loop: : InnerCG resNorm : 401605.2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.49 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + Inner Loop: : InnerCG resNorm : 376268.95 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + Inner Loop: : InnerCG resNorm : 363550.09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.64 seconds + Initialization: 0.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + Inner Loop: : InnerCG resNorm : 350389.86 + Inner Loop: : Time needed for inner loop: 4:12.52 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:12.52 minutes + Residuumnorm 1: 350389.86 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.74 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + Intermezzo Residuum: 350386.61 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 320583.93 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.92 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + PhiAdjSO: : 1:02.92 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Inner Loop: : InnerCG resNorm : 342483.12 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + PhiAdjSO: : 1:02.92 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.74 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.86 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Inner Loop: : InnerCG resNorm : 335347.71 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.95 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + PhiAdjSO: : 1:02.76 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.05 seconds + Inner Loop: : InnerCG resNorm : 324670.44 + Inner Loop: : Time needed for inner loop: 9:33.82 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 9:33.82 minutes + FWISO Subproblem: 4: d(10): Finished first / second inner loop ( 4, 3 steps ) + ************************************* + Residuumnorm 2: 324670.44 + + iteration: 10 PROBLEM Number: 5 + FWISO problem 5: d(10) + shot: 5: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.30 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118343 + Prä-Residuumnorm: 343464.6 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 296821.92 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.49 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Inner Loop: : InnerCG resNorm : 318889.51 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.49 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + Inner Loop: : InnerCG resNorm : 306162.75 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.53 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + Inner Loop: : InnerCG resNorm : 295382.58 + Inner Loop: : Time needed for inner loop: 3:09.04 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:09.04 minutes + Residuumnorm 1: 295382.58 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + Intermezzo Residuum: 295378.46 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 227593.45 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + PhiAdjSO: : 1:02.82 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.71 seconds + Inner Loop: : InnerCG resNorm : 288494.21 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.49 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.46 seconds + PhiAdjSO: : 1:02.93 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Inner Loop: : InnerCG resNorm : 282113.25 + Inner Loop: : Time needed for inner loop: 6:21.31 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:21.31 minutes + FWISO Subproblem: 5: d(10): Finished first / second inner loop ( 3, 2 steps ) + ************************************* + Residuumnorm 2: 282113.25 + + + Iteration Main Looop Counting Variable iter: 11 + + iteration: 11 PROBLEM Number: 0 + FWISO problem 0: d(11) + shot: 0: Solving forward problem... + Initialization: 0.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.29 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118380 + Prä-Residuumnorm: 380105.41 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 309018.99 und m_max 7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.48 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + Inner Loop: : InnerCG resNorm : 354515.93 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Inner Loop: : InnerCG resNorm : 322145.11 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.46 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + Inner Loop: : InnerCG resNorm : 308043.91 + Inner Loop: : Time needed for inner loop: 3:08.98 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.98 minutes + Residuumnorm 1: 308043.91 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.42 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.43 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + Intermezzo Residuum: 308045.94 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 345518.77 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + PhiAdjSO: : 1:02.83 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.43 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.70 seconds + Inner Loop: : InnerCG resNorm : 300814.93 + Inner Loop: : Time needed for inner loop: 3:10.21 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.21 minutes + FWISO Subproblem: 0: d(11): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 300814.93 + + iteration: 11 PROBLEM Number: 1 + FWISO problem 1: d(11) + shot: 1: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.24 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118470 + Prä-Residuumnorm: 398389.28 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 332156.1 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.36 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Inner Loop: : InnerCG resNorm : 357892.39 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Inner Loop: : InnerCG resNorm : 333390.79 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.46 seconds + Initialization: 0.46 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + Inner Loop: : InnerCG resNorm : 315895.86 + Inner Loop: : Time needed for inner loop: 3:08.74 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.74 minutes + Residuumnorm 1: 315895.86 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Intermezzo Residuum: 315894.37 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 364176.22 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.46 seconds + PhiAdjSO: : 1:02.69 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.47 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + Inner Loop: : InnerCG resNorm : 306178.56 + Inner Loop: : Time needed for inner loop: 3:10.37 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.37 minutes + FWISO Subproblem: 1: d(11): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 306178.56 + + iteration: 11 PROBLEM Number: 2 + FWISO problem 2: d(11) + shot: 2: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.27 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118517 + Prä-Residuumnorm: 552402.04 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 470299.37 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + Inner Loop: : InnerCG resNorm : 506090.73 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.48 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Inner Loop: : InnerCG resNorm : 483487.12 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + Inner Loop: : InnerCG resNorm : 463796.35 + Inner Loop: : Time needed for inner loop: 3:08.86 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.86 minutes + Residuumnorm 1: 463796.35 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.56 seconds + Intermezzo Residuum: 463797.52 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 505490.01 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + PhiAdjSO: : 1:02.83 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Inner Loop: : InnerCG resNorm : 450069.92 + Inner Loop: : Time needed for inner loop: 3:10.98 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.98 minutes + FWISO Subproblem: 2: d(11): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 450069.92 + + iteration: 11 PROBLEM Number: 3 + FWISO problem 3: d(11) + shot: 3: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.22 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118603 + Prä-Residuumnorm: 592901.4 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 472808.58 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + Inner Loop: : InnerCG resNorm : 544708.41 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.53 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.45 seconds + Inner Loop: : InnerCG resNorm : 515565.99 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.48 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.46 seconds + Inner Loop: : InnerCG resNorm : 485550.63 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + Inner Loop: : InnerCG resNorm : 462322.25 + Inner Loop: : Time needed for inner loop: 4:11.48 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:11.48 minutes + Residuumnorm 1: 462322.25 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.76 seconds + Intermezzo Residuum: 462349.4 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 504616.69 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + PhiAdjSO: : 1:02.80 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Inner Loop: : InnerCG resNorm : 449120.7 + Inner Loop: : Time needed for inner loop: 3:10.65 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.65 minutes + FWISO Subproblem: 3: d(11): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 449120.7 + + iteration: 11 PROBLEM Number: 4 + FWISO problem 4: d(11) + shot: 4: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.27 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118576 + Prä-Residuumnorm: 413062.72 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 308831.3 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.48 seconds + Initialization: 0.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + Inner Loop: : InnerCG resNorm : 377116.16 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + Inner Loop: : InnerCG resNorm : 347187.92 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.60 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.34 seconds + Inner Loop: : InnerCG resNorm : 337178.01 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + Initialization: 0.45 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + Inner Loop: : InnerCG resNorm : 326758.86 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Inner Loop: : InnerCG resNorm : 316727.07 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.60 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Inner Loop: : InnerCG resNorm : 308270.41 + Inner Loop: : Time needed for inner loop: 6:18.15 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 6 = m innere Iterationen + Inner Loop: : 6:18.15 minutes + Residuumnorm 1: 308270.41 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.92 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Intermezzo Residuum: 308270.25 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 378023.67 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.88 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + PhiAdjSO: : 1:03.03 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Inner Loop: : InnerCG resNorm : 302104.01 + Inner Loop: : Time needed for inner loop: 3:11.31 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.31 minutes + FWISO Subproblem: 4: d(11): Finished first / second inner loop ( 6, 1 steps ) + ************************************* + Residuumnorm 2: 302104.01 + + iteration: 11 PROBLEM Number: 5 + FWISO problem 5: d(11) + shot: 5: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.23 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118670 + Prä-Residuumnorm: 347001.73 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 269890.84 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Inner Loop: : InnerCG resNorm : 322776.89 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.59 seconds + Initialization: 0.47 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + Inner Loop: : InnerCG resNorm : 304835.11 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.60 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Inner Loop: : InnerCG resNorm : 293142.33 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Inner Loop: : InnerCG resNorm : 281421.6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.65 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + Inner Loop: : InnerCG resNorm : 269875.94 + Inner Loop: : Time needed for inner loop: 5:15.75 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:15.75 minutes + Residuumnorm 1: 269875.94 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + Intermezzo Residuum: 269872.97 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 288469.52 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + PhiAdjSO: : 1:03.21 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.96 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Inner Loop: : InnerCG resNorm : 262736.76 + Inner Loop: : Time needed for inner loop: 3:11.61 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.61 minutes + FWISO Subproblem: 5: d(11): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 262736.76 + + + Iteration Main Looop Counting Variable iter: 12 + + iteration: 12 PROBLEM Number: 0 + FWISO problem 0: d(12) + shot: 0: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.13 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118708 + Prä-Residuumnorm: 352124.05 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 308221.77 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + Inner Loop: : InnerCG resNorm : 330257.16 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.50 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + Inner Loop: : InnerCG resNorm : 310958.35 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + Inner Loop: : InnerCG resNorm : 295051.76 + Inner Loop: : Time needed for inner loop: 3:08.68 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.68 minutes + Residuumnorm 1: 295051.76 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Intermezzo Residuum: 295059.25 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 288075.14 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + PhiAdjSO: : 1:03.05 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Inner Loop: : InnerCG resNorm : 287242.2 + Inner Loop: : Time needed for inner loop: 3:11.14 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.14 minutes + FWISO Subproblem: 0: d(12): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 287242.2 + + iteration: 12 PROBLEM Number: 1 + FWISO problem 1: d(12) + shot: 1: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.21 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118818 + Prä-Residuumnorm: 375739.71 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 354917.17 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Inner Loop: : InnerCG resNorm : 338647.04 + Inner Loop: : Time needed for inner loop: 1:03.11 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:03.11 minutes + Residuumnorm 1: 338647.04 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.02 seconds + Intermezzo Residuum: 338646.91 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 309124.59 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + PhiAdjSO: : 1:02.91 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Inner Loop: : InnerCG resNorm : 325572.05 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + PhiAdjSO: : 1:02.90 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + Inner Loop: : InnerCG resNorm : 308741.27 + Inner Loop: : Time needed for inner loop: 6:22.35 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:22.35 minutes + FWISO Subproblem: 1: d(12): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 308741.27 + + iteration: 12 PROBLEM Number: 2 + FWISO problem 2: d(12) + shot: 2: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.35 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118965 + Prä-Residuumnorm: 545137.81 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 518130.14 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Inner Loop: : InnerCG resNorm : 499550.47 + Inner Loop: : Time needed for inner loop: 1:02.97 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:02.97 minutes + Residuumnorm 1: 499550.47 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + Intermezzo Residuum: 499540.18 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 448958.42 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + PhiAdjSO: : 1:02.75 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.47 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.67 seconds + Inner Loop: : InnerCG resNorm : 483014.49 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + PhiAdjSO: : 1:02.89 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.09 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Inner Loop: : InnerCG resNorm : 456480.55 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + PhiAdjSO: : 1:03.01 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.87 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Inner Loop: : InnerCG resNorm : 439625.59 + Inner Loop: : Time needed for inner loop: 9:32.52 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 9:32.52 minutes + FWISO Subproblem: 2: d(12): Finished first / second inner loop ( 1, 3 steps ) + ************************************* + Residuumnorm 2: 439625.59 + + iteration: 12 PROBLEM Number: 3 + FWISO problem 3: d(12) + shot: 3: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.28 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118993 + Prä-Residuumnorm: 577842.65 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 519321.32 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Inner Loop: : InnerCG resNorm : 524303.87 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + Inner Loop: : InnerCG resNorm : 493204.23 + Inner Loop: : Time needed for inner loop: 2:05.76 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.76 minutes + Residuumnorm 1: 493204.23 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.74 seconds + Intermezzo Residuum: 493197.59 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 442620.21 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + PhiAdjSO: : 1:02.82 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.42 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.75 seconds + Inner Loop: : InnerCG resNorm : 477693.33 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + PhiAdjSO: : 1:02.89 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.68 seconds + Inner Loop: : InnerCG resNorm : 458846.46 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.47 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.46 seconds + PhiAdjSO: : 1:02.64 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.73 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Inner Loop: : InnerCG resNorm : 421504.39 + Inner Loop: : Time needed for inner loop: 9:31.60 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 9:31.60 minutes + FWISO Subproblem: 3: d(12): Finished first / second inner loop ( 2, 3 steps ) + ************************************* + Residuumnorm 2: 421504.39 + + iteration: 12 PROBLEM Number: 4 + FWISO problem 4: d(12) + shot: 4: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.27 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 118991 + Prä-Residuumnorm: 400060.44 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 332760.14 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + Inner Loop: : InnerCG resNorm : 353570.45 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.43 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + Inner Loop: : InnerCG resNorm : 333340.18 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.50 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Inner Loop: : InnerCG resNorm : 321199.49 + Inner Loop: : Time needed for inner loop: 3:08.89 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.89 minutes + Residuumnorm 1: 321199.49 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.83 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Intermezzo Residuum: 321191.17 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 329511.91 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.99 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + PhiAdjSO: : 1:02.91 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Inner Loop: : InnerCG resNorm : 314985.87 + Inner Loop: : Time needed for inner loop: 3:11.41 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.41 minutes + FWISO Subproblem: 4: d(12): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 314985.87 + + iteration: 12 PROBLEM Number: 5 + FWISO problem 5: d(12) + shot: 5: Solving forward problem... + Initialization: 0.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.26 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119070 + Prä-Residuumnorm: 334247.9 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 289681.86 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.46 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.49 seconds + Inner Loop: : InnerCG resNorm : 310736.26 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.56 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + Inner Loop: : InnerCG resNorm : 295757.93 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + Inner Loop: : InnerCG resNorm : 283761.92 + Inner Loop: : Time needed for inner loop: 3:08.89 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.89 minutes + Residuumnorm 1: 283761.92 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.76 seconds + Intermezzo Residuum: 283755.84 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 250080.3 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.89 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + PhiAdjSO: : 1:03.20 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.88 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.75 seconds + Inner Loop: : InnerCG resNorm : 277052.03 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + PhiAdjSO: : 1:02.93 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.02 seconds + Inner Loop: : InnerCG resNorm : 270914.31 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + PhiAdjSO: : 1:02.91 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.00 seconds + Inner Loop: : InnerCG resNorm : 261818.25 + Inner Loop: : Time needed for inner loop: 9:33.62 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 9:33.62 minutes + FWISO Subproblem: 5: d(12): Finished first / second inner loop ( 3, 3 steps ) + ************************************* + Residuumnorm 2: 261818.25 + + + Iteration Main Looop Counting Variable iter: 13 + + iteration: 13 PROBLEM Number: 0 + FWISO problem 0: d(13) + shot: 0: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.41 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119130 + Prä-Residuumnorm: 340210.22 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 268014.01 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.44 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Inner Loop: : InnerCG resNorm : 309411.29 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Inner Loop: : InnerCG resNorm : 293110.52 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.49 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + Inner Loop: : InnerCG resNorm : 283251.92 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.61 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Inner Loop: : InnerCG resNorm : 269642.39 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Inner Loop: : InnerCG resNorm : 259050.54 + Inner Loop: : Time needed for inner loop: 5:15.28 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:15.28 minutes + Residuumnorm 1: 259050.54 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.74 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Intermezzo Residuum: 259050.04 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 250495.52 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.86 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + PhiAdjSO: : 1:02.99 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.74 seconds + Inner Loop: : InnerCG resNorm : 252415.64 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.87 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + PhiAdjSO: : 1:02.91 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.73 seconds + Inner Loop: : InnerCG resNorm : 245875.51 + Inner Loop: : Time needed for inner loop: 6:21.58 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:21.58 minutes + FWISO Subproblem: 0: d(13): Finished first / second inner loop ( 5, 2 steps ) + ************************************* + Residuumnorm 2: 245875.51 + + iteration: 13 PROBLEM Number: 1 + FWISO problem 1: d(13) + shot: 1: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.27 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119246 + Prä-Residuumnorm: 385919.61 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 328079.63 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + Inner Loop: : InnerCG resNorm : 349393.01 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + Initialization: 0.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Inner Loop: : InnerCG resNorm : 324762.42 + Inner Loop: : Time needed for inner loop: 2:05.82 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.82 minutes + Residuumnorm 1: 324762.42 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Intermezzo Residuum: 324764.55 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 351709.64 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + PhiAdjSO: : 1:02.96 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.45 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Inner Loop: : InnerCG resNorm : 312780.68 + Inner Loop: : Time needed for inner loop: 3:10.75 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.75 minutes + FWISO Subproblem: 1: d(13): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 312780.68 + + iteration: 13 PROBLEM Number: 2 + FWISO problem 2: d(13) + shot: 2: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.20 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119255 + Prä-Residuumnorm: 532699.77 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 455677.49 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.40 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + Inner Loop: : InnerCG resNorm : 488188.87 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Inner Loop: : InnerCG resNorm : 463058.86 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.51 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.86 seconds + Inner Loop: : InnerCG resNorm : 443697.99 + Inner Loop: : Time needed for inner loop: 3:09.08 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:09.08 minutes + Residuumnorm 1: 443697.99 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.75 seconds + Intermezzo Residuum: 443698.15 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 501371.46 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + PhiAdjSO: : 1:02.92 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.41 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.68 seconds + Inner Loop: : InnerCG resNorm : 430766.84 + Inner Loop: : Time needed for inner loop: 3:10.21 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.21 minutes + FWISO Subproblem: 2: d(13): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 430766.84 + + iteration: 13 PROBLEM Number: 3 + FWISO problem 3: d(13) + shot: 3: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.20 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119337 + Prä-Residuumnorm: 516869.5 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 418070.93 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + Inner Loop: : InnerCG resNorm : 468847.65 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.51 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + Inner Loop: : InnerCG resNorm : 446498.44 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.55 seconds + Initialization: 0.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Inner Loop: : InnerCG resNorm : 429541.4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.56 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + Inner Loop: : InnerCG resNorm : 413603.85 + Inner Loop: : Time needed for inner loop: 4:11.86 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:11.86 minutes + Residuumnorm 1: 413603.85 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Intermezzo Residuum: 413615.31 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 476551.51 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + PhiAdjSO: : 1:02.93 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.72 seconds + Inner Loop: : InnerCG resNorm : 404010.38 + Inner Loop: : Time needed for inner loop: 3:10.56 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.56 minutes + FWISO Subproblem: 3: d(13): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 404010.38 + + iteration: 13 PROBLEM Number: 4 + FWISO problem 4: d(13) + shot: 4: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.25 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119402 + Prä-Residuumnorm: 359281.11 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 268956.83 und m_max 9 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.40 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Inner Loop: : InnerCG resNorm : 336936.4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.53 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + Inner Loop: : InnerCG resNorm : 319328.3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + Inner Loop: : InnerCG resNorm : 309463.32 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.55 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + Inner Loop: : InnerCG resNorm : 300698.57 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.56 seconds + Initialization: 0.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.90 seconds + Inner Loop: : InnerCG resNorm : 291365.99 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.59 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + Inner Loop: : InnerCG resNorm : 282813.07 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.54 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.83 seconds + Inner Loop: : InnerCG resNorm : 274485.71 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.59 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.78 seconds + Inner Loop: : InnerCG resNorm : 266563.73 + Inner Loop: : Time needed for inner loop: 8:25.64 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 8 = m innere Iterationen + Inner Loop: : 8:25.64 minutes + Residuumnorm 1: 266563.73 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.74 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Intermezzo Residuum: 266563.3 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 266331.42 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.95 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + PhiAdjSO: : 1:03.12 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Inner Loop: : InnerCG resNorm : 260482.5 + Inner Loop: : Time needed for inner loop: 3:11.37 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.37 minutes + FWISO Subproblem: 4: d(13): Finished first / second inner loop ( 8, 1 steps ) + ************************************* + Residuumnorm 2: 260482.5 + + iteration: 13 PROBLEM Number: 5 + FWISO problem 5: d(13) + shot: 5: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.28 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119475 + Prä-Residuumnorm: 329175.9 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 256757.51 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.46 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.76 seconds + Inner Loop: : InnerCG resNorm : 291738.85 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.56 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.71 seconds + Inner Loop: : InnerCG resNorm : 280013.96 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.55 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + Inner Loop: : InnerCG resNorm : 270891.85 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.56 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + Inner Loop: : InnerCG resNorm : 255613.13 + Inner Loop: : Time needed for inner loop: 4:12.29 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:12.29 minutes + Residuumnorm 1: 255613.13 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.68 seconds + Intermezzo Residuum: 255613.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 301545.76 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.86 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + PhiAdjSO: : 1:02.83 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Inner Loop: : InnerCG resNorm : 247976.39 + Inner Loop: : Time needed for inner loop: 3:11.06 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.06 minutes + FWISO Subproblem: 5: d(13): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 247976.39 + + + Iteration Main Looop Counting Variable iter: 14 + + iteration: 14 PROBLEM Number: 0 + FWISO problem 0: d(14) + shot: 0: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.30 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119639 + Prä-Residuumnorm: 310524.23 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 270986.31 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.49 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.60 seconds + Inner Loop: : InnerCG resNorm : 294463.82 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.50 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + Inner Loop: : InnerCG resNorm : 275539.53 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.53 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + Inner Loop: : InnerCG resNorm : 263132.5 + Inner Loop: : Time needed for inner loop: 3:08.81 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:08.81 minutes + Residuumnorm 1: 263132.5 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Intermezzo Residuum: 263133.4 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 269581.03 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + PhiAdjSO: : 1:02.82 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Inner Loop: : InnerCG resNorm : 258158.81 + Inner Loop: : Time needed for inner loop: 3:10.75 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:10.75 minutes + FWISO Subproblem: 0: d(14): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 258158.81 + + iteration: 14 PROBLEM Number: 1 + FWISO problem 1: d(14) + shot: 1: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.27 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119661 + Prä-Residuumnorm: 359357.11 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 332427.66 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + Inner Loop: : InnerCG resNorm : 328240.09 + Inner Loop: : Time needed for inner loop: 1:03.22 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:03.22 minutes + Residuumnorm 1: 328240.09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.77 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.58 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Intermezzo Residuum: 328232.44 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 294751.61 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + PhiAdjSO: : 1:02.94 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.70 seconds + Inner Loop: : InnerCG resNorm : 315162.04 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.48 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + PhiAdjSO: : 1:02.85 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.81 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Inner Loop: : InnerCG resNorm : 294040.85 + Inner Loop: : Time needed for inner loop: 6:21.48 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:21.48 minutes + FWISO Subproblem: 1: d(14): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 294040.85 + + iteration: 14 PROBLEM Number: 2 + FWISO problem 2: d(14) + shot: 2: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.32 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119707 + Prä-Residuumnorm: 514172.18 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 489391.05 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.49 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.66 seconds + Inner Loop: : InnerCG resNorm : 475955.46 + Inner Loop: : Time needed for inner loop: 1:03.04 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:03.04 minutes + Residuumnorm 1: 475955.46 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.67 seconds + Intermezzo Residuum: 475947.68 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 435540.14 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.65 seconds + PhiAdjSO: : 1:02.92 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.68 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Inner Loop: : InnerCG resNorm : 462230.75 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.40 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.39 seconds + PhiAdjSO: : 1:02.73 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Inner Loop: : InnerCG resNorm : 438548.3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.67 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + PhiAdjSO: : 1:02.96 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.43 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.87 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Inner Loop: : InnerCG resNorm : 417324.23 + Inner Loop: : Time needed for inner loop: 9:31.75 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen + Inner Loop: : 9:31.75 minutes + FWISO Subproblem: 2: d(14): Finished first / second inner loop ( 1, 3 steps ) + ************************************* + Residuumnorm 2: 417324.23 + + iteration: 14 PROBLEM Number: 3 + FWISO problem 3: d(14) + shot: 3: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.30 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119670 + Prä-Residuumnorm: 511648.95 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 462748.62 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.35 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + Inner Loop: : InnerCG resNorm : 469448.12 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.48 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.44 seconds + Inner Loop: : InnerCG resNorm : 441705.13 + Inner Loop: : Time needed for inner loop: 2:05.56 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.56 minutes + Residuumnorm 1: 441705.13 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.69 seconds + Intermezzo Residuum: 441691.27 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 424564.37 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.53 seconds + PhiAdjSO: : 1:02.62 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Inner Loop: : InnerCG resNorm : 429017.17 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.39 seconds + PhiAdjSO: : 1:02.67 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.73 seconds + Inner Loop: : InnerCG resNorm : 413617.26 + Inner Loop: : Time needed for inner loop: 6:21.05 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:21.05 minutes + FWISO Subproblem: 3: d(14): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 413617.26 + + iteration: 14 PROBLEM Number: 4 + FWISO problem 4: d(14) + shot: 4: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.30 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119765 + Prä-Residuumnorm: 335868.34 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 304204 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.33 seconds + Initialization: 0.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + Inner Loop: : InnerCG resNorm : 306009.07 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + Inner Loop: : InnerCG resNorm : 286482.95 + Inner Loop: : Time needed for inner loop: 2:05.70 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:05.70 minutes + Residuumnorm 1: 286482.95 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.52 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.73 seconds + Intermezzo Residuum: 286475.11 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 224078.19 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.85 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.49 seconds + PhiAdjSO: : 1:02.62 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.80 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.76 seconds + Inner Loop: : InnerCG resNorm : 280399.61 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.55 seconds + PhiAdjSO: : 1:02.85 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.69 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.72 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Inner Loop: : InnerCG resNorm : 274861.47 + Inner Loop: : Time needed for inner loop: 6:21.39 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:21.39 minutes + FWISO Subproblem: 4: d(14): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 274861.47 + + iteration: 14 PROBLEM Number: 5 + FWISO problem 5: d(14) + shot: 5: Solving forward problem... + Initialization: 0.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.20 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119780 + Prä-Residuumnorm: 279798.83 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 233632.22 und m_max 7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.33 seconds + Initialization: 0.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + Inner Loop: : InnerCG resNorm : 266836.21 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.46 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.49 seconds + Inner Loop: : InnerCG resNorm : 254225.99 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + Inner Loop: : InnerCG resNorm : 246633.4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.44 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.47 seconds + Inner Loop: : InnerCG resNorm : 236029.82 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + Initialization: 0.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.63 seconds + Inner Loop: : InnerCG resNorm : 228591.39 + Inner Loop: : Time needed for inner loop: 5:14.29 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:14.29 minutes + Residuumnorm 1: 228591.39 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.56 seconds + Initialization: 0.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Intermezzo Residuum: 228596.68 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 230681.94 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.75 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.59 seconds + PhiAdjSO: : 1:02.95 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Initialization: 0.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Inner Loop: : InnerCG resNorm : 225097.3 + Inner Loop: : Time needed for inner loop: 3:11.01 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:11.01 minutes + FWISO Subproblem: 5: d(14): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 225097.3 + FWISO: d(15)= 0 + 2690118 + 1586895.4 + 1108691 + 849141.72 + 731349.55 + 669310.88 + 572036.23 + 478426.34 + 468376.76 + 422405.51 + 405591.27 + 380105.41 + 352124.05 + 340210.22 + 310524.23 + + + 2868113.2 + 1583899.4 + 1059064.2 + 882274.71 + 754686.86 + 704104.55 + 625060.96 + 579000.3 + 512038.79 + 472092.06 + 447010.86 + 398389.28 + 375739.71 + 385919.61 + 359357.11 + + + 2682703.5 + 1655011.6 + 1202482.9 + 1051337 + 964502.76 + 856932.94 + 759066.12 + 779732.98 + 685509.87 + 677191.22 + 626059.4 + 552402.04 + 545137.81 + 532699.77 + 514172.18 + + + 2198808.8 + 1454070.7 + 1154319.1 + 983717.18 + 932409.54 + 797072.47 + 737593.76 + 728076.33 + 676033.66 + 666844.57 + 647876.81 + 592901.4 + 577842.65 + 516869.5 + 511648.95 + + + 2149822.4 + 1340290.9 + 986145.81 + 825238.72 + 751102.95 + 623008.03 + 542982.89 + 526517.15 + 451843.1 + 478963.53 + 430015.15 + 413062.72 + 400060.44 + 359281.11 + 335868.34 + + + 1686014.7 + 1150971 + 803977.79 + 725433.9 + 623748.27 + 559482.92 + 463257.3 + 470459.25 + 399044.69 + 399453.3 + 343464.6 + 347001.73 + 334247.9 + 329175.9 + 279798.83 + + +end program after 14:39:30.00 hours on 64 procs at Tue Jun 27 15:22:11 2023 diff --git a/log/2023_06_27_noIC_VpMono_HighResolution/RunMpp.sh b/log/2023_06_27_noIC_VpMono_HighResolution/RunMpp.sh new file mode 100644 index 0000000000000000000000000000000000000000..32f1334f2bf2007377a18124946bcbfa77a14f3e --- /dev/null +++ b/log/2023_06_27_noIC_VpMono_HighResolution/RunMpp.sh @@ -0,0 +1,29 @@ +#!/bin/sh +### Job name +#SBATCH --job-name=MppFWILennart + +### File for the output +##vorher#SBATCH --output=Mpp%A ??????? +#SBATCH --output=Mpp%A + +### Time your job needs to execute +#SBATCH --time=200:00:00 + +### Use more than one node for parallel jobs on distributed-memory systems +###CR Version war 2, 4 geht, sofern genug frei. +#SBATCH --nodes=8 +###SBATCH --nodes=1 + +### Number of CPUS per task +#SBATCH --cpus-per-task=1 + +### Disable hyperthreading by setting the tasks per core to 1 +#SBATCH --ntasks-per-core=1 + +#SBATCH --mail-type=ALL + +#SBATCH --mail-user=uuwyh@student.kit.edu + +### Number of processes per node, in our case +#SBATCH --ntasks-per-node=16 +mpirun M++ diff --git a/log/2023_06_27_noIC_VpMono_HighResolution/logfile.log b/log/2023_06_27_noIC_VpMono_HighResolution/logfile.log new file mode 100644 index 0000000000000000000000000000000000000000..93ef206ad48612966a87f594571e0179fc8635c9 --- /dev/null +++ b/log/2023_06_27_noIC_VpMono_HighResolution/logfile.log @@ -0,0 +1,8976 @@ +start program on 128 procs at Mon Jun 26 23:46:11 2023 +Running on: node01 + reading config: ConfigVerbose........................... 2 + reading default: enableFileLogging....................... 1 + reading default: enableScreenLogging..................... 1 + reading default: precision............................... 8 + reading default: TimeLevel............................... 0 + reading config: Model................................... FWIInverse_DGTS + reading default: testAAO................................. 0 + reading config: ForwardSolver........................... VADGTS + reading config: ReconstructionType...................... SO + reading config: Mesh.................................... SeismogramGrid_test + reading config: level................................... 3 + reading default: plevel.................................. 3 + reading default: clevel.................................. 3 + reading config: Distribution............................ RCB + reading config: Overlap................................. dG1 + reading default: Scales.................................. 0 + reading default: CommSplit............................... 0 + reading default: DistributionVerbose..................... 0 + reading default: ClearDistribution....................... 1 + reading default: MeshesVerbose........................... 1 + reading default: MeshVerbose............................. 1 + Overlap: reading default: OverlapVerbose.......................... 0 + reading default: t0...................................... 0 + reading config: dt...................................... 0.0005 + reading config: T....................................... 0.6 + reading config: rkorder................................. -2 + reading config: SignalName.............................. Ricker + reading default: FrequencyFiltering...................... 0 + reading config: SignalFreq.............................. 25 + reading default: f_source................................ 25 + reading default: SourceInversion......................... 0 + reading config: SignalCutoff............................ 0.8 + reading config: SignalDelay............................. 0 + reading default: SaveFilteredSeismogram.................. 0 + reading config: SaveObservedSeismogram.................. 0 + reading config: numL.................................... 0 + reading default: dim..................................... 2 + reading config: Problem................................. VAcousticWaveC2Benchmark + reading default: RealDataLevel........................... 3 + reading default: InitialIterateLevel..................... 3 + reading config: deg..................................... 2 + reading config: parametrization......................... taup + reading default: shots................................... -1 + reading default: SourceStartX............................ -1e+100 + reading default: SourceStartY............................ -1e+100 + reading default: SourceEndX.............................. -1e+100 + reading default: SourceEndY.............................. -1e+100 + reading default: numberOfSourcesPerShot.................. 1 + reading config: FWISourceWaypoints...................... 2 + reading default: FWISourceIncludeLastWaypoint............ 1 + FWISourceCount0 + reading config: FWISourceCount0......................... 6 + reading config: FWISourceWaypoint0...................... 600,370 + FWISourceCount1 + reading config: FWISourceWaypoint1...................... 600,1620 + SOURCE LOCATIONS: + 0: ( 600.00000000, 370.00000000) + + + 1: ( 600.00000000, 620.00000000) + + + 2: ( 600.00000000, 870.00000000) + + + 3: ( 600.00000000, 1120) + + + 4: ( 600.00000000, 1370) + + + 5: ( 600.00000000, 1620) + + + reading config: source_factor........................... 242574257420000.5742 + reading config: Monoparam............................... Vp + monoparam = + Vp + reading default: z_perturb_0............................. 600 + reading default: z_perturb_1............................. 900 + reading default: z_perturb_2............................. 1200 + reading default: z_perturb_0_value....................... 1.05 + reading default: z_perturb_1_value....................... 1.1 + reading default: z_perturb_2_value....................... 0.95 + reading default: x_perturb............................... 900 + reading default: size_perturb............................ 200 + reading default: rho_bg.................................. 2000 + reading default: v_bg.................................... 3500 + reading default: tau_p_bg................................ 0.02 + reading default: impedance_bg............................ 1 + reading config: Qfactor................................. 100 + alphaValue = + 0 + reading default: FWIPrecon............................... 0 + reading default: FWIPreconType........................... 0 + reading default: FWIPreconRegularization................. 1e-08 + reading config: allowPlotting_M......................... 1 + reading config: allowPlotting_WF........................ 0 + reading default: plotFactor.............................. 1 + reading config: FWIReconstructRho....................... 0 + reading config: FWIReconstructV_P....................... 1 + reading config: FWIReconstructTauP...................... 0 + Mesh Info: + Mesh Name: ............................... SeismogramGrid_test + Distribution: ............................ RCB + Overlap: ................................. dG1 + CommSplit: ............................... 0 + Level: ................................... [3, -1, 0] + pLevel: .................................. 3 + Dimension: ............................... 2 + Cells: ................................... 87040 + Overlap: ................................. 21472 + Vertices: ................................ 98560 + Edges: ................................... 174672 + Faces: ................................... 218056 + ProcSets: ................................ 31900 + Mesh width [min, max]: ................... [12.500000, 29.474346] + + reading default: MatrixGraphVerbose...................... 0 + reading default: PaddingPML.............................. 0 + reading config: plot_tStep.............................. -1 + reading default: plotV................................... 0 + reading default: plot_rho................................ 1 + reading default: plot_kappa_0............................ 1 + reading default: plot_kappa_l............................ 0 + reading default: plot_velocity........................... 0 + reading config: compMeasure............................. 0 + Measure overall pressure p = p_0 + ... + p_L + reading default: Specfile................................ + reading config: FWIReceiverWaypoints.................... 2 + reading config: FWIReceiverIncludeLastWaypoint.......... 1 + FWIReceiverCount0 + reading config: FWIReceiverCount0....................... 64 + reading config: FWIReceiverWaypoint0.................... 1350.0, 370.0 + FWIReceiverCount1 + reading config: FWIReceiverWaypoint1.................... 1350.0, 1630.0 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + 0: ( 1350, 370.00000000) 1: ( 1350, 390.00000000) + 2: ( 1350, 410.00000000) 3: ( 1350, 430.00000000) + 4: ( 1350, 450.00000000) 5: ( 1350, 470.00000000) + 6: ( 1350, 490.00000000) 7: ( 1350, 510.00000000) + 8: ( 1350, 530.00000000) 9: ( 1350, 550.00000000) + 10: ( 1350, 570.00000000) 11: ( 1350, 590.00000000) + 12: ( 1350, 610.00000000) 13: ( 1350, 630.00000000) + 14: ( 1350, 650.00000000) 15: ( 1350, 670.00000000) + 16: ( 1350, 690.00000000) 17: ( 1350, 710.00000000) + 18: ( 1350, 730.00000000) 19: ( 1350, 750.00000000) + 20: ( 1350, 770.00000000) 21: ( 1350, 790.00000000) + 22: ( 1350, 810.00000000) 23: ( 1350, 830.00000000) + 24: ( 1350, 850.00000000) 25: ( 1350, 870.00000000) + 26: ( 1350, 890.00000000) 27: ( 1350, 910.00000000) + 28: ( 1350, 930.00000000) 29: ( 1350, 950.00000000) + 30: ( 1350, 970.00000000) 31: ( 1350, 990.00000000) + 32: ( 1350, 1010) 33: ( 1350, 1030) + 34: ( 1350, 1050) 35: ( 1350, 1070) + 36: ( 1350, 1090) 37: ( 1350, 1110) + 38: ( 1350, 1130) 39: ( 1350, 1150) + 40: ( 1350, 1170) 41: ( 1350, 1190) + 42: ( 1350, 1210) 43: ( 1350, 1230) + 44: ( 1350, 1250) 45: ( 1350, 1270) + 46: ( 1350, 1290) 47: ( 1350, 1310) + 48: ( 1350, 1330) 49: ( 1350, 1350) + 50: ( 1350, 1370) 51: ( 1350, 1390) + 52: ( 1350, 1410) 53: ( 1350, 1430) + 54: ( 1350, 1450) 55: ( 1350, 1470) + 56: ( 1350, 1490) 57: ( 1350, 1510) + 58: ( 1350, 1530) 59: ( 1350, 1550) + 60: ( 1350, 1570) 61: ( 1350, 1590) + 62: ( 1350, 1610) 63: ( 1350, 1630) + + reading default: UseGardener............................. 0 + reading default: MeasureComp............................. 0 + Measure overall pressure p = p_0 + ... + p_L + reading default: CountCellsOld........................... 0 + reading config: useTaper................................ 1 + reading default: TaperFromFile........................... + reading config: taperRadiusSource....................... 0 + reading default: taperBoxUpper........................... 1e+100 + reading default: taperBoxLower........................... -1e+100 + reading default: taperBoxLeft............................ -1e+100 + reading default: taperBoxRight........................... 1e+100 + reading config: taperRadiusReceiver..................... 0 + reading config: taperExponent........................... -0.1 + reading config: taperIgnoreSourceCells.................. 1 + reading config: taperIgnoreReceiverCells................ 1 + reading default: taperRhoMin............................. -1 + reading default: taperRhoMax............................. -1 + reading default: taperVpMin.............................. -1 + reading default: taperVpMax.............................. -1 + reading default: taperTaupMin............................ -1 + reading default: taperTaupMax............................ -1 + reading config: seismopath.............................. C2NoDampingT06dt0005/C2NoDampingT06dt0005 + reading config: ReadFormat.............................. FWI + Reading data from C2NoDampingT06dt0005/C2NoDampingT06dt00050 make sure it has 2 entries! + Reading data from C2NoDampingT06dt0005/C2NoDampingT06dt00051 make sure it has 2 entries! + Reading data from C2NoDampingT06dt0005/C2NoDampingT06dt00052 make sure it has 2 entries! + Reading data from C2NoDampingT06dt0005/C2NoDampingT06dt00053 make sure it has 2 entries! + Reading data from C2NoDampingT06dt0005/C2NoDampingT06dt00054 make sure it has 2 entries! + Reading data from C2NoDampingT06dt0005/C2NoDampingT06dt00055 make sure it has 2 entries! + FWISourceCount0 + FWISourceCount1 + SOURCE LOCATIONS: + 0: ( 600.00000000, 370.00000000) + + + 1: ( 600.00000000, 620.00000000) + + + 2: ( 600.00000000, 870.00000000) + + + 3: ( 600.00000000, 1120) + + + 4: ( 600.00000000, 1370) + + + 5: ( 600.00000000, 1620) + + + monoparam = + Vp + alphaValue = + 0 + Frequency Filter to: -1 + + + Mesh Info: + Mesh Name: ............................... SeismogramGrid_test + Distribution: ............................ RCB + Overlap: ................................. dG1 + CommSplit: ............................... 0 + Level: ................................... [3, -1, 0] + pLevel: .................................. 3 + Dimension: ............................... 2 + Cells: ................................... 87040 + Overlap: ................................. 21472 + Vertices: ................................ 98560 + Edges: ................................... 174672 + Faces: ................................... 218056 + ProcSets: ................................ 31900 + Mesh width [min, max]: ................... [12.500000, 29.474346] + + Measure overall pressure p = p_0 + ... + p_L + FWIReceiverCount0 + FWIReceiverCount1 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + 0: ( 1350, 370.00000000) 1: ( 1350, 390.00000000) + 2: ( 1350, 410.00000000) 3: ( 1350, 430.00000000) + 4: ( 1350, 450.00000000) 5: ( 1350, 470.00000000) + 6: ( 1350, 490.00000000) 7: ( 1350, 510.00000000) + 8: ( 1350, 530.00000000) 9: ( 1350, 550.00000000) + 10: ( 1350, 570.00000000) 11: ( 1350, 590.00000000) + 12: ( 1350, 610.00000000) 13: ( 1350, 630.00000000) + 14: ( 1350, 650.00000000) 15: ( 1350, 670.00000000) + 16: ( 1350, 690.00000000) 17: ( 1350, 710.00000000) + 18: ( 1350, 730.00000000) 19: ( 1350, 750.00000000) + 20: ( 1350, 770.00000000) 21: ( 1350, 790.00000000) + 22: ( 1350, 810.00000000) 23: ( 1350, 830.00000000) + 24: ( 1350, 850.00000000) 25: ( 1350, 870.00000000) + 26: ( 1350, 890.00000000) 27: ( 1350, 910.00000000) + 28: ( 1350, 930.00000000) 29: ( 1350, 950.00000000) + 30: ( 1350, 970.00000000) 31: ( 1350, 990.00000000) + 32: ( 1350, 1010) 33: ( 1350, 1030) + 34: ( 1350, 1050) 35: ( 1350, 1070) + 36: ( 1350, 1090) 37: ( 1350, 1110) + 38: ( 1350, 1130) 39: ( 1350, 1150) + 40: ( 1350, 1170) 41: ( 1350, 1190) + 42: ( 1350, 1210) 43: ( 1350, 1230) + 44: ( 1350, 1250) 45: ( 1350, 1270) + 46: ( 1350, 1290) 47: ( 1350, 1310) + 48: ( 1350, 1330) 49: ( 1350, 1350) + 50: ( 1350, 1370) 51: ( 1350, 1390) + 52: ( 1350, 1410) 53: ( 1350, 1430) + 54: ( 1350, 1450) 55: ( 1350, 1470) + 56: ( 1350, 1490) 57: ( 1350, 1510) + 58: ( 1350, 1530) 59: ( 1350, 1550) + 60: ( 1350, 1570) 61: ( 1350, 1590) + 62: ( 1350, 1610) 63: ( 1350, 1630) + + Measure overall pressure p = p_0 + ... + p_L + reading default: loadInitialModelFromFile................ 0 + reading default: loadRealModelFromFile................... 0 + reading default: PlotVerbose............................. 0 + reading default: PlotEnabled............................. 0 + reading default: PlotPrecision........................... 4 + reading config: FWINonlinearSolver...................... FWISO + reading default: FWI_MaxInnerLoopSteps_FWISO............. 10 + reading default: FWI_Gamma_FWISO......................... 0.9 + reading default: FWI_Damping_FWISO....................... 1 + reading default: FWI_ThetaMax_FWISO...................... 1 + reading default: FWI_ThetaInitial_FWISO.................. 0.4 + reading default: FWI_RegularizationStrategy_FWISO........ 0 + reading default: FWISO_Verbose........................... 1 + reading config: FWISO_Steps............................. 15 + reading default: FWISO_LineSearchSteps................... 3 + reading default: FWISO_Epsilon........................... 1e-10 + reading default: FWISO_Reduction......................... 1e-05 + reading default: FWISO_MinimalStepNumber................. 0 + reading default: FWI_Precon.............................. 0 + reading default: FWI_HierarchyLevel...................... -1 + reading default: FWI_SaveAdjointWF....................... 0 + reading default: FWI_SaveSeis............................ 0 + reading config: FWI_DebugPlottingLevel.................. 1 + reading default: FWI_BacktrackingFactor.................. 0.5 + reading default: FWI_BacktrackingActivated............... 0 + Memory Usage at start12527 + reading default: WriteSeismoToFileEvery.................. 2147483647 + Initialize Subproblems 12529 + Starting the Loops with max_iter: 15 and num_problems 6 + + + Iteration Main Looop Counting Variable iter: 0 + + iteration: 0 PROBLEM Number: 0 + FWISO problem 0: d(0) + shot: 0: Solving forward problem... + reading default: AssembleVerbose......................... 1 + reading default: startTime............................... 0 + reading default: endTime................................. 1 + reading default: maxStepSize............................. 1e+100 + reading default: stepSize................................ 0 + reading default: minStepSize............................. 0 + reading default: dt_min.................................. 0 + reading default: maxSteps................................ 0 + reading default: steps................................... 0 + reading default: K....................................... 0 + reading default: tEps.................................... 1e-15 + reading default: tTol.................................... 1e-06 + reading default: upwind.................................. 1 + reading config: dampingFlux............................. 1 + reading default: UseCollectTweak......................... 0 + reading default: Preconditioner_S........................ PointBlockJacobi + reading config: LinearSolver............................ LS + reading default: PreconditionerVerbose................... 0 + reading default: PreconditionerDamp...................... 1 + reading default: PointBlockJacobiLapack.................. 0 + reading config: LinearVerbose........................... -1 + reading config: LinearSteps............................. 100 + reading config: LinearEpsilon........................... 1e-12 + reading config: LinearReduction......................... 0.0001 + reading default: LinearMinimalStepNumber................. 0 + reading default: LinearPrintSteps........................ 800 + reading default: TimeIntegratorVerbose................... 1 + Initialization: 0.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.30 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 36385 + state_comps = + 1 + Prä-Residuumnorm: 9.339933e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.339933e+08 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.20 seconds + Inner Loop: : InnerCG resNorm : 9.3298049e+08 + Inner Loop: : Time needed for inner loop: 1:10.55 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:10.55 minutes + Residuumnorm 1: 9.3298049e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.22 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.68 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.83 seconds + Intermezzo Residuum: 20262376 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 9.339933e+08 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.82 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.20 seconds + PhiAdjSO: : 1:05.52 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.16 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.72 seconds + Inner Loop: : InnerCG resNorm : 13789062 + Inner Loop: : Time needed for inner loop: 3:47.95 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:47.95 minutes + FWISO Subproblem: 0: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 13789062 + reading default: PlotFactorIterates...................... 1 + reading default: PlotShot................................ -1 + + iteration: 0 PROBLEM Number: 1 + FWISO problem 1: d(0) + shot: 1: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.79 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 74780 + state_comps = + 1 + Prä-Residuumnorm: 9.7008053e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.7008053e+08 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.22 seconds + Initialization: 0.25 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.28 seconds + Inner Loop: : InnerCG resNorm : 9.6958891e+08 + Inner Loop: : Time needed for inner loop: 1:08.97 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:08.97 minutes + Residuumnorm 1: 9.6958891e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.42 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.01 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.96 seconds + Intermezzo Residuum: 18785875 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 9.7008053e+08 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.24 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.57 seconds + PhiAdjSO: : 1:06.00 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.99 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.59 seconds + Inner Loop: : InnerCG resNorm : 13142432 + Inner Loop: : Time needed for inner loop: 3:38.37 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:38.37 minutes + FWISO Subproblem: 1: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 13142432 + + iteration: 0 PROBLEM Number: 2 + FWISO problem 2: d(0) + shot: 2: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.65 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 73982 + state_comps = + 1 + Prä-Residuumnorm: 1.0324321e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0324321e+09 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.33 seconds + Initialization: 0.25 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.48 seconds + Inner Loop: : InnerCG resNorm : 1.0319364e+09 + Inner Loop: : Time needed for inner loop: 1:07.28 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:07.28 minutes + Residuumnorm 1: 1.0319364e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.40 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.10 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.04 seconds + Intermezzo Residuum: 22125202 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0324321e+09 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.62 seconds + PhiAdjSO: : 1:05.74 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.35 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.80 seconds + Inner Loop: : InnerCG resNorm : 14332746 + Inner Loop: : Time needed for inner loop: 3:30.82 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:30.82 minutes + FWISO Subproblem: 2: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 14332746 + + iteration: 0 PROBLEM Number: 3 + FWISO problem 3: d(0) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.58 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 74827 + state_comps = + 1 + Prä-Residuumnorm: 1.0882787e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0882787e+09 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.28 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.51 seconds + Inner Loop: : InnerCG resNorm : 1.0874116e+09 + Inner Loop: : Time needed for inner loop: 1:07.23 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:07.24 minutes + Residuumnorm 1: 1.0874116e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.98 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.75 seconds + Intermezzo Residuum: 19880183 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0882787e+09 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.27 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.66 seconds + PhiAdjSO: : 1:06.07 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.41 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.09 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.76 seconds + Inner Loop: : InnerCG resNorm : 13968698 + Inner Loop: : Time needed for inner loop: 3:30.42 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:30.42 minutes + FWISO Subproblem: 3: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 13968698 + + iteration: 0 PROBLEM Number: 4 + FWISO problem 4: d(0) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.47 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 77640 + state_comps = + 1 + Prä-Residuumnorm: 9.8805758e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.8805758e+08 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.40 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.94 seconds + Inner Loop: : InnerCG resNorm : 9.8716421e+08 + Inner Loop: : Time needed for inner loop: 1:08.77 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:08.77 minutes + Residuumnorm 1: 9.8716421e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.95 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.65 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.61 seconds + Intermezzo Residuum: 17860647 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 9.8805758e+08 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.94 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.73 seconds + PhiAdjSO: : 1:06.37 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.75 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.35 seconds + Inner Loop: : InnerCG resNorm : 12737294 + Inner Loop: : Time needed for inner loop: 3:37.33 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:37.33 minutes + FWISO Subproblem: 4: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 12737294 + + iteration: 0 PROBLEM Number: 5 + FWISO problem 5: d(0) + shot: 5: Solving forward problem... + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.47 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 78026 + state_comps = + 1 + Prä-Residuumnorm: 9.5387691e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5387691e+08 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.45 seconds + Initialization: 0.25 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.45 seconds + Inner Loop: : InnerCG resNorm : 9.5345245e+08 + Inner Loop: : Time needed for inner loop: 1:11.35 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:11.35 minutes + Residuumnorm 1: 9.5345245e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.05 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.79 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.63 seconds + Intermezzo Residuum: 11931257 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5387691e+08 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.94 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.62 seconds + PhiAdjSO: : 1:06.21 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.42 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.22 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.74 seconds + Inner Loop: : InnerCG resNorm : 8111713.9 + Inner Loop: : Time needed for inner loop: 3:48.43 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:48.43 minutes + FWISO Subproblem: 5: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 8111713.9 + + + Iteration Main Looop Counting Variable iter: 1 + + iteration: 1 PROBLEM Number: 0 + FWISO problem 0: d(1) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.98 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 79424 + Prä-Residuumnorm: 9.3280353e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3161527e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.38 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.76 seconds + Inner Loop: : InnerCG resNorm : 9.3271589e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.39 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.02 seconds + Inner Loop: : InnerCG resNorm : 9.3270214e+08 + Inner Loop: : Time needed for inner loop: 2:23.39 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:23.39 minutes + Residuumnorm 1: 9.3270214e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.38 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.39 seconds + Intermezzo Residuum: 6725279.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3161527e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.76 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.61 seconds + PhiAdjSO: : 1:06.06 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.00 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.65 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.87 seconds + Inner Loop: : InnerCG resNorm : 5573415.2 + Inner Loop: : Time needed for inner loop: 3:51.19 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:51.19 minutes + FWISO Subproblem: 0: d(1): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 5573415.2 + + iteration: 1 PROBLEM Number: 1 + FWISO problem 1: d(1) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.82 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 79530 + Prä-Residuumnorm: 9.6947803e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.688759e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.33 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.25 seconds + Inner Loop: : InnerCG resNorm : 9.6940544e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.31 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.51 seconds + Inner Loop: : InnerCG resNorm : 9.6938984e+08 + Inner Loop: : Time needed for inner loop: 2:18.24 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:18.24 minutes + Residuumnorm 1: 9.6938984e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.48 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.21 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.67 seconds + Intermezzo Residuum: 6743972.3 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 9.688759e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.44 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.71 seconds + PhiAdjSO: : 1:06.01 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.75 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.90 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.62 seconds + Inner Loop: : InnerCG resNorm : 5683079.8 + Inner Loop: : Time needed for inner loop: 3:38.62 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:38.62 minutes + FWISO Subproblem: 1: d(1): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 5683079.8 + + iteration: 1 PROBLEM Number: 2 + FWISO problem 2: d(1) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.85 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 80162 + Prä-Residuumnorm: 1.0317708e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0311099e+09 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.35 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.69 seconds + Inner Loop: : InnerCG resNorm : 1.0317051e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.34 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.71 seconds + Inner Loop: : InnerCG resNorm : 1.0316939e+09 + Inner Loop: : Time needed for inner loop: 2:14.92 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:14.92 minutes + Residuumnorm 1: 1.0316939e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.29 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.19 seconds + Intermezzo Residuum: 6593449.5 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0311099e+09 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.55 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.74 seconds + PhiAdjSO: : 1:05.92 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.30 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.78 seconds + Inner Loop: : InnerCG resNorm : 5738027 + Inner Loop: : Time needed for inner loop: 3:31.04 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:31.04 minutes + FWISO Subproblem: 2: d(1): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 5738027 + + iteration: 1 PROBLEM Number: 3 + FWISO problem 3: d(1) + shot: 3: Solving forward problem... + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.53 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 80301 + Prä-Residuumnorm: 1.0872811e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0862845e+09 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.25 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.39 seconds + Inner Loop: : InnerCG resNorm : 1.0872573e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.26 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.087247e+09 + Inner Loop: : Time needed for inner loop: 2:14.14 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:14.14 minutes + Residuumnorm 1: 1.087247e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.10 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.58 seconds + Intermezzo Residuum: 5926204 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0862845e+09 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.17 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.83 seconds + PhiAdjSO: : 1:05.95 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.12 seconds + Initialization: 0.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.56 seconds + Inner Loop: : InnerCG resNorm : 5253200.8 + Inner Loop: : Time needed for inner loop: 3:29.95 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.95 minutes + FWISO Subproblem: 3: d(1): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 5253200.8 + + iteration: 1 PROBLEM Number: 4 + FWISO problem 4: d(1) + shot: 4: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.41 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 81116 + Prä-Residuumnorm: 9.8700325e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.8595005e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.22 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.87 seconds + Inner Loop: : InnerCG resNorm : 9.8698042e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.19 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.99 seconds + Inner Loop: : InnerCG resNorm : 9.8697028e+08 + Inner Loop: : Time needed for inner loop: 2:17.11 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:17.11 minutes + Residuumnorm 1: 9.8697028e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.80 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.68 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.49 seconds + Intermezzo Residuum: 5586160.7 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 9.8595005e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.83 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.67 seconds + PhiAdjSO: : 1:05.93 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.13 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.52 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.43 seconds + Inner Loop: : InnerCG resNorm : 4985395.3 + Inner Loop: : Time needed for inner loop: 3:36.65 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:36.65 minutes + FWISO Subproblem: 4: d(1): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 4985395.3 + + iteration: 1 PROBLEM Number: 5 + FWISO problem 5: d(1) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.18 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 81105 + Prä-Residuumnorm: 9.5341075e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5294482e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.16 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.46 seconds + Inner Loop: : InnerCG resNorm : 9.5339671e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.14 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.50 seconds + Inner Loop: : InnerCG resNorm : 9.5338953e+08 + Inner Loop: : Time needed for inner loop: 2:22.10 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:22.10 minutes + Residuumnorm 1: 9.5338953e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.81 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.57 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.47 seconds + Intermezzo Residuum: 4601745.4 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5294482e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.91 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.60 seconds + PhiAdjSO: : 1:06.03 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.04 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.76 seconds + Inner Loop: : InnerCG resNorm : 4107311.6 + Inner Loop: : Time needed for inner loop: 3:50.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:50.00 minutes + FWISO Subproblem: 5: d(1): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 4107311.6 + + + Iteration Main Looop Counting Variable iter: 2 + + iteration: 2 PROBLEM Number: 0 + FWISO problem 0: d(2) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.59 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 81239 + Prä-Residuumnorm: 9.3269845e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3210439e+08 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.11 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.89 seconds + Inner Loop: : InnerCG resNorm : 9.3269113e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.20 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.91 seconds + Inner Loop: : InnerCG resNorm : 9.3268783e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.16 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.08 seconds + Inner Loop: : InnerCG resNorm : 9.3268503e+08 + Inner Loop: : Time needed for inner loop: 3:34.61 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:34.61 minutes + Residuumnorm 1: 9.3268503e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.46 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.01 seconds + Intermezzo Residuum: 3448030.5 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 8.3835929e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.78 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.58 seconds + PhiAdjSO: : 1:05.82 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.79 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.44 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.45 seconds + Inner Loop: : InnerCG resNorm : 3192485 + Inner Loop: : Time needed for inner loop: 3:50.11 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:50.11 minutes + FWISO Subproblem: 0: d(2): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 3192485 + + iteration: 2 PROBLEM Number: 1 + FWISO problem 1: d(2) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.57 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 81199 + Prä-Residuumnorm: 9.6939565e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.6909461e+08 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.12 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.28 seconds + Inner Loop: : InnerCG resNorm : 9.6937875e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.16 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.30 seconds + Inner Loop: : InnerCG resNorm : 9.6937537e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.14 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.15 seconds + Inner Loop: : InnerCG resNorm : 9.6937348e+08 + Inner Loop: : Time needed for inner loop: 3:26.38 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:26.38 minutes + Residuumnorm 1: 9.6937348e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.11 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.15 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.76 seconds + Intermezzo Residuum: 3428520.5 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 8.7191421e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.37 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.52 seconds + PhiAdjSO: : 1:05.86 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.71 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.48 seconds + Inner Loop: : InnerCG resNorm : 3245736.3 + Inner Loop: : Time needed for inner loop: 3:37.72 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:37.72 minutes + FWISO Subproblem: 1: d(2): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 3245736.3 + + iteration: 2 PROBLEM Number: 2 + FWISO problem 2: d(2) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.50 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 81371 + Prä-Residuumnorm: 1.0316953e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0313649e+09 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.08 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.61 seconds + Inner Loop: : InnerCG resNorm : 1.0316842e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.12 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.58 seconds + Inner Loop: : InnerCG resNorm : 1.0316819e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.10 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.48 seconds + Inner Loop: : InnerCG resNorm : 1.0316796e+09 + Inner Loop: : Time needed for inner loop: 3:21.22 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:21.22 minutes + Residuumnorm 1: 1.0316796e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.40 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.22 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.01 seconds + Intermezzo Residuum: 3432478.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 9.2793099e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.37 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.65 seconds + PhiAdjSO: : 1:05.82 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.08 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.76 seconds + Inner Loop: : InnerCG resNorm : 3193646.8 + Inner Loop: : Time needed for inner loop: 3:30.47 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:30.47 minutes + FWISO Subproblem: 2: d(2): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 3193646.8 + + iteration: 2 PROBLEM Number: 3 + FWISO problem 3: d(2) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.28 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 81389 + Prä-Residuumnorm: 1.0872506e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0867523e+09 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.28 seconds + Inner Loop: : InnerCG resNorm : 1.0872413e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.02 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.36 seconds + Inner Loop: : InnerCG resNorm : 1.0872385e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.01 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.29 seconds + Inner Loop: : InnerCG resNorm : 1.0872365e+09 + Inner Loop: : Time needed for inner loop: 3:20.19 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:20.19 minutes + Residuumnorm 1: 1.0872365e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.02 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.99 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.55 seconds + Intermezzo Residuum: 3522301.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 9.776286e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.20 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.65 seconds + PhiAdjSO: : 1:05.76 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.38 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.83 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.47 seconds + Inner Loop: : InnerCG resNorm : 3325267.6 + Inner Loop: : Time needed for inner loop: 3:29.37 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.37 minutes + FWISO Subproblem: 3: d(2): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 3325267.6 + + iteration: 2 PROBLEM Number: 4 + FWISO problem 4: d(2) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.12 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 82177 + Prä-Residuumnorm: 9.8696811e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.8644153e+08 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.94 seconds + Inner Loop: : InnerCG resNorm : 9.869646e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.94 seconds + Inner Loop: : InnerCG resNorm : 9.8696238e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.01 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.88 seconds + Inner Loop: : InnerCG resNorm : 9.8696082e+08 + Inner Loop: : Time needed for inner loop: 3:24.96 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:24.96 minutes + Residuumnorm 1: 9.8696082e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.82 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.59 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.44 seconds + Intermezzo Residuum: 3520021.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 8.8732345e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.89 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.52 seconds + PhiAdjSO: : 1:05.76 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.11 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.40 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.38 seconds + Inner Loop: : InnerCG resNorm : 3341592.9 + Inner Loop: : Time needed for inner loop: 3:36.36 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:36.36 minutes + FWISO Subproblem: 4: d(2): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 3341592.9 + + iteration: 2 PROBLEM Number: 5 + FWISO problem 5: d(2) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.12 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 82174 + Prä-Residuumnorm: 9.5339254e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5315958e+08 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.98 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.29 seconds + Inner Loop: : InnerCG resNorm : 9.5338659e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.49 seconds + Inner Loop: : InnerCG resNorm : 9.5338484e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.40 seconds + Inner Loop: : InnerCG resNorm : 9.5338292e+08 + Inner Loop: : Time needed for inner loop: 3:32.32 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:32.32 minutes + Residuumnorm 1: 9.5338292e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.52 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.44 seconds + Intermezzo Residuum: 2934724.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 8.5763396e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.86 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.49 seconds + PhiAdjSO: : 1:05.85 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.16 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.98 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.65 seconds + Inner Loop: : InnerCG resNorm : 2810078.8 + Inner Loop: : Time needed for inner loop: 3:47.20 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:47.20 minutes + FWISO Subproblem: 5: d(2): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 2810078.8 + + + Iteration Main Looop Counting Variable iter: 3 + + iteration: 3 PROBLEM Number: 0 + FWISO problem 0: d(3) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.62 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 82126 + Prä-Residuumnorm: 9.3268901e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3229297e+08 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.52 seconds + Inner Loop: : InnerCG resNorm : 9.326852e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.95 seconds + Inner Loop: : InnerCG resNorm : 9.3268418e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.94 seconds + Inner Loop: : InnerCG resNorm : 9.3268289e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.97 seconds + Inner Loop: : InnerCG resNorm : 9.3268216e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.00 seconds + Inner Loop: : InnerCG resNorm : 9.3268168e+08 + Inner Loop: : Time needed for inner loop: 5:59.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:59.00 minutes + Residuumnorm 1: 9.3268168e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.49 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.31 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.50 seconds + Intermezzo Residuum: 2395209.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 7.5451573e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.63 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.59 seconds + PhiAdjSO: : 1:05.68 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.36 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.63 seconds + Inner Loop: : InnerCG resNorm : 2330477.6 + Inner Loop: : Time needed for inner loop: 3:49.82 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:49.82 minutes + FWISO Subproblem: 0: d(3): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 2330477.6 + + iteration: 3 PROBLEM Number: 1 + FWISO problem 1: d(3) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.36 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 82276 + Prä-Residuumnorm: 9.6938351e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.6918282e+08 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.10 seconds + Inner Loop: : InnerCG resNorm : 9.6937407e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.22 seconds + Inner Loop: : InnerCG resNorm : 9.6937239e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.14 seconds + Inner Loop: : InnerCG resNorm : 9.6937185e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.22 seconds + Inner Loop: : InnerCG resNorm : 9.6937124e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.21 seconds + Inner Loop: : InnerCG resNorm : 9.6937093e+08 + Inner Loop: : Time needed for inner loop: 5:45.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:45.00 minutes + Residuumnorm 1: 9.6937093e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.19 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.13 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.49 seconds + Intermezzo Residuum: 2626849.6 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 7.8471296e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.27 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.38 seconds + PhiAdjSO: : 1:05.68 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.64 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.22 seconds + Inner Loop: : InnerCG resNorm : 2567374.4 + Inner Loop: : Time needed for inner loop: 3:37.25 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:37.25 minutes + FWISO Subproblem: 1: d(3): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 2567374.4 + + iteration: 3 PROBLEM Number: 2 + FWISO problem 2: d(3) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.41 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 84355 + Prä-Residuumnorm: 1.0316882e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0314679e+09 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.47 seconds + Inner Loop: : InnerCG resNorm : 1.0316798e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.46 seconds + Inner Loop: : InnerCG resNorm : 1.0316789e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.0316781e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.48 seconds + Inner Loop: : InnerCG resNorm : 1.0316776e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.41 seconds + Inner Loop: : InnerCG resNorm : 1.0316773e+09 + Inner Loop: : Time needed for inner loop: 5:36.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:36.00 minutes + Residuumnorm 1: 1.0316773e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.19 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.11 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.72 seconds + Intermezzo Residuum: 2695752 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 8.3513215e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.38 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.50 seconds + PhiAdjSO: : 1:05.79 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.08 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.64 seconds + Inner Loop: : InnerCG resNorm : 2634031.6 + Inner Loop: : Time needed for inner loop: 3:30.19 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:30.19 minutes + FWISO Subproblem: 2: d(3): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 2634031.6 + + iteration: 3 PROBLEM Number: 3 + FWISO problem 3: d(3) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.22 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 82402 + Prä-Residuumnorm: 1.0872436e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0869114e+09 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.22 seconds + Inner Loop: : InnerCG resNorm : 1.0872373e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.28 seconds + Inner Loop: : InnerCG resNorm : 1.087236e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.22 seconds + Inner Loop: : InnerCG resNorm : 1.0872351e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.23 seconds + Inner Loop: : InnerCG resNorm : 1.0872345e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.24 seconds + Inner Loop: : InnerCG resNorm : 1.0872343e+09 + Inner Loop: : Time needed for inner loop: 5:35.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:35.00 minutes + Residuumnorm 1: 1.0872343e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.86 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.45 seconds + Intermezzo Residuum: 2732014.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 8.7986008e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.07 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.62 seconds + PhiAdjSO: : 1:05.67 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.12 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.84 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.39 seconds + Inner Loop: : InnerCG resNorm : 2685811.3 + Inner Loop: : Time needed for inner loop: 3:28.81 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:28.81 minutes + FWISO Subproblem: 3: d(3): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 2685811.3 + + iteration: 3 PROBLEM Number: 4 + FWISO problem 4: d(3) + shot: 4: Solving forward problem... + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.07 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 83086 + Prä-Residuumnorm: 9.8696406e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.86613e+08 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.91 seconds + Inner Loop: : InnerCG resNorm : 9.8696099e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.98 seconds + Inner Loop: : InnerCG resNorm : 9.8695993e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.85 seconds + Inner Loop: : InnerCG resNorm : 9.8695927e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.98 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.87 seconds + Inner Loop: : InnerCG resNorm : 9.8695888e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.68 seconds + Inner Loop: : InnerCG resNorm : 9.8695858e+08 + Inner Loop: : Time needed for inner loop: 5:41.15 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:41.15 minutes + Residuumnorm 1: 9.8695858e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.78 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.61 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.43 seconds + Intermezzo Residuum: 2818161 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 7.9858782e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.96 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.45 seconds + PhiAdjSO: : 1:05.70 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.48 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.08 seconds + Inner Loop: : InnerCG resNorm : 2756352.4 + Inner Loop: : Time needed for inner loop: 3:38.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:38.00 minutes + FWISO Subproblem: 4: d(3): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 2756352.4 + + iteration: 3 PROBLEM Number: 5 + FWISO problem 5: d(3) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.03 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 83247 + Prä-Residuumnorm: 9.5338504e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5322973e+08 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.34 seconds + Inner Loop: : InnerCG resNorm : 9.5338298e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.98 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.59 seconds + Inner Loop: : InnerCG resNorm : 9.5338238e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.37 seconds + Inner Loop: : InnerCG resNorm : 9.5338176e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.40 seconds + Inner Loop: : InnerCG resNorm : 9.5338141e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.51 seconds + Inner Loop: : InnerCG resNorm : 9.5338125e+08 + Inner Loop: : Time needed for inner loop: 5:54.04 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:54.04 minutes + Residuumnorm 1: 9.5338125e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.76 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.56 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.56 seconds + Intermezzo Residuum: 2345071.2 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 7.7186449e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.95 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.53 seconds + PhiAdjSO: : 1:05.67 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.05 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.66 seconds + Inner Loop: : InnerCG resNorm : 2302454.5 + Inner Loop: : Time needed for inner loop: 3:46.92 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:46.92 minutes + FWISO Subproblem: 5: d(3): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 2302454.5 + + + Iteration Main Looop Counting Variable iter: 4 + + iteration: 4 PROBLEM Number: 0 + FWISO problem 0: d(4) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.57 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 83256 + Prä-Residuumnorm: 9.3268529e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3244767e+08 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.78 seconds + Inner Loop: : InnerCG resNorm : 9.3268274e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.04 seconds + Inner Loop: : InnerCG resNorm : 9.326822e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.79 seconds + Inner Loop: : InnerCG resNorm : 9.3268175e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.99 seconds + Inner Loop: : InnerCG resNorm : 9.3268141e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.98 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.95 seconds + Inner Loop: : InnerCG resNorm : 9.3268105e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.85 seconds + Inner Loop: : InnerCG resNorm : 9.3268086e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.88 seconds + Inner Loop: : InnerCG resNorm : 9.326807e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.02 seconds + Inner Loop: : InnerCG resNorm : 9.3268062e+08 + Inner Loop: : Time needed for inner loop: 9:33.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 8 = m innere Iterationen + Inner Loop: : 9:33.00 minutes + Residuumnorm 1: 9.3268062e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.41 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.31 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.29 seconds + Intermezzo Residuum: 1934750.4 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 6.7906145e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.62 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.41 seconds + PhiAdjSO: : 1:05.59 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.81 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.42 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.34 seconds + Inner Loop: : InnerCG resNorm : 1904796 + Inner Loop: : Time needed for inner loop: 3:49.59 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:49.59 minutes + FWISO Subproblem: 0: d(4): Finished first / second inner loop ( 8, 1 steps ) + ************************************* + Residuumnorm 2: 1904796 + + iteration: 4 PROBLEM Number: 1 + FWISO problem 1: d(4) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.43 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 83956 + Prä-Residuumnorm: 9.6938027e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.6925986e+08 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.24 seconds + Inner Loop: : InnerCG resNorm : 9.6937279e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.20 seconds + Inner Loop: : InnerCG resNorm : 9.6937151e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.13 seconds + Inner Loop: : InnerCG resNorm : 9.6937113e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.16 seconds + Inner Loop: : InnerCG resNorm : 9.6937066e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.12 seconds + Inner Loop: : InnerCG resNorm : 9.6937029e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.05 seconds + Inner Loop: : InnerCG resNorm : 9.6937005e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.01 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.12 seconds + Inner Loop: : InnerCG resNorm : 9.6936995e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.03 seconds + Inner Loop: : InnerCG resNorm : 9.6936979e+08 + Inner Loop: : Time needed for inner loop: 9:11.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 8 = m innere Iterationen + Inner Loop: : 9:11.00 minutes + Residuumnorm 1: 9.6936979e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.17 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.96 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.57 seconds + Intermezzo Residuum: 2182558.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 7.0623931e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.22 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.58 seconds + PhiAdjSO: : 1:05.59 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.17 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.57 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.52 seconds + Inner Loop: : InnerCG resNorm : 2141664.7 + Inner Loop: : Time needed for inner loop: 3:36.93 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:36.93 minutes + FWISO Subproblem: 1: d(4): Finished first / second inner loop ( 8, 1 steps ) + ************************************* + Residuumnorm 2: 2141664.7 + + iteration: 4 PROBLEM Number: 2 + FWISO problem 2: d(4) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.47 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 84578 + Prä-Residuumnorm: 1.0316873e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0315552e+09 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.41 seconds + Inner Loop: : InnerCG resNorm : 1.0316788e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.031678e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.46 seconds + Inner Loop: : InnerCG resNorm : 1.0316774e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.51 seconds + Inner Loop: : InnerCG resNorm : 1.031677e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.41 seconds + Inner Loop: : InnerCG resNorm : 1.0316768e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.50 seconds + Inner Loop: : InnerCG resNorm : 1.0316766e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.48 seconds + Inner Loop: : InnerCG resNorm : 1.0316764e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.38 seconds + Inner Loop: : InnerCG resNorm : 1.0316762e+09 + Inner Loop: : Time needed for inner loop: 8:58.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 8 = m innere Iterationen + Inner Loop: : 8:58.00 minutes + Residuumnorm 1: 1.0316762e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.11 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.68 seconds + Intermezzo Residuum: 2246467 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 7.516183e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.39 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.44 seconds + PhiAdjSO: : 1:05.52 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.95 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.54 seconds + Inner Loop: : InnerCG resNorm : 2205085.1 + Inner Loop: : Time needed for inner loop: 3:29.73 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.73 minutes + FWISO Subproblem: 2: d(4): Finished first / second inner loop ( 8, 1 steps ) + ************************************* + Residuumnorm 2: 2205085.1 + + iteration: 4 PROBLEM Number: 3 + FWISO problem 3: d(4) + shot: 3: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.12 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 84050 + Prä-Residuumnorm: 1.0872414e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.087042e+09 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.27 seconds + Inner Loop: : InnerCG resNorm : 1.087236e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.16 seconds + Inner Loop: : InnerCG resNorm : 1.087235e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.25 seconds + Inner Loop: : InnerCG resNorm : 1.0872345e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.24 seconds + Inner Loop: : InnerCG resNorm : 1.0872342e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.24 seconds + Inner Loop: : InnerCG resNorm : 1.0872339e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.15 seconds + Inner Loop: : InnerCG resNorm : 1.0872338e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.25 seconds + Inner Loop: : InnerCG resNorm : 1.0872336e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.23 seconds + Inner Loop: : InnerCG resNorm : 1.0872334e+09 + Inner Loop: : Time needed for inner loop: 8:56.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 8 = m innere Iterationen + Inner Loop: : 8:56.00 minutes + Residuumnorm 1: 1.0872334e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.02 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.16 seconds + Intermezzo Residuum: 2349439.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 7.9187244e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.14 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.53 seconds + PhiAdjSO: : 1:05.63 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.20 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.79 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.31 seconds + Inner Loop: : InnerCG resNorm : 2315744 + Inner Loop: : Time needed for inner loop: 3:28.78 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:28.78 minutes + FWISO Subproblem: 3: d(4): Finished first / second inner loop ( 8, 1 steps ) + ************************************* + Residuumnorm 2: 2315744 + + iteration: 4 PROBLEM Number: 4 + FWISO problem 4: d(4) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.08 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 83436 + Prä-Residuumnorm: 9.869625e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.8675187e+08 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.86 seconds + Inner Loop: : InnerCG resNorm : 9.8695974e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.88 seconds + Inner Loop: : InnerCG resNorm : 9.8695902e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.75 seconds + Inner Loop: : InnerCG resNorm : 9.8695859e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.74 seconds + Inner Loop: : InnerCG resNorm : 9.869582e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.75 seconds + Inner Loop: : InnerCG resNorm : 9.8695796e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.76 seconds + Inner Loop: : InnerCG resNorm : 9.8695776e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.71 seconds + Inner Loop: : InnerCG resNorm : 9.869576e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.76 seconds + Inner Loop: : InnerCG resNorm : 9.8695737e+08 + Inner Loop: : Time needed for inner loop: 9:08.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 8 = m innere Iterationen + Inner Loop: : 9:08.00 minutes + Residuumnorm 1: 9.8695737e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.72 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.43 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.38 seconds + Intermezzo Residuum: 2356864.4 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 7.1872791e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.74 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.64 seconds + PhiAdjSO: : 1:05.69 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.80 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.43 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.12 seconds + Inner Loop: : InnerCG resNorm : 2312314.5 + Inner Loop: : Time needed for inner loop: 3:35.54 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:35.54 minutes + FWISO Subproblem: 4: d(4): Finished first / second inner loop ( 8, 1 steps ) + ************************************* + Residuumnorm 2: 2312314.5 + + iteration: 4 PROBLEM Number: 5 + FWISO problem 5: d(4) + shot: 5: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.08 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 83378 + Prä-Residuumnorm: 9.53385e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5329182e+08 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.46 seconds + Inner Loop: : InnerCG resNorm : 9.533824e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.65 seconds + Inner Loop: : InnerCG resNorm : 9.5338161e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.59 seconds + Inner Loop: : InnerCG resNorm : 9.5338121e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.55 seconds + Inner Loop: : InnerCG resNorm : 9.5338102e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.41 seconds + Inner Loop: : InnerCG resNorm : 9.5338087e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.17 seconds + Inner Loop: : InnerCG resNorm : 9.533807e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.63 seconds + Inner Loop: : InnerCG resNorm : 9.5338054e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.48 seconds + Inner Loop: : InnerCG resNorm : 9.5338042e+08 + Inner Loop: : Time needed for inner loop: 9:30.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 8 = m innere Iterationen + Inner Loop: : 9:30.00 minutes + Residuumnorm 1: 9.5338042e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.56 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.39 seconds + Intermezzo Residuum: 1984329.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 6.9467801e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.91 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.47 seconds + PhiAdjSO: : 1:05.76 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.02 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.97 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.63 seconds + Inner Loop: : InnerCG resNorm : 1957548.3 + Inner Loop: : Time needed for inner loop: 3:49.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:49.00 minutes + FWISO Subproblem: 5: d(4): Finished first / second inner loop ( 8, 1 steps ) + ************************************* + Residuumnorm 2: 1957548.3 + + + Iteration Main Looop Counting Variable iter: 5 + + iteration: 5 PROBLEM Number: 0 + FWISO problem 0: d(5) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.42 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 84178 + Prä-Residuumnorm: 9.326836e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3253508e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.73 seconds + Inner Loop: : InnerCG resNorm : 9.3268184e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.92 seconds + Inner Loop: : InnerCG resNorm : 9.3268136e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.23 seconds + Inner Loop: : InnerCG resNorm : 9.3268102e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.93 seconds + Inner Loop: : InnerCG resNorm : 9.3268081e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.97 seconds + Inner Loop: : InnerCG resNorm : 9.3268067e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.78 seconds + Inner Loop: : InnerCG resNorm : 9.326805e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.22 seconds + Inner Loop: : InnerCG resNorm : 9.3268037e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.89 seconds + Inner Loop: : InnerCG resNorm : 9.326803e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.97 seconds + Inner Loop: : InnerCG resNorm : 9.3268018e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.85 seconds + Inner Loop: : InnerCG resNorm : 9.3268012e+08 + Inner Loop: : Time needed for inner loop: 11:57.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:57.00 minutes + Residuumnorm 1: 9.3268012e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.40 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.36 seconds + Intermezzo Residuum: 1694139.7 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 6.1115419e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.79 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.63 seconds + PhiAdjSO: : 1:05.65 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.59 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.80 seconds + Inner Loop: : InnerCG resNorm : 1677730.1 + Inner Loop: : Time needed for inner loop: 3:50.34 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:50.34 minutes + FWISO Subproblem: 0: d(5): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1677730.1 + + iteration: 5 PROBLEM Number: 1 + FWISO problem 1: d(5) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.30 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 83546 + Prä-Residuumnorm: 9.6937848e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.6930322e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.12 seconds + Inner Loop: : InnerCG resNorm : 9.6937173e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.19 seconds + Inner Loop: : InnerCG resNorm : 9.693708e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.99 seconds + Inner Loop: : InnerCG resNorm : 9.6937034e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.22 seconds + Inner Loop: : InnerCG resNorm : 9.6936999e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.18 seconds + Inner Loop: : InnerCG resNorm : 9.6936987e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.98 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.08 seconds + Inner Loop: : InnerCG resNorm : 9.6936969e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.98 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.11 seconds + Inner Loop: : InnerCG resNorm : 9.6936956e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.22 seconds + Inner Loop: : InnerCG resNorm : 9.6936948e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.06 seconds + Inner Loop: : InnerCG resNorm : 9.693694e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.00 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.11 seconds + Inner Loop: : InnerCG resNorm : 9.693693e+08 + Inner Loop: : Time needed for inner loop: 11:30.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:30.00 minutes + Residuumnorm 1: 9.693693e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.00 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.89 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.84 seconds + Intermezzo Residuum: 1946761.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 6.356142e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.11 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.61 seconds + PhiAdjSO: : 1:05.64 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.20 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.65 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.46 seconds + Inner Loop: : InnerCG resNorm : 1917523.8 + Inner Loop: : Time needed for inner loop: 3:36.81 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:36.81 minutes + FWISO Subproblem: 1: d(5): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1917523.8 + + iteration: 5 PROBLEM Number: 2 + FWISO problem 2: d(5) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.43 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 84955 + Prä-Residuumnorm: 1.031688e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0316054e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.42 seconds + Inner Loop: : InnerCG resNorm : 1.031678e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.36 seconds + Inner Loop: : InnerCG resNorm : 1.0316772e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.37 seconds + Inner Loop: : InnerCG resNorm : 1.0316767e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.46 seconds + Inner Loop: : InnerCG resNorm : 1.0316764e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.37 seconds + Inner Loop: : InnerCG resNorm : 1.0316762e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.45 seconds + Inner Loop: : InnerCG resNorm : 1.0316761e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.42 seconds + Inner Loop: : InnerCG resNorm : 1.031676e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.44 seconds + Inner Loop: : InnerCG resNorm : 1.0316759e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.34 seconds + Inner Loop: : InnerCG resNorm : 1.0316758e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.37 seconds + Inner Loop: : InnerCG resNorm : 1.0316757e+09 + Inner Loop: : Time needed for inner loop: 11:11.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:11.00 minutes + Residuumnorm 1: 1.0316757e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.10 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.98 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.45 seconds + Intermezzo Residuum: 1994023.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 6.7645688e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.45 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.53 seconds + PhiAdjSO: : 1:05.54 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.87 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.42 seconds + Inner Loop: : InnerCG resNorm : 1967099.1 + Inner Loop: : Time needed for inner loop: 3:29.33 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.33 minutes + FWISO Subproblem: 2: d(5): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1967099.1 + + iteration: 5 PROBLEM Number: 3 + FWISO problem 3: d(5) + shot: 3: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.02 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 83526 + Prä-Residuumnorm: 1.087241e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0871165e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.15 seconds + Inner Loop: : InnerCG resNorm : 1.0872351e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.20 seconds + Inner Loop: : InnerCG resNorm : 1.0872342e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.25 seconds + Inner Loop: : InnerCG resNorm : 1.0872338e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.21 seconds + Inner Loop: : InnerCG resNorm : 1.0872336e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.24 seconds + Inner Loop: : InnerCG resNorm : 1.0872334e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.18 seconds + Inner Loop: : InnerCG resNorm : 1.0872333e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.18 seconds + Inner Loop: : InnerCG resNorm : 1.0872332e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.17 seconds + Inner Loop: : InnerCG resNorm : 1.0872331e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.16 seconds + Inner Loop: : InnerCG resNorm : 1.087233e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.22 seconds + Inner Loop: : InnerCG resNorm : 1.0872329e+09 + Inner Loop: : Time needed for inner loop: 11:09.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:09.00 minutes + Residuumnorm 1: 1.0872329e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.79 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.19 seconds + Intermezzo Residuum: 2109825.7 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 7.1268499e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.24 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.50 seconds + PhiAdjSO: : 1:05.52 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.25 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.71 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.30 seconds + Inner Loop: : InnerCG resNorm : 2076537.5 + Inner Loop: : Time needed for inner loop: 3:28.73 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:28.73 minutes + FWISO Subproblem: 3: d(5): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 2076537.5 + + iteration: 5 PROBLEM Number: 4 + FWISO problem 4: d(5) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.96 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 84368 + Prä-Residuumnorm: 9.8696347e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.8683183e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.84 seconds + Inner Loop: : InnerCG resNorm : 9.8695905e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.79 seconds + Inner Loop: : InnerCG resNorm : 9.869582e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.73 seconds + Inner Loop: : InnerCG resNorm : 9.8695769e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.81 seconds + Inner Loop: : InnerCG resNorm : 9.8695744e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.71 seconds + Inner Loop: : InnerCG resNorm : 9.8695734e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.71 seconds + Inner Loop: : InnerCG resNorm : 9.8695722e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.70 seconds + Inner Loop: : InnerCG resNorm : 9.869571e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.66 seconds + Inner Loop: : InnerCG resNorm : 9.8695697e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.70 seconds + Inner Loop: : InnerCG resNorm : 9.8695688e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.73 seconds + Inner Loop: : InnerCG resNorm : 9.8695679e+08 + Inner Loop: : Time needed for inner loop: 11:25.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:25.00 minutes + Residuumnorm 1: 9.8695679e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.62 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.48 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.25 seconds + Intermezzo Residuum: 2112116.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 6.4685575e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.78 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.60 seconds + PhiAdjSO: : 1:05.72 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.25 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.02 seconds + Inner Loop: : InnerCG resNorm : 2076057.1 + Inner Loop: : Time needed for inner loop: 3:35.38 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:35.38 minutes + FWISO Subproblem: 4: d(5): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 2076057.1 + + iteration: 5 PROBLEM Number: 5 + FWISO problem 5: d(5) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.88 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 84380 + Prä-Residuumnorm: 9.5338338e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5332514e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.31 seconds + Inner Loop: : InnerCG resNorm : 9.5338157e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.55 seconds + Inner Loop: : InnerCG resNorm : 9.5338091e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.59 seconds + Inner Loop: : InnerCG resNorm : 9.5338059e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.36 seconds + Inner Loop: : InnerCG resNorm : 9.5338047e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.27 seconds + Inner Loop: : InnerCG resNorm : 9.533804e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.43 seconds + Inner Loop: : InnerCG resNorm : 9.5338029e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.45 seconds + Inner Loop: : InnerCG resNorm : 9.533802e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.24 seconds + Inner Loop: : InnerCG resNorm : 9.5338013e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.08 seconds + Inner Loop: : InnerCG resNorm : 9.5338007e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.22 seconds + Inner Loop: : InnerCG resNorm : 9.5337998e+08 + Inner Loop: : Time needed for inner loop: 11:51.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:51.00 minutes + Residuumnorm 1: 9.5337998e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.79 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.61 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.66 seconds + Intermezzo Residuum: 1754239.4 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 6.2520914e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.00 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.47 seconds + PhiAdjSO: : 1:05.63 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.20 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.25 seconds + Inner Loop: : InnerCG resNorm : 1725832.6 + Inner Loop: : Time needed for inner loop: 3:47.62 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:47.62 minutes + FWISO Subproblem: 5: d(5): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1725832.6 + + + Iteration Main Looop Counting Variable iter: 6 + + iteration: 6 PROBLEM Number: 0 + FWISO problem 0: d(6) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.49 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 85138 + Prä-Residuumnorm: 9.3268247e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3256365e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.62 seconds + Inner Loop: : InnerCG resNorm : 9.3268119e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.89 seconds + Inner Loop: : InnerCG resNorm : 9.3268082e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.13 seconds + Inner Loop: : InnerCG resNorm : 9.3268055e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.99 seconds + Inner Loop: : InnerCG resNorm : 9.3268037e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.80 seconds + Inner Loop: : InnerCG resNorm : 9.3268029e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.97 seconds + Inner Loop: : InnerCG resNorm : 9.3268017e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.39 seconds + Inner Loop: : InnerCG resNorm : 9.3268007e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.02 seconds + Inner Loop: : InnerCG resNorm : 9.3268002e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.93 seconds + Inner Loop: : InnerCG resNorm : 9.3267997e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.00 seconds + Inner Loop: : InnerCG resNorm : 9.3267991e+08 + Inner Loop: : Time needed for inner loop: 11:57.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:57.00 minutes + Residuumnorm 1: 9.3267991e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.36 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.45 seconds + Intermezzo Residuum: 1571667.6 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5.500381e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.77 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.55 seconds + PhiAdjSO: : 1:05.49 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.63 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.71 seconds + Inner Loop: : InnerCG resNorm : 1553557.7 + Inner Loop: : Time needed for inner loop: 3:50.16 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:50.16 minutes + FWISO Subproblem: 0: d(6): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1553557.7 + + iteration: 6 PROBLEM Number: 1 + FWISO problem 1: d(6) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.17 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 85081 + Prä-Residuumnorm: 9.6937496e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.6931475e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.11 seconds + Inner Loop: : InnerCG resNorm : 9.6937089e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.20 seconds + Inner Loop: : InnerCG resNorm : 9.6937023e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.23 seconds + Inner Loop: : InnerCG resNorm : 9.6936979e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.23 seconds + Inner Loop: : InnerCG resNorm : 9.6936953e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.15 seconds + Inner Loop: : InnerCG resNorm : 9.6936945e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.13 seconds + Inner Loop: : InnerCG resNorm : 9.6936931e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.06 seconds + Inner Loop: : InnerCG resNorm : 9.6936925e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.12 seconds + Inner Loop: : InnerCG resNorm : 9.6936916e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.10 seconds + Inner Loop: : InnerCG resNorm : 9.6936909e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.95 seconds + Inner Loop: : InnerCG resNorm : 9.6936904e+08 + Inner Loop: : Time needed for inner loop: 11:28.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:28.00 minutes + Residuumnorm 1: 9.6936904e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.01 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.95 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.97 seconds + Intermezzo Residuum: 1813336.7 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5.720507e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.20 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.62 seconds + PhiAdjSO: : 1:05.60 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.23 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.59 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.38 seconds + Inner Loop: : InnerCG resNorm : 1795238.6 + Inner Loop: : Time needed for inner loop: 3:36.79 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:36.79 minutes + FWISO Subproblem: 1: d(6): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1795238.6 + + iteration: 6 PROBLEM Number: 2 + FWISO problem 2: d(6) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.47 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 85229 + Prä-Residuumnorm: 1.0316855e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0316194e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.34 seconds + Inner Loop: : InnerCG resNorm : 1.0316774e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.34 seconds + Inner Loop: : InnerCG resNorm : 1.0316766e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.36 seconds + Inner Loop: : InnerCG resNorm : 1.0316762e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.41 seconds + Inner Loop: : InnerCG resNorm : 1.0316759e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.45 seconds + Inner Loop: : InnerCG resNorm : 1.0316757e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.50 seconds + Inner Loop: : InnerCG resNorm : 1.0316757e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.36 seconds + Inner Loop: : InnerCG resNorm : 1.0316756e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.41 seconds + Inner Loop: : InnerCG resNorm : 1.0316756e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.35 seconds + Inner Loop: : InnerCG resNorm : 1.0316755e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.39 seconds + Inner Loop: : InnerCG resNorm : 1.0316754e+09 + Inner Loop: : Time needed for inner loop: 11:11.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:11.00 minutes + Residuumnorm 1: 1.0316754e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.14 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.93 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.63 seconds + Intermezzo Residuum: 1821263.4 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 6.0880974e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.51 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.55 seconds + PhiAdjSO: : 1:05.52 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.43 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.91 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.54 seconds + Inner Loop: : InnerCG resNorm : 1803018.4 + Inner Loop: : Time needed for inner loop: 3:29.66 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.66 minutes + FWISO Subproblem: 2: d(6): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1803018.4 + + iteration: 6 PROBLEM Number: 3 + FWISO problem 3: d(6) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.08 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 85210 + Prä-Residuumnorm: 1.0872403e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0871406e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.17 seconds + Inner Loop: : InnerCG resNorm : 1.0872345e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.23 seconds + Inner Loop: : InnerCG resNorm : 1.0872336e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.20 seconds + Inner Loop: : InnerCG resNorm : 1.0872333e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.24 seconds + Inner Loop: : InnerCG resNorm : 1.0872331e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.26 seconds + Inner Loop: : InnerCG resNorm : 1.0872329e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.22 seconds + Inner Loop: : InnerCG resNorm : 1.0872329e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.26 seconds + Inner Loop: : InnerCG resNorm : 1.0872328e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.22 seconds + Inner Loop: : InnerCG resNorm : 1.0872328e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.20 seconds + Inner Loop: : InnerCG resNorm : 1.0872327e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.23 seconds + Inner Loop: : InnerCG resNorm : 1.0872327e+09 + Inner Loop: : Time needed for inner loop: 11:10.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:10.00 minutes + Residuumnorm 1: 1.0872327e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.98 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.79 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.31 seconds + Intermezzo Residuum: 1976904.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 6.4141603e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.17 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.57 seconds + PhiAdjSO: : 1:05.54 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.17 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.74 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.32 seconds + Inner Loop: : InnerCG resNorm : 1957171.9 + Inner Loop: : Time needed for inner loop: 3:28.69 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:28.69 minutes + FWISO Subproblem: 3: d(6): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1957171.9 + + iteration: 6 PROBLEM Number: 4 + FWISO problem 4: d(6) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.10 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 83986 + Prä-Residuumnorm: 9.8696367e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.8685836e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.81 seconds + Inner Loop: : InnerCG resNorm : 9.8695849e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.88 seconds + Inner Loop: : InnerCG resNorm : 9.8695761e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.80 seconds + Inner Loop: : InnerCG resNorm : 9.8695711e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.68 seconds + Inner Loop: : InnerCG resNorm : 9.869569e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.74 seconds + Inner Loop: : InnerCG resNorm : 9.8695685e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.79 seconds + Inner Loop: : InnerCG resNorm : 9.8695676e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.76 seconds + Inner Loop: : InnerCG resNorm : 9.8695664e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.67 seconds + Inner Loop: : InnerCG resNorm : 9.8695658e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.62 seconds + Inner Loop: : InnerCG resNorm : 9.8695652e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.81 seconds + Inner Loop: : InnerCG resNorm : 9.8695646e+08 + Inner Loop: : Time needed for inner loop: 11:24.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:24.00 minutes + Residuumnorm 1: 9.8695646e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.53 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.40 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.48 seconds + Intermezzo Residuum: 1944252 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5.821703e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.78 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.54 seconds + PhiAdjSO: : 1:05.69 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.77 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.36 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.06 seconds + Inner Loop: : InnerCG resNorm : 1923006.9 + Inner Loop: : Time needed for inner loop: 3:35.41 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:35.41 minutes + FWISO Subproblem: 4: d(6): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1923006.9 + + iteration: 6 PROBLEM Number: 5 + FWISO problem 5: d(6) + shot: 5: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.05 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 85358 + Prä-Residuumnorm: 9.5338205e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5333546e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.32 seconds + Inner Loop: : InnerCG resNorm : 9.5338081e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.46 seconds + Inner Loop: : InnerCG resNorm : 9.5338037e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.67 seconds + Inner Loop: : InnerCG resNorm : 9.5338014e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.63 seconds + Inner Loop: : InnerCG resNorm : 9.5338004e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.44 seconds + Inner Loop: : InnerCG resNorm : 9.5338e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.26 seconds + Inner Loop: : InnerCG resNorm : 9.5337993e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.45 seconds + Inner Loop: : InnerCG resNorm : 9.5337987e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.38 seconds + Inner Loop: : InnerCG resNorm : 9.5337985e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.32 seconds + Inner Loop: : InnerCG resNorm : 9.533798e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.42 seconds + Inner Loop: : InnerCG resNorm : 9.5337975e+08 + Inner Loop: : Time needed for inner loop: 11:51.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:51.00 minutes + Residuumnorm 1: 9.5337975e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.47 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.79 seconds + Intermezzo Residuum: 1625085.3 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5.6268745e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.91 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.49 seconds + PhiAdjSO: : 1:05.58 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.81 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.90 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.07 seconds + Inner Loop: : InnerCG resNorm : 1610145.5 + Inner Loop: : Time needed for inner loop: 3:49.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:49.00 minutes + FWISO Subproblem: 5: d(6): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1610145.5 + + + Iteration Main Looop Counting Variable iter: 7 + + iteration: 7 PROBLEM Number: 0 + FWISO problem 0: d(7) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.55 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 85302 + Prä-Residuumnorm: 9.3268155e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3262215e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.74 seconds + Inner Loop: : InnerCG resNorm : 9.3268068e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.97 seconds + Inner Loop: : InnerCG resNorm : 9.3268042e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.08 seconds + Inner Loop: : InnerCG resNorm : 9.3268023e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.27 seconds + Inner Loop: : InnerCG resNorm : 9.326801e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.80 seconds + Inner Loop: : InnerCG resNorm : 9.3268005e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.91 seconds + Inner Loop: : InnerCG resNorm : 9.3267995e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.13 seconds + Inner Loop: : InnerCG resNorm : 9.3267987e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.88 seconds + Inner Loop: : InnerCG resNorm : 9.3267983e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.14 seconds + Inner Loop: : InnerCG resNorm : 9.3267979e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.86 seconds + Inner Loop: : InnerCG resNorm : 9.3267975e+08 + Inner Loop: : Time needed for inner loop: 11:56.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:56.00 minutes + Residuumnorm 1: 9.3267975e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.32 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.40 seconds + Intermezzo Residuum: 1477253.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4.9503381e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.70 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.48 seconds + PhiAdjSO: : 1:05.39 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.45 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.61 seconds + Inner Loop: : InnerCG resNorm : 1461725.8 + Inner Loop: : Time needed for inner loop: 3:49.58 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:49.59 minutes + FWISO Subproblem: 0: d(7): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1461725.8 + + iteration: 7 PROBLEM Number: 1 + FWISO problem 1: d(7) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.19 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 84741 + Prä-Residuumnorm: 9.6937273e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.6934263e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.02 seconds + Inner Loop: : InnerCG resNorm : 9.6937029e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.03 seconds + Inner Loop: : InnerCG resNorm : 9.6936983e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.04 seconds + Inner Loop: : InnerCG resNorm : 9.6936944e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.29 seconds + Inner Loop: : InnerCG resNorm : 9.6936924e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.22 seconds + Inner Loop: : InnerCG resNorm : 9.6936916e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.04 seconds + Inner Loop: : InnerCG resNorm : 9.6936908e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.08 seconds + Inner Loop: : InnerCG resNorm : 9.6936903e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.99 seconds + Inner Loop: : InnerCG resNorm : 9.6936896e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.13 seconds + Inner Loop: : InnerCG resNorm : 9.6936889e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.12 seconds + Inner Loop: : InnerCG resNorm : 9.6936885e+08 + Inner Loop: : Time needed for inner loop: 11:29.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:29.00 minutes + Residuumnorm 1: 9.6936885e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.12 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.95 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.97 seconds + Intermezzo Residuum: 1701337.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5.1484445e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.18 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.62 seconds + PhiAdjSO: : 1:05.54 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.21 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.60 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.59 seconds + Inner Loop: : InnerCG resNorm : 1688725.9 + Inner Loop: : Time needed for inner loop: 3:36.91 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:36.91 minutes + FWISO Subproblem: 1: d(7): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1688725.9 + + iteration: 7 PROBLEM Number: 2 + FWISO problem 2: d(7) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.41 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 84749 + Prä-Residuumnorm: 1.0316828e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0316498e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.43 seconds + Inner Loop: : InnerCG resNorm : 1.031677e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.35 seconds + Inner Loop: : InnerCG resNorm : 1.0316762e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.32 seconds + Inner Loop: : InnerCG resNorm : 1.0316758e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.39 seconds + Inner Loop: : InnerCG resNorm : 1.0316756e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.39 seconds + Inner Loop: : InnerCG resNorm : 1.0316755e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.41 seconds + Inner Loop: : InnerCG resNorm : 1.0316754e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.41 seconds + Inner Loop: : InnerCG resNorm : 1.0316754e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.0316753e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.41 seconds + Inner Loop: : InnerCG resNorm : 1.0316753e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.36 seconds + Inner Loop: : InnerCG resNorm : 1.0316752e+09 + Inner Loop: : Time needed for inner loop: 11:11.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:11.00 minutes + Residuumnorm 1: 1.0316752e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.13 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.94 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.65 seconds + Intermezzo Residuum: 1720101.3 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5.4792734e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.41 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.49 seconds + PhiAdjSO: : 1:05.43 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.86 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.53 seconds + Inner Loop: : InnerCG resNorm : 1706253.3 + Inner Loop: : Time needed for inner loop: 3:29.30 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.30 minutes + FWISO Subproblem: 2: d(7): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1706253.3 + + iteration: 7 PROBLEM Number: 3 + FWISO problem 3: d(7) + shot: 3: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.98 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 84873 + Prä-Residuumnorm: 1.0872382e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0871884e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.76 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.12 seconds + Inner Loop: : InnerCG resNorm : 1.0872339e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.14 seconds + Inner Loop: : InnerCG resNorm : 1.0872333e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.20 seconds + Inner Loop: : InnerCG resNorm : 1.087233e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.17 seconds + Inner Loop: : InnerCG resNorm : 1.0872328e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.21 seconds + Inner Loop: : InnerCG resNorm : 1.0872327e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.15 seconds + Inner Loop: : InnerCG resNorm : 1.0872327e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.22 seconds + Inner Loop: : InnerCG resNorm : 1.0872326e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.15 seconds + Inner Loop: : InnerCG resNorm : 1.0872326e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.15 seconds + Inner Loop: : InnerCG resNorm : 1.0872325e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.16 seconds + Inner Loop: : InnerCG resNorm : 1.0872325e+09 + Inner Loop: : Time needed for inner loop: 11:08.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:08.00 minutes + Residuumnorm 1: 1.0872325e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.83 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.64 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.33 seconds + Intermezzo Residuum: 1872313.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5.7727333e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.13 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.56 seconds + PhiAdjSO: : 1:05.54 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.16 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.71 seconds + Initialization: 0.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.64 seconds + Inner Loop: : InnerCG resNorm : 1850231.7 + Inner Loop: : Time needed for inner loop: 3:28.89 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:28.89 minutes + FWISO Subproblem: 3: d(7): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1850231.7 + + iteration: 7 PROBLEM Number: 4 + FWISO problem 4: d(7) + shot: 4: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.05 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 86929 + Prä-Residuumnorm: 9.8696224e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.8690958e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.75 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.67 seconds + Inner Loop: : InnerCG resNorm : 9.8695799e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.75 seconds + Inner Loop: : InnerCG resNorm : 9.8695721e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.79 seconds + Inner Loop: : InnerCG resNorm : 9.8695675e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.80 seconds + Inner Loop: : InnerCG resNorm : 9.8695657e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.90 seconds + Inner Loop: : InnerCG resNorm : 9.8695653e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.79 seconds + Inner Loop: : InnerCG resNorm : 9.8695647e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.79 seconds + Inner Loop: : InnerCG resNorm : 9.8695642e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.69 seconds + Inner Loop: : InnerCG resNorm : 9.8695636e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.72 seconds + Inner Loop: : InnerCG resNorm : 9.8695629e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.70 seconds + Inner Loop: : InnerCG resNorm : 9.8695625e+08 + Inner Loop: : Time needed for inner loop: 11:24.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:24.00 minutes + Residuumnorm 1: 9.8695625e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.45 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.74 seconds + Intermezzo Residuum: 1828080.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5.239525e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.73 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.49 seconds + PhiAdjSO: : 1:05.59 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.77 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.38 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.11 seconds + Inner Loop: : InnerCG resNorm : 1814240.6 + Inner Loop: : Time needed for inner loop: 3:35.32 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:35.32 minutes + FWISO Subproblem: 4: d(7): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1814240.6 + + iteration: 7 PROBLEM Number: 5 + FWISO problem 5: d(7) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.96 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 85568 + Prä-Residuumnorm: 9.5338115e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5335786e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.22 seconds + Inner Loop: : InnerCG resNorm : 9.5338037e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.50 seconds + Inner Loop: : InnerCG resNorm : 9.5338007e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.45 seconds + Inner Loop: : InnerCG resNorm : 9.5337988e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.62 seconds + Inner Loop: : InnerCG resNorm : 9.5337981e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.29 seconds + Inner Loop: : InnerCG resNorm : 9.5337978e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.37 seconds + Inner Loop: : InnerCG resNorm : 9.5337972e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.51 seconds + Inner Loop: : InnerCG resNorm : 9.5337968e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.43 seconds + Inner Loop: : InnerCG resNorm : 9.5337966e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.49 seconds + Inner Loop: : InnerCG resNorm : 9.5337963e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.44 seconds + Inner Loop: : InnerCG resNorm : 9.5337958e+08 + Inner Loop: : Time needed for inner loop: 11:51.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:51.00 minutes + Residuumnorm 1: 9.5337958e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.80 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.64 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.75 seconds + Intermezzo Residuum: 1529543.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5.0641823e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.06 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.48 seconds + PhiAdjSO: : 1:05.54 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.97 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.90 seconds + Initialization: 0.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.21 seconds + Inner Loop: : InnerCG resNorm : 1517233.1 + Inner Loop: : Time needed for inner loop: 3:47.37 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:47.37 minutes + FWISO Subproblem: 5: d(7): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1517233.1 + + + Iteration Main Looop Counting Variable iter: 8 + + iteration: 8 PROBLEM Number: 0 + FWISO problem 0: d(8) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.45 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 85693 + Prä-Residuumnorm: 9.3268089e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3265119e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.80 seconds + Inner Loop: : InnerCG resNorm : 9.3268035e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.07 seconds + Inner Loop: : InnerCG resNorm : 9.3268015e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.13 seconds + Inner Loop: : InnerCG resNorm : 9.3268e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.31 seconds + Inner Loop: : InnerCG resNorm : 9.3267991e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.95 seconds + Inner Loop: : InnerCG resNorm : 9.3267987e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.98 seconds + Inner Loop: : InnerCG resNorm : 9.3267979e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.09 seconds + Inner Loop: : InnerCG resNorm : 9.3267973e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.86 seconds + Inner Loop: : InnerCG resNorm : 9.326797e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.82 seconds + Inner Loop: : InnerCG resNorm : 9.3267967e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.93 seconds + Inner Loop: : InnerCG resNorm : 9.3267963e+08 + Inner Loop: : Time needed for inner loop: 11:57.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:57.00 minutes + Residuumnorm 1: 9.3267963e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.37 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.33 seconds + Intermezzo Residuum: 1401593.7 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4.4553011e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.80 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.49 seconds + PhiAdjSO: : 1:05.40 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.74 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.74 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.36 seconds + Inner Loop: : InnerCG resNorm : 1388666.8 + Inner Loop: : Time needed for inner loop: 3:49.94 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:49.94 minutes + FWISO Subproblem: 0: d(8): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1388666.8 + + iteration: 8 PROBLEM Number: 1 + FWISO problem 1: d(8) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.24 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 85688 + Prä-Residuumnorm: 9.6937162e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.6935657e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.01 seconds + Inner Loop: : InnerCG resNorm : 9.6936984e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.02 seconds + Inner Loop: : InnerCG resNorm : 9.6936953e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.10 seconds + Inner Loop: : InnerCG resNorm : 9.6936918e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.20 seconds + Inner Loop: : InnerCG resNorm : 9.6936901e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.12 seconds + Inner Loop: : InnerCG resNorm : 9.6936893e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.13 seconds + Inner Loop: : InnerCG resNorm : 9.6936888e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.07 seconds + Inner Loop: : InnerCG resNorm : 9.6936885e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.09 seconds + Inner Loop: : InnerCG resNorm : 9.6936879e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.05 seconds + Inner Loop: : InnerCG resNorm : 9.6936874e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.17 seconds + Inner Loop: : InnerCG resNorm : 9.693687e+08 + Inner Loop: : Time needed for inner loop: 11:29.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:29.00 minutes + Residuumnorm 1: 9.693687e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.96 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.14 seconds + Intermezzo Residuum: 1608606.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4.6335948e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.16 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.59 seconds + PhiAdjSO: : 1:05.50 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.14 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.63 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.41 seconds + Inner Loop: : InnerCG resNorm : 1595303 + Inner Loop: : Time needed for inner loop: 3:36.64 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:36.64 minutes + FWISO Subproblem: 1: d(8): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1595303 + + iteration: 8 PROBLEM Number: 2 + FWISO problem 2: d(8) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.34 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 86465 + Prä-Residuumnorm: 1.031681e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0316645e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.44 seconds + Inner Loop: : InnerCG resNorm : 1.0316766e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.031676e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.38 seconds + Inner Loop: : InnerCG resNorm : 1.0316756e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.44 seconds + Inner Loop: : InnerCG resNorm : 1.0316754e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.42 seconds + Inner Loop: : InnerCG resNorm : 1.0316753e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.0316753e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.39 seconds + Inner Loop: : InnerCG resNorm : 1.0316752e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.39 seconds + Inner Loop: : InnerCG resNorm : 1.0316752e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.0316752e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.41 seconds + Inner Loop: : InnerCG resNorm : 1.0316751e+09 + Inner Loop: : Time needed for inner loop: 11:11.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:11.00 minutes + Residuumnorm 1: 1.0316751e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.18 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.02 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.75 seconds + Intermezzo Residuum: 1653673.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4.9313374e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.41 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.51 seconds + PhiAdjSO: : 1:05.43 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.47 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.00 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.43 seconds + Inner Loop: : InnerCG resNorm : 1640346.2 + Inner Loop: : Time needed for inner loop: 3:29.54 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.54 minutes + FWISO Subproblem: 2: d(8): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1640346.2 + + iteration: 8 PROBLEM Number: 3 + FWISO problem 3: d(8) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.95 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 87085 + Prä-Residuumnorm: 1.0872367e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0872118e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.27 seconds + Inner Loop: : InnerCG resNorm : 1.0872336e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.16 seconds + Inner Loop: : InnerCG resNorm : 1.087233e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.22 seconds + Inner Loop: : InnerCG resNorm : 1.0872328e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.21 seconds + Inner Loop: : InnerCG resNorm : 1.0872327e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.26 seconds + Inner Loop: : InnerCG resNorm : 1.0872325e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.18 seconds + Inner Loop: : InnerCG resNorm : 1.0872325e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.25 seconds + Inner Loop: : InnerCG resNorm : 1.0872325e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.22 seconds + Inner Loop: : InnerCG resNorm : 1.0872324e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.14 seconds + Inner Loop: : InnerCG resNorm : 1.0872324e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.20 seconds + Inner Loop: : InnerCG resNorm : 1.0872324e+09 + Inner Loop: : Time needed for inner loop: 11:09.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:09.00 minutes + Residuumnorm 1: 1.0872324e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.93 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.75 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.38 seconds + Intermezzo Residuum: 1795982.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 5.195453e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.12 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.53 seconds + PhiAdjSO: : 1:05.49 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.12 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.74 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.31 seconds + Inner Loop: : InnerCG resNorm : 1785159 + Inner Loop: : Time needed for inner loop: 3:28.51 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:28.51 minutes + FWISO Subproblem: 3: d(8): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1785159 + + iteration: 8 PROBLEM Number: 4 + FWISO problem 4: d(8) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.92 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 87161 + Prä-Residuumnorm: 9.869608e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.8693447e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.76 seconds + Inner Loop: : InnerCG resNorm : 9.8695759e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.90 seconds + Inner Loop: : InnerCG resNorm : 9.8695691e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.93 seconds + Inner Loop: : InnerCG resNorm : 9.8695651e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.79 seconds + Inner Loop: : InnerCG resNorm : 9.8695636e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.87 seconds + Inner Loop: : InnerCG resNorm : 9.8695632e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.70 seconds + Inner Loop: : InnerCG resNorm : 9.8695627e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.77 seconds + Inner Loop: : InnerCG resNorm : 9.8695623e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.79 seconds + Inner Loop: : InnerCG resNorm : 9.8695619e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.66 seconds + Inner Loop: : InnerCG resNorm : 9.8695614e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.72 seconds + Inner Loop: : InnerCG resNorm : 9.8695609e+08 + Inner Loop: : Time needed for inner loop: 11:25.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:25.00 minutes + Residuumnorm 1: 9.8695609e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.49 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.46 seconds + Intermezzo Residuum: 1738639.5 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4.7155657e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.77 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.47 seconds + PhiAdjSO: : 1:05.52 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.91 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.31 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.12 seconds + Inner Loop: : InnerCG resNorm : 1725114.1 + Inner Loop: : Time needed for inner loop: 3:35.35 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:35.35 minutes + FWISO Subproblem: 4: d(8): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1725114.1 + + iteration: 8 PROBLEM Number: 5 + FWISO problem 5: d(8) + shot: 5: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.94 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 87206 + Prä-Residuumnorm: 9.5338062e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5336898e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.31 seconds + Inner Loop: : InnerCG resNorm : 9.5338009e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.79 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.48 seconds + Inner Loop: : InnerCG resNorm : 9.5337986e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.58 seconds + Inner Loop: : InnerCG resNorm : 9.533797e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.47 seconds + Inner Loop: : InnerCG resNorm : 9.5337965e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.28 seconds + Inner Loop: : InnerCG resNorm : 9.5337962e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.57 seconds + Inner Loop: : InnerCG resNorm : 9.5337958e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.59 seconds + Inner Loop: : InnerCG resNorm : 9.5337954e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.58 seconds + Inner Loop: : InnerCG resNorm : 9.5337953e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.52 seconds + Inner Loop: : InnerCG resNorm : 9.533795e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.43 seconds + Inner Loop: : InnerCG resNorm : 9.5337946e+08 + Inner Loop: : Time needed for inner loop: 11:52.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:52.00 minutes + Residuumnorm 1: 9.5337946e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.38 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.93 seconds + Intermezzo Residuum: 1454288.7 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4.5577615e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.88 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.48 seconds + PhiAdjSO: : 1:05.55 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.74 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.07 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.16 seconds + Inner Loop: : InnerCG resNorm : 1443967.1 + Inner Loop: : Time needed for inner loop: 3:47.11 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:47.12 minutes + FWISO Subproblem: 5: d(8): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1443967.1 + + + Iteration Main Looop Counting Variable iter: 9 + + iteration: 9 PROBLEM Number: 0 + FWISO problem 0: d(9) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.58 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 87885 + Prä-Residuumnorm: 9.326805e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3266565e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.72 seconds + Inner Loop: : InnerCG resNorm : 9.3268013e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.98 seconds + Inner Loop: : InnerCG resNorm : 9.3267995e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.34 seconds + Inner Loop: : InnerCG resNorm : 9.3267983e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.15 seconds + Inner Loop: : InnerCG resNorm : 9.3267977e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.89 seconds + Inner Loop: : InnerCG resNorm : 9.3267973e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.05 seconds + Inner Loop: : InnerCG resNorm : 9.3267967e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.21 seconds + Inner Loop: : InnerCG resNorm : 9.3267962e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.83 seconds + Inner Loop: : InnerCG resNorm : 9.3267959e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.88 seconds + Inner Loop: : InnerCG resNorm : 9.3267956e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.92 seconds + Inner Loop: : InnerCG resNorm : 9.3267954e+08 + Inner Loop: : Time needed for inner loop: 11:57.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:57.00 minutes + Residuumnorm 1: 9.3267954e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.72 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.55 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.40 seconds + Intermezzo Residuum: 1338481.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4.0097693e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.97 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.49 seconds + PhiAdjSO: : 1:05.43 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.61 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.53 seconds + Inner Loop: : InnerCG resNorm : 1328313.4 + Inner Loop: : Time needed for inner loop: 3:50.23 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:50.23 minutes + FWISO Subproblem: 0: d(9): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1328313.4 + + iteration: 9 PROBLEM Number: 1 + FWISO problem 1: d(9) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.31 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 87301 + Prä-Residuumnorm: 9.6937094e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.6936341e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.09 seconds + Inner Loop: : InnerCG resNorm : 9.6936953e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.09 seconds + Inner Loop: : InnerCG resNorm : 9.6936928e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.28 seconds + Inner Loop: : InnerCG resNorm : 9.6936898e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.22 seconds + Inner Loop: : InnerCG resNorm : 9.6936882e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.16 seconds + Inner Loop: : InnerCG resNorm : 9.6936876e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.15 seconds + Inner Loop: : InnerCG resNorm : 9.6936871e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.10 seconds + Inner Loop: : InnerCG resNorm : 9.6936868e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.15 seconds + Inner Loop: : InnerCG resNorm : 9.6936865e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.11 seconds + Inner Loop: : InnerCG resNorm : 9.6936862e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.13 seconds + Inner Loop: : InnerCG resNorm : 9.6936858e+08 + Inner Loop: : Time needed for inner loop: 11:28.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:28.00 minutes + Residuumnorm 1: 9.6936858e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.94 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.02 seconds + Intermezzo Residuum: 1538682.5 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4.1702323e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.29 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.54 seconds + PhiAdjSO: : 1:05.48 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.25 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.74 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.54 seconds + Inner Loop: : InnerCG resNorm : 1527059.6 + Inner Loop: : Time needed for inner loop: 3:37.07 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:37.07 minutes + FWISO Subproblem: 1: d(9): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1527059.6 + + iteration: 9 PROBLEM Number: 2 + FWISO problem 2: d(9) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.34 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 87348 + Prä-Residuumnorm: 1.0316795e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0316713e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.0316764e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.43 seconds + Inner Loop: : InnerCG resNorm : 1.0316758e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.0316755e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.44 seconds + Inner Loop: : InnerCG resNorm : 1.0316753e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.42 seconds + Inner Loop: : InnerCG resNorm : 1.0316752e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.41 seconds + Inner Loop: : InnerCG resNorm : 1.0316752e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.44 seconds + Inner Loop: : InnerCG resNorm : 1.0316751e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.39 seconds + Inner Loop: : InnerCG resNorm : 1.0316751e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.36 seconds + Inner Loop: : InnerCG resNorm : 1.0316751e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.031675e+09 + Inner Loop: : Time needed for inner loop: 11:11.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:11.00 minutes + Residuumnorm 1: 1.031675e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.18 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.97 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.80 seconds + Intermezzo Residuum: 1592849.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4.4381973e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.43 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.53 seconds + PhiAdjSO: : 1:05.43 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.83 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.60 seconds + Inner Loop: : InnerCG resNorm : 1583392.1 + Inner Loop: : Time needed for inner loop: 3:29.44 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.44 minutes + FWISO Subproblem: 2: d(9): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1583392.1 + + iteration: 9 PROBLEM Number: 3 + FWISO problem 3: d(9) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.04 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 86715 + Prä-Residuumnorm: 1.0872358e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0872233e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.13 seconds + Inner Loop: : InnerCG resNorm : 1.0872334e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.16 seconds + Inner Loop: : InnerCG resNorm : 1.0872329e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.16 seconds + Inner Loop: : InnerCG resNorm : 1.0872326e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.21 seconds + Inner Loop: : InnerCG resNorm : 1.0872325e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.23 seconds + Inner Loop: : InnerCG resNorm : 1.0872324e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.18 seconds + Inner Loop: : InnerCG resNorm : 1.0872324e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.17 seconds + Inner Loop: : InnerCG resNorm : 1.0872324e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.21 seconds + Inner Loop: : InnerCG resNorm : 1.0872323e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.18 seconds + Inner Loop: : InnerCG resNorm : 1.0872323e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.17 seconds + Inner Loop: : InnerCG resNorm : 1.0872323e+09 + Inner Loop: : Time needed for inner loop: 11:09.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:09.00 minutes + Residuumnorm 1: 1.0872323e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.99 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.82 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.24 seconds + Intermezzo Residuum: 1739550.5 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4.6759035e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.23 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.47 seconds + PhiAdjSO: : 1:05.49 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.73 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.24 seconds + Inner Loop: : InnerCG resNorm : 1731172.4 + Inner Loop: : Time needed for inner loop: 3:28.73 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:28.73 minutes + FWISO Subproblem: 3: d(9): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1731172.4 + + iteration: 9 PROBLEM Number: 4 + FWISO problem 4: d(9) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.95 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 86812 + Prä-Residuumnorm: 9.8695986e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.869467e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.72 seconds + Inner Loop: : InnerCG resNorm : 9.8695729e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.83 seconds + Inner Loop: : InnerCG resNorm : 9.8695668e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.79 seconds + Inner Loop: : InnerCG resNorm : 9.8695633e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.76 seconds + Inner Loop: : InnerCG resNorm : 9.8695619e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.88 seconds + Inner Loop: : InnerCG resNorm : 9.8695616e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.77 seconds + Inner Loop: : InnerCG resNorm : 9.8695612e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.68 seconds + Inner Loop: : InnerCG resNorm : 9.8695608e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.78 seconds + Inner Loop: : InnerCG resNorm : 9.8695605e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.71 seconds + Inner Loop: : InnerCG resNorm : 9.8695601e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.72 seconds + Inner Loop: : InnerCG resNorm : 9.8695597e+08 + Inner Loop: : Time needed for inner loop: 11:26.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:26.00 minutes + Residuumnorm 1: 9.8695597e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.52 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.56 seconds + Intermezzo Residuum: 1669522.5 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4.2440051e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.74 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.57 seconds + PhiAdjSO: : 1:05.73 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.79 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.30 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.04 seconds + Inner Loop: : InnerCG resNorm : 1658463.1 + Inner Loop: : Time needed for inner loop: 3:35.31 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:35.31 minutes + FWISO Subproblem: 4: d(9): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1658463.1 + + iteration: 9 PROBLEM Number: 5 + FWISO problem 5: d(9) + shot: 5: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.79 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 88802 + Prä-Residuumnorm: 9.5338024e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5337441e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.17 seconds + Inner Loop: : InnerCG resNorm : 9.5337987e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.42 seconds + Inner Loop: : InnerCG resNorm : 9.533797e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.47 seconds + Inner Loop: : InnerCG resNorm : 9.5337957e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.56 seconds + Inner Loop: : InnerCG resNorm : 9.5337952e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.27 seconds + Inner Loop: : InnerCG resNorm : 9.533795e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.29 seconds + Inner Loop: : InnerCG resNorm : 9.5337946e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.58 seconds + Inner Loop: : InnerCG resNorm : 9.5337943e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.48 seconds + Inner Loop: : InnerCG resNorm : 9.5337942e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.49 seconds + Inner Loop: : InnerCG resNorm : 9.533794e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.52 seconds + Inner Loop: : InnerCG resNorm : 9.5337937e+08 + Inner Loop: : Time needed for inner loop: 11:51.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:51.00 minutes + Residuumnorm 1: 9.5337937e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.81 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.64 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.72 seconds + Intermezzo Residuum: 1391938.6 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4.1019837e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.09 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.49 seconds + PhiAdjSO: : 1:05.59 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.96 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.83 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.14 seconds + Inner Loop: : InnerCG resNorm : 1383190.9 + Inner Loop: : Time needed for inner loop: 3:47.31 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:47.31 minutes + FWISO Subproblem: 5: d(9): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1383190.9 + + + Iteration Main Looop Counting Variable iter: 10 + + iteration: 10 PROBLEM Number: 0 + FWISO problem 0: d(10) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.30 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 88964 + Prä-Residuumnorm: 9.3268025e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3267282e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.77 seconds + Inner Loop: : InnerCG resNorm : 9.3267997e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.02 seconds + Inner Loop: : InnerCG resNorm : 9.3267982e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.50 seconds + Inner Loop: : InnerCG resNorm : 9.3267971e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.24 seconds + Inner Loop: : InnerCG resNorm : 9.3267966e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.77 seconds + Inner Loop: : InnerCG resNorm : 9.3267962e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.12 seconds + Inner Loop: : InnerCG resNorm : 9.3267957e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.16 seconds + Inner Loop: : InnerCG resNorm : 9.3267953e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.80 seconds + Inner Loop: : InnerCG resNorm : 9.3267949e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.95 seconds + Inner Loop: : InnerCG resNorm : 9.3267948e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.95 seconds + Inner Loop: : InnerCG resNorm : 9.3267946e+08 + Inner Loop: : Time needed for inner loop: 11:58.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:58.00 minutes + Residuumnorm 1: 9.3267946e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.36 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.48 seconds + Intermezzo Residuum: 1282791.7 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.6087914e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.74 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.52 seconds + PhiAdjSO: : 1:05.39 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.61 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.27 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.93 seconds + Inner Loop: : InnerCG resNorm : 1275157.4 + Inner Loop: : Time needed for inner loop: 3:49.85 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:49.85 minutes + FWISO Subproblem: 0: d(10): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1275157.4 + + iteration: 10 PROBLEM Number: 1 + FWISO problem 1: d(10) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.09 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 88297 + Prä-Residuumnorm: 9.693704e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.6936664e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.20 seconds + Inner Loop: : InnerCG resNorm : 9.6936931e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.99 seconds + Inner Loop: : InnerCG resNorm : 9.693691e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.12 seconds + Inner Loop: : InnerCG resNorm : 9.6936883e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.18 seconds + Inner Loop: : InnerCG resNorm : 9.693687e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.21 seconds + Inner Loop: : InnerCG resNorm : 9.6936865e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.17 seconds + Inner Loop: : InnerCG resNorm : 9.6936861e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.13 seconds + Inner Loop: : InnerCG resNorm : 9.6936859e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.06 seconds + Inner Loop: : InnerCG resNorm : 9.6936855e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.18 seconds + Inner Loop: : InnerCG resNorm : 9.6936853e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.28 seconds + Inner Loop: : InnerCG resNorm : 9.693685e+08 + Inner Loop: : Time needed for inner loop: 11:29.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:29.00 minutes + Residuumnorm 1: 9.693685e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.08 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.90 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.09 seconds + Intermezzo Residuum: 1490136 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.753207e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.20 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.66 seconds + PhiAdjSO: : 1:05.52 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.16 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.65 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.75 seconds + Inner Loop: : InnerCG resNorm : 1479298.6 + Inner Loop: : Time needed for inner loop: 3:37.04 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:37.04 minutes + FWISO Subproblem: 1: d(10): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1479298.6 + + iteration: 10 PROBLEM Number: 2 + FWISO problem 2: d(10) + shot: 2: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.41 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 87635 + Prä-Residuumnorm: 1.0316786e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0316745e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.0316761e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.48 seconds + Inner Loop: : InnerCG resNorm : 1.0316757e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.44 seconds + Inner Loop: : InnerCG resNorm : 1.0316754e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.43 seconds + Inner Loop: : InnerCG resNorm : 1.0316752e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.53 seconds + Inner Loop: : InnerCG resNorm : 1.0316751e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.49 seconds + Inner Loop: : InnerCG resNorm : 1.0316751e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.44 seconds + Inner Loop: : InnerCG resNorm : 1.031675e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.45 seconds + Inner Loop: : InnerCG resNorm : 1.031675e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.47 seconds + Inner Loop: : InnerCG resNorm : 1.031675e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.48 seconds + Inner Loop: : InnerCG resNorm : 1.0316749e+09 + Inner Loop: : Time needed for inner loop: 11:11.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:11.00 minutes + Residuumnorm 1: 1.0316749e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.23 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.08 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.71 seconds + Intermezzo Residuum: 1535459.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.994374e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.34 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.47 seconds + PhiAdjSO: : 1:05.40 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.43 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.96 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.83 seconds + Inner Loop: : InnerCG resNorm : 1523168.7 + Inner Loop: : Time needed for inner loop: 3:29.75 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.75 minutes + FWISO Subproblem: 2: d(10): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1523168.7 + + iteration: 10 PROBLEM Number: 3 + FWISO problem 3: d(10) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.94 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 88327 + Prä-Residuumnorm: 1.087235e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0872287e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.21 seconds + Inner Loop: : InnerCG resNorm : 1.0872332e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.15 seconds + Inner Loop: : InnerCG resNorm : 1.0872327e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.14 seconds + Inner Loop: : InnerCG resNorm : 1.0872325e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.27 seconds + Inner Loop: : InnerCG resNorm : 1.0872324e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.23 seconds + Inner Loop: : InnerCG resNorm : 1.0872323e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.20 seconds + Inner Loop: : InnerCG resNorm : 1.0872323e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.26 seconds + Inner Loop: : InnerCG resNorm : 1.0872323e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.23 seconds + Inner Loop: : InnerCG resNorm : 1.0872322e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.20 seconds + Inner Loop: : InnerCG resNorm : 1.0872322e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.21 seconds + Inner Loop: : InnerCG resNorm : 1.0872322e+09 + Inner Loop: : Time needed for inner loop: 11:09.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:09.00 minutes + Residuumnorm 1: 1.0872322e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.78 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.19 seconds + Intermezzo Residuum: 1691480.6 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4.2083101e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.16 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.46 seconds + PhiAdjSO: : 1:05.34 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.15 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.71 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.28 seconds + Inner Loop: : InnerCG resNorm : 1684139.1 + Inner Loop: : Time needed for inner loop: 3:28.41 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:28.41 minutes + FWISO Subproblem: 3: d(10): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1684139.1 + + iteration: 10 PROBLEM Number: 4 + FWISO problem 4: d(10) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.82 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89161 + Prä-Residuumnorm: 9.8695921e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.8695263e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.66 seconds + Inner Loop: : InnerCG resNorm : 9.8695706e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.78 seconds + Inner Loop: : InnerCG resNorm : 9.8695651e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.70 seconds + Inner Loop: : InnerCG resNorm : 9.869562e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.73 seconds + Inner Loop: : InnerCG resNorm : 9.8695607e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.88 seconds + Inner Loop: : InnerCG resNorm : 9.8695604e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.83 seconds + Inner Loop: : InnerCG resNorm : 9.86956e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.77 seconds + Inner Loop: : InnerCG resNorm : 9.8695597e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.76 seconds + Inner Loop: : InnerCG resNorm : 9.8695594e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.75 seconds + Inner Loop: : InnerCG resNorm : 9.8695591e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.74 seconds + Inner Loop: : InnerCG resNorm : 9.8695588e+08 + Inner Loop: : Time needed for inner loop: 11:24.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:24.00 minutes + Residuumnorm 1: 9.8695588e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.52 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.50 seconds + Intermezzo Residuum: 1613554.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.819602e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.89 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.51 seconds + PhiAdjSO: : 1:05.57 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.93 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.20 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.13 seconds + Inner Loop: : InnerCG resNorm : 1603939.2 + Inner Loop: : Time needed for inner loop: 3:35.46 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:35.46 minutes + FWISO Subproblem: 4: d(10): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1603939.2 + + iteration: 10 PROBLEM Number: 5 + FWISO problem 5: d(10) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.80 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 90533 + Prä-Residuumnorm: 9.5338001e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.533771e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.26 seconds + Inner Loop: : InnerCG resNorm : 9.5337973e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.63 seconds + Inner Loop: : InnerCG resNorm : 9.5337959e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.58 seconds + Inner Loop: : InnerCG resNorm : 9.5337946e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.52 seconds + Inner Loop: : InnerCG resNorm : 9.5337942e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.37 seconds + Inner Loop: : InnerCG resNorm : 9.533794e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.47 seconds + Inner Loop: : InnerCG resNorm : 9.5337937e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.63 seconds + Inner Loop: : InnerCG resNorm : 9.5337935e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.54 seconds + Inner Loop: : InnerCG resNorm : 9.5337934e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.52 seconds + Inner Loop: : InnerCG resNorm : 9.5337932e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.47 seconds + Inner Loop: : InnerCG resNorm : 9.533793e+08 + Inner Loop: : Time needed for inner loop: 11:52.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:52.00 minutes + Residuumnorm 1: 9.533793e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.79 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.56 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.79 seconds + Intermezzo Residuum: 1339875.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.6917844e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.96 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.45 seconds + PhiAdjSO: : 1:05.45 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.93 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.95 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.19 seconds + Inner Loop: : InnerCG resNorm : 1332679.3 + Inner Loop: : Time needed for inner loop: 3:47.23 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:47.23 minutes + FWISO Subproblem: 5: d(10): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1332679.3 + + + Iteration Main Looop Counting Variable iter: 11 + + iteration: 11 PROBLEM Number: 0 + FWISO problem 0: d(11) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.17 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89178 + Prä-Residuumnorm: 9.3268003e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3267632e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.79 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.87 seconds + Inner Loop: : InnerCG resNorm : 9.3267982e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.81 seconds + Inner Loop: : InnerCG resNorm : 9.326797e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.37 seconds + Inner Loop: : InnerCG resNorm : 9.326796e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.03 seconds + Inner Loop: : InnerCG resNorm : 9.3267956e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.89 seconds + Inner Loop: : InnerCG resNorm : 9.3267952e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.01 seconds + Inner Loop: : InnerCG resNorm : 9.3267949e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.07 seconds + Inner Loop: : InnerCG resNorm : 9.3267945e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.90 seconds + Inner Loop: : InnerCG resNorm : 9.3267942e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.93 seconds + Inner Loop: : InnerCG resNorm : 9.326794e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.00 seconds + Inner Loop: : InnerCG resNorm : 9.3267939e+08 + Inner Loop: : Time needed for inner loop: 11:57.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:57.00 minutes + Residuumnorm 1: 9.3267939e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.55 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.36 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.40 seconds + Intermezzo Residuum: 1232649.4 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.2479115e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.83 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.43 seconds + PhiAdjSO: : 1:05.35 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.40 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.78 seconds + Inner Loop: : InnerCG resNorm : 1226121.8 + Inner Loop: : Time needed for inner loop: 3:49.98 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:49.98 minutes + FWISO Subproblem: 0: d(11): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1226121.8 + + iteration: 11 PROBLEM Number: 1 + FWISO problem 1: d(11) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.07 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 88484 + Prä-Residuumnorm: 9.6937005e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.6936817e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.11 seconds + Inner Loop: : InnerCG resNorm : 9.6936915e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.09 seconds + Inner Loop: : InnerCG resNorm : 9.6936897e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.06 seconds + Inner Loop: : InnerCG resNorm : 9.6936874e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.13 seconds + Inner Loop: : InnerCG resNorm : 9.6936861e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.08 seconds + Inner Loop: : InnerCG resNorm : 9.6936857e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.34 seconds + Inner Loop: : InnerCG resNorm : 9.6936854e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.32 seconds + Inner Loop: : InnerCG resNorm : 9.6936851e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.19 seconds + Inner Loop: : InnerCG resNorm : 9.6936848e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.05 seconds + Inner Loop: : InnerCG resNorm : 9.6936847e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.25 seconds + Inner Loop: : InnerCG resNorm : 9.6936844e+08 + Inner Loop: : Time needed for inner loop: 11:29.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:29.00 minutes + Residuumnorm 1: 9.6936844e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.06 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.95 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.01 seconds + Intermezzo Residuum: 1447021.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.3778851e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.31 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.51 seconds + PhiAdjSO: : 1:05.46 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.73 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.42 seconds + Inner Loop: : InnerCG resNorm : 1436977.9 + Inner Loop: : Time needed for inner loop: 3:37.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:37.00 minutes + FWISO Subproblem: 1: d(11): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1436977.9 + + iteration: 11 PROBLEM Number: 2 + FWISO problem 2: d(11) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.34 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 88494 + Prä-Residuumnorm: 1.0316781e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.031676e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.37 seconds + Inner Loop: : InnerCG resNorm : 1.0316759e+09 + Inner Loop: : Time needed for inner loop: 1:06.68 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:06.68 minutes + Residuumnorm 1: 1.0316759e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.37 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.94 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.66 seconds + Intermezzo Residuum: 2094668.3 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.5949348e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.50 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.60 seconds + PhiAdjSO: : 1:05.49 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.91 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.59 seconds + Inner Loop: : InnerCG resNorm : 1929550.2 + Inner Loop: : Time needed for inner loop: 3:29.55 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.55 minutes + FWISO Subproblem: 2: d(11): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 1929550.2 + + iteration: 11 PROBLEM Number: 3 + FWISO problem 3: d(11) + shot: 3: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.02 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89252 + Prä-Residuumnorm: 1.0872343e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0872312e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.73 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.08 seconds + Inner Loop: : InnerCG resNorm : 1.087233e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.79 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.13 seconds + Inner Loop: : InnerCG resNorm : 1.0872327e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.20 seconds + Inner Loop: : InnerCG resNorm : 1.0872324e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.10 seconds + Inner Loop: : InnerCG resNorm : 1.0872323e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.25 seconds + Inner Loop: : InnerCG resNorm : 1.0872323e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.16 seconds + Inner Loop: : InnerCG resNorm : 1.0872322e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.20 seconds + Inner Loop: : InnerCG resNorm : 1.0872322e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.18 seconds + Inner Loop: : InnerCG resNorm : 1.0872322e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.17 seconds + Inner Loop: : InnerCG resNorm : 1.0872321e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.13 seconds + Inner Loop: : InnerCG resNorm : 1.0872321e+09 + Inner Loop: : Time needed for inner loop: 11:08.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:08.00 minutes + Residuumnorm 1: 1.0872321e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.83 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.63 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.44 seconds + Intermezzo Residuum: 1635704.2 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.7874767e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.19 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.45 seconds + PhiAdjSO: : 1:05.37 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.03 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.67 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.40 seconds + Inner Loop: : InnerCG resNorm : 1627399.2 + Inner Loop: : Time needed for inner loop: 3:28.39 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:28.39 minutes + FWISO Subproblem: 3: d(11): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1627399.2 + + iteration: 11 PROBLEM Number: 4 + FWISO problem 4: d(11) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.92 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89305 + Prä-Residuumnorm: 9.8695868e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.8695539e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.71 seconds + Inner Loop: : InnerCG resNorm : 9.8695688e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.83 seconds + Inner Loop: : InnerCG resNorm : 9.8695636e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.78 seconds + Inner Loop: : InnerCG resNorm : 9.8695608e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.76 seconds + Inner Loop: : InnerCG resNorm : 9.8695597e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.72 seconds + Inner Loop: : InnerCG resNorm : 9.8695594e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.67 seconds + Inner Loop: : InnerCG resNorm : 9.8695591e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.71 seconds + Inner Loop: : InnerCG resNorm : 9.8695588e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.72 seconds + Inner Loop: : InnerCG resNorm : 9.8695585e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.78 seconds + Inner Loop: : InnerCG resNorm : 9.8695583e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.82 seconds + Inner Loop: : InnerCG resNorm : 9.869558e+08 + Inner Loop: : Time needed for inner loop: 11:24.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:24.00 minutes + Residuumnorm 1: 9.869558e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.41 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.51 seconds + Intermezzo Residuum: 1565038.7 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.43764e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.83 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.54 seconds + PhiAdjSO: : 1:05.52 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.81 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.22 seconds + Initialization: 0.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.13 seconds + Inner Loop: : InnerCG resNorm : 1556543.7 + Inner Loop: : Time needed for inner loop: 3:35.26 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:35.26 minutes + FWISO Subproblem: 4: d(11): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1556543.7 + + iteration: 11 PROBLEM Number: 5 + FWISO problem 5: d(11) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.92 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 90094 + Prä-Residuumnorm: 9.5337983e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5337838e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.24 seconds + Inner Loop: : InnerCG resNorm : 9.5337959e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.39 seconds + Inner Loop: : InnerCG resNorm : 9.5337948e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.77 seconds + Inner Loop: : InnerCG resNorm : 9.5337938e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.56 seconds + Inner Loop: : InnerCG resNorm : 9.5337934e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.67 seconds + Inner Loop: : InnerCG resNorm : 9.5337932e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.64 seconds + Inner Loop: : InnerCG resNorm : 9.533793e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.70 seconds + Inner Loop: : InnerCG resNorm : 9.5337928e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.48 seconds + Inner Loop: : InnerCG resNorm : 9.5337927e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.44 seconds + Inner Loop: : InnerCG resNorm : 9.5337925e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.41 seconds + Inner Loop: : InnerCG resNorm : 9.5337923e+08 + Inner Loop: : Time needed for inner loop: 11:52.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:52.00 minutes + Residuumnorm 1: 9.5337923e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.81 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.76 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.72 seconds + Intermezzo Residuum: 1293345.6 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.3226054e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.17 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.42 seconds + PhiAdjSO: : 1:05.42 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.15 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.01 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.15 seconds + Inner Loop: : InnerCG resNorm : 1286949 + Inner Loop: : Time needed for inner loop: 3:47.59 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:47.59 minutes + FWISO Subproblem: 5: d(11): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1286949 + + + Iteration Main Looop Counting Variable iter: 12 + + iteration: 12 PROBLEM Number: 0 + FWISO problem 0: d(12) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.32 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 90051 + Prä-Residuumnorm: 9.3267977e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3267792e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.94 seconds + Inner Loop: : InnerCG resNorm : 9.326796e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.21 seconds + Inner Loop: : InnerCG resNorm : 9.3267955e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.12 seconds + Inner Loop: : InnerCG resNorm : 9.3267948e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.83 seconds + Inner Loop: : InnerCG resNorm : 9.3267945e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.85 seconds + Inner Loop: : InnerCG resNorm : 9.3267942e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.11 seconds + Inner Loop: : InnerCG resNorm : 9.326794e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.15 seconds + Inner Loop: : InnerCG resNorm : 9.3267938e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.81 seconds + Inner Loop: : InnerCG resNorm : 9.3267936e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.90 seconds + Inner Loop: : InnerCG resNorm : 9.3267934e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.00 seconds + Inner Loop: : InnerCG resNorm : 9.3267933e+08 + Inner Loop: : Time needed for inner loop: 11:57.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:57.00 minutes + Residuumnorm 1: 9.3267933e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.46 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.65 seconds + Intermezzo Residuum: 1189136 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2.9231196e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.86 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.52 seconds + PhiAdjSO: : 1:05.25 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.40 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.71 seconds + Inner Loop: : InnerCG resNorm : 1181594.1 + Inner Loop: : Time needed for inner loop: 3:49.82 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:49.82 minutes + FWISO Subproblem: 0: d(12): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1181594.1 + + iteration: 12 PROBLEM Number: 1 + FWISO problem 1: d(12) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.18 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 90191 + Prä-Residuumnorm: 9.6936959e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.6936865e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.12 seconds + Inner Loop: : InnerCG resNorm : 9.6936891e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.01 seconds + Inner Loop: : InnerCG resNorm : 9.6936878e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.06 seconds + Inner Loop: : InnerCG resNorm : 9.6936859e+08 + Inner Loop: : Time needed for inner loop: 3:24.77 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:24.77 minutes + Residuumnorm 1: 9.6936859e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.14 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.24 seconds + Intermezzo Residuum: 1546607.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.0400952e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.37 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.57 seconds + PhiAdjSO: : 1:05.52 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.43 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.65 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.79 seconds + Inner Loop: : InnerCG resNorm : 1508258.1 + Inner Loop: : Time needed for inner loop: 3:37.51 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:37.51 minutes + FWISO Subproblem: 1: d(12): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 1508258.1 + + iteration: 12 PROBLEM Number: 2 + FWISO problem 2: d(12) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.40 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 90111 + Prä-Residuumnorm: 1.0316772e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.2850764e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.75 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.34 seconds + Inner Loop: : InnerCG resNorm : 1.0316758e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.39 seconds + Inner Loop: : InnerCG resNorm : 1.0316756e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.0316753e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.44 seconds + Inner Loop: : InnerCG resNorm : 1.0316751e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.79 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.37 seconds + Inner Loop: : InnerCG resNorm : 1.0316751e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.42 seconds + Inner Loop: : InnerCG resNorm : 1.031675e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.46 seconds + Inner Loop: : InnerCG resNorm : 1.031675e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.36 seconds + Inner Loop: : InnerCG resNorm : 1.031675e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.37 seconds + Inner Loop: : InnerCG resNorm : 1.0316749e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.36 seconds + Inner Loop: : InnerCG resNorm : 1.0316749e+09 + Inner Loop: : Time needed for inner loop: 11:10.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:10.00 minutes + Residuumnorm 1: 1.0316749e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.15 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.94 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.84 seconds + Intermezzo Residuum: 1513041.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.2354386e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.36 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.47 seconds + PhiAdjSO: : 1:05.37 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.43 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.04 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.49 seconds + Inner Loop: : InnerCG resNorm : 1506066.9 + Inner Loop: : Time needed for inner loop: 3:29.45 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.45 minutes + FWISO Subproblem: 2: d(12): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1506066.9 + + iteration: 12 PROBLEM Number: 3 + FWISO problem 3: d(12) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.95 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89470 + Prä-Residuumnorm: 1.0872338e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0872323e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.79 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.14 seconds + Inner Loop: : InnerCG resNorm : 1.0872328e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.13 seconds + Inner Loop: : InnerCG resNorm : 1.0872325e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.15 seconds + Inner Loop: : InnerCG resNorm : 1.0872323e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.24 seconds + Inner Loop: : InnerCG resNorm : 1.0872322e+09 + Inner Loop: : Time needed for inner loop: 4:28.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:28.00 minutes + Residuumnorm 1: 1.0872322e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.73 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.61 seconds + Intermezzo Residuum: 1716483.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.4087276e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.01 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.42 seconds + PhiAdjSO: : 1:05.39 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.05 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.62 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.29 seconds + Inner Loop: : InnerCG resNorm : 1693094.6 + Inner Loop: : Time needed for inner loop: 3:28.16 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:28.16 minutes + FWISO Subproblem: 3: d(12): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 1693094.6 + + iteration: 12 PROBLEM Number: 4 + FWISO problem 4: d(12) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.94 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 88834 + Prä-Residuumnorm: 9.8695781e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.8695616e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.74 seconds + Inner Loop: : InnerCG resNorm : 9.8695647e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.81 seconds + Inner Loop: : InnerCG resNorm : 9.8695612e+08 + Inner Loop: : Time needed for inner loop: 2:16.02 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:16.02 minutes + Residuumnorm 1: 9.8695612e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.81 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.56 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.45 seconds + Intermezzo Residuum: 1753796.6 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.0938733e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.88 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.54 seconds + PhiAdjSO: : 1:05.41 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.25 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.07 seconds + Inner Loop: : InnerCG resNorm : 1687960.4 + Inner Loop: : Time needed for inner loop: 3:35.18 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:35.18 minutes + FWISO Subproblem: 4: d(12): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 1687960.4 + + iteration: 12 PROBLEM Number: 5 + FWISO problem 5: d(12) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.79 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 90394 + Prä-Residuumnorm: 9.5337954e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.5337882e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.20 seconds + Inner Loop: : InnerCG resNorm : 9.5337938e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.51 seconds + Inner Loop: : InnerCG resNorm : 9.5337932e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.82 seconds + Inner Loop: : InnerCG resNorm : 9.5337926e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.63 seconds + Inner Loop: : InnerCG resNorm : 9.5337924e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.50 seconds + Inner Loop: : InnerCG resNorm : 9.5337922e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.97 seconds + Inner Loop: : InnerCG resNorm : 9.5337921e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.48 seconds + Inner Loop: : InnerCG resNorm : 9.533792e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.42 seconds + Inner Loop: : InnerCG resNorm : 9.5337918e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.71 seconds + Inner Loop: : InnerCG resNorm : 9.5337917e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.60 seconds + Inner Loop: : InnerCG resNorm : 9.5337916e+08 + Inner Loop: : Time needed for inner loop: 11:53.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:53.00 minutes + Residuumnorm 1: 9.5337916e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.03 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.85 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.89 seconds + Intermezzo Residuum: 1238025 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2.9903439e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.22 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.43 seconds + PhiAdjSO: : 1:05.47 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.25 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.98 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.39 seconds + Inner Loop: : InnerCG resNorm : 1230332.4 + Inner Loop: : Time needed for inner loop: 3:48.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:48.00 minutes + FWISO Subproblem: 5: d(12): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1230332.4 + + + Iteration Main Looop Counting Variable iter: 13 + + iteration: 13 PROBLEM Number: 0 + FWISO problem 0: d(13) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.57 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89603 + Prä-Residuumnorm: 9.3267978e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3267886e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.76 seconds + Inner Loop: : InnerCG resNorm : 9.3267956e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.98 seconds + Inner Loop: : InnerCG resNorm : 9.3267947e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.16 seconds + Inner Loop: : InnerCG resNorm : 9.3267941e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.22 seconds + Inner Loop: : InnerCG resNorm : 9.3267938e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.82 seconds + Inner Loop: : InnerCG resNorm : 9.3267936e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.97 seconds + Inner Loop: : InnerCG resNorm : 9.3267934e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.24 seconds + Inner Loop: : InnerCG resNorm : 9.3267931e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.98 seconds + Inner Loop: : InnerCG resNorm : 9.326793e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.98 seconds + Inner Loop: : InnerCG resNorm : 9.3267929e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.95 seconds + Inner Loop: : InnerCG resNorm : 9.3267928e+08 + Inner Loop: : Time needed for inner loop: 11:56.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:56.00 minutes + Residuumnorm 1: 9.3267928e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.46 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.25 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.63 seconds + Intermezzo Residuum: 1144057.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2.6308076e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.73 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.48 seconds + PhiAdjSO: : 1:05.31 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.55 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.26 seconds + Inner Loop: : InnerCG resNorm : 1137871.3 + Inner Loop: : Time needed for inner loop: 3:49.32 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:49.32 minutes + FWISO Subproblem: 0: d(13): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1137871.3 + + iteration: 13 PROBLEM Number: 1 + FWISO problem 1: d(13) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.19 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89749 + Prä-Residuumnorm: 9.6936936e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 8.7243157e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.43 seconds + Inner Loop: : InnerCG resNorm : 9.6936891e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.11 seconds + Inner Loop: : InnerCG resNorm : 9.6936869e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.19 seconds + Inner Loop: : InnerCG resNorm : 9.6936863e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.17 seconds + Inner Loop: : InnerCG resNorm : 9.6936852e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.14 seconds + Inner Loop: : InnerCG resNorm : 9.6936847e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.09 seconds + Inner Loop: : InnerCG resNorm : 9.6936845e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.29 seconds + Inner Loop: : InnerCG resNorm : 9.6936842e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.12 seconds + Inner Loop: : InnerCG resNorm : 9.693684e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.10 seconds + Inner Loop: : InnerCG resNorm : 9.6936837e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.09 seconds + Inner Loop: : InnerCG resNorm : 9.6936835e+08 + Inner Loop: : Time needed for inner loop: 11:28.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:28.00 minutes + Residuumnorm 1: 9.6936835e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.95 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.87 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.19 seconds + Intermezzo Residuum: 1384863.5 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2.736085e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.18 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.51 seconds + PhiAdjSO: : 1:05.40 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.13 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.54 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.54 seconds + Inner Loop: : InnerCG resNorm : 1378918 + Inner Loop: : Time needed for inner loop: 3:36.57 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:36.57 minutes + FWISO Subproblem: 1: d(13): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1378918 + + iteration: 13 PROBLEM Number: 2 + FWISO problem 2: d(13) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.31 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 91024 + Prä-Residuumnorm: 1.0316768e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0213599e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.47 seconds + Inner Loop: : InnerCG resNorm : 1.0316757e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.42 seconds + Inner Loop: : InnerCG resNorm : 1.0316754e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.41 seconds + Inner Loop: : InnerCG resNorm : 1.0316752e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.43 seconds + Inner Loop: : InnerCG resNorm : 1.031675e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.44 seconds + Inner Loop: : InnerCG resNorm : 1.031675e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.0316749e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.36 seconds + Inner Loop: : InnerCG resNorm : 1.0316749e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.39 seconds + Inner Loop: : InnerCG resNorm : 1.0316749e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.37 seconds + Inner Loop: : InnerCG resNorm : 1.0316749e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.44 seconds + Inner Loop: : InnerCG resNorm : 1.0316748e+09 + Inner Loop: : Time needed for inner loop: 11:11.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:11.00 minutes + Residuumnorm 1: 1.0316748e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.08 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.81 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.83 seconds + Intermezzo Residuum: 1466230.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2.9118937e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.31 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.40 seconds + PhiAdjSO: : 1:05.25 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.21 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.84 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.61 seconds + Inner Loop: : InnerCG resNorm : 1458115.9 + Inner Loop: : Time needed for inner loop: 3:29.02 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.02 minutes + FWISO Subproblem: 2: d(13): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1458115.9 + + iteration: 13 PROBLEM Number: 3 + FWISO problem 3: d(13) + shot: 3: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.99 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89736 + Prä-Residuumnorm: 1.0872336e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.7850887e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.20 seconds + Inner Loop: : InnerCG resNorm : 1.0872328e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.21 seconds + Inner Loop: : InnerCG resNorm : 1.0872325e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.22 seconds + Inner Loop: : InnerCG resNorm : 1.0872324e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.23 seconds + Inner Loop: : InnerCG resNorm : 1.0872322e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.27 seconds + Inner Loop: : InnerCG resNorm : 1.0872322e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.21 seconds + Inner Loop: : InnerCG resNorm : 1.0872322e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.27 seconds + Inner Loop: : InnerCG resNorm : 1.0872321e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.28 seconds + Inner Loop: : InnerCG resNorm : 1.0872321e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.21 seconds + Inner Loop: : InnerCG resNorm : 1.0872321e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.89 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.19 seconds + Inner Loop: : InnerCG resNorm : 1.087232e+09 + Inner Loop: : Time needed for inner loop: 11:09.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:09.00 minutes + Residuumnorm 1: 1.087232e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.74 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.34 seconds + Intermezzo Residuum: 1591949.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 3.0678543e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.13 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.46 seconds + PhiAdjSO: : 1:05.44 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.14 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.76 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.33 seconds + Inner Loop: : InnerCG resNorm : 1583046.3 + Inner Loop: : Time needed for inner loop: 3:28.56 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:28.56 minutes + FWISO Subproblem: 3: d(13): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1583046.3 + + iteration: 13 PROBLEM Number: 4 + FWISO problem 4: d(13) + shot: 4: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.99 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 90335 + Prä-Residuumnorm: 9.8695769e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 8.8826044e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.82 seconds + Inner Loop: : InnerCG resNorm : 9.8695668e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.72 seconds + Inner Loop: : InnerCG resNorm : 9.8695622e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.93 seconds + Inner Loop: : InnerCG resNorm : 9.8695603e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.86 seconds + Inner Loop: : InnerCG resNorm : 9.8695591e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.88 seconds + Inner Loop: : InnerCG resNorm : 9.8695589e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.92 seconds + Inner Loop: : InnerCG resNorm : 9.8695584e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.84 seconds + Inner Loop: : InnerCG resNorm : 9.8695582e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.79 seconds + Inner Loop: : InnerCG resNorm : 9.8695579e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.93 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.81 seconds + Inner Loop: : InnerCG resNorm : 9.8695578e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.84 seconds + Inner Loop: : InnerCG resNorm : 9.8695575e+08 + Inner Loop: : Time needed for inner loop: 11:26.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:26.00 minutes + Residuumnorm 1: 9.8695575e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.38 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.62 seconds + Intermezzo Residuum: 1528030.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2.7844856e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.76 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.50 seconds + PhiAdjSO: : 1:05.48 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.76 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.39 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.36 seconds + Inner Loop: : InnerCG resNorm : 1517062.8 + Inner Loop: : Time needed for inner loop: 3:35.47 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:35.47 minutes + FWISO Subproblem: 4: d(13): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1517062.8 + + iteration: 13 PROBLEM Number: 5 + FWISO problem 5: d(13) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.76 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89144 + Prä-Residuumnorm: 9.5337966e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.533793e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.74 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.35 seconds + Inner Loop: : InnerCG resNorm : 9.5337941e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.54 seconds + Inner Loop: : InnerCG resNorm : 9.5337931e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.47 seconds + Inner Loop: : InnerCG resNorm : 9.5337925e+08 + Inner Loop: : Time needed for inner loop: 3:32.05 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:32.05 minutes + Residuumnorm 1: 9.5337925e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.96 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.86 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.31 seconds + Intermezzo Residuum: 1308624.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2.6913099e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.17 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.32 seconds + PhiAdjSO: : 1:05.39 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.23 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.80 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.21 seconds + Inner Loop: : InnerCG resNorm : 1289445.3 + Inner Loop: : Time needed for inner loop: 3:47.45 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:47.45 minutes + FWISO Subproblem: 5: d(13): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 1289445.3 + + + Iteration Main Looop Counting Variable iter: 14 + + iteration: 14 PROBLEM Number: 0 + FWISO problem 0: d(14) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.66 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89875 + Prä-Residuumnorm: 9.3267972e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.3267925e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.03 seconds + Inner Loop: : InnerCG resNorm : 9.3267952e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.92 seconds + Inner Loop: : InnerCG resNorm : 9.3267946e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.94 seconds + Inner Loop: : InnerCG resNorm : 9.3267941e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.71 seconds + Inner Loop: : InnerCG resNorm : 9.3267937e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.03 seconds + Inner Loop: : InnerCG resNorm : 9.3267933e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.83 seconds + Inner Loop: : InnerCG resNorm : 9.3267931e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.05 seconds + Inner Loop: : InnerCG resNorm : 9.3267929e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.80 seconds + Inner Loop: : InnerCG resNorm : 9.3267927e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.89 seconds + Inner Loop: : InnerCG resNorm : 9.3267926e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.99 seconds + Inner Loop: : InnerCG resNorm : 9.3267925e+08 + Inner Loop: : Time needed for inner loop: 11:56.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:56.00 minutes + Residuumnorm 1: 9.3267925e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.46 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.34 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.51 seconds + Intermezzo Residuum: 1122239.4 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2.3677267e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.75 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.47 seconds + PhiAdjSO: : 1:05.28 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.52 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.99 seconds + Inner Loop: : InnerCG resNorm : 1117355.8 + Inner Loop: : Time needed for inner loop: 3:50.01 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:50.01 minutes + FWISO Subproblem: 0: d(14): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1117355.8 + + iteration: 14 PROBLEM Number: 1 + FWISO problem 1: d(14) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.25 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89107 + Prä-Residuumnorm: 9.6936941e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.4028808e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.15 seconds + Inner Loop: : InnerCG resNorm : 9.6936886e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.10 seconds + Inner Loop: : InnerCG resNorm : 9.6936871e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.24 seconds + Inner Loop: : InnerCG resNorm : 9.6936854e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.18 seconds + Inner Loop: : InnerCG resNorm : 9.6936844e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.21 seconds + Inner Loop: : InnerCG resNorm : 9.6936841e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.04 seconds + Inner Loop: : InnerCG resNorm : 9.6936839e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.16 seconds + Inner Loop: : InnerCG resNorm : 9.6936836e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.19 seconds + Inner Loop: : InnerCG resNorm : 9.6936835e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.14 seconds + Inner Loop: : InnerCG resNorm : 9.6936833e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.08 seconds + Inner Loop: : InnerCG resNorm : 9.6936831e+08 + Inner Loop: : Time needed for inner loop: 11:28.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:28.00 minutes + Residuumnorm 1: 9.6936831e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.06 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.90 seconds + Intermezzo Residuum: 1357879.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2.4624766e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.47 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.49 seconds + PhiAdjSO: : 1:05.36 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.37 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.55 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.40 seconds + Inner Loop: : InnerCG resNorm : 1350285.8 + Inner Loop: : Time needed for inner loop: 3:36.91 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:36.91 minutes + FWISO Subproblem: 1: d(14): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1350285.8 + + iteration: 14 PROBLEM Number: 2 + FWISO problem 2: d(14) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.27 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89170 + Prä-Residuumnorm: 1.031677e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0265186e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.76 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.37 seconds + Inner Loop: : InnerCG resNorm : 1.0316756e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.32 seconds + Inner Loop: : InnerCG resNorm : 1.0316753e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.47 seconds + Inner Loop: : InnerCG resNorm : 1.0316751e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.46 seconds + Inner Loop: : InnerCG resNorm : 1.031675e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.39 seconds + Inner Loop: : InnerCG resNorm : 1.0316749e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.53 seconds + Inner Loop: : InnerCG resNorm : 1.0316749e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.37 seconds + Inner Loop: : InnerCG resNorm : 1.0316749e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.0316748e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.0316748e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 1.0316748e+09 + Inner Loop: : Time needed for inner loop: 11:10.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:10.00 minutes + Residuumnorm 1: 1.0316748e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.23 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.02 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.98 seconds + Intermezzo Residuum: 1434957.2 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2.6207048e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.32 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.41 seconds + PhiAdjSO: : 1:05.31 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.82 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.49 seconds + Inner Loop: : InnerCG resNorm : 1427771.1 + Inner Loop: : Time needed for inner loop: 3:29.02 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.02 minutes + FWISO Subproblem: 2: d(14): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1427771.1 + + iteration: 14 PROBLEM Number: 3 + FWISO problem 3: d(14) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.06 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89874 + Prä-Residuumnorm: 1.0872333e+09 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1.0437434e+09 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.72 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.17 seconds + Inner Loop: : InnerCG resNorm : 1.0872326e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.19 seconds + Inner Loop: : InnerCG resNorm : 1.0872324e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.31 seconds + Inner Loop: : InnerCG resNorm : 1.0872322e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.85 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.29 seconds + Inner Loop: : InnerCG resNorm : 1.0872322e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.25 seconds + Inner Loop: : InnerCG resNorm : 1.0872321e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.20 seconds + Inner Loop: : InnerCG resNorm : 1.0872321e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.30 seconds + Inner Loop: : InnerCG resNorm : 1.087232e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.23 seconds + Inner Loop: : InnerCG resNorm : 1.087232e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.25 seconds + Inner Loop: : InnerCG resNorm : 1.087232e+09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.30 seconds + Inner Loop: : InnerCG resNorm : 1.087232e+09 + Inner Loop: : Time needed for inner loop: 11:09.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:09.00 minutes + Residuumnorm 1: 1.087232e+09 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.72 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.41 seconds + Intermezzo Residuum: 1551668.3 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2.7610681e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.16 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.46 seconds + PhiAdjSO: : 1:05.39 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.16 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.73 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.39 seconds + Inner Loop: : InnerCG resNorm : 1544584.9 + Inner Loop: : Time needed for inner loop: 3:28.57 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:28.57 minutes + FWISO Subproblem: 3: d(14): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1544584.9 + + iteration: 14 PROBLEM Number: 4 + FWISO problem 4: d(14) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.89 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 89251 + Prä-Residuumnorm: 9.8695745e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 9.6721801e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.79 seconds + Inner Loop: : InnerCG resNorm : 9.8695636e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.73 seconds + Inner Loop: : InnerCG resNorm : 9.8695608e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.84 seconds + Inner Loop: : InnerCG resNorm : 9.8695589e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.00 seconds + Inner Loop: : InnerCG resNorm : 9.8695581e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.89 seconds + Inner Loop: : InnerCG resNorm : 9.8695579e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.78 seconds + Inner Loop: : InnerCG resNorm : 9.8695576e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.94 seconds + Inner Loop: : InnerCG resNorm : 9.8695574e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.88 seconds + Inner Loop: : InnerCG resNorm : 9.8695572e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.75 seconds + Inner Loop: : InnerCG resNorm : 9.8695571e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.89 seconds + Inner Loop: : InnerCG resNorm : 9.8695569e+08 + Inner Loop: : Time needed for inner loop: 11:25.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:25.00 minutes + Residuumnorm 1: 9.8695569e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.43 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.54 seconds + Intermezzo Residuum: 1492095.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2.5060364e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.78 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.42 seconds + PhiAdjSO: : 1:05.42 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.69 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.44 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.47 seconds + Inner Loop: : InnerCG resNorm : 1482860 + Inner Loop: : Time needed for inner loop: 3:35.56 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:35.56 minutes + FWISO Subproblem: 4: d(14): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1482860 + + iteration: 14 PROBLEM Number: 5 + FWISO problem 5: d(14) + shot: 5: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.78 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 90629 + Prä-Residuumnorm: 9.533796e+08 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 8.5804132e+08 und m_max 10 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.74 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.45 seconds + Inner Loop: : InnerCG resNorm : 9.5337944e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.75 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.52 seconds + Inner Loop: : InnerCG resNorm : 9.5337936e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.50 seconds + Inner Loop: : InnerCG resNorm : 9.5337926e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.45 seconds + Inner Loop: : InnerCG resNorm : 9.5337922e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.54 seconds + Inner Loop: : InnerCG resNorm : 9.5337919e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.71 seconds + Inner Loop: : InnerCG resNorm : 9.5337918e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.58 seconds + Inner Loop: : InnerCG resNorm : 9.5337916e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.66 seconds + Inner Loop: : InnerCG resNorm : 9.5337914e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.56 seconds + Inner Loop: : InnerCG resNorm : 9.5337914e+08 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.65 seconds + Inner Loop: : InnerCG resNorm : 9.5337912e+08 + Inner Loop: : Time needed for inner loop: 11:52.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 10 = m innere Iterationen + Inner Loop: : 11:52.00 minutes + Residuumnorm 1: 9.5337912e+08 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.02 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.82 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.82 seconds + Intermezzo Residuum: 1212871.2 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 2.4221787e+08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.21 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.40 seconds + PhiAdjSO: : 1:05.37 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.17 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.23 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.13 seconds + Inner Loop: : InnerCG resNorm : 1207124.7 + Inner Loop: : Time needed for inner loop: 3:47.79 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:47.79 minutes + FWISO Subproblem: 5: d(14): Finished first / second inner loop ( 10, 1 steps ) + ************************************* + Residuumnorm 2: 1207124.7 + FWISO: d(15)= 0 + 9.339933e+08 + 9.3280353e+08 + 9.3269845e+08 + 9.3268901e+08 + 9.3268529e+08 + 9.326836e+08 + 9.3268247e+08 + 9.3268155e+08 + 9.3268089e+08 + 9.326805e+08 + 9.3268025e+08 + 9.3268003e+08 + 9.3267977e+08 + 9.3267978e+08 + 9.3267972e+08 + + + 9.7008053e+08 + 9.6947803e+08 + 9.6939565e+08 + 9.6938351e+08 + 9.6938027e+08 + 9.6937848e+08 + 9.6937496e+08 + 9.6937273e+08 + 9.6937162e+08 + 9.6937094e+08 + 9.693704e+08 + 9.6937005e+08 + 9.6936959e+08 + 9.6936936e+08 + 9.6936941e+08 + + + 1.0324321e+09 + 1.0317708e+09 + 1.0316953e+09 + 1.0316882e+09 + 1.0316873e+09 + 1.031688e+09 + 1.0316855e+09 + 1.0316828e+09 + 1.031681e+09 + 1.0316795e+09 + 1.0316786e+09 + 1.0316781e+09 + 1.0316772e+09 + 1.0316768e+09 + 1.031677e+09 + + + 1.0882787e+09 + 1.0872811e+09 + 1.0872506e+09 + 1.0872436e+09 + 1.0872414e+09 + 1.087241e+09 + 1.0872403e+09 + 1.0872382e+09 + 1.0872367e+09 + 1.0872358e+09 + 1.087235e+09 + 1.0872343e+09 + 1.0872338e+09 + 1.0872336e+09 + 1.0872333e+09 + + + 9.8805758e+08 + 9.8700325e+08 + 9.8696811e+08 + 9.8696406e+08 + 9.869625e+08 + 9.8696347e+08 + 9.8696367e+08 + 9.8696224e+08 + 9.869608e+08 + 9.8695986e+08 + 9.8695921e+08 + 9.8695868e+08 + 9.8695781e+08 + 9.8695769e+08 + 9.8695745e+08 + + + 9.5387691e+08 + 9.5341075e+08 + 9.5339254e+08 + 9.5338504e+08 + 9.53385e+08 + 9.5338338e+08 + 9.5338205e+08 + 9.5338115e+08 + 9.5338062e+08 + 9.5338024e+08 + 9.5338001e+08 + 9.5337983e+08 + 9.5337954e+08 + 9.5337966e+08 + 9.533796e+08 + + +end program after 22:10:06.00 hours on 128 procs at Tue Jun 27 21:56:17 2023 diff --git a/log/2023_06_27_noIC_VpMono_HighResolution/testconf.conf b/log/2023_06_27_noIC_VpMono_HighResolution/testconf.conf new file mode 100644 index 0000000000000000000000000000000000000000..615f7e44d0636c41934b02072157b113e306809e --- /dev/null +++ b/log/2023_06_27_noIC_VpMono_HighResolution/testconf.conf @@ -0,0 +1,105 @@ +# Regular Expression um aus Test_Config von Clion eine ... M++ Config zu machen +# \{"([A-Za-z0-9_ ]+)", +"([A-Za-z0-9_ ,\.\-]+)"}. + +#Durchlauf 2023Mai05 mit 4 Quellen, 8 Iterationen, Materialpunkt, level 1 (Ergebnisse ganz gut) +#Durchlauf 2023Mai05 mit 4 Quellen, 8 Iterationen, TwoMedium, level 1 +#Back to FastMode (2 Quellen, 2 Iterationen, Pkt.Material, level 0) +#21.06 Receiver wieder auf 64. Bei multi noch nicht, jetzt aber bei rho rekonstruktion +#Neuer größerer Durchlauf 26.Juni Ohne Inverse Crime für Vp; Neu: SignalName: Ricker; deg = 2; dt = 0.0005 + + #Problem= VAcousticWaveTwoMedium;//<----- Geometrie oder so Siehe: src/Problems/FWIInversionProblems.cpp + Problem= VAcousticWaveC2Benchmark; + FWISO_Steps = 15; #Anzahl Iterationen + Monoparam= Vp; #can be "multi"/empty or "Vp", "Tau_p", "Rho" + plot_tStep= -1; + level = 3; + T=0.6; + dt= 0.0005; + FWISourceCount0=6; #Anzahl Quellen 6, Empfänger default 64 unten + deg = 2; #In paper CRC deg = 2. Vor 26.Juni2023 wars 1 + FWIReconstructRho= 0; + FWIReconstructV_P= 1; + FWIReconstructTauP= 0; + numL=0;#!!! + + seismopath = C2NoDampingT06dt0005/C2NoDampingT06dt0005;#im Build Ordner! + #seismopath = readmePlease;//klappt in der ersten Iteration mit ..Please0 + #seismopath = ../FWI/conf/C2NoDampingT06dt0005/C2NoDampingT06dt0005;//mal sehen obs klappt + #seismopath = /home/lionbart/fwi/FWI/conf/C2NoDampingT06dt0005/C2NoDampingT06dt0005;//OUT OF RANGE ERROR + + ReadFormat = FWI;#IFOS ist falsches Format. + SpecfileNrOfSamples = 6; + + SaveObservedSeismogram = 0;#Plottet "d_obs", das Vorwärtsgelöste Wellenfeld (mit echten Materialparam) + + SignalName=Ricker;#RickerDerivative vorher!!! Geändert 26.Juni.2023 + + + + ConfigVerbose=2; + ForwardSolver= VADGTS; + Distribution= RCB; + Model = FWIInverse_DGTS; + Mesh= SeismogramGrid_test; + + useTaper=1; + taperRadiusSource=0; + taperRadiusReceiver=0; + taperExponent=-0.1; + taperIgnoreReceiverCells=1; + taperIgnoreSourceCells=1; + #Monoparam= Rho; #can be "multi"/empty or "Vp", "Tau_p", "Rho" + ReconstructionType=SO;#!!! + FWIReceiverWaypoints= 2; + FWIReceiverWaypoint0= 1350.0, 370.0; + FWIReceiverWaypoint1= 1350.0, 1630.0; + FWIReceiverIncludeLastWaypoint= 1; + FWIReceiverCount0= 64;//Anzahl Receiver + UseSparseMatrix=1; + Qfactor=100; + #SignalName=Ricker;# RickerDerivative vorher!!! Geändert 26.Juni.2023 + SignalDelay=0; + SignalCutoff=0.8; + SignalFreq=25; + #numL=0;#!!! + FWISourceWaypoints=2; + FWISourceWaypoint0=600,370; + FWISourceWaypoint1=600,1620; + #FWISourceCount0=2; #Anzahl Quelle + #FWISourceCount0=2; + FWIReceiverIncludeLastWaypoint=1; + measurement_space= point; + measurement_time= point; + compMeasure= 0; + source_component= 2; + perturbation_comp= 2; + dampingFlux= 1; + allowPlotting_M=1; + allowPlotting_WF=0; + plotfactor= 10; + parametrization= taup;#!!!! + #T=0.6; + #dt= 0.002; + #deg= 1; + #level = 0;#Feinheit des Gitters (1 mehr -> Halbierung)//Achtung: 3 Böse, <2 Gut + TimeVerbose= 1; + rkorder= -2; + #plot_tStep= -1; + #FWISO_Steps = 2;//scheint zu klappen! + Steps = 2;//scheint auch nichts zu bringen :( + + Kmax=150; + Keps= 1e-07; + Overlap= dG1; + debugAdjoint= 0; + debugFrechet= 1; + source_factor= 242574257420000.5742; + LinearSolver= LS; + LinearVerbose= -1; + LinearSteps=100; + LinearNthIterOutput= 1; + LinearEpsilon= 1e-12; + LinearReduction= 0.0001; + FWINonlinearSolver= FWISO;#!!! + FWI_DebugPlottingLevel= 1; + CGREGINNCanonic_Steps=3; diff --git a/log/2023_06_30_MultiHighRes_SO/RunMpp.sh b/log/2023_06_30_MultiHighRes_SO/RunMpp.sh new file mode 100644 index 0000000000000000000000000000000000000000..32f1334f2bf2007377a18124946bcbfa77a14f3e --- /dev/null +++ b/log/2023_06_30_MultiHighRes_SO/RunMpp.sh @@ -0,0 +1,29 @@ +#!/bin/sh +### Job name +#SBATCH --job-name=MppFWILennart + +### File for the output +##vorher#SBATCH --output=Mpp%A ??????? +#SBATCH --output=Mpp%A + +### Time your job needs to execute +#SBATCH --time=200:00:00 + +### Use more than one node for parallel jobs on distributed-memory systems +###CR Version war 2, 4 geht, sofern genug frei. +#SBATCH --nodes=8 +###SBATCH --nodes=1 + +### Number of CPUS per task +#SBATCH --cpus-per-task=1 + +### Disable hyperthreading by setting the tasks per core to 1 +#SBATCH --ntasks-per-core=1 + +#SBATCH --mail-type=ALL + +#SBATCH --mail-user=uuwyh@student.kit.edu + +### Number of processes per node, in our case +#SBATCH --ntasks-per-node=16 +mpirun M++ diff --git a/log/2023_06_30_MultiHighRes_SO/logfile.log b/log/2023_06_30_MultiHighRes_SO/logfile.log new file mode 100644 index 0000000000000000000000000000000000000000..d5c9a54c9c671049289dd243474983d03a614f25 --- /dev/null +++ b/log/2023_06_30_MultiHighRes_SO/logfile.log @@ -0,0 +1,4448 @@ +start program on 128 procs at Fri Jun 30 11:08:36 2023 +Running on: node01 + reading config: ConfigVerbose........................... 2 + reading default: enableFileLogging....................... 1 + reading default: enableScreenLogging..................... 1 + reading default: precision............................... 8 + reading default: TimeLevel............................... 0 + reading config: Model................................... FWIInverse_DGTS + reading default: testAAO................................. 0 + reading config: ForwardSolver........................... VADGTS + reading config: ReconstructionType...................... SO + reading config: Mesh.................................... SeismogramGrid_test + reading config: level................................... 3 + reading default: plevel.................................. 3 + reading default: clevel.................................. 3 + reading config: Distribution............................ RCB + reading config: Overlap................................. dG1 + reading default: Scales.................................. 0 + reading default: CommSplit............................... 0 + reading default: DistributionVerbose..................... 0 + reading default: ClearDistribution....................... 1 + reading default: MeshesVerbose........................... 1 + reading default: MeshVerbose............................. 1 + Overlap: reading default: OverlapVerbose.......................... 0 + reading default: t0...................................... 0 + reading config: dt...................................... 0.0005 + reading config: T....................................... 0.6 + reading config: rkorder................................. -2 + reading config: SignalName.............................. Ricker + reading default: FrequencyFiltering...................... 0 + reading config: SignalFreq.............................. 25 + reading default: f_source................................ 25 + reading default: SourceInversion......................... 0 + reading config: SignalCutoff............................ 0.8 + reading config: SignalDelay............................. 0 + reading default: SaveFilteredSeismogram.................. 0 + reading config: SaveObservedSeismogram.................. 0 + reading config: numL.................................... 0 + reading default: dim..................................... 2 + reading config: Problem................................. VAcousticWaveC2Benchmark + reading default: RealDataLevel........................... 3 + reading default: InitialIterateLevel..................... 3 + reading config: deg..................................... 2 + reading config: parametrization......................... taup + reading default: shots................................... -1 + reading default: SourceStartX............................ -1e+100 + reading default: SourceStartY............................ -1e+100 + reading default: SourceEndX.............................. -1e+100 + reading default: SourceEndY.............................. -1e+100 + reading default: numberOfSourcesPerShot.................. 1 + reading config: FWISourceWaypoints...................... 2 + reading default: FWISourceIncludeLastWaypoint............ 1 + FWISourceCount0 + reading config: FWISourceCount0......................... 6 + reading config: FWISourceWaypoint0...................... 600,370 + FWISourceCount1 + reading config: FWISourceWaypoint1...................... 600,1620 + SOURCE LOCATIONS: + 0: ( 600.00000000, 370.00000000) + + + 1: ( 600.00000000, 620.00000000) + + + 2: ( 600.00000000, 870.00000000) + + + 3: ( 600.00000000, 1120) + + + 4: ( 600.00000000, 1370) + + + 5: ( 600.00000000, 1620) + + + reading config: source_factor........................... 242574257420000.5742 + reading config: Monoparam............................... multi + monoparam = + multi + reading default: v_perturb............................... 1.05 + reading default: rho_perturb............................. 1.05 + reading default: tau_p_perturb........................... 4 + reading default: size_perturb............................ 200 + reading default: rho_bg.................................. 2000 + reading default: v_bg.................................... 3500 + reading default: tau_p_bg................................ 0.02 + reading default: impedance_bg............................ 1 + reading config: Qfactor................................. 100 + alphaValue = + 0 + reading default: FWIPrecon............................... 0 + reading default: FWIPreconType........................... 0 + reading default: FWIPreconRegularization................. 1e-08 + reading config: allowPlotting_M......................... 1 + reading config: allowPlotting_WF........................ 0 + reading default: plotFactor.............................. 1 + reading config: FWIReconstructRho....................... 1 + reading config: FWIReconstructV_P....................... 1 + reading config: FWIReconstructTauP...................... 0 + Mesh Info: + Mesh Name: ............................... SeismogramGrid_test + Distribution: ............................ RCB + Overlap: ................................. dG1 + CommSplit: ............................... 0 + Level: ................................... [3, -1, 0] + pLevel: .................................. 3 + Dimension: ............................... 2 + Cells: ................................... 87040 + Overlap: ................................. 21472 + Vertices: ................................ 98560 + Edges: ................................... 174672 + Faces: ................................... 218056 + ProcSets: ................................ 31900 + Mesh width [min, max]: ................... [12.500000, 29.474346] + + reading default: MatrixGraphVerbose...................... 0 + reading default: PaddingPML.............................. 0 + reading config: plot_tStep.............................. -1 + reading default: plotV................................... 0 + reading default: plot_rho................................ 1 + reading default: plot_kappa_0............................ 1 + reading default: plot_kappa_l............................ 0 + reading default: plot_velocity........................... 0 + reading config: compMeasure............................. 0 + Measure overall pressure p = p_0 + ... + p_L + reading default: Specfile................................ + reading config: FWIReceiverWaypoints.................... 2 + reading config: FWIReceiverIncludeLastWaypoint.......... 1 + FWIReceiverCount0 + reading config: FWIReceiverCount0....................... 64 + reading config: FWIReceiverWaypoint0.................... 1350.0, 370.0 + FWIReceiverCount1 + reading config: FWIReceiverWaypoint1.................... 1350.0, 1630.0 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + 0: ( 1350, 370.00000000) 1: ( 1350, 390.00000000) + 2: ( 1350, 410.00000000) 3: ( 1350, 430.00000000) + 4: ( 1350, 450.00000000) 5: ( 1350, 470.00000000) + 6: ( 1350, 490.00000000) 7: ( 1350, 510.00000000) + 8: ( 1350, 530.00000000) 9: ( 1350, 550.00000000) + 10: ( 1350, 570.00000000) 11: ( 1350, 590.00000000) + 12: ( 1350, 610.00000000) 13: ( 1350, 630.00000000) + 14: ( 1350, 650.00000000) 15: ( 1350, 670.00000000) + 16: ( 1350, 690.00000000) 17: ( 1350, 710.00000000) + 18: ( 1350, 730.00000000) 19: ( 1350, 750.00000000) + 20: ( 1350, 770.00000000) 21: ( 1350, 790.00000000) + 22: ( 1350, 810.00000000) 23: ( 1350, 830.00000000) + 24: ( 1350, 850.00000000) 25: ( 1350, 870.00000000) + 26: ( 1350, 890.00000000) 27: ( 1350, 910.00000000) + 28: ( 1350, 930.00000000) 29: ( 1350, 950.00000000) + 30: ( 1350, 970.00000000) 31: ( 1350, 990.00000000) + 32: ( 1350, 1010) 33: ( 1350, 1030) + 34: ( 1350, 1050) 35: ( 1350, 1070) + 36: ( 1350, 1090) 37: ( 1350, 1110) + 38: ( 1350, 1130) 39: ( 1350, 1150) + 40: ( 1350, 1170) 41: ( 1350, 1190) + 42: ( 1350, 1210) 43: ( 1350, 1230) + 44: ( 1350, 1250) 45: ( 1350, 1270) + 46: ( 1350, 1290) 47: ( 1350, 1310) + 48: ( 1350, 1330) 49: ( 1350, 1350) + 50: ( 1350, 1370) 51: ( 1350, 1390) + 52: ( 1350, 1410) 53: ( 1350, 1430) + 54: ( 1350, 1450) 55: ( 1350, 1470) + 56: ( 1350, 1490) 57: ( 1350, 1510) + 58: ( 1350, 1530) 59: ( 1350, 1550) + 60: ( 1350, 1570) 61: ( 1350, 1590) + 62: ( 1350, 1610) 63: ( 1350, 1630) + + reading default: UseGardener............................. 0 + reading default: MeasureComp............................. 0 + Measure overall pressure p = p_0 + ... + p_L + reading default: CountCellsOld........................... 0 + reading config: useTaper................................ 1 + reading default: TaperFromFile........................... + reading config: taperRadiusSource....................... 0 + reading default: taperBoxUpper........................... 1e+100 + reading default: taperBoxLower........................... -1e+100 + reading default: taperBoxLeft............................ -1e+100 + reading default: taperBoxRight........................... 1e+100 + reading config: taperRadiusReceiver..................... 0 + reading config: taperExponent........................... -0.1 + reading config: taperIgnoreSourceCells.................. 1 + reading config: taperIgnoreReceiverCells................ 1 + reading default: taperRhoMin............................. -1 + reading default: taperRhoMax............................. -1 + reading default: taperVpMin.............................. -1 + reading default: taperVpMax.............................. -1 + reading default: taperTaupMin............................ -1 + reading default: taperTaupMax............................ -1 + reading default: seismopath.............................. + reading default: PlotVerbose............................. 0 + reading default: PlotEnabled............................. 0 + reading default: PlotPrecision........................... 4 + Time before FWD->createRealData(real, obs); Fri Jun 30 11:08:42 2023 + Generating Real data for shot 0 + reading default: AssembleVerbose......................... 1 + reading default: startTime............................... 0 + reading default: endTime................................. 1 + reading default: maxStepSize............................. 1e+100 + reading default: stepSize................................ 0 + reading default: minStepSize............................. 0 + reading default: dt_min.................................. 0 + reading default: maxSteps................................ 0 + reading default: steps................................... 0 + reading default: K....................................... 0 + reading default: tEps.................................... 1e-15 + reading default: tTol.................................... 1e-06 + reading default: upwind.................................. 1 + reading config: dampingFlux............................. 1 + reading default: UseCollectTweak......................... 0 + reading default: Preconditioner_S........................ PointBlockJacobi + reading config: LinearSolver............................ LS + reading default: PreconditionerVerbose................... 0 + reading default: PreconditionerDamp...................... 1 + reading default: PointBlockJacobiLapack.................. 0 + reading config: LinearVerbose........................... -1 + reading config: LinearSteps............................. 100 + reading config: LinearEpsilon........................... 1e-12 + reading config: LinearReduction......................... 0.0001 + reading default: LinearMinimalStepNumber................. 0 + reading default: LinearPrintSteps........................ 800 + reading default: TimeIntegratorVerbose................... 1 + Initialization: 0.37 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.85 seconds + Generating Real data for shot 1 + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.49 seconds + Generating Real data for shot 2 + Initialization: 0.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.61 seconds + Generating Real data for shot 3 + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.31 seconds + Generating Real data for shot 4 + Initialization: 0.37 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.36 seconds + Generating Real data for shot 5 + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.30 seconds + Time after FWD->createRealData(real, obs); Fri Jun 30 11:11:42 2023 + FWISourceCount0 + FWISourceCount1 + SOURCE LOCATIONS: + 0: ( 600.00000000, 370.00000000) + + + 1: ( 600.00000000, 620.00000000) + + + 2: ( 600.00000000, 870.00000000) + + + 3: ( 600.00000000, 1120) + + + 4: ( 600.00000000, 1370) + + + 5: ( 600.00000000, 1620) + + + monoparam = + multi + alphaValue = + 0 + Frequency Filter to: -1 + + + Mesh Info: + Mesh Name: ............................... SeismogramGrid_test + Distribution: ............................ RCB + Overlap: ................................. dG1 + CommSplit: ............................... 0 + Level: ................................... [3, -1, 0] + pLevel: .................................. 3 + Dimension: ............................... 2 + Cells: ................................... 87040 + Overlap: ................................. 21472 + Vertices: ................................ 98560 + Edges: ................................... 174672 + Faces: ................................... 218056 + ProcSets: ................................ 31900 + Mesh width [min, max]: ................... [12.500000, 29.474346] + + Measure overall pressure p = p_0 + ... + p_L + FWIReceiverCount0 + FWIReceiverCount1 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + 0: ( 1350, 370.00000000) 1: ( 1350, 390.00000000) + 2: ( 1350, 410.00000000) 3: ( 1350, 430.00000000) + 4: ( 1350, 450.00000000) 5: ( 1350, 470.00000000) + 6: ( 1350, 490.00000000) 7: ( 1350, 510.00000000) + 8: ( 1350, 530.00000000) 9: ( 1350, 550.00000000) + 10: ( 1350, 570.00000000) 11: ( 1350, 590.00000000) + 12: ( 1350, 610.00000000) 13: ( 1350, 630.00000000) + 14: ( 1350, 650.00000000) 15: ( 1350, 670.00000000) + 16: ( 1350, 690.00000000) 17: ( 1350, 710.00000000) + 18: ( 1350, 730.00000000) 19: ( 1350, 750.00000000) + 20: ( 1350, 770.00000000) 21: ( 1350, 790.00000000) + 22: ( 1350, 810.00000000) 23: ( 1350, 830.00000000) + 24: ( 1350, 850.00000000) 25: ( 1350, 870.00000000) + 26: ( 1350, 890.00000000) 27: ( 1350, 910.00000000) + 28: ( 1350, 930.00000000) 29: ( 1350, 950.00000000) + 30: ( 1350, 970.00000000) 31: ( 1350, 990.00000000) + 32: ( 1350, 1010) 33: ( 1350, 1030) + 34: ( 1350, 1050) 35: ( 1350, 1070) + 36: ( 1350, 1090) 37: ( 1350, 1110) + 38: ( 1350, 1130) 39: ( 1350, 1150) + 40: ( 1350, 1170) 41: ( 1350, 1190) + 42: ( 1350, 1210) 43: ( 1350, 1230) + 44: ( 1350, 1250) 45: ( 1350, 1270) + 46: ( 1350, 1290) 47: ( 1350, 1310) + 48: ( 1350, 1330) 49: ( 1350, 1350) + 50: ( 1350, 1370) 51: ( 1350, 1390) + 52: ( 1350, 1410) 53: ( 1350, 1430) + 54: ( 1350, 1450) 55: ( 1350, 1470) + 56: ( 1350, 1490) 57: ( 1350, 1510) + 58: ( 1350, 1530) 59: ( 1350, 1550) + 60: ( 1350, 1570) 61: ( 1350, 1590) + 62: ( 1350, 1610) 63: ( 1350, 1630) + + Measure overall pressure p = p_0 + ... + p_L + reading default: loadInitialModelFromFile................ 0 + reading default: loadRealModelFromFile................... 0 + reading config: FWINonlinearSolver...................... FWISO + reading default: FWI_MaxInnerLoopSteps_FWISO............. 10 + reading default: FWI_Gamma_FWISO......................... 0.9 + reading default: FWI_Damping_FWISO....................... 1 + reading default: FWI_ThetaMax_FWISO...................... 1 + reading default: FWI_ThetaInitial_FWISO.................. 0.4 + reading default: FWI_RegularizationStrategy_FWISO........ 0 + reading default: FWISO_Verbose........................... 1 + reading config: FWISO_Steps............................. 10 + reading default: FWISO_LineSearchSteps................... 3 + reading default: FWISO_Epsilon........................... 1e-10 + reading default: FWISO_Reduction......................... 1e-05 + reading default: FWISO_MinimalStepNumber................. 0 + reading default: FWI_Precon.............................. 0 + reading default: FWI_HierarchyLevel...................... -1 + reading default: FWI_SaveAdjointWF....................... 0 + reading default: FWI_SaveSeis............................ 0 + reading config: FWI_DebugPlottingLevel.................. 1 + reading default: FWI_BacktrackingFactor.................. 0.5 + reading default: FWI_BacktrackingActivated............... 0 + Memory Usage at start31787 + reading default: WriteSeismoToFileEvery.................. 2147483647 + Initialize Subproblems 31793 + Starting the Loops with max_iter: 10 and num_problems 6 + + + Iteration Main Looop Counting Variable iter: 0 + + iteration: 0 PROBLEM Number: 0 + FWISO problem 0: d(0) + shot: 0: Solving forward problem... + Initialization: 0.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.90 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32051 + state_comps = + 1 + Prä-Residuumnorm: 26143792 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 26143792 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.16 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.37 seconds + Inner Loop: : InnerCG resNorm : 12571047 + Inner Loop: : Time needed for inner loop: 1:09.98 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:09.98 minutes + Residuumnorm 1: 12571047 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.01 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.53 seconds + Intermezzo Residuum: 12106333 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 26143792 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.47 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.98 seconds + PhiAdjSO: : 1:04.58 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.93 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.86 seconds + Inner Loop: : InnerCG resNorm : 7210497.3 + Inner Loop: : Time needed for inner loop: 3:47.65 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:47.65 minutes + FWISO Subproblem: 0: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 7210497.3 + reading default: PlotFactorIterates...................... 1 + reading default: PlotShot................................ -1 + + iteration: 0 PROBLEM Number: 1 + FWISO problem 1: d(0) + shot: 1: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.14 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 113817 + state_comps = + 1 + Prä-Residuumnorm: 19850061 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 19850061 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.19 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.35 seconds + Inner Loop: : InnerCG resNorm : 10078336 + Inner Loop: : Time needed for inner loop: 1:08.96 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:08.96 minutes + Residuumnorm 1: 10078336 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.23 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.67 seconds + Intermezzo Residuum: 9923489.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 19850061 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.24 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.30 seconds + PhiAdjSO: : 1:05.01 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.58 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.47 seconds + Inner Loop: : InnerCG resNorm : 6596187.9 + Inner Loop: : Time needed for inner loop: 3:36.49 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:36.49 minutes + FWISO Subproblem: 1: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 6596187.9 + + iteration: 0 PROBLEM Number: 2 + FWISO problem 2: d(0) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.45 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 117549 + state_comps = + 1 + Prä-Residuumnorm: 19118047 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 19118047 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.03 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.91 seconds + Inner Loop: : InnerCG resNorm : 9095968.5 + Inner Loop: : Time needed for inner loop: 1:07.37 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:07.37 minutes + Residuumnorm 1: 9095968.5 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.91 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.63 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.14 seconds + Intermezzo Residuum: 8628764.7 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 19118047 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.71 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.41 seconds + PhiAdjSO: : 1:05.19 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.14 seconds + Initialization: 0.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.32 seconds + Inner Loop: : InnerCG resNorm : 5708774.1 + Inner Loop: : Time needed for inner loop: 3:29.75 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.75 minutes + FWISO Subproblem: 2: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 5708774.1 + + iteration: 0 PROBLEM Number: 3 + FWISO problem 3: d(0) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.16 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 119704 + state_comps = + 1 + Prä-Residuumnorm: 10423303 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 10423303 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.20 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.67 seconds + Inner Loop: : InnerCG resNorm : 6192338 + Inner Loop: : Time needed for inner loop: 1:07.29 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:07.29 minutes + Residuumnorm 1: 6192338 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.80 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.49 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.02 seconds + Intermezzo Residuum: 6141732.2 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 10423303 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.67 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.33 seconds + PhiAdjSO: : 1:05.00 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.43 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.04 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.37 seconds + Inner Loop: : InnerCG resNorm : 4633099.4 + Inner Loop: : Time needed for inner loop: 3:29.38 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:29.38 minutes + FWISO Subproblem: 3: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 4633099.4 + + iteration: 0 PROBLEM Number: 4 + FWISO problem 4: d(0) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.06 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 122715 + state_comps = + 1 + Prä-Residuumnorm: 4322132.1 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4322132.1 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.17 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.94 seconds + Inner Loop: : InnerCG resNorm : 3102878.5 + Inner Loop: : Time needed for inner loop: 1:08.54 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:08.54 minutes + Residuumnorm 1: 3102878.5 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.01 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.93 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.42 seconds + Intermezzo Residuum: 3094694.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4322132.1 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.93 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.35 seconds + PhiAdjSO: : 1:05.14 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.96 seconds + Initialization: 0.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.12 seconds + Inner Loop: : InnerCG resNorm : 2541437.9 + Inner Loop: : Time needed for inner loop: 3:35.80 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:35.80 minutes + FWISO Subproblem: 4: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 2541437.9 + + iteration: 0 PROBLEM Number: 5 + FWISO problem 5: d(0) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.15 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 124259 + state_comps = + 1 + Prä-Residuumnorm: 4308252 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4308252 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.11 seconds + Inner Loop: : InnerCG resNorm : 2791119.9 + Inner Loop: : Time needed for inner loop: 1:11.49 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:11.49 minutes + Residuumnorm 1: 2791119.9 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.92 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.74 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.33 seconds + Intermezzo Residuum: 2805782.3 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4308252 und m_max 1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.58 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.46 seconds + PhiAdjSO: : 1:05.41 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.23 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.07 seconds + Inner Loop: : InnerCG resNorm : 2275121.5 + Inner Loop: : Time needed for inner loop: 3:48.85 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:48.85 minutes + FWISO Subproblem: 5: d(0): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 2275121.5 + + + Iteration Main Looop Counting Variable iter: 1 + + iteration: 1 PROBLEM Number: 0 + FWISO problem 0: d(1) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.73 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 125779 + Prä-Residuumnorm: 6250155.6 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1494215 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.78 seconds + Inner Loop: : InnerCG resNorm : 4288747.3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.47 seconds + Inner Loop: : InnerCG resNorm : 2755250.8 + Inner Loop: : Time needed for inner loop: 2:21.91 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:21.91 minutes + Residuumnorm 1: 2755250.8 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.77 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.54 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.06 seconds + Intermezzo Residuum: 2799086.4 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1494215 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.35 seconds + PhiAdjSO: : 1:05.10 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.45 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.11 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.37 seconds + Inner Loop: : InnerCG resNorm : 2238015.3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.21 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.35 seconds + PhiAdjSO: : 1:05.40 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.56 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.85 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.34 seconds + Inner Loop: : InnerCG resNorm : 1786471.5 + Inner Loop: : Time needed for inner loop: 7:41.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:41.00 minutes + FWISO Subproblem: 0: d(1): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 1786471.5 + + iteration: 1 PROBLEM Number: 1 + FWISO problem 1: d(1) + shot: 1: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.26 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 125856 + Prä-Residuumnorm: 4694237.1 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1110115.6 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.49 seconds + Inner Loop: : InnerCG resNorm : 2910738.3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.74 seconds + Inner Loop: : InnerCG resNorm : 2274494.8 + Inner Loop: : Time needed for inner loop: 2:17.88 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:17.88 minutes + Residuumnorm 1: 2274494.8 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.82 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.59 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.67 seconds + Intermezzo Residuum: 2286815.5 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1110115.6 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.34 seconds + PhiAdjSO: : 1:05.12 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.09 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.19 seconds + Inner Loop: : InnerCG resNorm : 1905146 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.35 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.48 seconds + PhiAdjSO: : 1:05.32 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.60 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.36 seconds + Inner Loop: : InnerCG resNorm : 1467151.4 + Inner Loop: : Time needed for inner loop: 7:17.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:17.00 minutes + FWISO Subproblem: 1: d(1): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 1467151.4 + + iteration: 1 PROBLEM Number: 2 + FWISO problem 2: d(1) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.33 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 126662 + Prä-Residuumnorm: 4121336.6 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 888449.26 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.53 seconds + Inner Loop: : InnerCG resNorm : 2946006.8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.74 seconds + Inner Loop: : InnerCG resNorm : 2104824.7 + Inner Loop: : Time needed for inner loop: 2:13.83 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:13.83 minutes + Residuumnorm 1: 2104824.7 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.13 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.76 seconds + Intermezzo Residuum: 2113741.8 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 888449.26 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.93 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.32 seconds + PhiAdjSO: : 1:05.20 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.13 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.32 seconds + Initialization: 0.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.46 seconds + Inner Loop: : InnerCG resNorm : 1709840.5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.00 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.43 seconds + PhiAdjSO: : 1:05.31 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.94 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.08 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.31 seconds + Inner Loop: : InnerCG resNorm : 1380134.4 + Inner Loop: : Time needed for inner loop: 6:57.27 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:57.27 minutes + FWISO Subproblem: 2: d(1): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 1380134.4 + + iteration: 1 PROBLEM Number: 3 + FWISO problem 3: d(1) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.92 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 126713 + Prä-Residuumnorm: 3649756.9 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1277975.4 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.54 seconds + Inner Loop: : InnerCG resNorm : 2941795.7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.60 seconds + Inner Loop: : InnerCG resNorm : 1800608.4 + Inner Loop: : Time needed for inner loop: 2:13.75 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:13.75 minutes + Residuumnorm 1: 1800608.4 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.38 seconds + Initialization: 0.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.93 seconds + Intermezzo Residuum: 1796518.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1277975.4 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.28 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.35 seconds + PhiAdjSO: : 1:05.17 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.41 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.55 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.14 seconds + Inner Loop: : InnerCG resNorm : 1417038.3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.29 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.33 seconds + PhiAdjSO: : 1:05.24 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.10 seconds + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.31 seconds + Inner Loop: : InnerCG resNorm : 1224923.2 + Inner Loop: : Time needed for inner loop: 7:00.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:00.00 minutes + FWISO Subproblem: 3: d(1): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 1224923.2 + + iteration: 1 PROBLEM Number: 4 + FWISO problem 4: d(1) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.02 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 126891 + Prä-Residuumnorm: 1780992.3 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 733881.72 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.49 seconds + Inner Loop: : InnerCG resNorm : 1439413.7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.74 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.93 seconds + Inner Loop: : InnerCG resNorm : 1172858.1 + Inner Loop: : Time needed for inner loop: 2:16.81 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:16.81 minutes + Residuumnorm 1: 1172858.1 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.41 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.18 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.05 seconds + Intermezzo Residuum: 1173072.2 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 733881.72 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.01 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.30 seconds + PhiAdjSO: : 1:05.06 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.10 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.41 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.69 seconds + Inner Loop: : InnerCG resNorm : 1017876.9 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.06 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.40 seconds + PhiAdjSO: : 1:05.23 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.11 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.28 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.92 seconds + Inner Loop: : InnerCG resNorm : 883372.13 + Inner Loop: : Time needed for inner loop: 7:13.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:13.00 minutes + FWISO Subproblem: 4: d(1): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 883372.13 + + iteration: 1 PROBLEM Number: 5 + FWISO problem 5: d(1) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.06 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 127017 + Prä-Residuumnorm: 1853808.1 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 797679.5 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.73 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.90 seconds + Inner Loop: : InnerCG resNorm : 1528883.2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.69 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.67 seconds + Inner Loop: : InnerCG resNorm : 1048648 + Inner Loop: : Time needed for inner loop: 2:21.83 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:21.83 minutes + Residuumnorm 1: 1048648 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.10 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.80 seconds + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.69 seconds + Intermezzo Residuum: 1050921 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 797679.5 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.70 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.22 seconds + PhiAdjSO: : 1:04.89 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.94 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.04 seconds + Inner Loop: : InnerCG resNorm : 848924.38 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.48 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.32 seconds + PhiAdjSO: : 1:05.22 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.75 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.19 seconds + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.67 seconds + Inner Loop: : InnerCG resNorm : 729377.82 + Inner Loop: : Time needed for inner loop: 7:32.22 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:32.22 minutes + FWISO Subproblem: 5: d(1): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 729377.82 + + + Iteration Main Looop Counting Variable iter: 2 + + iteration: 2 PROBLEM Number: 0 + FWISO problem 0: d(2) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.40 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 127187 + Prä-Residuumnorm: 2317102.5 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1435524.3 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.70 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.75 seconds + Inner Loop: : InnerCG resNorm : 1702211.1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.61 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.47 seconds + Inner Loop: : InnerCG resNorm : 1303101.1 + Inner Loop: : Time needed for inner loop: 2:21.37 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:21.37 minutes + Residuumnorm 1: 1303101.1 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.70 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.38 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.80 seconds + Intermezzo Residuum: 1303640.3 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1435524.3 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.34 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.10 seconds + PhiAdjSO: : 1:04.68 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.92 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.14 seconds + Inner Loop: : InnerCG resNorm : 1139703.4 + Inner Loop: : Time needed for inner loop: 3:47.22 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:47.22 minutes + FWISO Subproblem: 0: d(2): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 1139703.4 + + iteration: 2 PROBLEM Number: 1 + FWISO problem 1: d(2) + shot: 1: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.27 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 127260 + Prä-Residuumnorm: 2756891.4 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1704427.1 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.60 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.16 seconds + Inner Loop: : InnerCG resNorm : 1524421.6 + Inner Loop: : Time needed for inner loop: 1:08.17 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:08.17 minutes + Residuumnorm 1: 1524421.6 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.21 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.77 seconds + Intermezzo Residuum: 1521251.2 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1704427.1 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.05 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.18 seconds + PhiAdjSO: : 1:04.71 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.01 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.76 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.28 seconds + Inner Loop: : InnerCG resNorm : 1247895.4 + Inner Loop: : Time needed for inner loop: 3:35.68 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:35.68 minutes + FWISO Subproblem: 1: d(2): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 1247895.4 + + iteration: 2 PROBLEM Number: 2 + FWISO problem 2: d(2) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.22 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 127360 + Prä-Residuumnorm: 1975958.7 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1200961.1 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.63 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.64 seconds + Inner Loop: : InnerCG resNorm : 1223482.1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.56 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.16 seconds + Inner Loop: : InnerCG resNorm : 1011086.8 + Inner Loop: : Time needed for inner loop: 2:12.83 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:12.83 minutes + Residuumnorm 1: 1011086.8 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.52 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.42 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.02 seconds + Intermezzo Residuum: 1010505.9 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1200961.1 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.25 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.14 seconds + PhiAdjSO: : 1:04.71 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.39 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.95 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.37 seconds + Inner Loop: : InnerCG resNorm : 891548.17 + Inner Loop: : Time needed for inner loop: 3:28.45 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:28.45 minutes + FWISO Subproblem: 2: d(2): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 891548.17 + + iteration: 2 PROBLEM Number: 3 + FWISO problem 3: d(2) + shot: 3: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.06 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 127464 + Prä-Residuumnorm: 1589865 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1073281 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.61 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.34 seconds + Inner Loop: : InnerCG resNorm : 1124559.5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.12 seconds + Inner Loop: : InnerCG resNorm : 934290.6 + Inner Loop: : Time needed for inner loop: 2:12.40 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:12.40 minutes + Residuumnorm 1: 934290.6 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.23 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.79 seconds + Intermezzo Residuum: 934817.2 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1073281 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.13 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.20 seconds + PhiAdjSO: : 1:04.89 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.01 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.77 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.83 seconds + Inner Loop: : InnerCG resNorm : 840363.47 + Inner Loop: : Time needed for inner loop: 3:27.36 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:27.36 minutes + FWISO Subproblem: 3: d(2): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 840363.47 + + iteration: 2 PROBLEM Number: 4 + FWISO problem 4: d(2) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.87 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 127539 + Prä-Residuumnorm: 1493070.3 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1054154.9 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.05 seconds + Inner Loop: : InnerCG resNorm : 969839.07 + Inner Loop: : Time needed for inner loop: 1:08.04 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:08.04 minutes + Residuumnorm 1: 969839.07 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.13 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.91 seconds + Intermezzo Residuum: 967717.64 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1054154.9 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.94 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.14 seconds + PhiAdjSO: : 1:04.72 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.35 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.04 seconds + Inner Loop: : InnerCG resNorm : 815016.06 + Inner Loop: : Time needed for inner loop: 3:34.69 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:34.69 minutes + FWISO Subproblem: 4: d(2): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 815016.06 + + iteration: 2 PROBLEM Number: 5 + FWISO problem 5: d(2) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.00 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 127674 + Prä-Residuumnorm: 889354.95 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 636018.81 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.60 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.31 seconds + Inner Loop: : InnerCG resNorm : 708961.38 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.57 seconds + Inner Loop: : InnerCG resNorm : 631309.28 + Inner Loop: : Time needed for inner loop: 2:20.90 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:20.90 minutes + Residuumnorm 1: 631309.28 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.07 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.93 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.71 seconds + Intermezzo Residuum: 631401.04 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 636018.81 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.82 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.19 seconds + PhiAdjSO: : 1:04.89 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.80 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.69 seconds + Inner Loop: : InnerCG resNorm : 583905.98 + Inner Loop: : Time needed for inner loop: 3:45.71 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:45.71 minutes + FWISO Subproblem: 5: d(2): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 583905.98 + + + Iteration Main Looop Counting Variable iter: 3 + + iteration: 3 PROBLEM Number: 0 + FWISO problem 0: d(3) + shot: 0: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.51 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 127739 + Prä-Residuumnorm: 1375939.1 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 767197.2 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.86 seconds + Inner Loop: : InnerCG resNorm : 1172048.4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.54 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.64 seconds + Inner Loop: : InnerCG resNorm : 931796.71 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.40 seconds + Inner Loop: : InnerCG resNorm : 762709.21 + Inner Loop: : Time needed for inner loop: 3:31.88 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:31.88 minutes + Residuumnorm 1: 762709.21 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.65 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.48 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.34 seconds + Intermezzo Residuum: 760475.82 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 767197.2 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.39 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.16 seconds + PhiAdjSO: : 1:04.72 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.76 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.09 seconds + Inner Loop: : InnerCG resNorm : 695435.95 + Inner Loop: : Time needed for inner loop: 3:47.09 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:47.09 minutes + FWISO Subproblem: 0: d(3): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 695435.95 + + iteration: 3 PROBLEM Number: 1 + FWISO problem 1: d(3) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.44 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 127789 + Prä-Residuumnorm: 1578800.4 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 878473.17 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.54 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.15 seconds + Inner Loop: : InnerCG resNorm : 1119769.3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.46 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.11 seconds + Inner Loop: : InnerCG resNorm : 912561.71 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.50 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.27 seconds + Inner Loop: : InnerCG resNorm : 684010.05 + Inner Loop: : Time needed for inner loop: 3:24.28 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:24.28 minutes + Residuumnorm 1: 684010.05 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.74 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.89 seconds + Intermezzo Residuum: 683897.49 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 878473.17 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.74 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.20 seconds + PhiAdjSO: : 1:04.72 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.60 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.17 seconds + Inner Loop: : InnerCG resNorm : 598817.11 + Inner Loop: : Time needed for inner loop: 3:34.56 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:34.56 minutes + FWISO Subproblem: 1: d(3): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 598817.11 + + iteration: 3 PROBLEM Number: 2 + FWISO problem 2: d(3) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.28 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 127882 + Prä-Residuumnorm: 1334927.5 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 730215.88 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.54 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.51 seconds + Inner Loop: : InnerCG resNorm : 945489.5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.13 seconds + Inner Loop: : InnerCG resNorm : 801305.42 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.49 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.56 seconds + Inner Loop: : InnerCG resNorm : 646197.1 + Inner Loop: : Time needed for inner loop: 3:18.96 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:18.96 minutes + Residuumnorm 1: 646197.1 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.17 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.91 seconds + Intermezzo Residuum: 645500.69 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 730215.88 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.16 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.15 seconds + PhiAdjSO: : 1:04.73 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.09 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.44 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.23 seconds + Inner Loop: : InnerCG resNorm : 576588.62 + Inner Loop: : Time needed for inner loop: 3:27.32 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:27.32 minutes + FWISO Subproblem: 2: d(3): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 576588.62 + + iteration: 3 PROBLEM Number: 3 + FWISO problem 3: d(3) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.93 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 128005 + Prä-Residuumnorm: 1214638 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 737976.52 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.46 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.19 seconds + Inner Loop: : InnerCG resNorm : 1005785.4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.27 seconds + Inner Loop: : InnerCG resNorm : 780586.8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.33 seconds + Inner Loop: : InnerCG resNorm : 656553.15 + Inner Loop: : Time needed for inner loop: 3:18.38 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:18.38 minutes + Residuumnorm 1: 656553.15 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.96 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.81 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.32 seconds + Intermezzo Residuum: 656977.04 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 737976.52 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.79 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.08 seconds + PhiAdjSO: : 1:04.63 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.67 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.02 seconds + Inner Loop: : InnerCG resNorm : 594676.58 + Inner Loop: : Time needed for inner loop: 3:26.54 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:26.54 minutes + FWISO Subproblem: 3: d(3): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 594676.58 + + iteration: 3 PROBLEM Number: 4 + FWISO problem 4: d(3) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.98 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 128093 + Prä-Residuumnorm: 1189150.5 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 755620.14 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.53 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.10 seconds + Inner Loop: : InnerCG resNorm : 884373.38 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.94 seconds + Inner Loop: : InnerCG resNorm : 725588.32 + Inner Loop: : Time needed for inner loop: 2:15.87 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:15.87 minutes + Residuumnorm 1: 725588.32 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.49 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.44 seconds + Intermezzo Residuum: 725084.13 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 755620.14 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.40 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.14 seconds + PhiAdjSO: : 1:04.80 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.43 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.95 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.50 seconds + Inner Loop: : InnerCG resNorm : 642753.65 + Inner Loop: : Time needed for inner loop: 3:32.78 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:32.78 minutes + FWISO Subproblem: 4: d(3): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 642753.65 + + iteration: 3 PROBLEM Number: 5 + FWISO problem 5: d(3) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.78 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 128230 + Prä-Residuumnorm: 744770.65 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 479357.91 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.76 seconds + Inner Loop: : InnerCG resNorm : 639465.1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.43 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.50 seconds + Inner Loop: : InnerCG resNorm : 570751.45 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.18 seconds + Inner Loop: : InnerCG resNorm : 507058.63 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.62 seconds + Inner Loop: : InnerCG resNorm : 428259.66 + Inner Loop: : Time needed for inner loop: 4:41.48 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:41.48 minutes + Residuumnorm 1: 428259.66 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.06 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.22 seconds + Intermezzo Residuum: 428238.83 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 479357.91 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.09 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.13 seconds + PhiAdjSO: : 1:04.71 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.01 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.35 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.65 seconds + Inner Loop: : InnerCG resNorm : 398633.93 + Inner Loop: : Time needed for inner loop: 3:45.59 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:45.59 minutes + FWISO Subproblem: 5: d(3): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 398633.93 + + + Iteration Main Looop Counting Variable iter: 4 + + iteration: 4 PROBLEM Number: 0 + FWISO problem 0: d(4) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.37 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 128318 + Prä-Residuumnorm: 954529.66 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 672994.82 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.12 seconds + Inner Loop: : InnerCG resNorm : 806896.95 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.44 seconds + Inner Loop: : InnerCG resNorm : 689840.62 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.51 seconds + Inner Loop: : InnerCG resNorm : 616582.94 + Inner Loop: : Time needed for inner loop: 3:31.69 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:31.69 minutes + Residuumnorm 1: 616582.94 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.63 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.51 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.35 seconds + Intermezzo Residuum: 616481.43 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 479004.67 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.47 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.15 seconds + PhiAdjSO: : 1:04.63 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.47 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.59 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.77 seconds + Inner Loop: : InnerCG resNorm : 581691.1 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.46 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.13 seconds + PhiAdjSO: : 1:04.73 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.06 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.90 seconds + Inner Loop: : InnerCG resNorm : 546086.09 + Inner Loop: : Time needed for inner loop: 7:37.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:37.00 minutes + FWISO Subproblem: 0: d(4): Finished first / second inner loop ( 3, 2 steps ) + ************************************* + Residuumnorm 2: 546086.09 + + iteration: 4 PROBLEM Number: 1 + FWISO problem 1: d(4) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.00 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 128371 + Prä-Residuumnorm: 1054481.3 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 898565.08 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.91 seconds + Inner Loop: : InnerCG resNorm : 757505.82 + Inner Loop: : Time needed for inner loop: 1:07.84 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:07.84 minutes + Residuumnorm 1: 757505.82 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.80 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.82 seconds + Intermezzo Residuum: 757365.69 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 528059.3 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.85 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.13 seconds + PhiAdjSO: : 1:04.59 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.37 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.94 seconds + Inner Loop: : InnerCG resNorm : 682173.28 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.79 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.20 seconds + PhiAdjSO: : 1:04.83 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.06 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.97 seconds + Inner Loop: : InnerCG resNorm : 500455.88 + Inner Loop: : Time needed for inner loop: 7:11.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:11.00 minutes + FWISO Subproblem: 1: d(4): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 500455.88 + + iteration: 4 PROBLEM Number: 2 + FWISO problem 2: d(4) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.01 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 128483 + Prä-Residuumnorm: 1066359.5 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 744324.53 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.49 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.49 seconds + Inner Loop: : InnerCG resNorm : 738583.41 + Inner Loop: : Time needed for inner loop: 1:06.38 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:06.38 minutes + Residuumnorm 1: 738583.41 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.25 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.96 seconds + Intermezzo Residuum: 739020.92 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 524976.35 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.21 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.12 seconds + PhiAdjSO: : 1:04.61 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.19 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.48 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.04 seconds + Inner Loop: : InnerCG resNorm : 644617.09 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.38 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.21 seconds + PhiAdjSO: : 1:04.76 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.09 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.53 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.20 seconds + Inner Loop: : InnerCG resNorm : 532296.28 + Inner Loop: : Time needed for inner loop: 6:57.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:57.00 minutes + FWISO Subproblem: 2: d(4): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 532296.28 + + iteration: 4 PROBLEM Number: 3 + FWISO problem 3: d(4) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.73 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 128678 + Prä-Residuumnorm: 993358.32 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 733475.32 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.44 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.17 seconds + Inner Loop: : InnerCG resNorm : 808684.62 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.41 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.27 seconds + Inner Loop: : InnerCG resNorm : 638507.75 + Inner Loop: : Time needed for inner loop: 2:12.11 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:12.11 minutes + Residuumnorm 1: 638507.75 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.64 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.57 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.37 seconds + Intermezzo Residuum: 638544.13 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 543180.44 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.56 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.12 seconds + PhiAdjSO: : 1:04.59 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.29 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.64 seconds + Inner Loop: : InnerCG resNorm : 580502.33 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.61 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.18 seconds + PhiAdjSO: : 1:04.73 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.44 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.38 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.77 seconds + Inner Loop: : InnerCG resNorm : 523436.01 + Inner Loop: : Time needed for inner loop: 6:54.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:54.00 minutes + FWISO Subproblem: 3: d(4): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 523436.01 + + iteration: 4 PROBLEM Number: 4 + FWISO problem 4: d(4) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.79 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 128777 + Prä-Residuumnorm: 977666.36 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 799451.73 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.44 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.96 seconds + Inner Loop: : InnerCG resNorm : 728882.04 + Inner Loop: : Time needed for inner loop: 1:07.82 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:07.82 minutes + Residuumnorm 1: 728882.04 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.87 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.74 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.71 seconds + Intermezzo Residuum: 728510.4 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 559113.38 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.71 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.06 seconds + PhiAdjSO: : 1:04.62 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.67 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.29 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.90 seconds + Inner Loop: : InnerCG resNorm : 651206.53 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.81 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.23 seconds + PhiAdjSO: : 1:04.81 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.02 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.55 seconds + Inner Loop: : InnerCG resNorm : 519059.33 + Inner Loop: : Time needed for inner loop: 7:10.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:10.00 minutes + FWISO Subproblem: 4: d(4): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 519059.33 + + iteration: 4 PROBLEM Number: 5 + FWISO problem 5: d(4) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.89 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 128865 + Prä-Residuumnorm: 649694.43 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 533929.14 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.43 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.82 seconds + Inner Loop: : InnerCG resNorm : 545344 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.54 seconds + Inner Loop: : InnerCG resNorm : 478697.41 + Inner Loop: : Time needed for inner loop: 2:21.01 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:21.01 minutes + Residuumnorm 1: 478697.41 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.46 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.67 seconds + Intermezzo Residuum: 478720.35 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 376347.47 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.40 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.07 seconds + PhiAdjSO: : 1:04.55 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.53 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.55 seconds + Inner Loop: : InnerCG resNorm : 446508.59 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.48 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.23 seconds + PhiAdjSO: : 1:04.86 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.42 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.05 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.75 seconds + Inner Loop: : InnerCG resNorm : 412593.28 + Inner Loop: : Time needed for inner loop: 7:32.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:32.00 minutes + FWISO Subproblem: 5: d(4): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 412593.28 + + + Iteration Main Looop Counting Variable iter: 5 + + iteration: 5 PROBLEM Number: 0 + FWISO problem 0: d(5) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.17 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 128966 + Prä-Residuumnorm: 750053.45 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 475945.28 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.46 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.04 seconds + Inner Loop: : InnerCG resNorm : 655735.34 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.40 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.53 seconds + Inner Loop: : InnerCG resNorm : 559055.91 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.25 seconds + Inner Loop: : InnerCG resNorm : 502106.66 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.26 seconds + Inner Loop: : InnerCG resNorm : 457565.23 + Inner Loop: : Time needed for inner loop: 4:41.36 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:41.36 minutes + Residuumnorm 1: 457565.23 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.16 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.07 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.01 seconds + Intermezzo Residuum: 457425.81 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 563223.65 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.12 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.02 seconds + PhiAdjSO: : 1:04.46 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.04 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.08 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.76 seconds + Inner Loop: : InnerCG resNorm : 435860.72 + Inner Loop: : Time needed for inner loop: 3:46.22 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:46.22 minutes + FWISO Subproblem: 0: d(5): Finished first / second inner loop ( 4, 1 steps ) + ************************************* + Residuumnorm 2: 435860.72 + + iteration: 5 PROBLEM Number: 1 + FWISO problem 1: d(5) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.19 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 129037 + Prä-Residuumnorm: 801849.51 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 614958.79 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.01 seconds + Inner Loop: : InnerCG resNorm : 597879.35 + Inner Loop: : Time needed for inner loop: 1:07.85 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:07.85 minutes + Residuumnorm 1: 597879.35 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.77 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.76 seconds + Intermezzo Residuum: 597916.07 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 601698.38 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.86 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.01 seconds + PhiAdjSO: : 1:04.45 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.73 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.32 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.13 seconds + Inner Loop: : InnerCG resNorm : 533531.75 + Inner Loop: : Time needed for inner loop: 3:34.22 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:34.22 minutes + FWISO Subproblem: 1: d(5): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 533531.75 + + iteration: 5 PROBLEM Number: 2 + FWISO problem 2: d(5) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.01 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 129129 + Prä-Residuumnorm: 861998.24 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 541511.37 und m_max 4 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + Inner Loop: : InnerCG resNorm : 619433.89 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.36 seconds + Inner Loop: : InnerCG resNorm : 539963.21 + Inner Loop: : Time needed for inner loop: 2:12.38 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:12.38 minutes + Residuumnorm 1: 539963.21 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.21 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.18 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.04 seconds + Intermezzo Residuum: 539965.6 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 643183.04 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.16 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + PhiAdjSO: : 1:04.43 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.18 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.65 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.05 seconds + Inner Loop: : InnerCG resNorm : 497731.6 + Inner Loop: : Time needed for inner loop: 3:27.16 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:27.16 minutes + FWISO Subproblem: 2: d(5): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 497731.6 + + iteration: 5 PROBLEM Number: 3 + FWISO problem 3: d(5) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.76 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 129224 + Prä-Residuumnorm: 801531 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 532650.58 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.20 seconds + Inner Loop: : InnerCG resNorm : 624456.34 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.37 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.91 seconds + Inner Loop: : InnerCG resNorm : 539364.57 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.34 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.17 seconds + Inner Loop: : InnerCG resNorm : 469264.72 + Inner Loop: : Time needed for inner loop: 3:17.61 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:17.61 minutes + Residuumnorm 1: 469264.72 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.60 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.50 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.16 seconds + Intermezzo Residuum: 469385.6 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 619908.96 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.52 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.96 seconds + PhiAdjSO: : 1:04.41 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.46 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.18 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.69 seconds + Inner Loop: : InnerCG resNorm : 436668.03 + Inner Loop: : Time needed for inner loop: 3:24.96 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:24.96 minutes + FWISO Subproblem: 3: d(5): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 436668.03 + + iteration: 5 PROBLEM Number: 4 + FWISO problem 4: d(5) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.77 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 129316 + Prä-Residuumnorm: 732712.44 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 539234.47 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.96 seconds + Inner Loop: : InnerCG resNorm : 582141.32 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.35 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.00 seconds + Inner Loop: : InnerCG resNorm : 522178.37 + Inner Loop: : Time needed for inner loop: 2:15.52 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:15.52 minutes + Residuumnorm 1: 522178.37 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.28 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.16 seconds + Intermezzo Residuum: 522127.23 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 575870.09 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.38 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.95 seconds + PhiAdjSO: : 1:04.42 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.25 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.12 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.49 seconds + Inner Loop: : InnerCG resNorm : 485119.05 + Inner Loop: : Time needed for inner loop: 3:32.41 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:32.41 minutes + FWISO Subproblem: 4: d(5): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 485119.05 + + iteration: 5 PROBLEM Number: 5 + FWISO problem 5: d(5) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.59 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 129449 + Prä-Residuumnorm: 556007.4 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 411242.09 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.97 seconds + Inner Loop: : InnerCG resNorm : 477425.11 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.41 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.68 seconds + Inner Loop: : InnerCG resNorm : 437404.17 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.36 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.10 seconds + Inner Loop: : InnerCG resNorm : 379300.72 + Inner Loop: : Time needed for inner loop: 3:31.18 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:31.18 minutes + Residuumnorm 1: 379300.72 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.00 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.98 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.57 seconds + Intermezzo Residuum: 379192.84 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 439042.46 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.06 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.02 seconds + PhiAdjSO: : 1:04.61 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.93 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.46 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.83 seconds + Inner Loop: : InnerCG resNorm : 350108.25 + Inner Loop: : Time needed for inner loop: 3:45.67 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:45.67 minutes + FWISO Subproblem: 5: d(5): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 350108.25 + + + Iteration Main Looop Counting Variable iter: 6 + + iteration: 6 PROBLEM Number: 0 + FWISO problem 0: d(6) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.25 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 129541 + Prä-Residuumnorm: 513945.83 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 373079.12 und m_max 7 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.37 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.84 seconds + Inner Loop: : InnerCG resNorm : 473514.3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.36 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.64 seconds + Inner Loop: : InnerCG resNorm : 443263.6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.35 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.23 seconds + Inner Loop: : InnerCG resNorm : 408237.38 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.34 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.38 seconds + Inner Loop: : InnerCG resNorm : 367396 + Inner Loop: : Time needed for inner loop: 4:41.16 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen + Inner Loop: : 4:41.16 minutes + Residuumnorm 1: 367396 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.08 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.99 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.26 seconds + Intermezzo Residuum: 367357.33 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 347334.98 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.11 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + PhiAdjSO: : 1:04.36 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.99 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.21 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.89 seconds + Inner Loop: : InnerCG resNorm : 350928.58 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.18 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.10 seconds + PhiAdjSO: : 1:04.59 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.94 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.73 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.72 seconds + Inner Loop: : InnerCG resNorm : 331968.01 + Inner Loop: : Time needed for inner loop: 7:32.20 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:32.20 minutes + FWISO Subproblem: 0: d(6): Finished first / second inner loop ( 4, 2 steps ) + ************************************* + Residuumnorm 2: 331968.01 + + iteration: 6 PROBLEM Number: 1 + FWISO problem 1: d(6) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.97 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 129637 + Prä-Residuumnorm: 756810.27 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 522375.35 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.41 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.08 seconds + Inner Loop: : InnerCG resNorm : 571619.12 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.37 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.19 seconds + Inner Loop: : InnerCG resNorm : 491739.47 + Inner Loop: : Time needed for inner loop: 2:15.88 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:15.88 minutes + Residuumnorm 1: 491739.47 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.74 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.70 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.82 seconds + Intermezzo Residuum: 491627.92 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 511111.33 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.79 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.02 seconds + PhiAdjSO: : 1:04.43 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.27 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.72 seconds + Inner Loop: : InnerCG resNorm : 448885.91 + Inner Loop: : Time needed for inner loop: 3:33.56 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:33.56 minutes + FWISO Subproblem: 1: d(6): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 448885.91 + + iteration: 6 PROBLEM Number: 2 + FWISO problem 2: d(6) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.05 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 129683 + Prä-Residuumnorm: 711778.91 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 579460.9 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.55 seconds + Inner Loop: : InnerCG resNorm : 557356.59 + Inner Loop: : Time needed for inner loop: 1:06.36 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:06.36 minutes + Residuumnorm 1: 557356.59 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.18 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.12 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.72 seconds + Intermezzo Residuum: 557428.59 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 477986.73 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.21 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + PhiAdjSO: : 1:04.42 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.12 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.45 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.99 seconds + Inner Loop: : InnerCG resNorm : 506381.07 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.30 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.08 seconds + PhiAdjSO: : 1:04.53 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.11 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.51 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.05 seconds + Inner Loop: : InnerCG resNorm : 433000.59 + Inner Loop: : Time needed for inner loop: 6:57.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:57.00 minutes + FWISO Subproblem: 2: d(6): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 433000.59 + + iteration: 6 PROBLEM Number: 3 + FWISO problem 3: d(6) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.67 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 129819 + Prä-Residuumnorm: 670940.78 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 520892.24 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.13 seconds + Inner Loop: : InnerCG resNorm : 566730.72 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.13 seconds + Inner Loop: : InnerCG resNorm : 472967.47 + Inner Loop: : Time needed for inner loop: 2:11.88 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:11.88 minutes + Residuumnorm 1: 472967.47 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.60 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.13 seconds + Intermezzo Residuum: 472983.7 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 467018.72 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.63 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.04 seconds + PhiAdjSO: : 1:04.50 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.54 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.17 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.48 seconds + Inner Loop: : InnerCG resNorm : 437994.45 + Inner Loop: : Time needed for inner loop: 3:25.04 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:25.04 minutes + FWISO Subproblem: 3: d(6): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 437994.45 + + iteration: 6 PROBLEM Number: 4 + FWISO problem 4: d(6) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.72 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 129865 + Prä-Residuumnorm: 678610.42 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 589014.45 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.40 seconds + Inner Loop: : InnerCG resNorm : 544184.4 + Inner Loop: : Time needed for inner loop: 1:07.19 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:07.19 minutes + Residuumnorm 1: 544184.4 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.38 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.36 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.14 seconds + Intermezzo Residuum: 544151.18 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 480014.1 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.35 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.97 seconds + PhiAdjSO: : 1:04.45 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.19 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.13 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.49 seconds + Inner Loop: : InnerCG resNorm : 489270.2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.43 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.18 seconds + PhiAdjSO: : 1:04.71 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.23 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.81 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.43 seconds + Inner Loop: : InnerCG resNorm : 401083.19 + Inner Loop: : Time needed for inner loop: 7:07.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:07.00 minutes + FWISO Subproblem: 4: d(6): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 401083.19 + + iteration: 6 PROBLEM Number: 5 + FWISO problem 5: d(6) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.75 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 130003 + Prä-Residuumnorm: 514708.67 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 425366.99 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.85 seconds + Inner Loop: : InnerCG resNorm : 458409.06 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.72 seconds + Inner Loop: : InnerCG resNorm : 406465.59 + Inner Loop: : Time needed for inner loop: 2:21.18 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:21.18 minutes + Residuumnorm 1: 406465.59 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.76 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.70 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.67 seconds + Intermezzo Residuum: 406448.32 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 365788.42 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.73 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.00 seconds + PhiAdjSO: : 1:04.60 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.58 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.81 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.53 seconds + Inner Loop: : InnerCG resNorm : 378585.17 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.73 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.18 seconds + PhiAdjSO: : 1:04.84 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.71 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.06 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.80 seconds + Inner Loop: : InnerCG resNorm : 353712.41 + Inner Loop: : Time needed for inner loop: 7:34.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:34.00 minutes + FWISO Subproblem: 5: d(6): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 353712.41 + + + Iteration Main Looop Counting Variable iter: 7 + + iteration: 7 PROBLEM Number: 0 + FWISO problem 0: d(7) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.11 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 130096 + Prä-Residuumnorm: 477699.83 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 312090.96 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.34 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.99 seconds + Inner Loop: : InnerCG resNorm : 417882.07 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.37 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.41 seconds + Inner Loop: : InnerCG resNorm : 369289.16 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.34 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.32 seconds + Inner Loop: : InnerCG resNorm : 348403.77 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.32 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.48 seconds + Inner Loop: : InnerCG resNorm : 322449.74 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.34 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.74 seconds + Inner Loop: : InnerCG resNorm : 304713.18 + Inner Loop: : Time needed for inner loop: 5:54.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen + Inner Loop: : 5:54.00 minutes + Residuumnorm 1: 304713.18 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.29 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.32 seconds + Intermezzo Residuum: 304651.54 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 400269.51 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.32 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.01 seconds + PhiAdjSO: : 1:04.45 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.23 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.25 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.76 seconds + Inner Loop: : InnerCG resNorm : 294288.95 + Inner Loop: : Time needed for inner loop: 3:46.76 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:46.76 minutes + FWISO Subproblem: 0: d(7): Finished first / second inner loop ( 5, 1 steps ) + ************************************* + Residuumnorm 2: 294288.95 + + iteration: 7 PROBLEM Number: 1 + FWISO problem 1: d(7) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.11 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 130172 + Prä-Residuumnorm: 670928.07 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 567012.35 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.06 seconds + Inner Loop: : InnerCG resNorm : 525941.54 + Inner Loop: : Time needed for inner loop: 1:07.89 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:07.89 minutes + Residuumnorm 1: 525941.54 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.90 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.88 seconds + Intermezzo Residuum: 525948.15 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 407799.75 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.92 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.00 seconds + PhiAdjSO: : 1:04.45 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.80 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.25 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.01 seconds + Inner Loop: : InnerCG resNorm : 462019.34 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.96 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.13 seconds + PhiAdjSO: : 1:04.74 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.77 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.28 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.66 seconds + Inner Loop: : InnerCG resNorm : 383268.62 + Inner Loop: : Time needed for inner loop: 7:11.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:11.00 minutes + FWISO Subproblem: 1: d(7): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 383268.62 + + iteration: 7 PROBLEM Number: 2 + FWISO problem 2: d(7) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.00 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 130286 + Prä-Residuumnorm: 688988.82 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 504816.69 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.35 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.51 seconds + Inner Loop: : InnerCG resNorm : 523419.12 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.34 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.18 seconds + Inner Loop: : InnerCG resNorm : 464434.86 + Inner Loop: : Time needed for inner loop: 2:12.19 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:12.19 minutes + Residuumnorm 1: 464434.86 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.24 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.30 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.76 seconds + Intermezzo Residuum: 464391.77 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 575835.57 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.30 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + PhiAdjSO: : 1:04.43 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.45 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.72 seconds + Inner Loop: : InnerCG resNorm : 431976.3 + Inner Loop: : Time needed for inner loop: 3:26.88 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:26.88 minutes + FWISO Subproblem: 2: d(7): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 431976.3 + + iteration: 7 PROBLEM Number: 3 + FWISO problem 3: d(7) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.70 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 130357 + Prä-Residuumnorm: 631330.33 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 441126.21 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.35 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.22 seconds + Inner Loop: : InnerCG resNorm : 538803.84 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.96 seconds + Inner Loop: : InnerCG resNorm : 461800.67 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.34 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.08 seconds + Inner Loop: : InnerCG resNorm : 402751.6 + Inner Loop: : Time needed for inner loop: 3:17.57 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:17.57 minutes + Residuumnorm 1: 402751.6 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.51 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.52 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.18 seconds + Intermezzo Residuum: 402810 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 395502.53 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.56 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.05 seconds + PhiAdjSO: : 1:04.54 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.47 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.18 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.64 seconds + Inner Loop: : InnerCG resNorm : 379078.07 + Inner Loop: : Time needed for inner loop: 3:25.06 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:25.06 minutes + FWISO Subproblem: 3: d(7): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 379078.07 + + iteration: 7 PROBLEM Number: 4 + FWISO problem 4: d(7) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.61 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 130447 + Prä-Residuumnorm: 596920.69 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 466299.08 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.34 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.67 seconds + Inner Loop: : InnerCG resNorm : 472972.65 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.35 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.93 seconds + Inner Loop: : InnerCG resNorm : 430380.21 + Inner Loop: : Time needed for inner loop: 2:15.11 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:15.11 minutes + Residuumnorm 1: 430380.21 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.28 seconds + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.10 seconds + Intermezzo Residuum: 430314.94 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 509575.83 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.31 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.00 seconds + PhiAdjSO: : 1:04.40 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.21 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.07 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.64 seconds + Inner Loop: : InnerCG resNorm : 404805.31 + Inner Loop: : Time needed for inner loop: 3:32.32 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:32.32 minutes + FWISO Subproblem: 4: d(7): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 404805.31 + + iteration: 7 PROBLEM Number: 5 + FWISO problem 5: d(7) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.84 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 130580 + Prä-Residuumnorm: 508241.42 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 378020.07 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.36 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.70 seconds + Inner Loop: : InnerCG resNorm : 429658 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.34 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.58 seconds + Inner Loop: : InnerCG resNorm : 395217.92 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.29 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.37 seconds + Inner Loop: : InnerCG resNorm : 333771.14 + Inner Loop: : Time needed for inner loop: 3:33.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:33.00 minutes + Residuumnorm 1: 333771.14 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.21 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.21 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.27 seconds + Intermezzo Residuum: 333660.83 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 434716.87 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.29 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.00 seconds + PhiAdjSO: : 1:04.50 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.17 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.14 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.36 seconds + Inner Loop: : InnerCG resNorm : 305464.48 + Inner Loop: : Time needed for inner loop: 3:45.19 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:45.19 minutes + FWISO Subproblem: 5: d(7): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 305464.48 + + + Iteration Main Looop Counting Variable iter: 8 + + iteration: 8 PROBLEM Number: 0 + FWISO problem 0: d(8) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.39 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 130673 + Prä-Residuumnorm: 435103.37 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 314430.14 und m_max 9 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.35 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.86 seconds + Inner Loop: : InnerCG resNorm : 376485.18 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.36 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.58 seconds + Inner Loop: : InnerCG resNorm : 327159.6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.34 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.49 seconds + Inner Loop: : InnerCG resNorm : 308882.68 + Inner Loop: : Time needed for inner loop: 3:31.23 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:31.23 minutes + Residuumnorm 1: 308882.68 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.32 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.37 seconds + Intermezzo Residuum: 308875.85 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 328119.77 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.40 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + PhiAdjSO: : 1:04.39 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.67 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.20 seconds + Inner Loop: : InnerCG resNorm : 299034.51 + Inner Loop: : Time needed for inner loop: 3:46.68 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:46.68 minutes + FWISO Subproblem: 0: d(8): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 299034.51 + + iteration: 8 PROBLEM Number: 1 + FWISO problem 1: d(8) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.13 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 130723 + Prä-Residuumnorm: 529691.6 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 402885.98 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.34 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.97 seconds + Inner Loop: : InnerCG resNorm : 435287.87 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.33 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.27 seconds + Inner Loop: : InnerCG resNorm : 370673.59 + Inner Loop: : Time needed for inner loop: 2:15.75 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:15.75 minutes + Residuumnorm 1: 370673.59 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.87 seconds + Initialization: 0.31 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.77 seconds + Intermezzo Residuum: 370613.04 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 425822.9 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.89 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + PhiAdjSO: : 1:04.31 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.84 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.23 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.70 seconds + Inner Loop: : InnerCG resNorm : 345279.54 + Inner Loop: : Time needed for inner loop: 3:33.68 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:33.68 minutes + FWISO Subproblem: 1: d(8): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 345279.54 + + iteration: 8 PROBLEM Number: 2 + FWISO problem 2: d(8) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.07 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 130814 + Prä-Residuumnorm: 590124.48 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 511252.02 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.42 seconds + Inner Loop: : InnerCG resNorm : 472537.79 + Inner Loop: : Time needed for inner loop: 1:06.21 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:06.21 minutes + Residuumnorm 1: 472537.79 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.17 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.13 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.81 seconds + Intermezzo Residuum: 472561.61 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 443887.02 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.10 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.94 seconds + PhiAdjSO: : 1:04.34 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.10 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.66 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.09 seconds + Inner Loop: : InnerCG resNorm : 426190.61 + Inner Loop: : Time needed for inner loop: 3:26.98 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:26.98 minutes + FWISO Subproblem: 2: d(8): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 426190.61 + + iteration: 8 PROBLEM Number: 3 + FWISO problem 3: d(8) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.70 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 130906 + Prä-Residuumnorm: 534196.72 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 426903.26 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.36 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.14 seconds + Inner Loop: : InnerCG resNorm : 466128.13 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.33 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.06 seconds + Inner Loop: : InnerCG resNorm : 403499.06 + Inner Loop: : Time needed for inner loop: 2:11.72 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:11.72 minutes + Residuumnorm 1: 403499.06 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.90 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.49 seconds + Intermezzo Residuum: 403499.66 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 301187.08 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.95 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.99 seconds + PhiAdjSO: : 1:04.41 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.88 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.38 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.56 seconds + Inner Loop: : InnerCG resNorm : 379010.86 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.05 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.13 seconds + PhiAdjSO: : 1:04.61 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.31 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.70 seconds + Inner Loop: : InnerCG resNorm : 355338.96 + Inner Loop: : Time needed for inner loop: 6:52.05 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 6:52.05 minutes + FWISO Subproblem: 3: d(8): Finished first / second inner loop ( 2, 2 steps ) + ************************************* + Residuumnorm 2: 355338.96 + + iteration: 8 PROBLEM Number: 4 + FWISO problem 4: d(8) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.58 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 131019 + Prä-Residuumnorm: 555743.07 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 494937.63 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.41 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.50 seconds + Inner Loop: : InnerCG resNorm : 449815.14 + Inner Loop: : Time needed for inner loop: 1:07.33 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:07.33 minutes + Residuumnorm 1: 449815.14 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.33 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.29 seconds + Intermezzo Residuum: 449816.48 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 426981.2 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.40 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.06 seconds + PhiAdjSO: : 1:04.55 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.74 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.43 seconds + Inner Loop: : InnerCG resNorm : 404731.04 + Inner Loop: : Time needed for inner loop: 3:32.12 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:32.12 minutes + FWISO Subproblem: 4: d(8): Finished first / second inner loop ( 1, 1 steps ) + ************************************* + Residuumnorm 2: 404731.04 + + iteration: 8 PROBLEM Number: 5 + FWISO problem 5: d(8) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.86 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 131133 + Prä-Residuumnorm: 402358.28 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 333630.26 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.46 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.80 seconds + Inner Loop: : InnerCG resNorm : 364254.63 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.01 seconds + Inner Loop: : InnerCG resNorm : 335600.89 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.41 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.48 seconds + Inner Loop: : InnerCG resNorm : 293569.5 + Inner Loop: : Time needed for inner loop: 3:31.86 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:31.86 minutes + Residuumnorm 1: 293569.5 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.01 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.97 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 41.90 seconds + Intermezzo Residuum: 293529.39 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 309736.15 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.02 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.09 seconds + PhiAdjSO: : 1:04.67 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.98 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.42 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.38 seconds + Inner Loop: : InnerCG resNorm : 274104.46 + Inner Loop: : Time needed for inner loop: 3:45.15 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:45.15 minutes + FWISO Subproblem: 5: d(8): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 274104.46 + + + Iteration Main Looop Counting Variable iter: 9 + + iteration: 9 PROBLEM Number: 0 + FWISO problem 0: d(9) + shot: 0: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.21 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 131223 + Prä-Residuumnorm: 382239.24 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 248604.79 und m_max 8 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.45 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.02 seconds + Inner Loop: : InnerCG resNorm : 349607.67 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.44 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.54 seconds + Inner Loop: : InnerCG resNorm : 311590.98 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.40 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.70 seconds + Inner Loop: : InnerCG resNorm : 291827.25 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.40 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.26 seconds + Inner Loop: : InnerCG resNorm : 271086.01 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.41 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.66 seconds + Inner Loop: : InnerCG resNorm : 260385.35 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.70 seconds + Inner Loop: : InnerCG resNorm : 243826.76 + Inner Loop: : Time needed for inner loop: 7:05.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 6 = m innere Iterationen + Inner Loop: : 7:05.00 minutes + Residuumnorm 1: 243826.76 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.92 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.88 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.38 seconds + Intermezzo Residuum: 243778.23 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 259428.52 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.96 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.07 seconds + PhiAdjSO: : 1:04.49 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.86 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.87 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.94 seconds + Inner Loop: : InnerCG resNorm : 233216.95 + Inner Loop: : Time needed for inner loop: 3:45.85 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:45.85 minutes + FWISO Subproblem: 0: d(9): Finished first / second inner loop ( 6, 1 steps ) + ************************************* + Residuumnorm 2: 233216.95 + + iteration: 9 PROBLEM Number: 1 + FWISO problem 1: d(9) + shot: 1: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.98 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 131272 + Prä-Residuumnorm: 554057.15 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 487737.84 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.94 seconds + Inner Loop: : InnerCG resNorm : 441913 + Inner Loop: : Time needed for inner loop: 1:07.78 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen + Inner Loop: : 1:07.78 minutes + Residuumnorm 1: 441913 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.90 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.92 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.69 seconds + Intermezzo Residuum: 441957 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 400869.49 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.96 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.00 seconds + PhiAdjSO: : 1:04.49 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.89 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.20 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.82 seconds + Inner Loop: : InnerCG resNorm : 404702.18 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.95 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.14 seconds + PhiAdjSO: : 1:04.67 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.85 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.18 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.72 seconds + Inner Loop: : InnerCG resNorm : 340597.52 + Inner Loop: : Time needed for inner loop: 7:11.00 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen + Inner Loop: : 7:11.00 minutes + FWISO Subproblem: 1: d(9): Finished first / second inner loop ( 1, 2 steps ) + ************************************* + Residuumnorm 2: 340597.52 + + iteration: 9 PROBLEM Number: 2 + FWISO problem 2: d(9) + shot: 2: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.95 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 131386 + Prä-Residuumnorm: 618929.07 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 482586.09 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.48 seconds + Inner Loop: : InnerCG resNorm : 487660.72 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.40 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.14 seconds + Inner Loop: : InnerCG resNorm : 426542.82 + Inner Loop: : Time needed for inner loop: 2:12.25 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:12.25 minutes + Residuumnorm 1: 426542.82 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.23 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.24 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.69 seconds + Intermezzo Residuum: 426509.84 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 418998.25 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.28 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.06 seconds + PhiAdjSO: : 1:04.49 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.21 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.46 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.71 seconds + Inner Loop: : InnerCG resNorm : 396522.8 + Inner Loop: : Time needed for inner loop: 3:26.85 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:26.85 minutes + FWISO Subproblem: 2: d(9): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 396522.8 + + iteration: 9 PROBLEM Number: 3 + FWISO problem 3: d(9) + shot: 3: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.68 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 131459 + Prä-Residuumnorm: 511841.96 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 368134.62 und m_max 5 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.41 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.18 seconds + Inner Loop: : InnerCG resNorm : 449536.54 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.40 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.09 seconds + Inner Loop: : InnerCG resNorm : 389092.84 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.38 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.10 seconds + Inner Loop: : InnerCG resNorm : 351607.98 + Inner Loop: : Time needed for inner loop: 3:17.79 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:17.79 minutes + Residuumnorm 1: 351607.98 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.57 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.56 seconds + Initialization: 0.30 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.07 seconds + Intermezzo Residuum: 351614.55 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 400212.57 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.69 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.05 seconds + PhiAdjSO: : 1:04.51 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.50 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.18 seconds + Initialization: 0.26 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.67 seconds + Inner Loop: : InnerCG resNorm : 334319.47 + Inner Loop: : Time needed for inner loop: 3:25.22 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:25.22 minutes + FWISO Subproblem: 3: d(9): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 334319.47 + + iteration: 9 PROBLEM Number: 4 + FWISO problem 4: d(9) + shot: 4: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.64 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 131615 + Prä-Residuumnorm: 574002.79 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 460079.55 und m_max 3 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.42 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.39 seconds + Inner Loop: : InnerCG resNorm : 463134.93 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.39 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.05 seconds + Inner Loop: : InnerCG resNorm : 393061.73 + Inner Loop: : Time needed for inner loop: 2:15.08 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen + Inner Loop: : 2:15.08 minutes + Residuumnorm 1: 393061.73 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.66 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.66 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.06 seconds + Intermezzo Residuum: 393037.56 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 396909.25 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.68 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.06 seconds + PhiAdjSO: : 1:04.59 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.59 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.19 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 37.79 seconds + Inner Loop: : InnerCG resNorm : 362172.38 + Inner Loop: : Time needed for inner loop: 3:33.54 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:33.54 minutes + FWISO Subproblem: 4: d(9): Finished first / second inner loop ( 2, 1 steps ) + ************************************* + Residuumnorm 2: 362172.38 + + iteration: 9 PROBLEM Number: 5 + FWISO problem 5: d(9) + shot: 5: Solving forward problem... + Initialization: 0.32 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.76 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 131744 + Prä-Residuumnorm: 404916.13 + Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 302176.08 und m_max 6 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.41 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.87 seconds + Inner Loop: : InnerCG resNorm : 367846.71 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.37 seconds + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.85 seconds + Inner Loop: : InnerCG resNorm : 328378.13 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.36 seconds + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.06 seconds + Inner Loop: : InnerCG resNorm : 288747.2 + Inner Loop: : Time needed for inner loop: 3:31.15 minutes + Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen + Inner Loop: : 3:31.15 minutes + Residuumnorm 1: 288747.2 + ----- Intermezzo: Change Operators and Recalculate Residuum ----- + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.83 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.82 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 42.11 seconds + Intermezzo Residuum: 288688.1 + ----- Intermezzo Ende ----- + Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 280534.67 und m_max 2 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.80 seconds + PhiAdjSO: : Starting ImplicitMidpointRule (Order=2) + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.03 seconds + PhiAdjSO: : 1:04.56 minutes + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.77 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.14 seconds + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 40.65 seconds + Inner Loop: : InnerCG resNorm : 268227.97 + Inner Loop: : Time needed for inner loop: 3:44.62 minutes + Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen + Inner Loop: : 3:44.62 minutes + FWISO Subproblem: 5: d(9): Finished first / second inner loop ( 3, 1 steps ) + ************************************* + Residuumnorm 2: 268227.97 + FWISO: d(10)= 0 + 26143792 + 6250155.6 + 2317102.5 + 1375939.1 + 954529.66 + 750053.45 + 513945.83 + 477699.83 + 435103.37 + 382239.24 + + + 19850061 + 4694237.1 + 2756891.4 + 1578800.4 + 1054481.3 + 801849.51 + 756810.27 + 670928.07 + 529691.6 + 554057.15 + + + 19118047 + 4121336.6 + 1975958.7 + 1334927.5 + 1066359.5 + 861998.24 + 711778.91 + 688988.82 + 590124.48 + 618929.07 + + + 10423303 + 3649756.9 + 1589865 + 1214638 + 993358.32 + 801531 + 670940.78 + 631330.33 + 534196.72 + 511841.96 + + + 4322132.1 + 1780992.3 + 1493070.3 + 1189150.5 + 977666.36 + 732712.44 + 678610.42 + 596920.69 + 555743.07 + 574002.79 + + + 4308252 + 1853808.1 + 889354.95 + 744770.65 + 649694.43 + 556007.4 + 514708.67 + 508241.42 + 402358.28 + 404916.13 + + +end program after 9:44:59.00 hours on 128 procs at Fri Jun 30 20:53:35 2023 diff --git a/log/2023_06_30_MultiHighRes_SO/testconf.conf b/log/2023_06_30_MultiHighRes_SO/testconf.conf new file mode 100644 index 0000000000000000000000000000000000000000..423aa94008cf3769d945302bab2038128895d3ad --- /dev/null +++ b/log/2023_06_30_MultiHighRes_SO/testconf.conf @@ -0,0 +1,108 @@ +# Regular Expression um aus Test_Config von Clion eine ... M++ Config zu machen +# \{"([A-Za-z0-9_ ]+)", +"([A-Za-z0-9_ ,\.\-]+)"}. + +#Durchlauf 2023Mai05 mit 4 Quellen, 8 Iterationen, Materialpunkt, level 1 (Ergebnisse ganz gut) +#Durchlauf 2023Mai05 mit 4 Quellen, 8 Iterationen, TwoMedium, level 1 +#Back to FastMode (2 Quellen, 2 Iterationen, Pkt.Material, level 0) +#21.06 Receiver wieder auf 64. Bei multi noch nicht, jetzt aber bei rho rekonstruktion +#Neuer größerer Durchlauf 26.Juni Ohne Inverse Crime für Vp + + #ReconstructionType=Classical; + #FWINonlinearSolver= FWI_mSDREGINN; + + + #Problem= VAcousticWaveTwoMedium;//<----- Geometrie oder so Siehe: src/Problems/FWIInversionProblems.cpp + Problem= VAcousticWaveC2Benchmark; + FWISO_Steps = 10; #Anzahl Iterationen + Monoparam= multi; #can be "multi"/empty or "Vp", "Tau_p", "Rho" + plot_tStep= -1; + level = 3;#3 nicht auf Laptop starten, sonst stürzt ab + T=0.6; + dt= 0.0005; + FWISourceCount0=6; #Anzahl Quellen, Empfänger default 64 + deg = 2; #In paper CRC deg = 2. Vor 26.Juni2023 wars 1 + FWIReconstructRho= 1; + FWIReconstructV_P= 1; + FWIReconstructTauP= 0; + + #seismopath = C2NoDampingT06dt0005/C2NoDampingT06dt0005;#im Build Ordner! + #ReadFormat = FWI;#IFOS ist falsches Format. + #SpecfileNrOfSamples = 6; + + SaveObservedSeismogram = 0;#Plottet "d_obs", das Vorwärtsgelöste Wellenfeld (mit echten Materialparam) + + SignalName=Ricker;#RickerDerivative vorher!!! Geändert 26.Juni.2023 + ReconstructionType=SO;#!!! + FWINonlinearSolver= FWISO;#!!! + numL=0;#!!! + + + + ConfigVerbose=2; + ForwardSolver= VADGTS; + Distribution= RCB; + Model = FWIInverse_DGTS; + Mesh= SeismogramGrid_test; + + useTaper=1; + taperRadiusSource=0; + taperRadiusReceiver=0; + taperExponent=-0.1; + taperIgnoreReceiverCells=1; + taperIgnoreSourceCells=1; + #Monoparam= Rho; #can be "multi"/empty or "Vp", "Tau_p", "Rho" + #ReconstructionType=SO;#!!! + FWIReceiverWaypoints= 2; + FWIReceiverWaypoint0= 1350.0, 370.0; + FWIReceiverWaypoint1= 1350.0, 1630.0; + FWIReceiverIncludeLastWaypoint= 1; + FWIReceiverCount0= 64;//Anzahl Receiver + UseSparseMatrix=1; + Qfactor=100; + #SignalName=Ricker;# RickerDerivative vorher!!! Geändert 26.Juni.2023 + SignalDelay=0; + SignalCutoff=0.8; + SignalFreq=25; + #numL=0;#!!! + FWISourceWaypoints=2; + FWISourceWaypoint0=600,370; + FWISourceWaypoint1=600,1620; + #FWISourceCount0=2; #Anzahl Quelle + #FWISourceCount0=2; + FWIReceiverIncludeLastWaypoint=1; + measurement_space= point; + measurement_time= point; + compMeasure= 0; + source_component= 2; + perturbation_comp= 2; + dampingFlux= 1; + allowPlotting_M=1; + allowPlotting_WF=0; + plotfactor= 10; + parametrization= taup;#!!!! + #T=0.6; + #dt= 0.002; + #deg= 1; + #level = 0;#Feinheit des Gitters (1 mehr -> Halbierung)//Achtung: 3 Böse, <2 Gut + TimeVerbose= 1; + rkorder= -2; + #plot_tStep= -1; + #FWISO_Steps = 2;//scheint zu klappen! + Steps = 2;//scheint auch nichts zu bringen :( + + Kmax=150; + Keps= 1e-07; + Overlap= dG1; + debugAdjoint= 0; + debugFrechet= 1; + source_factor= 242574257420000.5742; + LinearSolver= LS;#Könnte man auf GMRES (Schreibweise?) ändern.. + LinearVerbose= -1; + LinearSteps=100; + LinearNthIterOutput= 1; + LinearEpsilon= 1e-12; + LinearReduction= 0.0001; + #FWINonlinearSolver= FWI_mSDREGINN; + FWI_DebugPlottingLevel= 1; + CGREGINNCanonic_Steps=3; + diff --git a/log/2023_07_06_Multi_FO_Iter10/RunMpp.sh b/log/2023_07_06_Multi_FO_Iter10/RunMpp.sh new file mode 100644 index 0000000000000000000000000000000000000000..d3bcf67bed8989e7cf1531f7b537bdde02fe53f6 --- /dev/null +++ b/log/2023_07_06_Multi_FO_Iter10/RunMpp.sh @@ -0,0 +1,29 @@ +#!/bin/sh +### Job name +#SBATCH --job-name=MppFWILennart + +### File for the output +##vorher#SBATCH --output=Mpp%A ??????? +#SBATCH --output=Mpp%A + +### Time your job needs to execute +#SBATCH --time=222:00:00 + +### Use more than one node for parallel jobs on distributed-memory systems +###CR Version war 2, 4 geht, sofern genug frei. +#SBATCH --nodes=8 +###SBATCH --nodes=1 + +### Number of CPUS per task +#SBATCH --cpus-per-task=1 + +### Disable hyperthreading by setting the tasks per core to 1 +#SBATCH --ntasks-per-core=1 + +#SBATCH --mail-type=ALL + +#SBATCH --mail-user=uuwyh@student.kit.edu + +### Number of processes per node, in our case +#SBATCH --ntasks-per-node=16 +mpirun M++ diff --git a/log/2023_07_06_Multi_FO_Iter10/logfile.log b/log/2023_07_06_Multi_FO_Iter10/logfile.log new file mode 100644 index 0000000000000000000000000000000000000000..de28013113c6cd77c10f845aa455c2aba2bf7626 --- /dev/null +++ b/log/2023_07_06_Multi_FO_Iter10/logfile.log @@ -0,0 +1,4333 @@ +start program on 128 procs at Wed Jul 5 15:52:50 2023 +Running on: node01 + reading config: ConfigVerbose........................... 2 + reading default: enableFileLogging....................... 1 + reading default: enableScreenLogging..................... 1 + reading default: precision............................... 8 + reading default: TimeLevel............................... 0 + reading config: Model................................... FWIInverse_DGTS + reading default: testAAO................................. 0 + reading config: ForwardSolver........................... VADGTS + reading config: ReconstructionType...................... Classical + reading config: Mesh.................................... SeismogramGrid_test + reading config: level................................... 3 + reading default: plevel.................................. 3 + reading default: clevel.................................. 3 + reading config: Distribution............................ RCB + reading config: Overlap................................. dG1 + reading default: Scales.................................. 0 + reading default: CommSplit............................... 0 + reading default: DistributionVerbose..................... 0 + reading default: ClearDistribution....................... 1 + reading default: MeshesVerbose........................... 1 + reading default: MeshVerbose............................. 1 + Overlap: reading default: OverlapVerbose.......................... 0 + reading default: t0...................................... 0 + reading config: dt...................................... 0.0005 + reading config: T....................................... 0.6 + reading config: rkorder................................. -2 + reading config: SignalName.............................. Ricker + reading default: FrequencyFiltering...................... 0 + reading config: SignalFreq.............................. 25 + reading default: f_source................................ 25 + reading default: SourceInversion......................... 0 + reading config: SignalCutoff............................ 0.8 + reading config: SignalDelay............................. 0 + reading default: SaveFilteredSeismogram.................. 0 + reading config: SaveObservedSeismogram.................. 0 + reading config: numL.................................... 0 + reading default: dim..................................... 2 + reading config: Problem................................. VAcousticWaveC2Benchmark + reading default: RealDataLevel........................... 3 + reading default: InitialIterateLevel..................... 3 + reading config: deg..................................... 2 + reading config: parametrization......................... taup + reading default: shots................................... -1 + reading default: SourceStartX............................ -1e+100 + reading default: SourceStartY............................ -1e+100 + reading default: SourceEndX.............................. -1e+100 + reading default: SourceEndY.............................. -1e+100 + reading default: numberOfSourcesPerShot.................. 1 + reading config: FWISourceWaypoints...................... 2 + reading default: FWISourceIncludeLastWaypoint............ 1 + FWISourceCount0 + reading config: FWISourceCount0......................... 6 + reading config: FWISourceWaypoint0...................... 600,370 + FWISourceCount1 + reading config: FWISourceWaypoint1...................... 600,1620 + SOURCE LOCATIONS: + 0: ( 600.00000000, 370.00000000) + + + 1: ( 600.00000000, 620.00000000) + + + 2: ( 600.00000000, 870.00000000) + + + 3: ( 600.00000000, 1120) + + + 4: ( 600.00000000, 1370) + + + 5: ( 600.00000000, 1620) + + + reading config: source_factor........................... 242574257420000.5742 + reading config: Monoparam............................... multi + monoparam = + multi + reading default: v_perturb............................... 1.05 + reading default: rho_perturb............................. 1.05 + reading default: tau_p_perturb........................... 4 + reading default: size_perturb............................ 200 + reading default: rho_bg.................................. 2000 + reading default: v_bg.................................... 3500 + reading default: tau_p_bg................................ 0.02 + reading default: impedance_bg............................ 1 + reading config: Qfactor................................. 100 + alphaValue = + 0 + reading default: FWIPrecon............................... 0 + reading default: FWIPreconType........................... 0 + reading default: FWIPreconRegularization................. 1e-08 + reading config: allowPlotting_M......................... 1 + reading config: allowPlotting_WF........................ 0 + reading default: plotFactor.............................. 1 + reading config: FWIReconstructRho....................... 1 + reading config: FWIReconstructV_P....................... 1 + reading config: FWIReconstructTauP...................... 0 + Mesh Info: + Mesh Name: ............................... SeismogramGrid_test + Distribution: ............................ RCB + Overlap: ................................. dG1 + CommSplit: ............................... 0 + Level: ................................... [3, -1, 0] + pLevel: .................................. 3 + Dimension: ............................... 2 + Cells: ................................... 87040 + Overlap: ................................. 21472 + Vertices: ................................ 98560 + Edges: ................................... 174672 + Faces: ................................... 218056 + ProcSets: ................................ 31900 + Mesh width [min, max]: ................... [12.500000, 29.474346] + + reading default: MatrixGraphVerbose...................... 0 + reading default: PaddingPML.............................. 0 + reading config: plot_tStep.............................. -1 + reading default: plotV................................... 0 + reading default: plot_rho................................ 1 + reading default: plot_kappa_0............................ 1 + reading default: plot_kappa_l............................ 0 + reading default: plot_velocity........................... 0 + reading config: compMeasure............................. 0 + Measure overall pressure p = p_0 + ... + p_L + reading default: Specfile................................ + reading config: FWIReceiverWaypoints.................... 2 + reading config: FWIReceiverIncludeLastWaypoint.......... 1 + FWIReceiverCount0 + reading config: FWIReceiverCount0....................... 64 + reading config: FWIReceiverWaypoint0.................... 1350.0, 370.0 + FWIReceiverCount1 + reading config: FWIReceiverWaypoint1.................... 1350.0, 1630.0 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + 0: ( 1350, 370.00000000) 1: ( 1350, 390.00000000) + 2: ( 1350, 410.00000000) 3: ( 1350, 430.00000000) + 4: ( 1350, 450.00000000) 5: ( 1350, 470.00000000) + 6: ( 1350, 490.00000000) 7: ( 1350, 510.00000000) + 8: ( 1350, 530.00000000) 9: ( 1350, 550.00000000) + 10: ( 1350, 570.00000000) 11: ( 1350, 590.00000000) + 12: ( 1350, 610.00000000) 13: ( 1350, 630.00000000) + 14: ( 1350, 650.00000000) 15: ( 1350, 670.00000000) + 16: ( 1350, 690.00000000) 17: ( 1350, 710.00000000) + 18: ( 1350, 730.00000000) 19: ( 1350, 750.00000000) + 20: ( 1350, 770.00000000) 21: ( 1350, 790.00000000) + 22: ( 1350, 810.00000000) 23: ( 1350, 830.00000000) + 24: ( 1350, 850.00000000) 25: ( 1350, 870.00000000) + 26: ( 1350, 890.00000000) 27: ( 1350, 910.00000000) + 28: ( 1350, 930.00000000) 29: ( 1350, 950.00000000) + 30: ( 1350, 970.00000000) 31: ( 1350, 990.00000000) + 32: ( 1350, 1010) 33: ( 1350, 1030) + 34: ( 1350, 1050) 35: ( 1350, 1070) + 36: ( 1350, 1090) 37: ( 1350, 1110) + 38: ( 1350, 1130) 39: ( 1350, 1150) + 40: ( 1350, 1170) 41: ( 1350, 1190) + 42: ( 1350, 1210) 43: ( 1350, 1230) + 44: ( 1350, 1250) 45: ( 1350, 1270) + 46: ( 1350, 1290) 47: ( 1350, 1310) + 48: ( 1350, 1330) 49: ( 1350, 1350) + 50: ( 1350, 1370) 51: ( 1350, 1390) + 52: ( 1350, 1410) 53: ( 1350, 1430) + 54: ( 1350, 1450) 55: ( 1350, 1470) + 56: ( 1350, 1490) 57: ( 1350, 1510) + 58: ( 1350, 1530) 59: ( 1350, 1550) + 60: ( 1350, 1570) 61: ( 1350, 1590) + 62: ( 1350, 1610) 63: ( 1350, 1630) + + reading default: UseGardener............................. 0 + reading default: MeasureComp............................. 0 + Measure overall pressure p = p_0 + ... + p_L + reading default: CountCellsOld........................... 0 + reading config: useTaper................................ 1 + reading default: TaperFromFile........................... + reading config: taperRadiusSource....................... 0 + reading default: taperBoxUpper........................... 1e+100 + reading default: taperBoxLower........................... -1e+100 + reading default: taperBoxLeft............................ -1e+100 + reading default: taperBoxRight........................... 1e+100 + reading config: taperRadiusReceiver..................... 0 + reading config: taperExponent........................... -0.1 + reading config: taperIgnoreSourceCells.................. 1 + reading config: taperIgnoreReceiverCells................ 1 + reading default: taperRhoMin............................. -1 + reading default: taperRhoMax............................. -1 + reading default: taperVpMin.............................. -1 + reading default: taperVpMax.............................. -1 + reading default: taperTaupMin............................ -1 + reading default: taperTaupMax............................ -1 + reading default: seismopath.............................. + reading default: PlotVerbose............................. 0 + reading default: PlotEnabled............................. 0 + reading default: PlotPrecision........................... 4 + Time before FWD->createRealData(real, obs); Wed Jul 5 15:52:55 2023 + Generating Real data for shot 0 + reading default: AssembleVerbose......................... 1 + reading default: startTime............................... 0 + reading default: endTime................................. 1 + reading default: maxStepSize............................. 1e+100 + reading default: stepSize................................ 0 + reading default: minStepSize............................. 0 + reading default: dt_min.................................. 0 + reading default: maxSteps................................ 0 + reading default: steps................................... 0 + reading default: K....................................... 0 + reading default: tEps.................................... 1e-15 + reading default: tTol.................................... 1e-06 + reading default: upwind.................................. 1 + reading config: dampingFlux............................. 1 + reading default: UseCollectTweak......................... 0 + reading default: Preconditioner_S........................ PointBlockJacobi + reading config: LinearSolver............................ LS + reading default: PreconditionerVerbose................... 0 + reading default: PreconditionerDamp...................... 1 + reading default: PointBlockJacobiLapack.................. 0 + reading config: LinearVerbose........................... -1 + reading config: LinearSteps............................. 100 + reading config: LinearEpsilon........................... 1e-12 + reading config: LinearReduction......................... 0.0001 + reading default: LinearMinimalStepNumber................. 0 + reading default: LinearPrintSteps........................ 800 + reading default: TimeIntegratorVerbose................... 1 + Initialization: 0.37 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.08 seconds + Generating Real data for shot 1 + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.64 seconds + Generating Real data for shot 2 + Initialization: 0.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.69 seconds + Generating Real data for shot 3 + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.36 seconds + Generating Real data for shot 4 + Initialization: 0.37 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.49 seconds + Generating Real data for shot 5 + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.46 seconds + Time after FWD->createRealData(real, obs); Wed Jul 5 15:55:56 2023 + FWISourceCount0 + FWISourceCount1 + SOURCE LOCATIONS: + 0: ( 600.00000000, 370.00000000) + + + 1: ( 600.00000000, 620.00000000) + + + 2: ( 600.00000000, 870.00000000) + + + 3: ( 600.00000000, 1120) + + + 4: ( 600.00000000, 1370) + + + 5: ( 600.00000000, 1620) + + + monoparam = + multi + alphaValue = + 0 + Frequency Filter to: -1 + + + Mesh Info: + Mesh Name: ............................... SeismogramGrid_test + Distribution: ............................ RCB + Overlap: ................................. dG1 + CommSplit: ............................... 0 + Level: ................................... [3, -1, 0] + pLevel: .................................. 3 + Dimension: ............................... 2 + Cells: ................................... 87040 + Overlap: ................................. 21472 + Vertices: ................................ 98560 + Edges: ................................... 174672 + Faces: ................................... 218056 + ProcSets: ................................ 31900 + Mesh width [min, max]: ................... [12.500000, 29.474346] + + Measure overall pressure p = p_0 + ... + p_L + FWIReceiverCount0 + FWIReceiverCount1 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.0005 + 0: ( 1350, 370.00000000) 1: ( 1350, 390.00000000) + 2: ( 1350, 410.00000000) 3: ( 1350, 430.00000000) + 4: ( 1350, 450.00000000) 5: ( 1350, 470.00000000) + 6: ( 1350, 490.00000000) 7: ( 1350, 510.00000000) + 8: ( 1350, 530.00000000) 9: ( 1350, 550.00000000) + 10: ( 1350, 570.00000000) 11: ( 1350, 590.00000000) + 12: ( 1350, 610.00000000) 13: ( 1350, 630.00000000) + 14: ( 1350, 650.00000000) 15: ( 1350, 670.00000000) + 16: ( 1350, 690.00000000) 17: ( 1350, 710.00000000) + 18: ( 1350, 730.00000000) 19: ( 1350, 750.00000000) + 20: ( 1350, 770.00000000) 21: ( 1350, 790.00000000) + 22: ( 1350, 810.00000000) 23: ( 1350, 830.00000000) + 24: ( 1350, 850.00000000) 25: ( 1350, 870.00000000) + 26: ( 1350, 890.00000000) 27: ( 1350, 910.00000000) + 28: ( 1350, 930.00000000) 29: ( 1350, 950.00000000) + 30: ( 1350, 970.00000000) 31: ( 1350, 990.00000000) + 32: ( 1350, 1010) 33: ( 1350, 1030) + 34: ( 1350, 1050) 35: ( 1350, 1070) + 36: ( 1350, 1090) 37: ( 1350, 1110) + 38: ( 1350, 1130) 39: ( 1350, 1150) + 40: ( 1350, 1170) 41: ( 1350, 1190) + 42: ( 1350, 1210) 43: ( 1350, 1230) + 44: ( 1350, 1250) 45: ( 1350, 1270) + 46: ( 1350, 1290) 47: ( 1350, 1310) + 48: ( 1350, 1330) 49: ( 1350, 1350) + 50: ( 1350, 1370) 51: ( 1350, 1390) + 52: ( 1350, 1410) 53: ( 1350, 1430) + 54: ( 1350, 1450) 55: ( 1350, 1470) + 56: ( 1350, 1490) 57: ( 1350, 1510) + 58: ( 1350, 1530) 59: ( 1350, 1550) + 60: ( 1350, 1570) 61: ( 1350, 1590) + 62: ( 1350, 1610) 63: ( 1350, 1630) + + Measure overall pressure p = p_0 + ... + p_L + reading default: loadInitialModelFromFile................ 0 + reading default: loadRealModelFromFile................... 0 + reading config: FWINonlinearSolver...................... FWI_CGREGINN + reading default: CGREGINNType............................ Canonic + reading default: FWI_MaxInnerLoopSteps_CGREGINN.......... 10 + reading default: FWI_Gamma_CGREGINN...................... 0.9 + reading default: FWI_Damping_CGREGINN.................... 1 + reading default: FWI_ThetaMax_CGREGINN................... 1 + reading default: FWI_ThetaInitial_CGREGINN............... 0.4 + reading default: FWI_RegularizationStrategy_CGREGINN..... 0 + reading default: CGREGINNCanonic_Verbose................. 1 + reading default: CGREGINNCanonic_Steps................... 10 + reading default: CGREGINNCanonic_LineSearchSteps......... 3 + reading default: CGREGINNCanonic_Epsilon................. 1e-10 + reading default: CGREGINNCanonic_Reduction............... 1e-05 + reading default: CGREGINNCanonic_MinimalStepNumber....... 0 + reading default: FWI_Precon.............................. 0 + reading default: FWI_HierarchyLevel...................... -1 + reading default: FWI_SaveAdjointWF....................... 0 + reading default: FWI_SaveSeis............................ 0 + reading config: FWI_DebugPlottingLevel.................. 1 + reading default: FWI_BacktrackingFactor.................. 0.5 + reading default: FWI_BacktrackingActivated............... 0 + Memory Usage at start31876 + reading default: WriteSeismoToFileEvery.................. 2147483647 + reading default: AAORecalculateWFEveryOuter.............. 1 + Initialize Subproblems 31880 + before get iterate 31887 + after get iterate 31887 + CGREGINNCanonic problem 0: d(0) + shot: 0: Solving forward problem... + Initialization: 0.36 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.07 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 32131 + state_comps = + 1 + after Defect 32136 + ************************************* + CGREGINNCanonic Subproblem 0: d(0): Starting inner loop ( ||r||_2 = 26143792, theta*||r||_2 = 26143792, theta = 1, m_max = 1 ) + Before innerstep 32136 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 0: d(0), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.37 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.6593217e+21 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.6593217e+21 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.6593217e+21 + CGREGINNCanonic Subproblem0: d(0), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.50 seconds + alpha = + 1.4530012e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 77256060 + after innerstep 44837 + CGREGINNCanonic Subproblem: 0: d(0), inner(0): ||r||_2 = 12571047 + CGREGINNCanonic Subproblem: 0: d(0): Finished inner loop ( 1 steps ) + ************************************* + reading default: PlotFactorIterates...................... 1 + reading default: PlotShot................................ -1 + Before finishIterate 44851 + After finishIterate 44851 + before get iterate 44851 + after get iterate 44851 + CGREGINNCanonic problem 1: d(0) + shot: 1: Solving forward problem... + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.70 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34424 + state_comps = + 1 + after Defect 34424 + ************************************* + CGREGINNCanonic Subproblem 1: d(0): Starting inner loop ( ||r||_2 = 21108721, theta*||r||_2 = 21108721, theta = 1, m_max = 1 ) + Before innerstep 34424 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 1: d(0), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.47 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.605969e+21 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.605969e+21 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.605969e+21 + CGREGINNCanonic Subproblem1: d(0), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.36 seconds + alpha = + 2.0461375e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 67236763 + after innerstep 44978 + CGREGINNCanonic Subproblem: 1: d(0), inner(0): ||r||_2 = 10932503 + CGREGINNCanonic Subproblem: 1: d(0): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 44990 + After finishIterate 44990 + before get iterate 44990 + after get iterate 44990 + CGREGINNCanonic problem 2: d(0) + shot: 2: Solving forward problem... + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.48 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34680 + state_comps = + 1 + after Defect 34680 + ************************************* + CGREGINNCanonic Subproblem 2: d(0): Starting inner loop ( ||r||_2 = 18612739, theta*||r||_2 = 18612739, theta = 1, m_max = 1 ) + Before innerstep 34680 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 2: d(0), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.13 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.142657e+21 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.142657e+21 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.142657e+21 + CGREGINNCanonic Subproblem2: d(0), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.56 seconds + alpha = + 2.4036545e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 66017635 + after innerstep 45054 + CGREGINNCanonic Subproblem: 2: d(0), inner(0): ||r||_2 = 8714648.1 + CGREGINNCanonic Subproblem: 2: d(0): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 45067 + After finishIterate 45067 + before get iterate 45067 + after get iterate 45067 + CGREGINNCanonic problem 3: d(0) + shot: 3: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.16 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34702 + state_comps = + 1 + after Defect 34702 + ************************************* + CGREGINNCanonic Subproblem 3: d(0): Starting inner loop ( ||r||_2 = 10115944, theta*||r||_2 = 10115944, theta = 1, m_max = 1 ) + Before innerstep 34702 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 3: d(0), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.66 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.7332069e+20 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.7332069e+20 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.7332069e+20 + CGREGINNCanonic Subproblem3: d(0), inner(0): Solving linearized forward problem + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.46 seconds + alpha = + 4.3310542e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 32511549 + after innerstep 45158 + CGREGINNCanonic Subproblem: 3: d(0), inner(0): ||r||_2 = 5252125.7 + CGREGINNCanonic Subproblem: 3: d(0): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 45170 + After finishIterate 45170 + before get iterate 45170 + after get iterate 45170 + CGREGINNCanonic problem 4: d(0) + shot: 4: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.16 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 34874 + state_comps = + 1 + after Defect 34874 + ************************************* + CGREGINNCanonic Subproblem 4: d(0): Starting inner loop ( ||r||_2 = 4613315.4, theta*||r||_2 = 4613315.4, theta = 1, m_max = 1 ) + Before innerstep 34874 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 4: d(0), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.72 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.8448165e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.8448165e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.8448165e+19 + CGREGINNCanonic Subproblem4: d(0), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.23 seconds + alpha = + 2.274046e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 1988264.3 + after innerstep 45260 + CGREGINNCanonic Subproblem: 4: d(0), inner(0): ||r||_2 = 3560494.9 + CGREGINNCanonic Subproblem: 4: d(0): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 45272 + After finishIterate 45272 + before get iterate 45272 + after get iterate 45272 + CGREGINNCanonic problem 5: d(0) + shot: 5: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.02 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 35034 + state_comps = + 1 + after Defect 35034 + ************************************* + CGREGINNCanonic Subproblem 5: d(0): Starting inner loop ( ||r||_2 = 4699903.3, theta*||r||_2 = 4699903.3, theta = 1, m_max = 1 ) + Before innerstep 35034 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 5: d(0), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.03 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.8873269e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.8873269e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.8873269e+19 + CGREGINNCanonic Subproblem5: d(0), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.62 seconds + alpha = + 1.8052851e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 2244617.2 + after innerstep 45383 + CGREGINNCanonic Subproblem: 5: d(0), inner(0): ||r||_2 = 3144864.5 + CGREGINNCanonic Subproblem: 5: d(0): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 45395 + After finishIterate 45395 + before get iterate 45395 + after get iterate 45395 + CGREGINNCanonic problem 0: d(1) + shot: 0: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.84 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 35102 + after Defect 35102 + ************************************* + CGREGINNCanonic Subproblem 0: d(1): Starting inner loop ( ||r||_2 = 12571047, theta*||r||_2 = 6044694.4, theta = 0.48084254, m_max = 2 ) + Before innerstep 35102 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 0: d(1), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.90 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.8415841e+20 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.8415841e+20 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.8415841e+20 + CGREGINNCanonic Subproblem0: d(1), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.68 seconds + alpha = + 1.5944699e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 22478261 + after innerstep 45537 + CGREGINNCanonic Subproblem: 0: d(1), inner(0): ||r||_2 = 7281619.2 + Before innerstep 45537 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 22478261 + CGREGINNCanonic Subproblem 0: d(1), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.13 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.5332207e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.5332207e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.5332207e+19 + CGREGINNCanonic Subproblem0: d(1), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.89 seconds + alpha = + 4.4459343e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 53565938 + after innerstep 45480 + CGREGINNCanonic Subproblem: 0: d(1), inner(1): ||r||_2 = 3847428.4 + CGREGINNCanonic Subproblem: 0: d(1): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 45493 + After finishIterate 45493 + before get iterate 45493 + after get iterate 45493 + CGREGINNCanonic problem 1: d(1) + shot: 1: Solving forward problem... + Initialization: 0.35 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.48 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 35467 + after Defect 35467 + ************************************* + CGREGINNCanonic Subproblem 1: d(1): Starting inner loop ( ||r||_2 = 10932503, theta*||r||_2 = 5662096.9, theta = 0.51791404, m_max = 2 ) + Before innerstep 35467 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 1: d(1), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.1647457e+20 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.1647457e+20 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.1647457e+20 + CGREGINNCanonic Subproblem1: d(1), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.23 seconds + alpha = + 1.6342234e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 8452042.7 + after innerstep 45612 + CGREGINNCanonic Subproblem: 1: d(1), inner(0): ||r||_2 = 4881939.9 + CGREGINNCanonic Subproblem: 1: d(1): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 45624 + After finishIterate 45624 + before get iterate 45624 + after get iterate 45624 + CGREGINNCanonic problem 2: d(1) + shot: 2: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.65 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 35572 + after Defect 35572 + ************************************* + CGREGINNCanonic Subproblem 2: d(1): Starting inner loop ( ||r||_2 = 8714648.1, theta*||r||_2 = 4080275, theta = 0.4682088, m_max = 2 ) + Before innerstep 35572 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 2: d(1), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.68 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0865941e+20 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0865941e+20 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0865941e+20 + CGREGINNCanonic Subproblem2: d(1), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.69 seconds + alpha = + 3.3706544e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 12345134 + after innerstep 45709 + CGREGINNCanonic Subproblem: 2: d(1), inner(0): ||r||_2 = 4286254.1 + Before innerstep 45709 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 12345134 + CGREGINNCanonic Subproblem 2: d(1), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.75 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.7854141e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.7854141e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.7854141e+19 + CGREGINNCanonic Subproblem2: d(1), inner(1): Solving linearized forward problem + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.72 seconds + alpha = + 3.5961667e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 23727686 + after innerstep 45651 + CGREGINNCanonic Subproblem: 2: d(1), inner(1): ||r||_2 = 2908798.4 + CGREGINNCanonic Subproblem: 2: d(1): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 45663 + After finishIterate 45663 + before get iterate 45663 + after get iterate 45663 + CGREGINNCanonic problem 3: d(1) + shot: 3: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.20 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 36102 + after Defect 36102 + ************************************* + CGREGINNCanonic Subproblem 3: d(1): Starting inner loop ( ||r||_2 = 5252125.7, theta*||r||_2 = 2726865.9, theta = 0.51919282, m_max = 2 ) + Before innerstep 36102 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 3: d(1), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.5135396e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.5135396e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.5135396e+19 + CGREGINNCanonic Subproblem3: d(1), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.36 seconds + alpha = + 1.7643513e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 2027623 + after innerstep 45841 + CGREGINNCanonic Subproblem: 3: d(1), inner(0): ||r||_2 = 3636894.6 + Before innerstep 45841 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 2027623 + CGREGINNCanonic Subproblem 3: d(1), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0261227e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0261227e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0261227e+19 + CGREGINNCanonic Subproblem3: d(1), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.06 seconds + alpha = + 7.557937e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 11635082 + after innerstep 45781 + CGREGINNCanonic Subproblem: 3: d(1), inner(1): ||r||_2 = 2341928.5 + CGREGINNCanonic Subproblem: 3: d(1): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 45794 + After finishIterate 45794 + before get iterate 45794 + after get iterate 45794 + CGREGINNCanonic problem 4: d(1) + shot: 4: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.12 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 36529 + after Defect 36529 + ************************************* + CGREGINNCanonic Subproblem 4: d(1): Starting inner loop ( ||r||_2 = 3560494.9, theta*||r||_2 = 2747942.1, theta = 0.77178657, m_max = 2 ) + Before innerstep 36529 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 4: d(1), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.00 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.1264591e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.1264591e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.1264591e+19 + CGREGINNCanonic Subproblem4: d(1), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.06 seconds + alpha = + 1.4701357e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 1324111 + after innerstep 45948 + CGREGINNCanonic Subproblem: 4: d(1), inner(0): ||r||_2 = 2286278.5 + CGREGINNCanonic Subproblem: 4: d(1): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 45960 + After finishIterate 45960 + before get iterate 45960 + after get iterate 45960 + CGREGINNCanonic problem 5: d(1) + shot: 5: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.22 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 36632 + after Defect 36632 + ************************************* + CGREGINNCanonic Subproblem 5: d(1): Starting inner loop ( ||r||_2 = 3144864.5, theta*||r||_2 = 2104335.3, theta = 0.66913387, m_max = 2 ) + Before innerstep 36632 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 5: d(1), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.88 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0408259e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0408259e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0408259e+19 + CGREGINNCanonic Subproblem5: d(1), inner(0): Solving linearized forward problem + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.61 seconds + alpha = + 2.4698781e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 634934.78 + after innerstep 46039 + CGREGINNCanonic Subproblem: 5: d(1), inner(0): ||r||_2 = 2251728 + Before innerstep 46039 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 634934.78 + CGREGINNCanonic Subproblem 5: d(1), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.87 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.4221762e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.4221762e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.4221762e+18 + CGREGINNCanonic Subproblem5: d(1), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.21 seconds + alpha = + 4.1901582e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 3801184.7 + after innerstep 45986 + CGREGINNCanonic Subproblem: 5: d(1), inner(1): ||r||_2 = 1557601.8 + CGREGINNCanonic Subproblem: 5: d(1): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 45998 + After finishIterate 45998 + before get iterate 45998 + after get iterate 45998 + CGREGINNCanonic problem 0: d(2) + shot: 0: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.66 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 36968 + after Defect 36968 + ************************************* + CGREGINNCanonic Subproblem 0: d(2): Starting inner loop ( ||r||_2 = 3945049.3, theta*||r||_2 = 2920998.4, theta = 0.74042127, m_max = 3 ) + Before innerstep 36968 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 0: d(2), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.66 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.6990539e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.6990539e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.6990539e+19 + CGREGINNCanonic Subproblem0: d(2), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.81 seconds + alpha = + 3.9098442e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 2597323.6 + after innerstep 46069 + CGREGINNCanonic Subproblem: 0: d(2), inner(0): ||r||_2 = 2982991.1 + Before innerstep 46069 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 2597323.6 + CGREGINNCanonic Subproblem 0: d(2), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.91 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 9.6725721e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 9.6725721e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 9.6725721e+18 + CGREGINNCanonic Subproblem0: d(2), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.59 seconds + alpha = + 4.1785267e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 8433524.3 + after innerstep 46005 + CGREGINNCanonic Subproblem: 0: d(2), inner(1): ||r||_2 = 2195341.8 + CGREGINNCanonic Subproblem: 0: d(2): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 46018 + After finishIterate 46018 + before get iterate 46018 + after get iterate 46018 + CGREGINNCanonic problem 1: d(2) + shot: 1: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.50 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 37404 + after Defect 37404 + ************************************* + CGREGINNCanonic Subproblem 1: d(2): Starting inner loop ( ||r||_2 = 3958283.4, theta*||r||_2 = 1845045.5, theta = 0.46612264, m_max = 2 ) + Before innerstep 37404 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 1: d(2), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.1457735e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.1457735e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.1457735e+19 + CGREGINNCanonic Subproblem1: d(2), inner(0): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.48 seconds + alpha = + 2.683047e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 2264560.9 + after innerstep 46232 + CGREGINNCanonic Subproblem: 1: d(2), inner(0): ||r||_2 = 2693280.5 + Before innerstep 46232 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 2264560.9 + CGREGINNCanonic Subproblem 1: d(2), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.02 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.1977893e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.1977893e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.1977893e+19 + CGREGINNCanonic Subproblem1: d(2), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.35 seconds + alpha = + 2.9447753e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 5613752.8 + after innerstep 46167 + CGREGINNCanonic Subproblem: 1: d(2), inner(1): ||r||_2 = 1931352.1 + CGREGINNCanonic Subproblem: 1: d(2): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 46179 + After finishIterate 46179 + before get iterate 46179 + after get iterate 46179 + CGREGINNCanonic problem 2: d(2) + shot: 2: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.43 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 37507 + after Defect 37507 + ************************************* + CGREGINNCanonic Subproblem 2: d(2): Starting inner loop ( ||r||_2 = 3511458.3, theta*||r||_2 = 2577777, theta = 0.7341044, m_max = 3 ) + Before innerstep 37507 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 2: d(2), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.83 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.6136493e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.6136493e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.6136493e+19 + CGREGINNCanonic Subproblem2: d(2), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.58 seconds + alpha = + 1.6425078e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 1244685.1 + after innerstep 46332 + CGREGINNCanonic Subproblem: 2: d(2), inner(0): ||r||_2 = 2163122.1 + CGREGINNCanonic Subproblem: 2: d(2): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 46344 + After finishIterate 46344 + before get iterate 46344 + after get iterate 46344 + CGREGINNCanonic problem 3: d(2) + shot: 3: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.13 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 37546 + after Defect 37546 + ************************************* + CGREGINNCanonic Subproblem 3: d(2): Starting inner loop ( ||r||_2 = 2478284.4, theta*||r||_2 = 1882495.9, theta = 0.75959641, m_max = 3 ) + Before innerstep 37546 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 3: d(2), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.71 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 7.6526515e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 7.6526515e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 7.6526515e+18 + CGREGINNCanonic Subproblem3: d(2), inner(0): Solving linearized forward problem + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.56 seconds + alpha = + 3.4246524e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 897521.63 + after innerstep 46432 + CGREGINNCanonic Subproblem: 3: d(2), inner(0): ||r||_2 = 1875494.9 + CGREGINNCanonic Subproblem: 3: d(2): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 46444 + After finishIterate 46444 + before get iterate 46444 + after get iterate 46444 + CGREGINNCanonic problem 4: d(2) + shot: 4: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.16 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 37638 + after Defect 37638 + ************************************* + CGREGINNCanonic Subproblem 4: d(2): Starting inner loop ( ||r||_2 = 2363947, theta*||r||_2 = 1642016.3, theta = 0.69460791, m_max = 2 ) + Before innerstep 37638 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 4: d(2), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.74 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.1587647e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.1587647e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.1587647e+19 + CGREGINNCanonic Subproblem4: d(2), inner(0): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.07 seconds + alpha = + 2.0077416e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 467101.1 + after innerstep 46523 + CGREGINNCanonic Subproblem: 4: d(2), inner(0): ||r||_2 = 1813724.4 + Before innerstep 46523 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 467101.1 + CGREGINNCanonic Subproblem 4: d(2), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.650757e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.650757e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.650757e+18 + CGREGINNCanonic Subproblem4: d(2), inner(1): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.68 seconds + alpha = + 3.8089786e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 1731353.6 + after innerstep 46469 + CGREGINNCanonic Subproblem: 4: d(2), inner(1): ||r||_2 = 1377681.4 + CGREGINNCanonic Subproblem: 4: d(2): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 46482 + After finishIterate 46482 + before get iterate 46482 + after get iterate 46482 + CGREGINNCanonic problem 5: d(2) + shot: 5: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.14 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 37813 + after Defect 37813 + ************************************* + CGREGINNCanonic Subproblem 5: d(2): Starting inner loop ( ||r||_2 = 1547748.8, theta*||r||_2 = 1291700, theta = 0.83456693, m_max = 3 ) + Before innerstep 37813 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 5: d(2), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.59 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.9607469e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.9607469e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.9607469e+18 + CGREGINNCanonic Subproblem5: d(2), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.85 seconds + alpha = + 1.7206057e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 117257.28 + after innerstep 46632 + CGREGINNCanonic Subproblem: 5: d(2), inner(0): ||r||_2 = 1308066.3 + Before innerstep 46632 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 117257.28 + CGREGINNCanonic Subproblem 5: d(2), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.69 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0678613e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0678613e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0678613e+18 + CGREGINNCanonic Subproblem5: d(2), inner(1): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.25 seconds + alpha = + 5.9335939e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 817433.33 + after innerstep 46569 + CGREGINNCanonic Subproblem: 5: d(2), inner(1): ||r||_2 = 1040209.6 + CGREGINNCanonic Subproblem: 5: d(2): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 46581 + After finishIterate 46581 + before get iterate 46581 + after get iterate 46581 + CGREGINNCanonic problem 0: d(3) + shot: 0: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.70 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 37914 + after Defect 37914 + ************************************* + CGREGINNCanonic Subproblem 0: d(3): Starting inner loop ( ||r||_2 = 2164004.3, theta*||r||_2 = 1442047.4, theta = 0.66637915, m_max = 4 ) + Before innerstep 37914 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 0: d(3), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.54 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0257427e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0257427e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0257427e+19 + CGREGINNCanonic Subproblem0: d(3), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.59 seconds + alpha = + 1.5862963e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 258111.33 + after innerstep 46710 + CGREGINNCanonic Subproblem: 0: d(3), inner(0): ||r||_2 = 1751169.4 + Before innerstep 46710 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 258111.33 + CGREGINNCanonic Subproblem 0: d(3), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.65 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.8074978e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.8074978e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.8074978e+18 + CGREGINNCanonic Subproblem0: d(3), inner(1): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.67 seconds + alpha = + 6.7150958e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 1614282.5 + after innerstep 46649 + CGREGINNCanonic Subproblem: 0: d(3), inner(1): ||r||_2 = 1362828.3 + CGREGINNCanonic Subproblem: 0: d(3): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 46661 + After finishIterate 46661 + before get iterate 46661 + after get iterate 46661 + CGREGINNCanonic problem 1: d(3) + shot: 1: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.44 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 38042 + after Defect 38042 + ************************************* + CGREGINNCanonic Subproblem 1: d(3): Starting inner loop ( ||r||_2 = 1950771.1, theta*||r||_2 = 1430034.9, theta = 0.73306132, m_max = 3 ) + Before innerstep 38042 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 1: d(3), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.59 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.9300935e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.9300935e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.9300935e+18 + CGREGINNCanonic Subproblem1: d(3), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.22 seconds + alpha = + 2.3135893e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 263892.89 + after innerstep 46838 + CGREGINNCanonic Subproblem: 1: d(3), inner(0): ||r||_2 = 1629883.1 + Before innerstep 46838 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 263892.89 + CGREGINNCanonic Subproblem 1: d(3), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.66 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.3592959e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.3592959e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.3592959e+18 + CGREGINNCanonic Subproblem1: d(3), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.95 seconds + alpha = + 5.7336903e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 2044861.4 + after innerstep 46784 + CGREGINNCanonic Subproblem: 1: d(3), inner(1): ||r||_2 = 1136031.3 + CGREGINNCanonic Subproblem: 1: d(3): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 46797 + After finishIterate 46797 + before get iterate 46797 + after get iterate 46797 + CGREGINNCanonic problem 2: d(3) + shot: 2: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.36 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 38309 + after Defect 38309 + ************************************* + CGREGINNCanonic Subproblem 2: d(3): Starting inner loop ( ||r||_2 = 2357183.6, theta*||r||_2 = 1557377, theta = 0.66069396, m_max = 3 ) + Before innerstep 38309 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 2: d(3), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0374393e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0374393e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0374393e+19 + CGREGINNCanonic Subproblem2: d(3), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.72 seconds + alpha = + 2.4224096e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 608776.43 + after innerstep 46908 + CGREGINNCanonic Subproblem: 2: d(3), inner(0): ||r||_2 = 1741419.3 + Before innerstep 46908 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 608776.43 + CGREGINNCanonic Subproblem 2: d(3), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.67 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.0980338e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.0980338e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.0980338e+18 + CGREGINNCanonic Subproblem2: d(3), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.11 seconds + alpha = + 3.9983338e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 1861315.2 + after innerstep 46856 + CGREGINNCanonic Subproblem: 2: d(3), inner(1): ||r||_2 = 1337668.2 + CGREGINNCanonic Subproblem: 2: d(3): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 46868 + After finishIterate 46868 + before get iterate 46868 + after get iterate 46868 + CGREGINNCanonic problem 3: d(3) + shot: 3: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.03 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 38368 + after Defect 38368 + ************************************* + CGREGINNCanonic Subproblem 3: d(3): Starting inner loop ( ||r||_2 = 2219477, theta*||r||_2 = 1517316.1, theta = 0.68363677, m_max = 3 ) + Before innerstep 38368 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 3: d(3), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0837819e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0837819e+19 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0837819e+19 + CGREGINNCanonic Subproblem3: d(3), inner(0): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.59 seconds + alpha = + 1.9434572e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 409347.24 + after innerstep 47000 + CGREGINNCanonic Subproblem: 3: d(3), inner(0): ||r||_2 = 1677224.6 + Before innerstep 47000 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 409347.24 + CGREGINNCanonic Subproblem 3: d(3), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.1521871e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.1521871e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.1521871e+18 + CGREGINNCanonic Subproblem3: d(3), inner(1): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.31 seconds + alpha = + 5.0233233e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 1490273 + after innerstep 46943 + CGREGINNCanonic Subproblem: 3: d(3), inner(1): ||r||_2 = 1313031.2 + CGREGINNCanonic Subproblem: 3: d(3): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 46955 + After finishIterate 46955 + before get iterate 46955 + after get iterate 46955 + CGREGINNCanonic problem 4: d(3) + shot: 4: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.88 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 38452 + after Defect 38452 + ************************************* + CGREGINNCanonic Subproblem 4: d(3): Starting inner loop ( ||r||_2 = 1418214.4, theta*||r||_2 = 1201658.6, theta = 0.84730396, m_max = 3 ) + Before innerstep 38452 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 4: d(3), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.0191179e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.0191179e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.0191179e+18 + CGREGINNCanonic Subproblem4: d(3), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.15 seconds + alpha = + 2.9715572e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 178291.18 + after innerstep 47101 + CGREGINNCanonic Subproblem: 4: d(3), inner(0): ||r||_2 = 1187329.2 + CGREGINNCanonic Subproblem: 4: d(3): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 47114 + After finishIterate 47114 + before get iterate 47114 + after get iterate 47114 + CGREGINNCanonic problem 5: d(3) + shot: 5: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.27 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 38514 + after Defect 38514 + ************************************* + CGREGINNCanonic Subproblem 5: d(3): Starting inner loop ( ||r||_2 = 1040396.9, theta*||r||_2 = 781452.75, theta = 0.75111024, m_max = 4 ) + Before innerstep 38514 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 5: d(3), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.4456247e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.4456247e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.4456247e+17 + CGREGINNCanonic Subproblem5: d(3), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.69 seconds + alpha = + 2.5115712e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 40658.937 + after innerstep 47193 + CGREGINNCanonic Subproblem: 5: d(3), inner(0): ||r||_2 = 959427.9 + Before innerstep 47193 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 40658.937 + CGREGINNCanonic Subproblem 5: d(3), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.66 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.5642485e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.5642485e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.5642485e+17 + CGREGINNCanonic Subproblem5: d(3), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.24 seconds + alpha = + 6.8515369e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 565696.73 + after innerstep 47143 + CGREGINNCanonic Subproblem: 5: d(3), inner(1): ||r||_2 = 781953.98 + Before innerstep 47143 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 565696.73 + CGREGINNCanonic Subproblem 5: d(3), inner(2): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.60 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.1234625e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.1234625e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.1234625e+17 + CGREGINNCanonic Subproblem5: d(3), inner(2): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.93 seconds + alpha = + 4.2007878e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 1448764.6 + after innerstep 47101 + CGREGINNCanonic Subproblem: 5: d(3), inner(2): ||r||_2 = 631655.58 + CGREGINNCanonic Subproblem: 5: d(3): Finished inner loop ( 3 steps ) + ************************************* + Before finishIterate 47113 + After finishIterate 47113 + before get iterate 47113 + after get iterate 47113 + CGREGINNCanonic problem 0: d(4) + shot: 0: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.50 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 38740 + after Defect 38740 + ************************************* + CGREGINNCanonic Subproblem 0: d(4): Starting inner loop ( ||r||_2 = 1590454.8, theta*||r||_2 = 953861.32, theta = 0.59974123, m_max = 4 ) + Before innerstep 38740 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 0: d(4), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.70 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.3417097e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.3417097e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.3417097e+18 + CGREGINNCanonic Subproblem0: d(4), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.88 seconds + alpha = + 2.1946051e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 160946.48 + after innerstep 47300 + CGREGINNCanonic Subproblem: 0: d(4), inner(0): ||r||_2 = 1334204.4 + Before innerstep 47300 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 160946.48 + CGREGINNCanonic Subproblem 0: d(4), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 9.6484835e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 9.6484835e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 9.6484835e+17 + CGREGINNCanonic Subproblem0: d(4), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.44 seconds + alpha = + 4.4439532e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 597528.05 + after innerstep 47245 + CGREGINNCanonic Subproblem: 0: d(4), inner(1): ||r||_2 = 1160322.4 + Before innerstep 47245 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 597528.05 + CGREGINNCanonic Subproblem 0: d(4), inner(2): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.8863539e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.8863539e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.8863539e+17 + CGREGINNCanonic Subproblem0: d(4), inner(2): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.63 seconds + alpha = + 5.898436e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 2160566.8 + after innerstep 47201 + CGREGINNCanonic Subproblem: 0: d(4), inner(2): ||r||_2 = 910593.65 + CGREGINNCanonic Subproblem: 0: d(4): Finished inner loop ( 3 steps ) + ************************************* + Before finishIterate 47213 + After finishIterate 47213 + before get iterate 47213 + after get iterate 47213 + CGREGINNCanonic problem 1: d(4) + shot: 1: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.21 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 38798 + after Defect 38798 + ************************************* + CGREGINNCanonic Subproblem 1: d(4): Starting inner loop ( ||r||_2 = 1316056.5, theta*||r||_2 = 868275.13, theta = 0.65975519, m_max = 4 ) + Before innerstep 38798 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 1: d(4), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.69 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.8415144e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.8415144e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.8415144e+18 + CGREGINNCanonic Subproblem1: d(4), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.20 seconds + alpha = + 3.4182728e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 215173.39 + after innerstep 47392 + CGREGINNCanonic Subproblem: 1: d(4), inner(0): ||r||_2 = 1050785.6 + Before innerstep 47392 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 215173.39 + CGREGINNCanonic Subproblem 1: d(4), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.74 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.9107474e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.9107474e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.9107474e+17 + CGREGINNCanonic Subproblem1: d(4), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.14 seconds + alpha = + 8.0816497e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 1223563.3 + after innerstep 47337 + CGREGINNCanonic Subproblem: 1: d(4), inner(1): ||r||_2 = 739286.82 + CGREGINNCanonic Subproblem: 1: d(4): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 47350 + After finishIterate 47350 + before get iterate 47350 + after get iterate 47350 + CGREGINNCanonic problem 2: d(4) + shot: 2: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.23 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 39073 + after Defect 39073 + ************************************* + CGREGINNCanonic Subproblem 2: d(4): Starting inner loop ( ||r||_2 = 1437196.6, theta*||r||_2 = 1193371.9, theta = 0.83034698, m_max = 3 ) + Before innerstep 39073 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 2: d(4), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.56 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.9049169e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.9049169e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.9049169e+18 + CGREGINNCanonic Subproblem2: d(4), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.51 seconds + alpha = + 2.281923e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 151264.04 + after innerstep 47459 + CGREGINNCanonic Subproblem: 2: d(4), inner(0): ||r||_2 = 1183651.5 + CGREGINNCanonic Subproblem: 2: d(4): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 47471 + After finishIterate 47471 + before get iterate 47471 + after get iterate 47471 + CGREGINNCanonic problem 3: d(4) + shot: 3: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.00 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 39009 + after Defect 39009 + ************************************* + CGREGINNCanonic Subproblem 3: d(4): Starting inner loop ( ||r||_2 = 1571054.4, theta*||r||_2 = 1322542.5, theta = 0.84181838, m_max = 3 ) + Before innerstep 39009 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 3: d(4), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.8852679e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.8852679e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.8852679e+18 + CGREGINNCanonic Subproblem3: d(4), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.23 seconds + alpha = + 1.9430151e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 146680.82 + after innerstep 47578 + CGREGINNCanonic Subproblem: 3: d(4), inner(0): ||r||_2 = 1306051.2 + CGREGINNCanonic Subproblem: 3: d(4): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 47590 + After finishIterate 47590 + before get iterate 47590 + after get iterate 47590 + CGREGINNCanonic problem 4: d(4) + shot: 4: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.98 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 39103 + after Defect 39103 + ************************************* + CGREGINNCanonic Subproblem 4: d(4): Starting inner loop ( ||r||_2 = 1232824.8, theta*||r||_2 = 940119.62, theta = 0.76257356, m_max = 3 ) + Before innerstep 39103 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 4: d(4), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.79 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.2065846e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.2065846e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.2065846e+18 + CGREGINNCanonic Subproblem4: d(4), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.98 seconds + alpha = + 4.7846006e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 276216.21 + after innerstep 47644 + CGREGINNCanonic Subproblem: 4: d(4), inner(0): ||r||_2 = 968594.34 + Before innerstep 47644 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 276216.21 + CGREGINNCanonic Subproblem 4: d(4), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.2032701e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.2032701e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.2032701e+17 + CGREGINNCanonic Subproblem4: d(4), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.34 seconds + alpha = + 3.5700004e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 609661.23 + after innerstep 47591 + CGREGINNCanonic Subproblem: 4: d(4), inner(1): ||r||_2 = 844657.11 + CGREGINNCanonic Subproblem: 4: d(4): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 47604 + After finishIterate 47604 + before get iterate 47604 + after get iterate 47604 + CGREGINNCanonic problem 5: d(4) + shot: 5: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.90 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 39345 + after Defect 39345 + ************************************* + CGREGINNCanonic Subproblem 5: d(4): Starting inner loop ( ||r||_2 = 704875.57, theta*||r||_2 = 587918.03, theta = 0.83407349, m_max = 5 ) + Before innerstep 39345 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 5: d(4), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.61 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.4120402e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.4120402e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.4120402e+17 + CGREGINNCanonic Subproblem5: d(4), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.92 seconds + alpha = + 2.359857e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 19001.397 + after innerstep 47735 + CGREGINNCanonic Subproblem: 5: d(4), inner(0): ||r||_2 = 645428.14 + Before innerstep 47735 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 19001.397 + CGREGINNCanonic Subproblem 5: d(4), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.79 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.0181668e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.0181668e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.0181668e+17 + CGREGINNCanonic Subproblem5: d(4), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.81 seconds + alpha = + 4.4635775e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 125978.78 + after innerstep 47683 + CGREGINNCanonic Subproblem: 5: d(4), inner(1): ||r||_2 = 572009.59 + CGREGINNCanonic Subproblem: 5: d(4): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 47695 + After finishIterate 47695 + before get iterate 47695 + after get iterate 47695 + CGREGINNCanonic problem 0: d(5) + shot: 0: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.51 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 39437 + after Defect 39437 + ************************************* + CGREGINNCanonic Subproblem 0: d(5): Starting inner loop ( ||r||_2 = 1003870.2, theta*||r||_2 = 735998.28, theta = 0.73316082, m_max = 5 ) + Before innerstep 39437 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 0: d(5), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.70 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.5927504e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.5927504e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.5927504e+17 + CGREGINNCanonic Subproblem0: d(5), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.81 seconds + alpha = + 3.611196e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 85974.322 + after innerstep 47828 + CGREGINNCanonic Subproblem: 0: d(5), inner(0): ||r||_2 = 875178.87 + Before innerstep 47828 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 85974.322 + CGREGINNCanonic Subproblem 0: d(5), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.3799423e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.3799423e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.3799423e+17 + CGREGINNCanonic Subproblem0: d(5), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.86 seconds + alpha = + 3.6328339e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 297841.56 + after innerstep 47775 + CGREGINNCanonic Subproblem: 0: d(5), inner(1): ||r||_2 = 775799.7 + Before innerstep 47775 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 297841.56 + CGREGINNCanonic Subproblem 0: d(5), inner(2): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.69 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.5525596e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.5525596e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.5525596e+17 + CGREGINNCanonic Subproblem0: d(5), inner(2): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.72 seconds + alpha = + 4.9798234e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 678727.65 + after innerstep 47726 + CGREGINNCanonic Subproblem: 0: d(5), inner(2): ||r||_2 = 688109.78 + CGREGINNCanonic Subproblem: 0: d(5): Finished inner loop ( 3 steps ) + ************************************* + Before finishIterate 47738 + After finishIterate 47738 + before get iterate 47738 + after get iterate 47738 + CGREGINNCanonic problem 1: d(5) + shot: 1: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.24 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 39570 + after Defect 39570 + ************************************* + CGREGINNCanonic Subproblem 1: d(5): Starting inner loop ( ||r||_2 = 911308.06, theta*||r||_2 = 541116.2, theta = 0.59377967, m_max = 4 ) + Before innerstep 39570 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 1: d(5), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 9.8104821e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 9.8104821e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 9.8104821e+17 + CGREGINNCanonic Subproblem1: d(5), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.42 seconds + alpha = + 2.7068003e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 71879.127 + after innerstep 47918 + CGREGINNCanonic Subproblem: 1: d(5), inner(0): ||r||_2 = 750745.8 + Before innerstep 47918 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 71879.127 + CGREGINNCanonic Subproblem 1: d(5), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.79 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.1834007e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.1834007e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.1834007e+17 + CGREGINNCanonic Subproblem1: d(5), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.02 seconds + alpha = + 7.0382532e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 289095.87 + after innerstep 47867 + CGREGINNCanonic Subproblem: 1: d(5), inner(1): ||r||_2 = 640009.4 + Before innerstep 47867 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 289095.87 + CGREGINNCanonic Subproblem 1: d(5), inner(2): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.66 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.4698056e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.4698056e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.4698056e+17 + CGREGINNCanonic Subproblem1: d(5), inner(2): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.44 seconds + alpha = + 3.0924965e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 753654.03 + after innerstep 47819 + CGREGINNCanonic Subproblem: 1: d(5), inner(2): ||r||_2 = 520633.58 + CGREGINNCanonic Subproblem: 1: d(5): Finished inner loop ( 3 steps ) + ************************************* + Before finishIterate 47832 + After finishIterate 47832 + before get iterate 47832 + after get iterate 47832 + CGREGINNCanonic problem 2: d(5) + shot: 2: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.24 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 39662 + after Defect 39662 + ************************************* + CGREGINNCanonic Subproblem 2: d(5): Starting inner loop ( ||r||_2 = 1312730.9, theta*||r||_2 = 981019.95, theta = 0.74731228, m_max = 3 ) + Before innerstep 39662 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 2: d(5), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.54 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.6328872e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.6328872e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.6328872e+18 + CGREGINNCanonic Subproblem2: d(5), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.70 seconds + alpha = + 4.4444954e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 322553.02 + after innerstep 48010 + CGREGINNCanonic Subproblem: 2: d(5), inner(0): ||r||_2 = 999043.39 + Before innerstep 48010 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 322553.02 + CGREGINNCanonic Subproblem 2: d(5), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.66 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.1294197e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.1294197e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.1294197e+17 + CGREGINNCanonic Subproblem2: d(5), inner(1): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.67 seconds + alpha = + 4.3964664e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 878664.32 + after innerstep 47958 + CGREGINNCanonic Subproblem: 2: d(5), inner(1): ||r||_2 = 799060.87 + CGREGINNCanonic Subproblem: 2: d(5): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 47970 + After finishIterate 47970 + before get iterate 47970 + after get iterate 47970 + CGREGINNCanonic problem 3: d(5) + shot: 3: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.96 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 39830 + after Defect 39830 + ************************************* + CGREGINNCanonic Subproblem 3: d(5): Starting inner loop ( ||r||_2 = 1387574.1, theta*||r||_2 = 1051276.9, theta = 0.75763655, m_max = 3 ) + Before innerstep 39830 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 3: d(5), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.69 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.557396e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.557396e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.557396e+18 + CGREGINNCanonic Subproblem3: d(5), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.41 seconds + alpha = + 4.275752e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 284724 + after innerstep 48076 + CGREGINNCanonic Subproblem: 3: d(5), inner(0): ||r||_2 = 1119947.9 + Before innerstep 48076 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 284724 + CGREGINNCanonic Subproblem 3: d(5), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.84 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.1591246e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.1591246e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.1591246e+18 + CGREGINNCanonic Subproblem3: d(5), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.49 seconds + alpha = + 3.9489472e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 993966.2 + after innerstep 48026 + CGREGINNCanonic Subproblem: 3: d(5), inner(1): ||r||_2 = 888747.32 + CGREGINNCanonic Subproblem: 3: d(5): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 48038 + After finishIterate 48038 + before get iterate 48038 + after get iterate 48038 + CGREGINNCanonic problem 4: d(5) + shot: 4: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.93 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 39877 + after Defect 39877 + ************************************* + CGREGINNCanonic Subproblem 4: d(5): Starting inner loop ( ||r||_2 = 966107.76, theta*||r||_2 = 851418, theta = 0.88128678, m_max = 3 ) + Before innerstep 39877 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 4: d(5), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.63 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.9708087e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.9708087e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.9708087e+17 + CGREGINNCanonic Subproblem4: d(5), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.94 seconds + alpha = + 3.508082e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 85787.228 + after innerstep 48167 + CGREGINNCanonic Subproblem: 4: d(5), inner(0): ||r||_2 = 828730.83 + CGREGINNCanonic Subproblem: 4: d(5): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 48180 + After finishIterate 48180 + before get iterate 48180 + after get iterate 48180 + CGREGINNCanonic problem 5: d(5) + shot: 5: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.03 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 39929 + after Defect 39929 + ************************************* + CGREGINNCanonic Subproblem 5: d(5): Starting inner loop ( ||r||_2 = 669010.51, theta*||r||_2 = 502203.54, theta = 0.75066614, m_max = 5 ) + Before innerstep 39929 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 5: d(5), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.3314957e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.3314957e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.3314957e+17 + CGREGINNCanonic Subproblem5: d(5), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.89 seconds + alpha = + 1.9411025e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 12552.672 + after innerstep 48264 + CGREGINNCanonic Subproblem: 5: d(5), inner(0): ||r||_2 = 618096.19 + Before innerstep 48264 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 12552.672 + CGREGINNCanonic Subproblem 5: d(5), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.74 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.2961816e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.2961816e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.2961816e+17 + CGREGINNCanonic Subproblem5: d(5), inner(1): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.11 seconds + alpha = + 6.5367641e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 122951.15 + after innerstep 48214 + CGREGINNCanonic Subproblem: 5: d(5), inner(1): ||r||_2 = 544692.3 + Before innerstep 48214 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 122951.15 + CGREGINNCanonic Subproblem 5: d(5), inner(2): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.64 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.3086763e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.3086763e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.3086763e+17 + CGREGINNCanonic Subproblem5: d(5), inner(2): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.62 seconds + alpha = + 6.7654804e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 465928.63 + after innerstep 48167 + CGREGINNCanonic Subproblem: 5: d(5), inner(2): ||r||_2 = 454825.45 + CGREGINNCanonic Subproblem: 5: d(5): Finished inner loop ( 3 steps ) + ************************************* + Before finishIterate 48179 + After finishIterate 48179 + before get iterate 48179 + after get iterate 48179 + CGREGINNCanonic problem 0: d(6) + shot: 0: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.26 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 40024 + after Defect 40024 + ************************************* + CGREGINNCanonic Subproblem 0: d(6): Starting inner loop ( ||r||_2 = 818532.85, theta*||r||_2 = 540104.59, theta = 0.65984474, m_max = 6 ) + Before innerstep 40024 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 0: d(6), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.73 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.8172513e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.8172513e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.8172513e+17 + CGREGINNCanonic Subproblem0: d(6), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.55 seconds + alpha = + 4.1192632e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 64772.376 + after innerstep 48334 + CGREGINNCanonic Subproblem: 0: d(6), inner(0): ||r||_2 = 715825.42 + Before innerstep 48334 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 64772.376 + CGREGINNCanonic Subproblem 0: d(6), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.81 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.7285501e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.7285501e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.7285501e+17 + CGREGINNCanonic Subproblem0: d(6), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.67 seconds + alpha = + 7.4429585e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 311168 + after innerstep 48283 + CGREGINNCanonic Subproblem: 0: d(6), inner(1): ||r||_2 = 619635.75 + Before innerstep 48283 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 311168 + CGREGINNCanonic Subproblem 0: d(6), inner(2): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.66 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0487678e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0487678e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0487678e+17 + CGREGINNCanonic Subproblem0: d(6), inner(2): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.48 seconds + alpha = + 1.0724054e-06 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 877958.33 + after innerstep 48236 + CGREGINNCanonic Subproblem: 0: d(6), inner(2): ||r||_2 = 521344.46 + CGREGINNCanonic Subproblem: 0: d(6): Finished inner loop ( 3 steps ) + ************************************* + Before finishIterate 48248 + After finishIterate 48248 + before get iterate 48248 + after get iterate 48248 + CGREGINNCanonic problem 1: d(6) + shot: 1: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.13 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 40267 + after Defect 40267 + ************************************* + CGREGINNCanonic Subproblem 1: d(6): Starting inner loop ( ||r||_2 = 921647.99, theta*||r||_2 = 672053.22, theta = 0.72918645, m_max = 5 ) + Before innerstep 40267 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 1: d(6), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.64 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.6221409e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.6221409e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.6221409e+18 + CGREGINNCanonic Subproblem1: d(6), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.12 seconds + alpha = + 2.5276744e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 103640.82 + after innerstep 48424 + CGREGINNCanonic Subproblem: 1: d(6), inner(0): ||r||_2 = 660862.58 + CGREGINNCanonic Subproblem: 1: d(6): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 48437 + After finishIterate 48437 + before get iterate 48437 + after get iterate 48437 + CGREGINNCanonic problem 2: d(6) + shot: 2: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.33 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 40398 + after Defect 40398 + ************************************* + CGREGINNCanonic Subproblem 2: d(6): Starting inner loop ( ||r||_2 = 906327.38, theta*||r||_2 = 791818.48, theta = 0.87365614, m_max = 3 ) + Before innerstep 40398 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 2: d(6), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.6090618e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.6090618e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.6090618e+17 + CGREGINNCanonic Subproblem2: d(6), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.70 seconds + alpha = + 3.9036436e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 100711.75 + after innerstep 48516 + CGREGINNCanonic Subproblem: 2: d(6), inner(0): ||r||_2 = 750794.87 + CGREGINNCanonic Subproblem: 2: d(6): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 48528 + After finishIterate 48528 + before get iterate 48528 + after get iterate 48528 + CGREGINNCanonic problem 3: d(6) + shot: 3: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.98 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 40490 + after Defect 40490 + ************************************* + CGREGINNCanonic Subproblem 3: d(6): Starting inner loop ( ||r||_2 = 1046662.3, theta*||r||_2 = 919825.95, theta = 0.87881827, m_max = 3 ) + Before innerstep 40490 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 3: d(6), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.63 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.3775524e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.3775524e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.3775524e+18 + CGREGINNCanonic Subproblem3: d(6), inner(0): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.43 seconds + alpha = + 1.9946881e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 54809.793 + after innerstep 48635 + CGREGINNCanonic Subproblem: 3: d(6), inner(0): ||r||_2 = 904839.03 + CGREGINNCanonic Subproblem: 3: d(6): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 48647 + After finishIterate 48647 + before get iterate 48647 + after get iterate 48647 + CGREGINNCanonic problem 4: d(6) + shot: 4: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.03 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 40625 + after Defect 40625 + ************************************* + CGREGINNCanonic Subproblem 4: d(6): Starting inner loop ( ||r||_2 = 891843.43, theta*||r||_2 = 707372.84, theta = 0.7931581, m_max = 3 ) + Before innerstep 40625 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 4: d(6), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.2358532e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.2358532e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.2358532e+17 + CGREGINNCanonic Subproblem4: d(6), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.23 seconds + alpha = + 3.6760545e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 70754.057 + after innerstep 48726 + CGREGINNCanonic Subproblem: 4: d(6), inner(0): ||r||_2 = 776449.33 + Before innerstep 48726 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 70754.057 + CGREGINNCanonic Subproblem 4: d(6), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.68 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.0438212e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.0438212e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.0438212e+17 + CGREGINNCanonic Subproblem4: d(6), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.11 seconds + alpha = + 3.9796915e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 376097.31 + after innerstep 48680 + CGREGINNCanonic Subproblem: 4: d(6), inner(1): ||r||_2 = 632071.75 + CGREGINNCanonic Subproblem: 4: d(6): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 48693 + After finishIterate 48693 + before get iterate 48693 + after get iterate 48693 + CGREGINNCanonic problem 5: d(6) + shot: 5: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.07 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 40753 + after Defect 40753 + ************************************* + CGREGINNCanonic Subproblem 5: d(6): Starting inner loop ( ||r||_2 = 585856.21, theta*||r||_2 = 488473.68, theta = 0.83377743, m_max = 5 ) + Before innerstep 40753 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 5: d(6), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.4899188e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.4899188e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.4899188e+17 + CGREGINNCanonic Subproblem5: d(6), inner(0): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.21 seconds + alpha = + 2.9479288e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 30328.388 + after innerstep 48818 + CGREGINNCanonic Subproblem: 5: d(6), inner(0): ||r||_2 = 490343.7 + Before innerstep 48818 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 30328.388 + CGREGINNCanonic Subproblem 5: d(6), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.8177196e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.8177196e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.8177196e+16 + CGREGINNCanonic Subproblem5: d(6), inner(1): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.88 seconds + alpha = + 4.0593937e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 69988.553 + after innerstep 48773 + CGREGINNCanonic Subproblem: 5: d(6), inner(1): ||r||_2 = 452709.41 + CGREGINNCanonic Subproblem: 5: d(6): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 48785 + After finishIterate 48785 + before get iterate 48785 + after get iterate 48785 + CGREGINNCanonic problem 0: d(7) + shot: 0: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.54 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 40954 + after Defect 40954 + ************************************* + CGREGINNCanonic Subproblem 0: d(7): Starting inner loop ( ||r||_2 = 580535.9, theta*||r||_2 = 344757.2, theta = 0.59386026, m_max = 6 ) + Before innerstep 40954 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 0: d(7), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.70 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.8667558e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.8667558e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.8667558e+17 + CGREGINNCanonic Subproblem0: d(7), inner(0): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.02 seconds + alpha = + 2.2603926e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 14647.33 + after innerstep 48910 + CGREGINNCanonic Subproblem: 0: d(7), inner(0): ||r||_2 = 521318.34 + Before innerstep 48910 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 14647.33 + CGREGINNCanonic Subproblem 0: d(7), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.73 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.3673616e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.3673616e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.3673616e+16 + CGREGINNCanonic Subproblem0: d(7), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.80 seconds + alpha = + 3.2888852e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 38956.59 + after innerstep 48866 + CGREGINNCanonic Subproblem: 0: d(7), inner(1): ||r||_2 = 494246.07 + Before innerstep 48866 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 38956.59 + CGREGINNCanonic Subproblem 0: d(7), inner(2): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.65 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.3797591e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.3797591e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.3797591e+16 + CGREGINNCanonic Subproblem0: d(7), inner(2): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.45 seconds + alpha = + 8.12967e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 136723.53 + after innerstep 48820 + CGREGINNCanonic Subproblem: 0: d(7), inner(2): ||r||_2 = 457244.67 + Before innerstep 48820 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 136723.53 + CGREGINNCanonic Subproblem 0: d(7), inner(3): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.68 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.6072791e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.6072791e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.6072791e+16 + CGREGINNCanonic Subproblem0: d(7), inner(3): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.81 seconds + alpha = + 8.5835511e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 460647.37 + after innerstep 48819 + CGREGINNCanonic Subproblem: 0: d(7), inner(3): ||r||_2 = 401003.41 + Before innerstep 48819 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 460647.37 + CGREGINNCanonic Subproblem 0: d(7), inner(4): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.68 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 7.3767076e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 7.3767076e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 7.3767076e+16 + CGREGINNCanonic Subproblem0: d(7), inner(4): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.98 seconds + alpha = + 3.3247403e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 742447.24 + after innerstep 48777 + CGREGINNCanonic Subproblem: 0: d(7), inner(4): ||r||_2 = 369036.81 + Before innerstep 48777 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 742447.24 + CGREGINNCanonic Subproblem 0: d(7), inner(5): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.66 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.6036244e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.6036244e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.6036244e+16 + CGREGINNCanonic Subproblem0: d(7), inner(5): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.64 seconds + alpha = + 6.1639097e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 1298610.7 + after innerstep 48808 + CGREGINNCanonic Subproblem: 0: d(7), inner(5): ||r||_2 = 318455.61 + CGREGINNCanonic Subproblem: 0: d(7): Finished inner loop ( 6 steps ) + ************************************* + Before finishIterate 48820 + After finishIterate 48820 + before get iterate 48820 + after get iterate 48820 + CGREGINNCanonic problem 1: d(7) + shot: 1: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.22 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 40944 + after Defect 40944 + ************************************* + CGREGINNCanonic Subproblem 1: d(7): Starting inner loop ( ||r||_2 = 869862.27, theta*||r||_2 = 570862.6, theta = 0.6562678, m_max = 4 ) + Before innerstep 40944 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 1: d(7), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.82 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0791122e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0791122e+18 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0791122e+18 + CGREGINNCanonic Subproblem1: d(7), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.04 seconds + alpha = + 3.1851393e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 109477.14 + after innerstep 49000 + CGREGINNCanonic Subproblem: 1: d(7), inner(0): ||r||_2 = 641404.13 + Before innerstep 49000 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 109477.14 + CGREGINNCanonic Subproblem 1: d(7), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.76 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.3921884e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.3921884e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.3921884e+17 + CGREGINNCanonic Subproblem1: d(7), inner(1): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.37 seconds + alpha = + 6.2945057e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 323055.48 + after innerstep 48955 + CGREGINNCanonic Subproblem: 1: d(7), inner(1): ||r||_2 = 509571.05 + CGREGINNCanonic Subproblem: 1: d(7): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 48968 + After finishIterate 48968 + before get iterate 48968 + after get iterate 48968 + CGREGINNCanonic problem 2: d(7) + shot: 2: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.25 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 41097 + after Defect 41097 + ************************************* + CGREGINNCanonic Subproblem 2: d(7): Starting inner loop ( ||r||_2 = 875837.83, theta*||r||_2 = 688662.99, theta = 0.78629053, m_max = 3 ) + Before innerstep 41097 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 2: d(7), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.64 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.737988e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.737988e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.737988e+17 + CGREGINNCanonic Subproblem2: d(7), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.61 seconds + alpha = + 4.6969295e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 104525.45 + after innerstep 49093 + CGREGINNCanonic Subproblem: 2: d(7), inner(0): ||r||_2 = 737696.88 + Before innerstep 49093 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 104525.45 + CGREGINNCanonic Subproblem 2: d(7), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.80 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.374194e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.374194e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.374194e+17 + CGREGINNCanonic Subproblem2: d(7), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.47 seconds + alpha = + 3.8718174e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 390669.2 + after innerstep 49047 + CGREGINNCanonic Subproblem: 2: d(7), inner(1): ||r||_2 = 612069.52 + CGREGINNCanonic Subproblem: 2: d(7): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 49059 + After finishIterate 49059 + before get iterate 49059 + after get iterate 49059 + CGREGINNCanonic problem 3: d(7) + shot: 3: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.98 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 41259 + after Defect 41259 + ************************************* + CGREGINNCanonic Subproblem 3: d(7): Starting inner loop ( ||r||_2 = 1017130.8, theta*||r||_2 = 804485.79, theta = 0.79093645, m_max = 3 ) + Before innerstep 41259 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 3: d(7), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.56 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.1280615e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.1280615e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.1280615e+17 + CGREGINNCanonic Subproblem3: d(7), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.54 seconds + alpha = + 3.3227704e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 89740.329 + after innerstep 49185 + CGREGINNCanonic Subproblem: 3: d(7), inner(0): ||r||_2 = 872432.84 + Before innerstep 49185 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 89740.329 + CGREGINNCanonic Subproblem 3: d(7), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.78 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.3013369e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.3013369e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.3013369e+17 + CGREGINNCanonic Subproblem3: d(7), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.40 seconds + alpha = + 5.0007659e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 486493.14 + after innerstep 49139 + CGREGINNCanonic Subproblem: 3: d(7), inner(1): ||r||_2 = 701644.43 + CGREGINNCanonic Subproblem: 3: d(7): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 49151 + After finishIterate 49151 + before get iterate 49151 + after get iterate 49151 + CGREGINNCanonic problem 4: d(7) + shot: 4: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.99 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 41341 + after Defect 41341 + ************************************* + CGREGINNCanonic Subproblem 4: d(7): Starting inner loop ( ||r||_2 = 756596.55, theta*||r||_2 = 678348.62, theta = 0.89657905, m_max = 3 ) + Before innerstep 41341 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 4: d(7), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.61 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.4867579e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.4867579e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.4867579e+17 + CGREGINNCanonic Subproblem4: d(7), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.64 seconds + alpha = + 4.2386917e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 62644.862 + after innerstep 49275 + CGREGINNCanonic Subproblem: 4: d(7), inner(0): ||r||_2 = 652063.26 + CGREGINNCanonic Subproblem: 4: d(7): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 49288 + After finishIterate 49288 + before get iterate 49288 + after get iterate 49288 + CGREGINNCanonic problem 5: d(7) + shot: 5: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.04 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 41424 + after Defect 41424 + ************************************* + CGREGINNCanonic Subproblem 5: d(7): Starting inner loop ( ||r||_2 = 521806.75, theta*||r||_2 = 391563.62, theta = 0.75039969, m_max = 5 ) + Before innerstep 41424 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 5: d(7), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.67 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0521012e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0521012e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0521012e+17 + CGREGINNCanonic Subproblem5: d(7), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.96 seconds + alpha = + 3.0542558e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 9814.504 + after innerstep 49341 + CGREGINNCanonic Subproblem: 5: d(7), inner(0): ||r||_2 = 490128.11 + Before innerstep 49341 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 9814.504 + CGREGINNCanonic Subproblem 5: d(7), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0674131e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0674131e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.0674131e+17 + CGREGINNCanonic Subproblem5: d(7), inner(1): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.94 seconds + alpha = + 5.6333714e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 115095.43 + after innerstep 49296 + CGREGINNCanonic Subproblem: 5: d(7), inner(1): ||r||_2 = 424852.66 + Before innerstep 49296 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 115095.43 + CGREGINNCanonic Subproblem 5: d(7), inner(2): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.67 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.3718769e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.3718769e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.3718769e+16 + CGREGINNCanonic Subproblem5: d(7), inner(2): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.41 seconds + alpha = + 5.2398438e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 301425.74 + after innerstep 49230 + CGREGINNCanonic Subproblem: 5: d(7), inner(2): ||r||_2 = 369358.02 + CGREGINNCanonic Subproblem: 5: d(7): Finished inner loop ( 3 steps ) + ************************************* + Before finishIterate 49242 + After finishIterate 49242 + before get iterate 49242 + after get iterate 49242 + CGREGINNCanonic problem 0: d(8) + shot: 0: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.67 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 41613 + after Defect 41613 + ************************************* + CGREGINNCanonic Subproblem 0: d(8): Starting inner loop ( ||r||_2 = 546120.79, theta*||r||_2 = 435220.12, theta = 0.79693013, m_max = 9 ) + Before innerstep 41613 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 0: d(8), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.60 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.9064819e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.9064819e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.9064819e+17 + CGREGINNCanonic Subproblem0: d(8), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 39.09 seconds + alpha = + 3.0153859e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 35519.889 + after innerstep 49433 + CGREGINNCanonic Subproblem: 0: d(8), inner(0): ||r||_2 = 423529.45 + CGREGINNCanonic Subproblem: 0: d(8): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 49445 + After finishIterate 49445 + before get iterate 49445 + after get iterate 49445 + CGREGINNCanonic problem 1: d(8) + shot: 1: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.31 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 41713 + after Defect 41713 + ************************************* + CGREGINNCanonic Subproblem 1: d(8): Starting inner loop ( ||r||_2 = 702207.85, theta*||r||_2 = 581522.12, theta = 0.8281339, m_max = 3 ) + Before innerstep 41713 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 1: d(8), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.476433e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.476433e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.476433e+17 + CGREGINNCanonic Subproblem1: d(8), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.27 seconds + alpha = + 2.7782361e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 49988.967 + after innerstep 49524 + CGREGINNCanonic Subproblem: 1: d(8), inner(0): ||r||_2 = 558112.67 + CGREGINNCanonic Subproblem: 1: d(8): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 49537 + After finishIterate 49537 + before get iterate 49537 + after get iterate 49537 + CGREGINNCanonic problem 2: d(8) + shot: 2: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.24 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 41805 + after Defect 41805 + ************************************* + CGREGINNCanonic Subproblem 2: d(8): Starting inner loop ( ||r||_2 = 680557.78, theta*||r||_2 = 607836.96, theta = 0.89314526, m_max = 3 ) + Before innerstep 41805 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 2: d(8), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.67 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.0683766e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.0683766e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.0683766e+17 + CGREGINNCanonic Subproblem2: d(8), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.45 seconds + alpha = + 2.3063357e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 21640.445 + after innerstep 49617 + CGREGINNCanonic Subproblem: 2: d(8), inner(0): ||r||_2 = 607897.09 + Before innerstep 49617 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 21640.445 + CGREGINNCanonic Subproblem 2: d(8), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.67 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.5947731e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.5947731e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.5947731e+17 + CGREGINNCanonic Subproblem2: d(8), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.45 seconds + alpha = + 5.5059381e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 130069.29 + after innerstep 49570 + CGREGINNCanonic Subproblem: 2: d(8), inner(1): ||r||_2 = 530820.22 + CGREGINNCanonic Subproblem: 2: d(8): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 49583 + After finishIterate 49583 + before get iterate 49583 + after get iterate 49583 + CGREGINNCanonic problem 3: d(8) + shot: 3: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.89 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 41924 + after Defect 41924 + ************************************* + CGREGINNCanonic Subproblem 3: d(8): Starting inner loop ( ||r||_2 = 813615.12, theta*||r||_2 = 728566.48, theta = 0.89546822, m_max = 3 ) + Before innerstep 41924 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 3: d(8), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.56 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.2374854e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.2374854e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 6.2374854e+17 + CGREGINNCanonic Subproblem3: d(8), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.26 seconds + alpha = + 2.165215e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 29242.305 + after innerstep 49709 + CGREGINNCanonic Subproblem: 3: d(8), inner(0): ||r||_2 = 725498.21 + CGREGINNCanonic Subproblem: 3: d(8): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 49721 + After finishIterate 49721 + before get iterate 49721 + after get iterate 49721 + CGREGINNCanonic problem 4: d(8) + shot: 4: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.08 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 41988 + after Defect 41988 + ************************************* + CGREGINNCanonic Subproblem 4: d(8): Starting inner loop ( ||r||_2 = 746738.17, theta*||r||_2 = 602558.82, theta = 0.80692115, m_max = 3 ) + Before innerstep 41988 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 4: d(8), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.68 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.462483e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.462483e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.462483e+17 + CGREGINNCanonic Subproblem4: d(8), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.97 seconds + alpha = + 4.337822e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 65152.501 + after innerstep 49801 + CGREGINNCanonic Subproblem: 4: d(8), inner(0): ||r||_2 = 638289.99 + Before innerstep 49801 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 65152.501 + CGREGINNCanonic Subproblem 4: d(8), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.86 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.9273077e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.9273077e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.9273077e+17 + CGREGINNCanonic Subproblem4: d(8), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.03 seconds + alpha = + 3.5542143e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 224202.34 + after innerstep 49752 + CGREGINNCanonic Subproblem: 4: d(8), inner(1): ||r||_2 = 549553.45 + CGREGINNCanonic Subproblem: 4: d(8): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 49764 + After finishIterate 49764 + before get iterate 49764 + after get iterate 49764 + CGREGINNCanonic problem 5: d(8) + shot: 5: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.92 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 42184 + after Defect 42184 + ************************************* + CGREGINNCanonic Subproblem 5: d(8): Starting inner loop ( ||r||_2 = 493389.22, theta*||r||_2 = 411289.15, theta = 0.83359979, m_max = 5 ) + Before innerstep 42184 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 5: d(8), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.52 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.9354126e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.9354126e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.9354126e+17 + CGREGINNCanonic Subproblem5: d(8), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.81 seconds + alpha = + 2.183547e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 13995.688 + after innerstep 49893 + CGREGINNCanonic Subproblem: 5: d(8), inner(0): ||r||_2 = 423249.46 + Before innerstep 49893 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 13995.688 + CGREGINNCanonic Subproblem 5: d(8), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.68 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.0344226e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.0344226e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 8.0344226e+16 + CGREGINNCanonic Subproblem5: d(8), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.81 seconds + alpha = + 2.9774771e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 33681.908 + after innerstep 49845 + CGREGINNCanonic Subproblem: 5: d(8), inner(1): ||r||_2 = 393993.83 + CGREGINNCanonic Subproblem: 5: d(8): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 49858 + After finishIterate 49858 + before get iterate 49858 + after get iterate 49858 + CGREGINNCanonic problem 0: d(9) + shot: 0: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.33 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 42349 + after Defect 42349 + ************************************* + CGREGINNCanonic Subproblem 0: d(9): Starting inner loop ( ||r||_2 = 450033.76, theta*||r||_2 = 322780.91, theta = 0.71723712, m_max = 7 ) + Before innerstep 42349 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 0: d(9), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.59 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.1429201e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.1429201e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.1429201e+17 + CGREGINNCanonic Subproblem0: d(9), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.55 seconds + alpha = + 5.5891847e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 35703.663 + after innerstep 49927 + CGREGINNCanonic Subproblem: 0: d(9), inner(0): ||r||_2 = 371783.12 + Before innerstep 49927 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 35703.663 + CGREGINNCanonic Subproblem 0: d(9), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.2761697e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.2761697e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.2761697e+16 + CGREGINNCanonic Subproblem0: d(9), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.93 seconds + alpha = + 4.2139751e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 74475.062 + after innerstep 49881 + CGREGINNCanonic Subproblem: 0: d(9), inner(1): ||r||_2 = 340380.17 + Before innerstep 49881 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 74475.062 + CGREGINNCanonic Subproblem 0: d(9), inner(2): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.63 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.4535709e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.4535709e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.4535709e+16 + CGREGINNCanonic Subproblem0: d(9), inner(2): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.79 seconds + alpha = + 4.3810954e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 108134.16 + after innerstep 49836 + CGREGINNCanonic Subproblem: 0: d(9), inner(2): ||r||_2 = 323946.98 + Before innerstep 49836 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 108134.16 + CGREGINNCanonic Subproblem 0: d(9), inner(3): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.61 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.0920095e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.0920095e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.0920095e+16 + CGREGINNCanonic Subproblem0: d(9), inner(3): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.90 seconds + alpha = + 4.0552172e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 173277.49 + after innerstep 49836 + CGREGINNCanonic Subproblem: 0: d(9), inner(3): ||r||_2 = 303688.48 + CGREGINNCanonic Subproblem: 0: d(9): Finished inner loop ( 4 steps ) + ************************************* + Before finishIterate 49848 + After finishIterate 49848 + Calculating Final Residual: + shot: 0: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.42 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + before get iterate 42400 + after get iterate 42400 + CGREGINNCanonic problem 1: d(9) + shot: 1: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.30 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 42190 + after Defect 42190 + ************************************* + CGREGINNCanonic Subproblem 1: d(9): Starting inner loop ( ||r||_2 = 661232.6, theta*||r||_2 = 492830.22, theta = 0.74532051, m_max = 3 ) + Before innerstep 42190 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 1: d(9), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.68 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.5207676e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.5207676e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.5207676e+17 + CGREGINNCanonic Subproblem1: d(9), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.31 seconds + alpha = + 2.6359883e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 31412.257 + after innerstep 50019 + CGREGINNCanonic Subproblem: 1: d(9), inner(0): ||r||_2 = 564304.21 + Before innerstep 50019 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 31412.257 + CGREGINNCanonic Subproblem 1: d(9), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.983128e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.983128e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.983128e+17 + CGREGINNCanonic Subproblem1: d(9), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 36.05 seconds + alpha = + 4.0166757e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 119927.46 + after innerstep 49973 + CGREGINNCanonic Subproblem: 1: d(9), inner(1): ||r||_2 = 488330.13 + CGREGINNCanonic Subproblem: 1: d(9): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 49985 + After finishIterate 49985 + Calculating Final Residual: + shot: 1: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.13 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + before get iterate 42644 + after get iterate 42644 + CGREGINNCanonic problem 2: d(9) + shot: 2: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.12 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 42434 + after Defect 42434 + ************************************* + CGREGINNCanonic Subproblem 2: d(9): Starting inner loop ( ||r||_2 = 617413.55, theta*||r||_2 = 496295.99, theta = 0.80383074, m_max = 4 ) + Before innerstep 42434 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 2: d(9), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.58 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.2708252e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.2708252e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.2708252e+17 + CGREGINNCanonic Subproblem2: d(9), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.48 seconds + alpha = + 3.2288764e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 23674.813 + after innerstep 50110 + CGREGINNCanonic Subproblem: 2: d(9), inner(0): ||r||_2 = 554497.85 + Before innerstep 50110 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 23674.813 + CGREGINNCanonic Subproblem 2: d(9), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.63 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.3976249e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.3976249e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.3976249e+17 + CGREGINNCanonic Subproblem2: d(9), inner(1): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.56 seconds + alpha = + 5.1006402e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 128888.1 + after innerstep 50065 + CGREGINNCanonic Subproblem: 2: d(9), inner(1): ||r||_2 = 485621.51 + CGREGINNCanonic Subproblem: 2: d(9): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 50078 + After finishIterate 50078 + Calculating Final Residual: + shot: 2: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 28.18 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + before get iterate 42850 + after get iterate 42850 + CGREGINNCanonic problem 3: d(9) + shot: 3: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.96 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 42705 + after Defect 42705 + ************************************* + CGREGINNCanonic Subproblem 3: d(9): Starting inner loop ( ||r||_2 = 770840.58, theta*||r||_2 = 621236.92, theta = 0.8059214, m_max = 3 ) + Before innerstep 42705 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 3: d(9), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.57 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.9001685e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.9001685e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 2.9001685e+17 + CGREGINNCanonic Subproblem3: d(9), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.33 seconds + alpha = + 5.3794229e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 83925.629 + after innerstep 50172 + CGREGINNCanonic Subproblem: 3: d(9), inner(0): ||r||_2 = 661111.78 + Before innerstep 50172 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 83925.629 + CGREGINNCanonic Subproblem 3: d(9), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.59 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.0468737e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.0468737e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 3.0468737e+17 + CGREGINNCanonic Subproblem3: d(9), inner(1): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 34.27 seconds + alpha = + 4.3243269e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 343212.37 + after innerstep 50129 + CGREGINNCanonic Subproblem: 3: d(9), inner(1): ||r||_2 = 550984.84 + CGREGINNCanonic Subproblem: 3: d(9): Finished inner loop ( 2 steps ) + ************************************* + Before finishIterate 50141 + After finishIterate 50141 + Calculating Final Residual: + shot: 3: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 27.87 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + before get iterate 43055 + after get iterate 43055 + CGREGINNCanonic problem 4: d(9) + shot: 4: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 29.98 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 42875 + after Defect 42875 + ************************************* + CGREGINNCanonic Subproblem 4: d(9): Starting inner loop ( ||r||_2 = 624649.92, theta*||r||_2 = 564346.58, theta = 0.90346057, m_max = 3 ) + Before innerstep 42875 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 4: d(9), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.62 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.9737684e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.9737684e+17 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 1.9737684e+17 + CGREGINNCanonic Subproblem4: d(9), inner(0): Solving linearized forward problem + Initialization: 0.29 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 35.95 seconds + alpha = + 4.1350172e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 33748.217 + after innerstep 50238 + CGREGINNCanonic Subproblem: 4: d(9), inner(0): ||r||_2 = 555853.72 + CGREGINNCanonic Subproblem: 4: d(9): Finished inner loop ( 1 steps ) + ************************************* + Before finishIterate 50250 + After finishIterate 50250 + Calculating Final Residual: + shot: 4: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 30.04 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + before get iterate 43117 + after get iterate 43117 + CGREGINNCanonic problem 5: d(9) + shot: 5: Solving forward problem... + Initialization: 0.34 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 33.00 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + after NonlinearEvaluation 42967 + after Defect 42967 + ************************************* + CGREGINNCanonic Subproblem 5: d(9): Starting inner loop ( ||r||_2 = 449155.25, theta*||r||_2 = 336974.15, theta = 0.75023981, m_max = 5 ) + Before innerstep 42967 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 0 + CGREGINNCanonic Subproblem 5: d(9), inner(0): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.61 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.7304411e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.7304411e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 5.7304411e+16 + CGREGINNCanonic Subproblem5: d(9), inner(0): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.77 seconds + alpha = + 4.0570632e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 9432.1694 + after innerstep 50360 + CGREGINNCanonic Subproblem: 5: d(9), inner(0): ||r||_2 = 422454.61 + Before innerstep 50360 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 9432.1694 + CGREGINNCanonic Subproblem 5: d(9), inner(1): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.63 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 9.4884086e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 9.4884086e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 9.4884086e+16 + CGREGINNCanonic Subproblem5: d(9), inner(1): Solving linearized forward problem + Initialization: 0.27 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.93 seconds + alpha = + 5.958067e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 145032.61 + after innerstep 50317 + CGREGINNCanonic Subproblem: 5: d(9), inner(1): ||r||_2 = 349153.78 + Before innerstep 50317 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 145032.61 + CGREGINNCanonic Subproblem 5: d(9), inner(2): Solving backpropagation problem + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 0 + TI: Starting ImplicitMidpointRule (Order=2) + TI: 31.77 seconds + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.4019541e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.4019541e+16 + FWD.scalarProductL2(iterateUpdatePN, iterateUpdatePN) = + 4.4019541e+16 + CGREGINNCanonic Subproblem5: d(9), inner(2): Solving linearized forward problem + Initialization: 0.28 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 38.72 seconds + alpha = + 5.3334552e-07 + FWD.scalarProductL2(iterateMUpdate, iterateMUpdate) = + 267162.19 + after innerstep 50276 + CGREGINNCanonic Subproblem: 5: d(9), inner(2): ||r||_2 = 313486.83 + CGREGINNCanonic Subproblem: 5: d(9): Finished inner loop ( 3 steps ) + ************************************* + Before finishIterate 50289 + After finishIterate 50289 + Calculating Final Residual: + shot: 5: Solving forward problem... + Initialization: 0.33 seconds + TI: Starting ImplicitMidpointRule (Order=2) + TI: 32.85 seconds + Assembling Linearized Operators + Assembling Linearized Operators + Done! + Done! + CGREGINNCanonic: d(10)= 0 + 26143792 + 12571047 + 3945049.3 + 2164004.3 + 1590454.8 + 1003870.2 + 818532.85 + 580535.9 + 546120.79 + 450033.76 + 303676.87 + + + 21108721 + 10932503 + 3958283.4 + 1950771.1 + 1316056.5 + 911308.06 + 921647.99 + 869862.27 + 702207.85 + 661232.6 + 488334.43 + + + 18612739 + 8714648.1 + 3511458.3 + 2357183.6 + 1437196.6 + 1312730.9 + 906327.38 + 875837.83 + 680557.78 + 617413.55 + 485568.41 + + + 10115944 + 5252125.7 + 2478284.4 + 2219477 + 1571054.4 + 1387574.1 + 1046662.3 + 1017130.8 + 813615.12 + 770840.58 + 551002.25 + + + 4613315.4 + 3560494.9 + 2363947 + 1418214.4 + 1232824.8 + 966107.76 + 891843.43 + 756596.55 + 746738.17 + 624649.92 + 555832.46 + + + 4699903.3 + 3144864.5 + 1547748.8 + 1040396.9 + 704875.57 + 669010.51 + 585856.21 + 521806.75 + 493389.22 + 449155.25 + 313430.08 + + +end program after 2:49:19.00 hours on 128 procs at Wed Jul 5 18:42:09 2023 diff --git a/log/2023_07_06_Multi_FO_Iter10/testconf.conf b/log/2023_07_06_Multi_FO_Iter10/testconf.conf new file mode 100644 index 0000000000000000000000000000000000000000..aaf0c68c6e16765e0035aad05bbdcfb874d91a1e --- /dev/null +++ b/log/2023_07_06_Multi_FO_Iter10/testconf.conf @@ -0,0 +1,111 @@ +# Regular Expression um aus Test_Config von Clion eine ... M++ Config zu machen +# \{"([A-Za-z0-9_ ]+)", +"([A-Za-z0-9_ ,\.\-]+)"}. + +#Durchlauf 2023Mai05 mit 4 Quellen, 8 Iterationen, Materialpunkt, level 1 (Ergebnisse ganz gut) +#Durchlauf 2023Mai05 mit 4 Quellen, 8 Iterationen, TwoMedium, level 1 +#Back to FastMode (2 Quellen, 2 Iterationen, Pkt.Material, level 0) +#21.06 Receiver wieder auf 64. Bei multi noch nicht, jetzt aber bei rho rekonstruktion +#Neuer größerer Durchlauf 26.Juni Ohne Inverse Crime für Vp + + ReconstructionType=Classical; + FWINonlinearSolver= FWI_CGREGINN; + CGREGINNCanonic_Step = 10; + + #reading config: CGREGINNType............................ Canonic##??? wohin? + + + #Problem= VAcousticWaveTwoMedium;//<----- Geometrie oder so Siehe: src/Problems/FWIInversionProblems.cpp + Problem= VAcousticWaveC2Benchmark; + FWISO_Steps = 10; #Anzahl Iterationen + Monoparam= multi; #can be "multi"/empty or "Vp", "Tau_p", "Rho" + plot_tStep= -1; + level = 3;#3 nicht auf Laptop starten, sonst stürzt ab + T=0.6; + dt= 0.0005; + FWISourceCount0=6; #Anzahl Quellen, Empfänger default 64 + deg = 2; #In paper CRC deg = 2. Vor 26.Juni2023 wars 1 + FWIReconstructRho= 1; + FWIReconstructV_P= 1; + FWIReconstructTauP= 0; + + #seismopath = C2NoDampingT06dt0005/C2NoDampingT06dt0005;#im Build Ordner! + #ReadFormat = FWI;#IFOS ist falsches Format. + #SpecfileNrOfSamples = 6; + + SaveObservedSeismogram = 0;#Plottet "d_obs", das Vorwärtsgelöste Wellenfeld (mit echten Materialparam) + + SignalName=Ricker;#RickerDerivative vorher!!! Geändert 26.Juni.2023 + #ReconstructionType=SO;#!!! + #FWINonlinearSolver= FWISO;#!!! + numL=0;#!!! + + + + ConfigVerbose=2; + ForwardSolver= VADGTS; + Distribution= RCB; + Model = FWIInverse_DGTS; + Mesh= SeismogramGrid_test; + + useTaper=1; + taperRadiusSource=0; + taperRadiusReceiver=0; + taperExponent=-0.1; + taperIgnoreReceiverCells=1; + taperIgnoreSourceCells=1; + #Monoparam= Rho; #can be "multi"/empty or "Vp", "Tau_p", "Rho" + #ReconstructionType=SO;#!!! + FWIReceiverWaypoints= 2; + FWIReceiverWaypoint0= 1350.0, 370.0; + FWIReceiverWaypoint1= 1350.0, 1630.0; + FWIReceiverIncludeLastWaypoint= 1; + FWIReceiverCount0= 64;//Anzahl Receiver + UseSparseMatrix=1; + Qfactor=100; + #SignalName=Ricker;# RickerDerivative vorher!!! Geändert 26.Juni.2023 + SignalDelay=0; + SignalCutoff=0.8; + SignalFreq=25; + #numL=0;#!!! + FWISourceWaypoints=2; + FWISourceWaypoint0=600,370; + FWISourceWaypoint1=600,1620; + #FWISourceCount0=2; #Anzahl Quelle + #FWISourceCount0=2; + FWIReceiverIncludeLastWaypoint=1; + measurement_space= point; + measurement_time= point; + compMeasure= 0; + source_component= 2; + perturbation_comp= 2; + dampingFlux= 1; + allowPlotting_M=1; + allowPlotting_WF=0; + plotfactor= 10; + parametrization= taup;#!!!! + #T=0.6; + #dt= 0.002; + #deg= 1; + #level = 0;#Feinheit des Gitters (1 mehr -> Halbierung)//Achtung: 3 Böse, <2 Gut + TimeVerbose= 1; + rkorder= -2; + #plot_tStep= -1; + #FWISO_Steps = 2;//scheint zu klappen! + #Steps = 2;//scheint auch nichts zu bringen :( + + Kmax=150; + Keps= 1e-07; + Overlap= dG1; + debugAdjoint= 0; + debugFrechet= 1; + source_factor= 242574257420000.5742; + LinearSolver= LS;#Könnte man auf GMRES (Schreibweise?) ändern.. + LinearVerbose= -1; + LinearSteps=100; + LinearNthIterOutput= 1; + LinearEpsilon= 1e-12; + LinearReduction= 0.0001; + #FWINonlinearSolver= FWI_mSDREGINN; + FWI_DebugPlottingLevel= 1; + #CGREGINNCanonic_Steps=3; + diff --git a/log/zPythonScripteTest/err_n_plots/Fehler.txt b/log/zPythonScripteTest/err_n_plots/Fehler.txt new file mode 100644 index 0000000000000000000000000000000000000000..f2563168ba6a4544b2cbb69f40f732f2d7c573ad --- /dev/null +++ b/log/zPythonScripteTest/err_n_plots/Fehler.txt @@ -0,0 +1,28 @@ +Große Fehlerberechnung +Fehlerberechnung Vp +(1,0.6879)(2,0.627)(3,0.6176)(4,0.6106)(5,0.6064)(6,0.6037)(7,0.6011)(8,0.5991)(9,0.598)(10,0.5963) +array([4718.29833984, 4300.62402344, 4235.69287109, 4187.86669922, + 4158.75195312, 4140.49755859, 4122.90625 , 4108.9921875 , + 4101.35107422, 4089.53686523]) +array([0.6879, 0.627 , 0.6176, 0.6106, 0.6064, 0.6037, 0.6011, 0.5991, + 0.598 , 0.5963]) + + +Fehlerberechnung noICVP +(1,0.6969)(2,0.6472)(3,0.6344)(4,0.6337)(5,0.6494)(6,0.6744)(7,0.6967)(8,0.7177)(9,0.7373)(10,0.7552) +array([4779.52587891, 4438.74511719, 4351.01220703, 4346.46923828, + 4454.16210938, 4625.52929688, 4778.50390625, 4922.58251953, + 5056.80419922, 5179.53173828]) +array([0.6969, 0.6472, 0.6344, 0.6337, 0.6494, 0.6744, 0.6967, 0.7177, + 0.7373, 0.7552]) + + +Fehlerberechnung Rho +(1,0.9684)(2,0.9491)(3,0.9363)(4,0.9256)(5,0.9122)(6,0.9053)(7,0.9013)(8,0.8925)(9,0.8888)(10,0.8824) +array([3795.26147461, 3719.7644043 , 3669.37963867, 3627.44824219, + 3575.26586914, 3547.89819336, 3532.49926758, 3497.74951172, + 3483.45214844, 3458.18847656]) +array([0.9684, 0.9491, 0.9363, 0.9256, 0.9122, 0.9053, 0.9013, 0.8925, + 0.8888, 0.8824]) + + diff --git a/log/zPythonScripteTest/err_n_plots/FehlerInfNorm.txt b/log/zPythonScripteTest/err_n_plots/FehlerInfNorm.txt new file mode 100644 index 0000000000000000000000000000000000000000..3b1b043d539149d32720e72a2044d5ec56344804 --- /dev/null +++ b/log/zPythonScripteTest/err_n_plots/FehlerInfNorm.txt @@ -0,0 +1,28 @@ +Infinity Norm für Tikzpicture formatiert +Fehlerberechnung InfNormVp +(1,0.7765)(2,0.7453)(3,0.7451)(4,0.725)(5,0.7198)(6,0.7171)(7,0.7132)(8,0.7107)(9,0.7071)(10,0.7063) +array([271.78564453, 260.84887695, 260.77734375, 253.73413086, + 251.92504883, 250.97143555, 249.62011719, 248.74707031, + 247.50244141, 247.21411133]) +array([0.7765, 0.7453, 0.7451, 0.725 , 0.7198, 0.7171, 0.7132, 0.7107, + 0.7071, 0.7063]) + + +Fehlerberechnung InfNormnoICVP +(1,0.7408)(2,0.8024)(3,0.7719)(4,0.766)(5,0.7569)(6,0.8394)(7,1.0294)(8,1.1774)(9,1.3086)(10,1.4205) +array([259.2746582 , 280.82617188, 270.15942383, 268.08789062, + 264.91479492, 293.80273438, 360.30517578, 412.09008789, + 457.99658203, 497.15942383]) +array([0.7408, 0.8024, 0.7719, 0.766 , 0.7569, 0.8394, 1.0294, 1.1774, + 1.3086, 1.4205]) + + +Fehlerberechnung InfNormRho 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'_' + iter_fnName.format(nriter) + '.png') + +def plotInitReal(plotter): + plotter.screenshot('aa_REAL_Init__' + titlePrefix[j] + '_' + '.png') + +def dontConfuseNames(plotter): + plotter.screenshot('aa_REAL_Other_Init__' + titlePrefix[j] + '_' + '.png') + +path = ['/home/lionbart/Desktop/Logs_Plots_MA/2023_06_21_zVp15/', + '/home/lionbart/Desktop/Logs_Plots_MA/2023_06_27_noIC_VpMono_HighResolution/', + '/home/lionbart/Desktop/Logs_Plots_MA/2023_06_27_IC_RhoMono_HighResolution/', + '/home/lionbart/Desktop/Logs_Plots_MA/2023_06_30_MultiHighRes_SO/', + '/home/lionbart/Desktop/Logs_Plots_MA/2023_07_06_Multi_FO_Iter10/' + ] +titlePrefix = ['Vp', 'noICVP', 'Rho', 'MultiSO', 'MultiFO'] +prefix = ['Vp', 'Vp', 'Rho'] + +real_fn = 'Vp_fwi_m_real.vtu' +initial_fn = 'Vp_fwi_m_initial.vtu' +iter_fn = 'Vp__fwi_FWISO_iterate_m_allshots_5_{}.vtu' +iter_fnName = 'Vp__fwi_FWISO_iterate_m_allshots_5_{}' + +######Pseudoconfig Area###### +makeMapping = False +#frame = [450, 1500, 300, 1690]#Alt... Nicht ROI=RegionOfInterest (CRC Paper) beachtet :// +frame = [650, 1300, 370, 1620] +zoom = 2.2 +createPlot = True +plotOffScreen = False #Der Screenshot ist anders, wenn offScreen geplotted wird :(( wtf + + + +with open('Fehler.txt', 'w') as outfile: + outfile.write('Große Fehlerberechnung ' + '\n') +with open('FehlerInfNorm.txt', 'w') as outfile: + outfile.write('Infinity Norm für Tikzpicture formatiert ' + '\n') + +for j in range(3): # range(len(path)): + if j == 1: + initial_other_fn = 'Rho_fwi_m_real.vtu' + + if j == 2: + real_fn = 'Rho_fwi_m_real.vtu' + initial_fn = 'Rho_fwi_m_initial.vtu' + iter_fn = 'Rho__fwi_FWISO_iterate_m_allshots_5_{}.vtu' + iter_fnName = 'Rho__fwi_FWISO_iterate_m_allshots_5_{}' + initial_other_fn = 'Vp_fwi_m_initial.vtu' + + # real_centers = pv.read(path+real_fn).cell_centers() + # exit() + real_vtu = pv.read(path[j] + real_fn) + real_vtu_cells = real_vtu.cell_centers() + initial_vtu = pv.read(path[j] + initial_fn) + #initial_other_vtu = pv.read(path[j] + initial_other_fn) + initial_vtu_cells = initial_vtu.cell_centers() + #initial_other_vtu_cells = initial_other_vtu.cell_centers() + iter_vtu = pv.read(path[j] + iter_fn.format(0)) + + iter_vtu_celldata = iter_vtu.cell_data[prefix[j]] + real_vtu_celldata = real_vtu.cell_data[prefix[j]] + initial_vtu_celldata = initial_vtu.cell_data[prefix[j]] + #if j == 1: + #initial_other_vtu_celldata = initial_other_vtu.cell_data['Rho'] + #elif j == 2: + #initial_other_vtu_celldata = initial_other_vtu.cell_data['Vp'] + result_vtu = pv.read(path[j] + real_fn) + result_vtu_celldata = result_vtu.cell_data[prefix[j]] + + pointmapping = [] # Hält Geometrie fest (die teils nicht übereinstimmt) + if makeMapping: # always... otherwise weird + for (i, p) in enumerate(real_vtu_cells.points): + if frame[0] > p[0] or p[0] > frame[1]: + #if 1000 > p[0] or p[0] > 1100: + result_vtu_celldata[i] = 0 + continue + elif frame[2] > p[1] or p[1] > frame[3]: + #elif 700 > p[1] or p[1] > 800: + result_vtu_celldata[i] = 0 + continue + pointmapping.append((i, iter_vtu.find_containing_cell(p))) + pointmapSave = np.array(pointmapping) + file = open(titlePrefix[j] + "_pointmapping.npy", "wb") + # save array to the file + np.save(file, pointmapSave) + # close the file + file.close + elif not makeMapping: + file = open(titlePrefix[j] + "_pointmapping.npy", "rb") + pointmapping = np.load(file) + file.close + for (i, p) in enumerate(real_vtu_cells.points): + if frame[0] > p[0] or p[0] > frame[1]: + result_vtu_celldata[i] = 0 + elif frame[2] > p[1] or p[1] > frame[3]: + result_vtu_celldata[i] = 0 + + with open('Fehler.txt', 'a') as outfile: + outfile.write('Fehlerberechnung ' + titlePrefix[j] + '\n') + with open('FehlerInfNorm.txt', 'a') as outfile: + outfile.write('Fehlerberechnung InfNorm' + titlePrefix[j] + '\n') + + #Berechne Fehler: Real - Homogen + print(titlePrefix[j] + '_' + prefix[j] + 'Homogenes Feld Wert') + print(initial_vtu_celldata[0]) + for t in pointmapping: + result_vtu_celldata[t[0]] = real_vtu_celldata[t[0]] - initial_vtu_celldata[t[1]] + RealMinusInit = np.array(result_vtu_celldata) + RealMinusInitNorm = np.linalg.norm(RealMinusInit) + RealMinusInitInfNorm = max(abs(RealMinusInit)) + + ### Plot Config + legende = dict(height=0.1, position_x=0.89, position_y=0.5)#Gut aktuell!! + legendeDiff = dict(height=0.1, position_x=0.2, position_y=0.06) + annotationsDiff = {0: "0"} + if prefix[j] == 'Vp': + annotationsIter = {3500: "3500"} + climIter = [3250, 3750]#Angepasst an Start. + climIter = [3200, 3800]#Angepasst an Endskale (von Paraview abgeschaut) + climReal = [3325, 3850]#3500 - 175 und 3500 + 350 + climReal = [3150, 3850]#3500 - 350 und 3500 + 350 Idee, dass symmetrie plotting arbeit spart... + #Idee: Das zu Array machen und einlesen + elif prefix[j] == 'Rho': + annotationsIter = {2000: "2000"} + climIter = [1900, 2100]#Eventuell für höhere Iterationen schlecht!? + climReal = [1900, 2200]#2000 - 100 und 2000 + 200 + climReal = [1800, 2200]#2000 - 200 und 2000 + 200 Idee, dass symmetrie plotting arbeit spart... + + norm = np.zeros(10) + infnorm = np.zeros(10) + for nriter in range(10): # 10): + plPlot = pv.Plotter(window_size=(600, 1000), off_screen = plotOffScreen) # Plotter für Ergebnis bauen + pl = pv.Plotter(window_size=(600, 1000), off_screen = True) # Plotter für Differenz bauen + + iter_vtu_celldata = pv.read(path[j] + iter_fn.format(nriter)).cell_data[prefix[j]] + print('Iteration Path: ' + path[j] + iter_fn.format(nriter)) + + for t in pointmapping: + result_vtu_celldata[t[0]] = real_vtu_celldata[t[0]] - iter_vtu_celldata[t[1]] + #iteration + #iter_vtu_celldata[t[0]] = + # result_vtu.plot() #abgelöst durch pl = pv.Plotter() + + #1. Versuch: (rausscheibeen) + #add_legend (pyvista ding argument loc + + ### Fehlerberechnung + resultNp = np.array(result_vtu_celldata) + norm[nriter] = np.linalg.norm(resultNp) + infnorm[nriter] = max(abs(resultNp)) + with open('Fehler.txt', 'a') as outfile: + outfile.write('(' + str(nriter + 1) + ',' + str(np.around(norm[nriter]/RealMinusInitNorm, 4)) + ')') + with open('FehlerInfNorm.txt', 'a') as outfile: + outfile.write('(' + str(nriter + 1) + ',' + str(np.around(infnorm[nriter]/RealMinusInitInfNorm, 4)) + ')') + + iter_vtu = pv.read(path[j] + iter_fn.format(nriter)) + iter_vtu_celldata = iter_vtu.cell_data[prefix[j]] + + + legendeTest = dict(background_color = [0,0,0], + fmt='%4.0f', n_labels = 5, + vertical = True, position_x = 0.8, position_y = 0.1, height = 0.8, width= 0.2, + label_font_size = 30, title_font_size = 40, + #interactive = True, #shadow = False, outline = False, + color = [0,0,0],) + + if createPlot: + ### Plot Iteration (For figures in MA) ### + _ = plPlot.add_mesh(iter_vtu, scalar_bar_args = legendeTest, clim=climReal, cmap = 'RdYlBu',) + #annotations = annotationsIter,) + #_ = plPlot.add_mesh(iter_vtu, show_scalar_bar=False) + #_ = plPlot.add_mesh(iter_vtu, scalar_bar_args = legende, annotations = annotationsIter, clim=climIter) + #plPlot.show_axes() + #plPlot.camera.position = (0.0, 0.0, 1000.0) + plPlot.camera_position = 'xy' + #print(plPlot.camera_position) + #plPlot.camera_position = [(1000.0014953613281, 1000.0, 20438.471894650203),#position + #(1000.0014953613281, 1000.0, 0.0), #focal point + #(0.0, 1.0, 0.0)] #set_viewup + plPlot.camera_position = [(1100.0014953613281, 1000.0, 6512.327012542534),#position + (1100.0014953613281, 1000.0, 0.0), #focal point + (0.0, 1.0, 0.0)] #set_viewup + + plPlot.camera.zoom(zoom) + #plPlot.plot(cmap = 'RdYlBu') + plPlot.show(before_close_callback=plotReal) + #print(plPlot.camera_position) #Seeeeehr hilfreich. Nach rumschieben mit interactive ausgabe der aktuellen pos. + + ### Plot Diff ### No longer supported, since no plot made it into the Thesis. + #_ = pl.add_mesh(result_vtu, scalar_bar_args = legendeTest, cmap = 'RdYlBu',) + #, annotations=annotationsDiff) + #pl.camera_position = [(1100.0014953613281, 1000.0, 6512.327012542534),#position + # (1100.0014953613281, 1000.0, 0.0), #focal point + # (0.0, 1.0, 0.0)] #set_viewup + #pl.camera.zoom(zoom) + #pl.show(before_close_callback=plotDiff) + #print(pl.camera_position) + + if nriter == 0 and createPlot == True: + #CreatePlot of Real_Init; Benennung leider etwas verwirrt... Herzlichen Glückwunsch + plVp = pv.Plotter(window_size=(600, 1000), off_screen = plotOffScreen) + plRho = pv.Plotter(window_size=(600, 1000), off_screen = plotOffScreen) + _ = plVp.add_mesh(real_vtu, scalar_bar_args = legendeTest, clim=climReal, cmap = 'RdYlBu') + #annotations = annotationsIter, + _ = plRho.add_mesh(initial_vtu, scalar_bar_args = legendeTest, clim=climReal, cmap = 'RdYlBu') + + plVp.camera_position = [(1100.0014953613281, 1000.0, 6512.327012542534),#position + (1100.0014953613281, 1000.0, 0.0), #focal point + (0.0, 1.0, 0.0)] #set_viewup + plRho.camera_position = [(1100.0014953613281, 1000.0, 6512.327012542534),#position + (1100.0014953613281, 1000.0, 0.0), #focal point + (0.0, 1.0, 0.0)] #set_viewup + + plVp.camera.zoom(zoom) + plRho.camera.zoom(zoom) + plVp.show(before_close_callback=plotInitReal) + plRho.show(before_close_callback=dontConfuseNames) + + ####pl.show(screenshot = 'diffplot'+iter_fn.format(nriter)+'.png') + + # window_size = (200, 200), + #Berechnung Fehler und Relativer Fehler + Abspeichern + normNormalized = norm/RealMinusInitNorm#norm[0] + normNormalized = np.around(normNormalized, 4) + with open('Fehler.txt', 'a') as outfile: + outfile.write('\n' + repr(norm) + '\n') + outfile.write(repr(normNormalized) + '\n') + outfile.write('\n\n') + + infnormNormalized = infnorm/RealMinusInitInfNorm + infnormNormalized = np.around(infnormNormalized, 4) + with open('FehlerInfNorm.txt', 'a') as outfile: + outfile.write('\n' + repr(infnorm) + '\n') + outfile.write(repr(infnormNormalized) + '\n') + outfile.write('\n\n') + +exit() + +# pl.view_xy() +# pl.export_obj('diffplot'+iter_fn.format(nriter)+'.obj') #Kann man machen, muss man aber nicht. +# pl.save_graphic('diffplot'+iter_fn.format(nriter)+'.svg') + +# CR Idee# savePlot(path+'diffplot'+iter_fn.format(nriter)+'.obj', 'RealPlotMATPLOTLIB'+iter_fnName.format(nriter)+'.png', 3300, 3740) + +# import pyvista as pv +# >>> true_vtu = pv.read('Vp_fwi_m_real.vtu') +# >>> true_vtu_data = pv.read('Vp_fwi_m_real.vtu' + +# >>> true_vtu_data = true_vtu.cell_data['Vp'] + +# >>> true_vtu_data +# pyvista_ndarray([3500., 3500., 3500., ..., 3500., 3500., 3500.], +# dtype=float32) +# >>> iter_data = pv.read('Vp__fwi_FWISO_iterate_m_allshots_5_14.vtu').cell_data['Vp'] +# >>> iter_data +# pyvista_ndarray([3500., 3500., 3500., ..., 3500., 3500., 3500.], +# dtype=float32) +# >>> diff = true_vtu_data-iter_data + +# >>> import numpy as np +# >>> diffnp = np.array(diff) +# >>> diffnp +# array([0., 0., 0., ..., 0., 0., 0.], dtype=float32) +# >>> diffnp.norm() +# Traceback (most recent call last): +# File "<stdin>", line 1, in <module> +# AttributeError: 'numpy.ndarray' object has no attribute 'norm' +# >>> diff.linalg.norm() + +# >>> np.linalg.norm(diff) +# 9635.88 +# >>> initial_data = pv.read('Vp_fwi_m_initial.vtu').cell_data['Vp'] +# >>> np.linalg.norm(initial_data-true_vtu_data) +# 6858.548 +# >>> iter_data = pv.read('Vp__fwi_FWISO_iterate_m_allshots_5_1.vtu').cell_data['Vp'] +# >>> diff = true_vtu_data-iter_data +# >>> np.linalg.norm(diff) +# 8466.148 +# >>> np.linalg.norm(diff,ord=2) +##8466.148 +# >>> iter_data = pv.read('Vp__fwi_FWISO_iterate_m_allshots_5_0.vtu').cell_data['Vp'] +# >>> diff = true_vtu_data-iter_data +# >>> np.linalg.norm(diff,ord=2) +# 8278.743 +## + +# See PyCharm help at https://www.jetbrains.com/help/pycharm/ + diff --git a/log/zPythonScripteTest/err_n_plots/multiLink.bash b/log/zPythonScripteTest/err_n_plots/multiLink.bash new file mode 100644 index 0000000000000000000000000000000000000000..3e5fbe078cc86e69453a4c17068bdc9b55b90f81 --- /dev/null +++ b/log/zPythonScripteTest/err_n_plots/multiLink.bash @@ -0,0 +1,3 @@ +#!/bin/bash +cd ../err_n_plots_multi + diff --git a/log/zPythonScripteTest/err_n_plots/noICVP_pointmapping.npy b/log/zPythonScripteTest/err_n_plots/noICVP_pointmapping.npy new file mode 100644 index 0000000000000000000000000000000000000000..361c6819dfd4f17600cbc3a49026e071e43c73a1 Binary files /dev/null and b/log/zPythonScripteTest/err_n_plots/noICVP_pointmapping.npy differ diff --git a/log/zPythonScripteTest/err_n_plots_multi/FehlerMulti.txt b/log/zPythonScripteTest/err_n_plots_multi/FehlerMulti.txt new file mode 100644 index 0000000000000000000000000000000000000000..e4947c8e121a1a390c4c2a3d5ee63ed6db70750a --- /dev/null +++ b/log/zPythonScripteTest/err_n_plots_multi/FehlerMulti.txt @@ -0,0 +1,37 @@ +Große Fehlerberechnung +Fehlerberechnung MultiSO_Vp +(1,0.7319)(2,0.6723)(3,0.6633)(4,0.6539)(5,0.6492)(6,0.6464)(7,0.6439)(8,0.642)(9,0.6408)(10,0.6393) +array([2049.37304688, 1882.30603027, 1857.17687988, 1830.9420166 , + 1817.81677246, 1809.98852539, 1803.04516602, 1797.4642334 , + 1794.28295898, 1789.99645996]) +array([0.7319, 0.6723, 0.6633, 0.6539, 0.6492, 0.6464, 0.6439, 0.642 , + 0.6408, 0.6393]) + + +Fehlerberechnung MultiSO_Rho +(1,1.0148)(2,1.0066)(3,1.0042)(4,0.9999)(5,0.9974)(6,0.9952)(7,0.9927)(8,0.9905)(9,0.9888)(10,0.9865) +array([1623.70141602, 1610.52697754, 1606.72729492, 1599.91931152, + 1595.7722168 , 1592.27319336, 1588.27197266, 1584.87145996, + 1582.02404785, 1578.41833496]) +array([1.0148, 1.0066, 1.0042, 0.9999, 0.9974, 0.9952, 0.9927, 0.9905, + 0.9888, 0.9865]) + + +Fehlerberechnung MultiFO_Vp +(1,0.7883)(2,0.707)(3,0.6825)(4,0.6696)(5,0.6622)(6,0.6559)(7,0.653)(8,0.6486)(9,0.6475)(10,0.6456) +array([2207.17138672, 1979.56420898, 1911.12097168, 1874.76855469, + 1854.0526123 , 1836.56176758, 1828.52819824, 1816.10986328, + 1812.93078613, 1807.65405273]) +array([0.7883, 0.707 , 0.6825, 0.6696, 0.6622, 0.6559, 0.653 , 0.6486, + 0.6475, 0.6456]) + + +Fehlerberechnung MultiFO_Rho +(1,1.0274)(2,1.013)(3,1.0088)(4,1.0054)(5,1.0036)(6,1.0012)(7,0.9995)(8,0.997)(9,0.9963)(10,0.9944) +array([1643.78210449, 1620.80615234, 1614.01623535, 1608.59606934, + 1605.70446777, 1601.87768555, 1599.16357422, 1595.27832031, + 1594.12915039, 1590.99963379]) +array([1.0274, 1.013 , 1.0088, 1.0054, 1.0036, 1.0012, 0.9995, 0.997 , + 0.9963, 0.9944]) + + diff --git a/log/zPythonScripteTest/err_n_plots_multi/FehlerMultiInfNorm.txt b/log/zPythonScripteTest/err_n_plots_multi/FehlerMultiInfNorm.txt new file mode 100644 index 0000000000000000000000000000000000000000..b99970ba1fea66f53e0a8d2d8a528cdea9a0d302 --- /dev/null +++ b/log/zPythonScripteTest/err_n_plots_multi/FehlerMultiInfNorm.txt @@ -0,0 +1,37 @@ +Infinity Norm für Tikzpicture formatiert +Fehlerberechnung InfNormMultiSO_Vp +(1,0.8123)(2,0.7349)(3,0.7391)(4,0.7223)(5,0.7163)(6,0.7127)(7,0.7081)(8,0.7045)(9,0.704)(10,0.701) +array([142.14648438, 128.61401367, 129.33935547, 126.39648438, + 125.35498047, 124.71777344, 123.92480469, 123.28076172, + 123.20727539, 122.67626953]) +array([0.8123, 0.7349, 0.7391, 0.7223, 0.7163, 0.7127, 0.7081, 0.7045, + 0.704 , 0.701 ]) + + +Fehlerberechnung InfNormMultiSO_Rho +(1,1.0208)(2,1.0289)(3,1.0299)(4,1.0354)(5,1.0383)(6,1.0399)(7,1.0424)(8,1.0453)(9,1.0489)(10,1.0521) +array([102.07763672, 102.88879395, 102.9942627 , 103.53881836, + 103.82666016, 103.98718262, 104.24377441, 104.53295898, + 104.88513184, 105.20666504]) +array([1.0208, 1.0289, 1.0299, 1.0354, 1.0383, 1.0399, 1.0424, 1.0453, + 1.0489, 1.0521]) + + +Fehlerberechnung InfNormMultiFO_Vp +(1,0.8484)(2,0.7865)(3,0.7936)(4,0.7655)(5,0.7594)(6,0.7356)(7,0.7336)(8,0.7149)(9,0.7133)(10,0.7066) +array([148.46459961, 137.63916016, 138.87719727, 133.96899414, + 132.89550781, 128.72387695, 128.37817383, 125.10522461, + 124.83569336, 123.66357422]) +array([0.8484, 0.7865, 0.7936, 0.7655, 0.7594, 0.7356, 0.7336, 0.7149, + 0.7133, 0.7066]) + + +Fehlerberechnung InfNormMultiFO_Rho +(1,1.0165)(2,1.0213)(3,1.0246)(4,1.0298)(5,1.0271)(6,1.0333)(7,1.0351)(8,1.0389)(9,1.0368)(10,1.0408) +array([101.65454102, 102.13208008, 102.45849609, 102.97839355, + 102.71484375, 103.32910156, 103.51123047, 103.890625 , + 103.67724609, 104.07824707]) +array([1.0165, 1.0213, 1.0246, 1.0298, 1.0271, 1.0333, 1.0351, 1.0389, + 1.0368, 1.0408]) + + diff --git 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b/log/zPythonScripteTest/err_n_plots_multi/errors_multis.py new file mode 100644 index 0000000000000000000000000000000000000000..fb899142888289202daa8d7d1b12d9b1ad0fbfbd --- /dev/null +++ b/log/zPythonScripteTest/err_n_plots_multi/errors_multis.py @@ -0,0 +1,207 @@ +# Error Berechnung für Multi Rekonstruktionen +import pyvista as pv +import numpy as np + +def plotReal(plotter):#Das ist dum benannt, aber bleibt halt jetzt so. solle: "plotIter" heißen + plotter.screenshot('IterPlot__' + titlePrefix[j] + '_' + iter_fnName.format(nriter) + '.png') + +def plotDiff(plotter): + plotter.screenshot('DiffPlot__' + titlePrefix[j] + '_' + iter_fnName.format(nriter) + '.png') + +def plotInitReal(plotter): + plotter.screenshot('_REAL_Init__' + titlePrefix[j] + '_' + prefix[k] + '.png') + +path = ['/home/lionbart/Desktop/Logs_Plots_MA/2023_06_30_MultiHighRes_SO/', + '/home/lionbart/Desktop/Logs_Plots_MA/2023_07_06_Multi_FO_Iter10/' + ] +titlePrefix = ['MultiSO', 'MultiFO'] +prefix = ['Vp', 'Rho'] + + +######Pseudoconfig Area###### +makeMapping = False +frame = [650, 1300, 370, 1620] +zoom = 2.2 +createPlot = True #Bei True musst du q drücken die ganze Zeit oder das fixen +plotOffScreen = False #Der Screenshot ist anders, wenn offScreen geplotted wird :(( wtf + +with open('FehlerMulti.txt', 'w') as outfile: + outfile.write('Große Fehlerberechnung ' + '\n') +with open('FehlerMultiInfNorm.txt', 'w') as outfile: + outfile.write('Infinity Norm für Tikzpicture formatiert ' + '\n') + +for j in range(2): #Schleife über path + for k in range(2): #Schleife über prefix + if j == 0 and k == 0: + real_fn = 'Vp_fwi_m_real.vtu' + initial_fn = 'Vp_fwi_m_initial.vtu' + iter_fn = 'Vp__fwi_FWISO_iterate_m_allshots_5_{}.vtu' + iter_fnName = 'Vp__fwi_FWISO_iterate_m_allshots_5_{}' + climIter = [3400, 3640]#ist das noch aktuell und gewollt? + elif j == 0 and k == 1: + real_fn = 'Rho_fwi_m_real.vtu' + initial_fn = 'Rho_fwi_m_initial.vtu' + iter_fn = 'Rho__fwi_FWISO_iterate_m_allshots_5_{}.vtu' + iter_fnName = 'Rho__fwi_FWISO_iterate_m_allshots_5_{}' + elif j == 1 and k == 0: + real_fn = 'Vp_fwi_m_real.vtu' + initial_fn = 'Vp_fwi_m_initial.vtu' + iter_fn = 'Vp__fwi_CGREGINNCanonic_iterate_m_allshots_5_{}.vtu' + iter_fnName = 'Vp__fwi_CGREGINNCanonic_iterate_m_allshots_5_{}' + elif j == 1 and k == 1: + real_fn = 'Rho_fwi_m_real.vtu' + initial_fn = 'Rho_fwi_m_initial.vtu' + iter_fn = 'Rho__fwi_CGREGINNCanonic_iterate_m_allshots_5_{}.vtu' + iter_fnName = 'Rho__fwi_CGREGINNCanonic_iterate_m_allshots_5_{}' + else: + print('ich verstehe das noch nicht. Filenames ändern ist schwierig') + print('j pathschleife = ' + str(j) + ' und k = ' + str(k) + ' und ' + iter_fnName) + + real_vtu = pv.read(path[j] + real_fn) + real_vtu_cells = real_vtu.cell_centers() + initial_vtu = pv.read(path[j] + initial_fn) + initial_vtu_cells = initial_vtu.cell_centers() + iter_vtu = pv.read(path[j] + iter_fn.format(0)) + + iter_vtu_celldata = iter_vtu.cell_data[prefix[k]] + real_vtu_celldata = real_vtu.cell_data[prefix[k]] + initial_vtu_celldata = initial_vtu.cell_data[prefix[k]] + result_vtu = pv.read(path[j] + real_fn) + result_vtu_celldata = result_vtu.cell_data[prefix[k]] + + pointmapping = [] # Hält Geometrie fest (die teils nicht übereinstimmt) + if makeMapping: + for (i, p) in enumerate(real_vtu_cells.points): + if frame[0] > p[0] or p[0] > frame[1]: + #if 1000 > p[0] or p[0] > 1100: + result_vtu_celldata[i] = 0 + continue + elif frame[2] > p[1] or p[1] > frame[3]: + #elif 700 > p[1] or p[1] > 800: + result_vtu_celldata[i] = 0 + continue + pointmapping.append((i, iter_vtu.find_containing_cell(p))) + pointmapSave = np.array(pointmapping) + file = open(titlePrefix[j] + '_' + prefix[k] + "_pointmapping.npy", "wb") + # save array to the file + np.save(file, pointmapSave) + # close the file + file.close + else: + #Reuse the already created pointmapping file. + file = open(titlePrefix[j] + '_' + prefix[k] + "_pointmapping.npy", "rb") + pointmapping = np.load(file) + file.close + for (i, p) in enumerate(real_vtu_cells.points): + if frame[0] > p[0] or p[0] > frame[1]: + result_vtu_celldata[i] = 0 + elif frame[2] > p[1] or p[1] > frame[3]: + result_vtu_celldata[i] = 0 + + with open('FehlerMulti.txt', 'a') as outfile: + outfile.write('Fehlerberechnung ' + titlePrefix[j] + '_' + prefix[k] + '\n') + with open('FehlerMultiInfNorm.txt', 'a') as outfile: + outfile.write('Fehlerberechnung InfNorm' + titlePrefix[j] + '_' + prefix[k] + '\n') + + #Berechne Fehler: Real - Homogen + print(titlePrefix[j] + '_' + prefix[k] + 'Homogenes Feld Wert') + for t in pointmapping: + result_vtu_celldata[t[0]] = real_vtu_celldata[t[0]] - initial_vtu_celldata[t[1]] + RealMinusInit = np.array(result_vtu_celldata) + RealMinusInitNorm = np.linalg.norm(RealMinusInit) + #RealMinusInit = np.reshape(RealMinusInit, -1) + + RealMinusInitInfNorm = max(abs(RealMinusInit)) + #np.linalg.norm(RealMinusInit, ord=np.inf) + + norm = np.zeros(10) + infnorm = np.zeros(10) + for nriter in range(10): # 10): + plPlot = pv.Plotter(window_size=(600, 1000), off_screen = plotOffScreen) # Plotter für Ergebnis bauen + #pl = pv.Plotter(window_size=(600, 1000), off_screen = plotOffScreen) # Plotter für Differenz bauen + + iter_vtu_celldata = pv.read(path[j] + iter_fn.format(nriter)).cell_data[prefix[k]] + for t in pointmapping: + result_vtu_celldata[t[0]] = real_vtu_celldata[t[0]] - iter_vtu_celldata[t[1]] + ### Fehlerberechnung + resultNp = np.array(result_vtu_celldata) + norm[nriter] = np.linalg.norm(resultNp) + infnorm[nriter] = max(abs(resultNp)) + #Formatierung schon für tikzpicture + with open('FehlerMulti.txt', 'a') as outfile: + outfile.write('(' + repr(nriter + 1) + ',' + str(np.around(norm[nriter]/RealMinusInitNorm, 4)) + ')') + with open('FehlerMultiInfNorm.txt', 'a') as outfile: + outfile.write('(' + repr(nriter + 1) + ',' + str(np.around(infnorm[nriter]/RealMinusInitInfNorm, 4)) + ')') + + + ### Plot Config + legende = dict(height=0.1, position_x=0.2, position_y=0.06)#Gut aktuell!! + legendeDiff = dict(height=0.1, position_x=0.2, position_y=0.06) + annotationsDiff = {0: "0"} + if prefix[k] == 'Vp': + annotationsIter = {3500: "3500"} + climIter = [3250, 3750]#äEventuell für höhere Iterationen schlecht!? + climReal = [3325, 3850]#Neu: 3335 und 3850, damit Farben ähnlich zu Monoparam #Alt:3500 - 175 und 3500 + 175 + climReal = [3325, 3675]#3500 - 175 und 3500 + 175 Idee, dass symmetrie plotting arbeit spart... + elif prefix[k] == 'Rho': + annotationsIter = {2000: "2000"} + climIter = [1900, 2100]#Eventuell für höhere Iterationen schlecht!? + climReal = [1900, 2200]#Neu 1900, 2200, s.o. #Alt:2000 - 100 und 2000 + 100 + climReal = [1900, 2100]#2000 - 200 und 2000 + 200 Idee, dass symmetrie plotting arbeit spart... + + iter_vtu = pv.read(path[j] + iter_fn.format(nriter)) + iter_vtu_celldata = iter_vtu.cell_data[prefix[k]] + + legendeTest = dict(background_color = [0,0,0], + fmt='%4.0f', n_labels = 5, + vertical = True, position_x = 0.8, position_y = 0.1, height = 0.8, width= 0.2, + label_font_size = 30, title_font_size = 40, + #interactive = True, #shadow = False, outline = False, + color = [0,0,0],) + + if createPlot: + ### Plot Iteration (For figures in MA) + _ = plPlot.add_mesh(iter_vtu, scalar_bar_args = legendeTest, clim=climReal, cmap = 'RdYlBu') #, annotations=annotationsIter) + plPlot.camera_position = [(1100.0014953613281, 1000.0, 6512.327012542534),#position + (1100.0014953613281, 1000.0, 0.0), #focal point + (0.0, 1.0, 0.0)] #set_viewup + #plPlot.camera_position = 'xy' + #plPlot.show_axes() + plPlot.camera.zoom(zoom) + print(plPlot.camera_position) + plPlot.show(before_close_callback=plotReal) + + ### Plot Diff + #_ = pl.add_mesh(result_vtu, scalar_bar_args = legendeDiff, annotations=annotationsDiff, cmap = 'RdYlBu') + #pl.set_viewup([0, 1, 0]) + #pl.camera.zoom(zoom) + ####pl.show(screenshot = 'diffplot'+iter_fn.format(nriter)+'.png') + #pl.show(before_close_callback=plotDiff) + if nriter == 0 and createPlot == True: + #CreatePlot of Real_Init + plVp = pv.Plotter(window_size=(600, 1000), off_screen = plotOffScreen) + _ = plVp.add_mesh(real_vtu, scalar_bar_args = legendeTest, clim=climReal, cmap = 'RdYlBu') + #, annotations = annotationsIter + plVp.camera_position = [(1100.0014953613281, 1000.0, 6512.327012542534),#position + (1100.0014953613281, 1000.0, 0.0), #focal point + (0.0, 1.0, 0.0)] #set_viewup + plVp.camera.zoom(zoom) + plVp.show(before_close_callback=plotInitReal) + ####pl.show(screenshot = 'diffplot'+iter_fn.format(nriter)+'.png') + + # window_size = (200, 200), + norm = np.array(norm) + normNormalized = norm/RealMinusInitNorm#norm[0] + normNormalized = np.around(normNormalized, 4) + with open('FehlerMulti.txt', 'a') as outfile: + outfile.write('\n' + repr(norm) + '\n') + outfile.write(repr(normNormalized) + '\n') + outfile.write('\n\n') + + infnormNormalized = infnorm/RealMinusInitInfNorm + infnormNormalized = np.around(infnormNormalized, 4) + with open('FehlerMultiInfNorm.txt', 'a') as outfile: + outfile.write('\n' + repr(infnorm) + '\n') + outfile.write(repr(infnormNormalized) + '\n') + outfile.write('\n\n') + diff --git a/tools/plottools/errors.py b/tools/plottools/errors.py new file mode 100644 index 0000000000000000000000000000000000000000..bc49447e89c139c2741d4d29f47dbaf5d19abbe2 --- /dev/null +++ b/tools/plottools/errors.py @@ -0,0 +1,119 @@ +import pyvista as pv +import numpy as np +path='/home/lionbart/Desktop/Logs_Plots_MA/2023_06_27_noIC_VpMono_HighResolution/' +real_fn = 'Vp_fwi_m_real.vtu' +initial_fn = 'Vp_fwi_m_initial.vtu' +iter_fn = 'Vp__fwi_FWISO_iterate_m_allshots_5_{}.vtu' +iter_fnName = 'Vp__fwi_FWISO_iterate_m_allshots_5_{}' +#real_fn = 'Vp_fwi_m_real.csv' +#initial_fn = 'Vp_fwi_m_initial.csv' +#iter_fn = 'Vp__fwi_FWISO_iterate_m_allshots_5_0.csv' + +def plotReal(plotter): + plotter.screenshot('DiffPlot'+iter_fnName.format(nriter)+'.png') + +def plotDiff(plotter): + plotter.screenshot('ResultPlot'+iter_fnName.format(nriter)+'.png') + +#real_centers = pv.read(path+real_fn).cell_centers() +#exit() +real_vtu = pv.read(path+real_fn) +real_vtu_cells=real_vtu.cell_centers() +initial_vtu = pv.read(path+initial_fn) +iter_vtu = pv.read(path+iter_fn.format(0)) + +iter_vtu_celldata = iter_vtu.cell_data['Vp'] +real_vtu_celldata=real_vtu.cell_data['Vp'] +result_vtu = pv.read(path+real_fn) +result_vtu_celldata = result_vtu.cell_data['Vp'] +#initial_data = pv.read(path+initial_fn) +#iter_data = pv.read(path+iter_fn) +pointmapping =[] #Hält Geometrie fest (die teils nicht übereinstimmt) +for (i,p) in enumerate(real_vtu_cells.points): + #if 450 > p[0] or p[0] > 1500: + if 1000 > p[0] or p[0] > 1100: + result_vtu_celldata[i] = 0 + continue + elif 700 > p[1] or p[1] > 800: + #elif 300 > p[1] or p[1] > 1690: + result_vtu_celldata[i] = 0 + continue + pointmapping.append((i,iter_vtu.find_containing_cell(p))) + +#Plot Real Initial Field +#plReal = pv.Plotter() +#_ = plReal.add_mesh(real_vtu) + +for nriter in range(2): + plPlot = pv.Plotter() #Plotter für Ergebnis bauen + pl = pv.Plotter() #Plotter für Differenz bauen + + iter_vtu_celldata = pv.read(path+iter_fn.format(nriter)).cell_data['Vp'] + + for t in pointmapping: + result_vtu_celldata[t[0]] = real_vtu_celldata[t[0]] - iter_vtu_celldata[t[1]] + #result_vtu.plot() #abgelöst durch pl = pv.Plotter() + + #Plot Iteration + _ = plPlot.add_mesh(iter_vtu) + plPlot.set_viewup([0, 1, 0]) + plPlot.camera.zoom(3) + plPlot.show(before_close_callback = plotReal) + + #Plot Diff + _ = pl.add_mesh(result_vtu) +# _ = pl.add_mesh(result_vtu) + pl.set_viewup([0, 1, 0]) + pl.camera.zoom(3) + ####pl.show(screenshot = 'diffplot'+iter_fn.format(nriter)+'.png') + pl.show(before_close_callback = plotDiff) +exit() + + + + #pl.view_xy() + #pl.export_obj('diffplot'+iter_fn.format(nriter)+'.obj') #Kann man machen, muss man aber nicht. + #pl.save_graphic('diffplot'+iter_fn.format(nriter)+'.svg') + + +#import pyvista as pv +#>>> true_vtu = pv.read('Vp_fwi_m_real.vtu') +#>>> true_vtu_data = pv.read('Vp_fwi_m_real.vtu' + +#>>> true_vtu_data = true_vtu.cell_data['Vp'] + +#>>> true_vtu_data +#pyvista_ndarray([3500., 3500., 3500., ..., 3500., 3500., 3500.], +# dtype=float32) +#>>> iter_data = pv.read('Vp__fwi_FWISO_iterate_m_allshots_5_14.vtu').cell_data['Vp'] +#>>> iter_data +#pyvista_ndarray([3500., 3500., 3500., ..., 3500., 3500., 3500.], +# dtype=float32) +#>>> diff = true_vtu_data-iter_data + +#>>> import numpy as np +#>>> diffnp = np.array(diff) +#>>> diffnp +#array([0., 0., 0., ..., 0., 0., 0.], dtype=float32) +#>>> diffnp.norm() +#Traceback (most recent call last): +# File "<stdin>", line 1, in <module> +#AttributeError: 'numpy.ndarray' object has no attribute 'norm' +#>>> diff.linalg.norm() + +#>>> np.linalg.norm(diff) +#9635.88 +#>>> initial_data = pv.read('Vp_fwi_m_initial.vtu').cell_data['Vp'] +#>>> np.linalg.norm(initial_data-true_vtu_data) +#6858.548 +#>>> iter_data = pv.read('Vp__fwi_FWISO_iterate_m_allshots_5_1.vtu').cell_data['Vp'] +#>>> diff = true_vtu_data-iter_data +#>>> np.linalg.norm(diff) +#8466.148 +#>>> np.linalg.norm(diff,ord=2) +##8466.148 +#>>> iter_data = pv.read('Vp__fwi_FWISO_iterate_m_allshots_5_0.vtu').cell_data['Vp'] +#>>> diff = true_vtu_data-iter_data +#>>> np.linalg.norm(diff,ord=2) +#8278.743 +## diff --git a/tools/plottools/errorsCSV.py b/tools/plottools/errorsCSV.py new file mode 100644 index 0000000000000000000000000000000000000000..5c6b89d70d814928c3e5c1e671ffed36f066933c --- /dev/null +++ b/tools/plottools/errorsCSV.py @@ -0,0 +1,75 @@ +import pyvista as pv +import numpy as np +path='/home/lionbart/Desktop/Logs_Plots_MA/2023_06_27_noIC_VpMono_HighResolution/ClipCSV/' +#real_fn = 'Vp_fwi_m_real.vtu' +#initial_fn = 'Vp_fwi_m_initial.vtu' +#iter_fn = 'Vp__fwi_FWISO_iterate_m_allshots_5_0.vtu' +real_fn = 'Vp_fwi_m_real.csv' +initial_fn = 'Vp_fwi_m_initial.csv' +iter_fn = 'Vp__fwi_FWISO_iterate_m_allshots_5_0.csv' + +import csv + +with open('file.csv', 'r') as file: + reader = csv.reader(file) + for row in reader: + print(row) + +#real_centers = pv.read(path+real_fn).cell_centers() +#exit() +#real_data = pv.read(path+real_fn).cell_data['Vp'] +#initial_data = pv.read(path+initial_fn).cell_data['Vp'] +#iter_data = pv.read(path+iter_fn).cell_data['Vp'] +real_data = pv.read(path+real_fn) +initial_data = pv.read(path+initial_fn) +iter_data = pv.read(path+iter_fn) +diff = real_data-iter_data +difftrue = real_data-initial_data +print("true - initial") +print(np.linalg.norm(difftrue)) +print("true-iter") +print(np.linalg.norm(diff)) + +exit() + +#import pyvista as pv +#>>> true_vtu = pv.read('Vp_fwi_m_real.vtu') +#>>> true_vtu_data = pv.read('Vp_fwi_m_real.vtu' + +#>>> true_vtu_data = true_vtu.cell_data['Vp'] + +#>>> true_vtu_data +#pyvista_ndarray([3500., 3500., 3500., ..., 3500., 3500., 3500.], +# dtype=float32) +#>>> iter_data = pv.read('Vp__fwi_FWISO_iterate_m_allshots_5_14.vtu').cell_data['Vp'] +#>>> iter_data +#pyvista_ndarray([3500., 3500., 3500., ..., 3500., 3500., 3500.], +# dtype=float32) +#>>> diff = true_vtu_data-iter_data + +#>>> import numpy as np +#>>> diffnp = np.array(diff) +#>>> diffnp +#array([0., 0., 0., ..., 0., 0., 0.], dtype=float32) +#>>> diffnp.norm() +#Traceback (most recent call last): +# File "<stdin>", line 1, in <module> +#AttributeError: 'numpy.ndarray' object has no attribute 'norm' +#>>> diff.linalg.norm() + +#>>> np.linalg.norm(diff) +#9635.88 +#>>> initial_data = pv.read('Vp_fwi_m_initial.vtu').cell_data['Vp'] +#>>> np.linalg.norm(initial_data-true_vtu_data) +#6858.548 +#>>> iter_data = pv.read('Vp__fwi_FWISO_iterate_m_allshots_5_1.vtu').cell_data['Vp'] +#>>> diff = true_vtu_data-iter_data +#>>> np.linalg.norm(diff) +#8466.148 +#>>> np.linalg.norm(diff,ord=2) +##8466.148 +#>>> iter_data = pv.read('Vp__fwi_FWISO_iterate_m_allshots_5_0.vtu').cell_data['Vp'] +#>>> diff = true_vtu_data-iter_data +#>>> np.linalg.norm(diff,ord=2) +#8278.743 +## diff --git a/tools/plottools/fwiPlot.py b/tools/plottools/fwiPlot.py new file mode 100644 index 0000000000000000000000000000000000000000..2a3145412bc6472cae6088a01bd00febca4463fa --- /dev/null +++ b/tools/plottools/fwiPlot.py @@ -0,0 +1,294 @@ +import fwiPlotLib +import pyvista as pv +import os.path +import os +from time import time +LSDFpath = '/home/cr/LSDF/' + + + +class PlotConfig: + def __init__(self): + self.name = '' + self.fn_shots = '' + self.input_path = '/tmp/' + self.algo = '' + self.fn_input_final = '' + self.fn_input_true = '' + self.fn_input_initial = '' + + self.path_errors = '' + self.final = 100 + + self.fn_output_final = '' + self.fn_output_true = '' + self.fn_output_initial = '' + self.fn_output_diff = '' + + self.data_name = '' + + self.bounding_box = [(-100000, 100000), (-100000, 100000)] + + self.cmap = 'RdYlBu' + + self.midpoint_iterate = 1.0 + self.vmin_iterate = -1000 + self.vmax_iterate = 1000 + + self.midpoint_diff = 0.0 + self.vmin_diff = -1000 + self.vmax_diff = 1000 + + self.ticks_middle = [] + + self.normalization_value = -100000 + + self.normone = None + self.normtwo = None + + self.plotting = False + self.plot_iterates = False + self.errors = True + self.frequency = '' + + + def __init__(self, dict, lsdf=False): + self.name = dict['name'] + self.fn_shots = dict['fn_shots'] + self.frequency = dict['frequency'] + + if lsdf is True: + self.input_path = LSDFpath + dict['input_path'] + else: + self.input_path = dict['input_path'] + self.algo = dict['algo'] + self.fn_input_true = self.input_path + dict['fn_input_true'] + self.fn_input_initial = self.input_path + dict['fn_input_initial'] + + self.final = dict['final'] + + self.pdf_output_path = self.input_path + dict['pdf_path'] + if os.path.exists(self.pdf_output_path) is False: + os.mkdir(self.pdf_output_path) + self.data_name = dict['data_name'] + + self.fn_output_final = self.pdf_output_path + self.name + self.algo + self.data_name + 'Final.pdf' + self.fn_output_true = self.pdf_output_path + self.name + self.algo + self.data_name + 'True.pdf' + self.fn_output_initial = self.pdf_output_path + self.name + self.algo + self.data_name + 'Initial.pdf' + self.fn_output_diff = self.pdf_output_path + self.name + self.algo + self.data_name + 'Diff.pdf' + + + self.bounding_box = dict['bounding_box'] + + self.cmap = dict['cmap'] + + self.midpoint_iterate = dict['midpoint_iterate'] + self.vmin_iterate = dict['vmin_iterate'] + self.vmax_iterate = dict['vmax_iterate'] + + self.midpoint_diff = dict['midpoint_diff'] + self.vmin_diff = dict['vmin_diff'] + self.vmax_diff = dict['vmax_diff'] + + self.ticks_middle = dict['ticks_middle'] + + self.normalization_value = dict['normalization_value'] + + self.plotting = dict['plotting'] + self.plot_iterates = dict['plot_iterates'] + self.path_errors = self.input_path + dict['path_errors'] + + if os.path.exists(self.path_errors) is False: + os.mkdir(self.path_errors) + self.errors = dict['errors'] + + self.normone = fwiPlotLib.MidpointNormalize(midpoint=self.midpoint_iterate, + vmin=self.vmin_iterate, + vmax=self.vmax_iterate) + self.normtwo = fwiPlotLib.MidpointNormalize(midpoint=self.midpoint_diff, + vmin=self.vmin_diff, + vmax=self.vmax_diff) + self.fn_input_final = self.make_iterate_input_fn(self.final) + + def make_iterate_input_fn(self, nr): + return self.input_fn() + self.fn_shots + '_' + str(nr) + '.vtu' + + def make_iterate_output_fn(self, nr): + return self.input_fn() + self.fn_shots + '_' + str(nr) + '.pdf' + + def input_fn(self): + return self.input_path + self.data_name + '__fwi_' + self.algo + self.frequency + '_iterate_m_allshots_' + + +def setParametersFromTickmiddleCamembert(conf, p): + conf['ticks_middle'] = [1, 1 + p] + conf['vmin_diff'] = -p * 0.5 + conf['vmax_diff'] = p * 0.5 + conf['vmax_iterate'] = 1 + p * 1.5 + conf['vmin_iterate'] = 1 - p + +def getBasicConfig(namestring, algo): + if namestring == 'Camembert': + plot1 = {'name': 'Camembert', 'algo': algo, 'cmap': 'RdYlBu', 'fn_shots': '14', 'final': 9, + 'pdf_path': 'pdfs/', + 'path_errors': 'errors/', 'input_path': '', + 'data_name': 'VpExp', 'fn_input_true': 'VpExp_fwi_m_real.vtu', 'fn_input_initial': '', + 'bounding_box': [(-100000, 100000), (-100000, 100000)], 'midpoint_iterate': 1.0, + 'midpoint_diff': 0, + 'vmin_diff': -0.08, 'vmax_diff': 0.20, 'vmin_iterate': 0.90, 'vmax_iterate': 1.20, + 'ticks_middle': [], + 'normalization_value': 1.0 / 4000.0, 'plotting': True, 'plot_iterates': True, 'errors': True, + 'frequency': ''} + return plot1 + if namestring == 'Marmousi': + plot1 = {'name': 'Marmousi', 'algo': algo, 'cmap': 'RdYlBu', 'fn_shots': '19', 'final': 3, + 'pdf_path': 'pdfs/', + 'path_errors': 'errors/', 'input_path': '', + 'data_name': 'VpExp', 'fn_input_true': 'VpExp_fwi_m_real.vtu', 'fn_input_initial': 'VpExp_fwi_m_initial.vtu', + 'bounding_box': [(-100000, 100000), (-100000, 100000)], 'midpoint_iterate': 1.0, + 'midpoint_diff': 0, + 'vmin_diff': -0.08, 'vmax_diff': 0.20, 'vmin_iterate': 0.90, 'vmax_iterate': 1.20, + 'ticks_middle': [], + 'normalization_value': 1.0 / 2500.0, 'plotting': True, 'plot_iterates': True, 'errors': True, + 'frequency': ''} + return plot1 + if namestring == 'C2': + plot1 = {'name': 'C2', 'algo': algo, 'cmap': 'RdYlBu', 'fn_shots': '5', 'final': 9, + 'pdf_path': 'pdfs/', + 'path_errors': 'errors/', 'input_path': '', + 'data_name': 'VpExp', 'fn_input_true': 'VpExp_fwi_m_real.vtu', 'fn_input_initial': '', + 'bounding_box': [(600, 1400), (370, 1620)], 'midpoint_iterate': 1.0, + 'midpoint_diff': 0, + 'vmin_diff': -0.08, 'vmax_diff': 0.20, 'vmin_iterate': 0.90, 'vmax_iterate': 1.20, + 'ticks_middle': [], + 'normalization_value': 1.0 / 3500.0, 'plotting': True, 'plot_iterates': True, 'errors': True, + 'frequency': ''} + return plot1 + else: + exit("sting not known") + + +def vtuPlotIterates(config, createMapping=False): + fn_input_final = config.make_iterate_input_fn(config.final) + fn_input_true = config.fn_input_true + fn_input_initial = config.fn_input_initial + + fn_output_final = config.fn_output_final + print(fn_output_final) + fn_output_true = config.fn_output_true + fn_output_initial = config.fn_output_initial + fn_output_diff = config.fn_output_diff + + data_name = config.data_name + + normalization_value = config.normalization_value + + cmap = config.cmap + + vtu_final = pv.read(fn_input_final) + vtu_true = pv.read(fn_input_true) + if config.fn_input_initial == config.input_path: + vtu_initial = pv.read(fn_input_true) + vtu_initial.cell_data[data_name] = 1.0/normalization_value + else: + vtu_initial = pv.read(fn_input_initial) + if createMapping is False: + x_Val_f, x_Val, y_Val, ImageMapping = fwiPlotLib.vtuMapping(vtu_final, config.bounding_box) + image_true = fwiPlotLib.fillImage(vtu_true.cell_data[data_name] * normalization_value, ImageMapping, x_Val_f, + y_Val, x_Val) + image_initial = fwiPlotLib.fillImage(vtu_initial.cell_data[data_name] * normalization_value, ImageMapping, + x_Val_f, y_Val, x_Val) + image_final = fwiPlotLib.fillImage(vtu_final.cell_data[data_name] * normalization_value, ImageMapping, + x_Val_f, y_Val, x_Val) + else: + image_true = fwiPlotLib.fillImageAndMapping(vtu_true, data_name, config.bounding_box) * normalization_value + image_initial = fwiPlotLib.fillImageAndMapping(vtu_initial, data_name, + config.bounding_box) * normalization_value + image_final = fwiPlotLib.fillImageAndMapping(vtu_final, data_name, config.bounding_box) * normalization_value + + image_diff = image_true - image_final + ticks_middle = config.ticks_middle + vmin = config.vmin_iterate + vmax = config.vmax_iterate + if config.plotting is True: + fwiPlotLib.savePlot(image_true, fn_output_true, vmin, vmax, cmap=cmap, norm=config.normone, + ticksmiddle=ticks_middle) + + fwiPlotLib.savePlot(image_initial, fn_output_initial, vmin, vmax, cmap=cmap, norm=config.normone, + ticksmiddle=ticks_middle) + if config.plot_iterates is True: + s_rel_linf = 'relative error linf\n 0 1 \n' + s_rel_l2 = 'relative error l2 \n0 1 \n' + image_initial -= image_true + norm_l2, norm_l_inf = fwiPlotLib.calculateErrors(image_initial) + print(norm_l2) + print(norm_l_inf) + for i in range(config.final + 1): + vtu_iterate = pv.read(config.make_iterate_input_fn(i)) + if createMapping is False: + image_iterate = fwiPlotLib.fillImage(vtu_iterate.cell_data[data_name] * normalization_value, + ImageMapping, + x_Val_f, y_Val, x_Val) + else: + image_iterate = fwiPlotLib.fillImageAndMapping(vtu_iterate,data_name, config.bounding_box) * normalization_value + + fwiPlotLib.savePlot(image_iterate, config.make_iterate_output_fn(i), vmin, vmax, cmap=cmap, + norm=config.normone, ticksmiddle=ticks_middle) + image_iterate -= image_true + # fwiPlotLib.savePlot(image_iterate, "test" + str(i), config.vmin_diff, config.vmax_diff, cmap=cmap, + # norm=config.normtwo) + l2, l_inf = fwiPlotLib.calculateErrors(image_iterate) + print(str(l2)) + s_rel_l2 += str(i + 1) + ' ' + str(l2 / norm_l2) + '\n' + s_rel_linf += str(i + 1) + ' ' + str(l_inf / norm_l_inf) + '\n' + if i in range(config.final): + fwiPlotLib.savePlot(image_iterate, "test" + str(i), config.vmin_diff, config.vmax_diff, cmap=cmap, + norm=config.normtwo) + f = open(config.path_errors + 'errorlinf_rel_' + config.name, 'w+') + f.write(s_rel_linf) + f.close() + f = open(config.path_errors + 'errorl2_rel_' + config.name, 'w+') + f.write(s_rel_l2) + f.close() + fwiPlotLib.savePlot(image_final, fn_output_final, vmin, vmax, cmap=cmap, norm=config.normone, + ticksmiddle=ticks_middle) + + fwiPlotLib.savePlot(image_diff, fn_output_diff, config.vmin_diff, config.vmax_diff, cmap=cmap, + norm=config.normtwo) + + + + # if config.errors is True: + # s_rel_linf = 'relative error linf\n 0 1 \n' + # s_rel_l2 = 'relative error l2 \n0 1 \n' + # image_initial -= image_true + # norm_l2, norm_l_inf = fwiPlotLib.calculateErrors(image_initial) + # print(norm_l2) + # print(norm_l_inf) + # for i in range(config.final+1): + # vtu_iterate = pv.read(config.make_iterate_input_fn(i)) + # print( config.make_iterate_input_fn(i)) + # if createMapping is False: + # image_iterate = fwiPlotLib.fillImage(vtu_iterate.cell_data[data_name] * normalization_value, + # ImageMapping, + # x_Val_f, y_Val, x_Val) + # else: + # image_iterate = fwiPlotLib.fillImageAndMapping(vtu_iterate, data_name, + # config.bounding_box) * normalization_value + # image_iterate -= image_true + # l2, l_inf = fwiPlotLib.calculateErrors(image_iterate) + # fwiPlotLib.savePlot(image_iterate, "test" + str(i), config.vmin_diff, config.vmax_diff, cmap=cmap, + # norm=config.normtwo) + # print(str(l2)) + # s_rel_l2 += str(i + 1) + ' ' + str(l2 / norm_l2) + '\n' + # s_rel_linf += str(i + 1) + ' ' + str(l_inf / norm_l_inf) + '\n' + # + # f = open(config.path_errors + 'errorlinf_rel_' + config.name, 'w+') + # f.write(s_rel_linf) + # f.close() + # f = open(config.path_errors + 'errorl2_rel_' + config.name, 'w+') + # f.write(s_rel_l2) + # f.close() + +# config = PlotConfig(Plot1) +# vtuPlot(config) diff --git a/tools/plottools/fwiPlotLib.py b/tools/plottools/fwiPlotLib.py new file mode 100644 index 0000000000000000000000000000000000000000..12e2078dc3d947d28dc1c1a56f7702c3031b10f6 --- /dev/null +++ b/tools/plottools/fwiPlotLib.py @@ -0,0 +1,148 @@ +import matplotlib.pyplot as plt +import numpy as np +from mpl_toolkits.axes_grid1 import make_axes_locatable +from matplotlib.colors import Normalize + +def QGSLS(omegas,tauls,taup): + Qomega = np.zeros(omegas.shape) + for i,omega in enumerate(omegas): + sum2 = 0.0 + sum1 = 0.0 + for taul in tauls: + prod = omega * taul/(1.0+omega*taul*omega*taul) + sum1 += omega * taul * prod + sum2 += prod + Qomega[i] = (1.0/taup + sum1)/sum2 + return Qomega +class MidpointNormalize(Normalize): + def __init__(self, vmin=None, vmax=None, midpoint=None, clip=False): + self.midpoint = midpoint + Normalize.__init__(self, vmin, vmax, clip) + + def __call__(self, value, clip=None): + x, y = [self.vmin, self.midpoint, self.vmax], [0, 0.5, 1] + return np.ma.masked_array(np.interp(value, x, y)) + + +def savePlot(Img, filename, vmin, vmax, title="", colorbar=True, show_axis=False, ticksmiddle=None, text=None, + norm=None, cmap="viridis"): + + plt.clf() + plt.cla() + fig, ax = plt.subplots() + + [i.set_linewidth(0.2) for i in plt.gca().spines.values()] + + ax.get_xaxis().set_visible(show_axis) + ax.get_yaxis().set_visible(show_axis) + if norm is not None: + imgplot = plt.imshow(Img, interpolation='nearest', norm=norm) + else: + imgplot = plt.imshow(Img, interpolation='nearest', vmin=vmin, vmax=vmax, norm=norm) + imgplot.set_cmap(cmap) + if colorbar: + # cb = plt.colorbar(imgplot, shrink=.45, pad=.02, aspect=10) + divider = make_axes_locatable(ax) + cax = divider.append_axes("top", size="5%", pad=0.1) + if ticksmiddle is None: + tickz = [vmin, vmax] + else: + tickz = [vmin] + tickz.extend(ticksmiddle) + tickz.append(vmax) + cb = plt.colorbar(imgplot, cax=cax, orientation='horizontal', ticks=tickz) + cax.xaxis.set_ticks_position("top") + cb.outline.set_linewidth(0.2) + + if title: + # plt.title(title) + ax.text(0.05, 0.05, title, + verticalalignment='bottom', horizontalalignment='left', + transform=ax.transAxes, color='white', fontsize=14) + + if text: + # plt.title(title) + ax.text(0.05, 0.03, text, + verticalalignment='bottom', horizontalalignment='left', + transform=ax.transAxes, color='white', fontsize=14) + + # fig.set_size_inches(6,4) + plt.savefig(filename, dpi=300, bbox_inches="tight", pad_inches=0.02) + plt.close() + + +def createImageMapping(centers): + def take_first_of_first(elem): + return elem[0][0] + + def take_second_of_first(elem): + return elem[0][1] + + return sorted(sorted([(centers.points[i, 0:2], i) for i in range(0, len(centers.points))], + key=take_first_of_first), key=take_second_of_first) + + +def get_coordinate_values(x_list,y_list, bounding_box_): + # x_set = sorted(set([points[j][0] for j in range(len(points))])) + # y_set = sorted(set([points[j][1] for j in range(len(points))])) + x_values_full = len(x_list) + if bounding_box_ is not None: + x_values_new = [j for j in range(x_values_full) if bounding_box_[0][0] <= x_list[j] <= bounding_box_[0][1]] + y_values_new = [j for j in range(len(y_list)) if bounding_box_[1][0] <= y_list[j] <= bounding_box_[1][1]] + return x_values_full, x_values_new, y_values_new + else: + return x_values_full, [j for j in range(x_values_full)], [j for j in range(len(y_list))] + +def preprocess(points): + x = sorted([p[0] for p in points]) + y = sorted([p[1] for p in points]) + x_ = [x[0]] + y_ = [y[0]] + xcur = x[0] + ycur = y[0] + for i in range(len(x)): + if (abs(xcur - x[i])) > 1e-4: + xcur = x[i] + x_.append(xcur) + for i in range(len(y)): + if (abs(ycur - y[i])) > 1e-4: + ycur = y[i] + y_.append(ycur) + return x_, y_ +def vtuMapping(vtu, bounding_box): + centers = vtu.cell_centers() + points = centers.points + + imageMapping = createImageMapping(centers) + x,y = preprocess(points) + x_val_f, x_val, y_val = get_coordinate_values(x, y, bounding_box) + return x_val_f, x_val, y_val, imageMapping + + +def fillImage(cellData, imageMapping, xFullLength, yValues, xValues): + image = np.zeros((len(yValues), len(xValues)), dtype=float) + for i in range(0, len(yValues)): + for j in range(0, len(xValues)): + image[i][j] = cellData[imageMapping[yValues[i] * xFullLength + xValues[j]][1]] + return image + +def fillImageAndMapping(vtu, comp, bounding_box): + x_full_length, x_values, y_values, image_mapping = vtuMapping(vtu, bounding_box) + image = np.zeros((len(y_values), len(x_values)), dtype=float) + for i in range(0, len(y_values)): + for j in range(0, len(x_values)): + image[i][j] = vtu.cell_data[comp][image_mapping[y_values[i] * x_full_length + x_values[j]][1]] + return image + +def fillCelldata(cellData, image, imageMapping, xFullLength, yValues, xValues): + test = np.zeros(cellData.shape) + for i in range(0, len(yValues)): + for j in range(0, len(xValues)): + test[imageMapping[yValues[i] * xFullLength + xValues[j]][1]] = image[j][i] + # cellData[imageMapping[yValues[i] * xFullLength + xValues[j]][1]] = image[i][j] + return test + +def calculateErrors(image): + error_l2 = np.linalg.norm(image, 'fro') + error_l_inf = max(abs(image.max()), abs(image.min())) + return error_l2, error_l_inf diff --git a/tools/plottools/fwiPlot_plotErrors.py b/tools/plottools/fwiPlot_plotErrors.py new file mode 100644 index 0000000000000000000000000000000000000000..d45629271fde359dffe422d52eb32a2faf5ee3b7 --- /dev/null +++ b/tools/plottools/fwiPlot_plotErrors.py @@ -0,0 +1,264 @@ +import fwiPlotLib +import pyvista as pv +import os.path +import os +from time import time +LSDFpath = '/home/cr/LSDF/' + + + +class PlotConfig: + def __init__(self): + self.name = '' + self.fn_shots = '' + self.input_path = '/tmp/' + self.algo = '' + self.fn_input_final = '' + self.fn_input_true = '' + self.fn_input_initial = '' + + self.path_errors = '' + self.final = 100 + + self.fn_output_final = '' + self.fn_output_true = '' + self.fn_output_initial = '' + self.fn_output_diff = '' + + self.data_name = '' + + self.bounding_box = [(-100000, 100000), (-100000, 100000)] + + self.cmap = 'RdYlBu' + + self.midpoint_iterate = 1.0 + self.vmin_iterate = -1000 + self.vmax_iterate = 1000 + + self.midpoint_diff = 0.0 + self.vmin_diff = -1000 + self.vmax_diff = 1000 + + self.ticks_middle = [] + + self.normalization_value = -100000 + + self.normone = None + self.normtwo = None + + self.plotting = False + self.plot_iterates = False + self.errors = True + self.frequency = '' + + + def __init__(self, dict, lsdf=False): + self.name = dict['name'] + self.fn_shots = dict['fn_shots'] + self.frequency = dict['frequency'] + + if lsdf is True: + self.input_path = LSDFpath + dict['input_path'] + else: + self.input_path = dict['input_path'] + self.algo = dict['algo'] + self.fn_input_true = self.input_path + dict['fn_input_true'] + self.fn_input_initial = self.input_path + dict['fn_input_initial'] + + self.final = dict['final'] + + self.pdf_output_path = self.input_path + dict['pdf_path'] + if os.path.exists(self.pdf_output_path) is False: + os.mkdir(self.pdf_output_path) + self.data_name = dict['data_name'] + + self.fn_output_final = self.pdf_output_path + self.name + self.algo + self.data_name + 'Final.pdf' + self.fn_output_true = self.pdf_output_path + self.name + self.algo + self.data_name + 'True.pdf' + self.fn_output_initial = self.pdf_output_path + self.name + self.algo + self.data_name + 'Initial.pdf' + self.fn_output_diff = self.pdf_output_path + self.name + self.algo + self.data_name + 'Diff.pdf' + + + self.bounding_box = dict['bounding_box'] + + self.cmap = dict['cmap'] + + self.midpoint_iterate = dict['midpoint_iterate'] + self.vmin_iterate = dict['vmin_iterate'] + self.vmax_iterate = dict['vmax_iterate'] + + self.midpoint_diff = dict['midpoint_diff'] + self.vmin_diff = dict['vmin_diff'] + self.vmax_diff = dict['vmax_diff'] + + self.ticks_middle = dict['ticks_middle'] + + self.normalization_value = dict['normalization_value'] + + self.plotting = dict['plotting'] + self.plot_iterates = dict['plot_iterates'] + self.path_errors = self.input_path + dict['path_errors'] + + if os.path.exists(self.path_errors) is False: + os.mkdir(self.path_errors) + self.errors = dict['errors'] + + self.normone = fwiPlotLib.MidpointNormalize(midpoint=self.midpoint_iterate, + vmin=self.vmin_iterate, + vmax=self.vmax_iterate) + self.normtwo = fwiPlotLib.MidpointNormalize(midpoint=self.midpoint_diff, + vmin=self.vmin_diff, + vmax=self.vmax_diff) + self.fn_input_final = self.make_iterate_input_fn(self.final) + + def make_iterate_input_fn(self, nr): + return self.input_fn() + self.fn_shots + '_' + str(nr) + '.vtu' + + def make_iterate_output_fn(self, nr): + return self.input_fn() + self.fn_shots + '_' + str(nr) + '.pdf' + + def input_fn(self): + return self.input_path + self.data_name + '__fwi_' + self.algo + self.frequency + '_iterate_m_allshots_' + + +def getBasicConfig(namestring, algo): + if namestring == 'C2': + plot1 = {'name': 'C2', 'algo': algo, 'cmap': 'RdYlBu', 'fn_shots': '5', 'final': 9, + 'pdf_path': 'pdfs/', + 'path_errors': 'errors/', 'input_path': '', + 'data_name': 'VpExp', 'fn_input_true': 'VpExp_fwi_m_real.vtu', 'fn_input_initial': '', + 'bounding_box': [(600, 1400), (370, 1620)], 'midpoint_iterate': 1.0, + 'midpoint_diff': 0, + 'vmin_diff': -0.08, 'vmax_diff': 0.20, 'vmin_iterate': 0.90, 'vmax_iterate': 1.20, + 'ticks_middle': [], + 'normalization_value': 1.0 / 3500.0, 'plotting': True, 'plot_iterates': True, 'errors': True, + 'frequency': ''} + return plot1 + else: + exit("srting not known") + + +def vtuPlotIterates(config, createMapping=False): + fn_input_final = config.make_iterate_input_fn(config.final) + fn_input_true = config.fn_input_true + fn_input_initial = config.fn_input_initial + + fn_output_final = config.fn_output_final + print(fn_output_final) + fn_output_true = config.fn_output_true + fn_output_initial = config.fn_output_initial + fn_output_diff = config.fn_output_diff + + data_name = config.data_name + + normalization_value = config.normalization_value + + cmap = config.cmap + + vtu_final = pv.read(fn_input_final) + vtu_true = pv.read(fn_input_true) + if config.fn_input_initial == config.input_path: + vtu_initial = pv.read(fn_input_true) + vtu_initial.cell_data[data_name] = 1.0/normalization_value + else: + vtu_initial = pv.read(fn_input_initial) + + # if createMapping is False: + x_Val_f, x_Val, y_Val, ImageMapping = fwiPlotLib.vtuMapping(vtu_final, config.bounding_box) + image_true = fwiPlotLib.fillImage(vtu_true.cell_data[data_name] * normalization_value, ImageMapping, x_Val_f, + y_Val, x_Val) + image_initial = fwiPlotLib.fillImage(vtu_initial.cell_data[data_name] * normalization_value, ImageMapping, + x_Val_f, y_Val, x_Val) + image_final = fwiPlotLib.fillImage(vtu_final.cell_data[data_name] * normalization_value, ImageMapping, + x_Val_f, y_Val, x_Val) + # else: + # image_true = fwiPlotLib.fillImageAndMapping(vtu_true, data_name, config.bounding_box) * normalization_value + # image_initial = fwiPlotLib.fillImageAndMapping(vtu_initial, data_name, + # config.bounding_box) * normalization_value + # image_final = fwiPlotLib.fillImageAndMapping(vtu_final, data_name, config.bounding_box) * normalization_value + + image_diff = image_true - image_final + ticks_middle = config.ticks_middle + vmin = config.vmin_iterate + vmax = config.vmax_iterate + if config.plotting is True: + fwiPlotLib.savePlot(image_true, fn_output_true, vmin, vmax, cmap=cmap, norm=config.normone, + ticksmiddle=ticks_middle) + + fwiPlotLib.savePlot(image_initial, fn_output_initial, vmin, vmax, cmap=cmap, norm=config.normone, + ticksmiddle=ticks_middle) + if config.plot_iterates is True: + s_rel_linf = 'relative error linf\n 0 1 \n' + s_rel_l2 = 'relative error l2 \n0 1 \n' + image_initial -= image_true + norm_l2, norm_l_inf = fwiPlotLib.calculateErrors(image_initial) + print(norm_l2) + print(norm_l_inf) + for i in range(config.final + 1): + vtu_iterate = pv.read(config.make_iterate_input_fn(i)) + if createMapping is False: + image_iterate = fwiPlotLib.fillImage(vtu_iterate.cell_data[data_name] * normalization_value, + ImageMapping, + x_Val_f, y_Val, x_Val) + else: + image_iterate = fwiPlotLib.fillImageAndMapping(vtu_iterate,data_name, config.bounding_box) * normalization_value + + fwiPlotLib.savePlot(image_iterate, config.make_iterate_output_fn(i), vmin, vmax, cmap=cmap, + norm=config.normone, ticksmiddle=ticks_middle) + image_iterate -= image_true + # fwiPlotLib.savePlot(image_iterate, "test" + str(i), config.vmin_diff, config.vmax_diff, cmap=cmap, + # norm=config.normtwo) + l2, l_inf = fwiPlotLib.calculateErrors(image_iterate) + print(str(l2)) + s_rel_l2 += str(i + 1) + ' ' + str(l2 / norm_l2) + '\n' + s_rel_linf += str(i + 1) + ' ' + str(l_inf / norm_l_inf) + '\n' + # if i in range(config.final): + # fwiPlotLib.savePlot(image_iterate, "test" + str(i), config.vmin_diff, config.vmax_diff, cmap=cmap, + # norm=config.normtwo) + f = open(config.path_errors + 'errorlinf_rel_' + config.name, 'w+') + f.write(s_rel_linf) + f.close() + f = open(config.path_errors + 'errorl2_rel_' + config.name, 'w+') + f.write(s_rel_l2) + f.close() + fwiPlotLib.savePlot(image_final, fn_output_final, vmin, vmax, cmap=cmap, norm=config.normone, + ticksmiddle=ticks_middle) + + fwiPlotLib.savePlot(image_diff, fn_output_diff, config.vmin_diff, config.vmax_diff, cmap=cmap, + norm=config.normtwo) + + + + # if config.errors is True: + # s_rel_linf = 'relative error linf\n 0 1 \n' + # s_rel_l2 = 'relative error l2 \n0 1 \n' + # image_initial -= image_true + # norm_l2, norm_l_inf = fwiPlotLib.calculateErrors(image_initial) + # print(norm_l2) + # print(norm_l_inf) + # for i in range(config.final+1): + # vtu_iterate = pv.read(config.make_iterate_input_fn(i)) + # print( config.make_iterate_input_fn(i)) + # if createMapping is False: + # image_iterate = fwiPlotLib.fillImage(vtu_iterate.cell_data[data_name] * normalization_value, + # ImageMapping, + # x_Val_f, y_Val, x_Val) + # else: + # image_iterate = fwiPlotLib.fillImageAndMapping(vtu_iterate, data_name, + # config.bounding_box) * normalization_value + # image_iterate -= image_true + # l2, l_inf = fwiPlotLib.calculateErrors(image_iterate) + # fwiPlotLib.savePlot(image_iterate, "test" + str(i), config.vmin_diff, config.vmax_diff, cmap=cmap, + # norm=config.normtwo) + # print(str(l2)) + # s_rel_l2 += str(i + 1) + ' ' + str(l2 / norm_l2) + '\n' + # s_rel_linf += str(i + 1) + ' ' + str(l_inf / norm_l_inf) + '\n' + # + # f = open(config.path_errors + 'errorlinf_rel_' + config.name, 'w+') + # f.write(s_rel_linf) + # f.close() + # f = open(config.path_errors + 'errorl2_rel_' + config.name, 'w+') + # f.write(s_rel_l2) + # f.close() + +# config = PlotConfig(Plot1) +# vtuPlot(config) diff --git a/tools/plottools/plotC2MSD.py b/tools/plottools/plotC2MSD.py new file mode 100644 index 0000000000000000000000000000000000000000..ea14383045e657c87d3395bd5a2e9d26a8f9ebee --- /dev/null +++ b/tools/plottools/plotC2MSD.py @@ -0,0 +1,49 @@ +from fwiPlot import PlotConfig, getBasicConfig, vtuPlotIterates, setParametersFromTickmiddleCamembert +#python3 plotC2MSD.py ausführen in console in dem ordner. Configs hier beachten. +Conf = getBasicConfig('C2', 'FWISO') +#Conf['ticks_middle'] = [0.9, 1, 1.05] +Conf['ticks_middle'] = [1] +Conf['vmin_diff'] = -0.1 +Conf['vmax_diff'] = 0.1 +#Conf['vmax_iterate'] = 1.1 +Conf['vmax_iterate'] = 1.05 +#Conf['vmin_iterate'] = 0.85 +Conf['vmin_iterate'] = 0.95 +Conf['plot_iterates'] = True +#final ist anzahl iterationen - 1 +Conf['final'] = 5 +Conf['normalization_value'] = 1/2000.0 +Conf['data_name'] ='Rho' +#Conf['input_path'] = '/home/lionbart/Desktop/Logs_Plots_MA/2023_06_21_zVp15/' +#Conf['input_path'] = '/home/lionbart/Desktop/Logs_Plots_MA/2023_06_27_IC_RhoMono_HighResolution/vtuClipping/' +#Conf['input_path'] = '/home/lionbart/Desktop/Logs_Plots_MA/2023_06_27_noIC_VpMono_HighResolution/vtuClipping_iter5_secondTry/' +Conf['input_path'] = '/home/lionbart/Desktop/Logs_Plots_MA/2023_06_27_IC_RhoMono_HighResolution/vtuClipping/' +#Conf['input_path'] = '/home/lionbart/Desktop/Logs_Plots_MA/2023_06_27_noIC_VpMono_HighResolution/vtuClipping_quelle5/' + +Conf['fn_input_true']='Rho_fwi_m_real.vtu' +Conf['fn_input_initial']='Rho_fwi_m_initial.vtu' +#Conf['fn_input_true']='Vp_fwi_m_real.vtu' +#Conf['fn_input_initial']='Vp_fwi_m_initial.vtu' +vtuPlotIterates(PlotConfig(Conf)) + +#python3 plotC2MSD.py ausführen in console in dem ordner. Configs hier beachten. + +#Conf['fn_input_true']='Rho_fwi_m_real.vtu' +#Conf['fn_input_initial']='Rho_fwi_m_initial.vtu' +#Bei Multi ist einmal Vp und das andere mal Rho + + +#Conf['final'] = 11 +#Conf['input_path'] = 'c2-aao-msd-with-damping/2022-07-29T16-41-45/0/vtu/' +#vtuPlotIterates(PlotConfig(Conf)) +#Conf['input_path'] = 'c2-aao-msd-multiparam/2022-07-29_20:43:20/vtu/' +#Conf['data_name'] = 'TaupExp' +#Conf['ticks_middle'] = [0.45, 1, 2.0] +#Conf['vmin_diff'] = -0.1 +#Conf['vmax_diff'] = 0.1 +#Conf['vmax_iterate'] = 1.1 +#Conf['vmin_iterate'] = 0.85 +#Conf['fn_input_true'] = 'TaupExp_fwi_m_real.vtu' +#Conf['fn_input_initial'] = 'TaupExp_initialValue.vtu' +#Conf['normalization_value'] = 1.0 / 0.0767 +#vtuPlotIterates(PlotConfig(Conf))