7 m 21 s

FWITestReduced2D.TestFWIInverseMainDGTSVA: 1 total, 1 passed

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  • 7 m 21 s
    FWITestReduced2D
    • 7 m 21 s
      passedTestFWIInverseMainDGTSVA
      • start program on 1 procs at Mon May 8 12:11:50 2023
        Running on: lionbart-Alienware-13-R2
        FWISourceCount0
        FWISourceCount1
        SOURCE LOCATIONS:
        0: ( 600.00000000, 370.00000000)

        1: ( 600.00000000, 1620)

        monoparam =

        alphaValue =
        0
        Mesh Info:
        Mesh Name: ............................... SeismogramGrid_test
        Distribution: ............................ RCB
        Overlap: ................................. dG1
        CommSplit: ............................... 0
        Level: ................................... [0, -1]
        pLevel: .................................. 0
        Dimension: ............................... 2
        Cells: ................................... 1360
        Overlap: ................................. 0
        Vertices: ................................ 1435
        Edges: ................................... 2794
        Faces: ................................... 2794
        ProcSets: ................................ 0
        Mesh width [min, max]: ................... [100.000000, 235.794769]
        Measure overall pressure p = p_0 + ... + p_L
        FWIReceiverCount0
        FWIReceiverCount1
        ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.002
        ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.002
        0: ( 1350, 370.00000000) 1: ( 1350, 410.64516129)
        2: ( 1350, 451.29032258) 3: ( 1350, 491.93548387)
        4: ( 1350, 532.58064516) 5: ( 1350, 573.22580645)
        6: ( 1350, 613.87096774) 7: ( 1350, 654.51612903)
        8: ( 1350, 695.16129032) 9: ( 1350, 735.80645161)
        10: ( 1350, 776.45161290) 11: ( 1350, 817.09677419)
        12: ( 1350, 857.74193548) 13: ( 1350, 898.38709677)
        14: ( 1350, 939.03225806) 15: ( 1350, 979.67741935)
        16: ( 1350, 1020.323) 17: ( 1350, 1060.968)
        18: ( 1350, 1101.613) 19: ( 1350, 1142.258)
        20: ( 1350, 1182.903) 21: ( 1350, 1223.548)
        22: ( 1350, 1264.194) 23: ( 1350, 1304.839)
        24: ( 1350, 1345.484) 25: ( 1350, 1386.129)
        26: ( 1350, 1426.774) 27: ( 1350, 1467.419)
        28: ( 1350, 1508.065) 29: ( 1350, 1548.71)
        30: ( 1350, 1589.355) 31: ( 1350, 1630)
        Measure overall pressure p = p_0 + ... + p_L
        Time before FWD->createRealData(real, obs); Mon May 8 12:11:51 2023
        Generating Real data for shot 0
        Initialization: 0.20 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.34 seconds
        Generating Real data for shot 1
        Initialization: 0.18 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.47 seconds
        Time after FWD->createRealData(real, obs); Mon May 8 12:11:55 2023
        FWISourceCount0
        FWISourceCount1
        SOURCE LOCATIONS:
        0: ( 600.00000000, 370.00000000)

        1: ( 600.00000000, 1620)

        monoparam =

        alphaValue =
        0
        Frequency Filter to: -1

        Mesh Info:
        Mesh Name: ............................... SeismogramGrid_test
        Distribution: ............................ RCB
        Overlap: ................................. dG1
        CommSplit: ............................... 0
        Level: ................................... [0, -1]
        pLevel: .................................. 0
        Dimension: ............................... 2
        Cells: ................................... 1360
        Overlap: ................................. 0
        Vertices: ................................ 1435
        Edges: ................................... 2794
        Faces: ................................... 2794
        ProcSets: ................................ 0
        Mesh width [min, max]: ................... [100.000000, 235.794769]
        Measure overall pressure p = p_0 + ... + p_L
        FWIReceiverCount0
        FWIReceiverCount1
        ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.002
        ReceiverStart: 0 ReceiverEnd: 0.6 ReceiverDt: 0.002
        0: ( 1350, 370.00000000) 1: ( 1350, 410.64516129)
        2: ( 1350, 451.29032258) 3: ( 1350, 491.93548387)
        4: ( 1350, 532.58064516) 5: ( 1350, 573.22580645)
        6: ( 1350, 613.87096774) 7: ( 1350, 654.51612903)
        8: ( 1350, 695.16129032) 9: ( 1350, 735.80645161)
        10: ( 1350, 776.45161290) 11: ( 1350, 817.09677419)
        12: ( 1350, 857.74193548) 13: ( 1350, 898.38709677)
        14: ( 1350, 939.03225806) 15: ( 1350, 979.67741935)
        16: ( 1350, 1020.323) 17: ( 1350, 1060.968)
        18: ( 1350, 1101.613) 19: ( 1350, 1142.258)
        20: ( 1350, 1182.903) 21: ( 1350, 1223.548)
        22: ( 1350, 1264.194) 23: ( 1350, 1304.839)
        24: ( 1350, 1345.484) 25: ( 1350, 1386.129)
        26: ( 1350, 1426.774) 27: ( 1350, 1467.419)
        28: ( 1350, 1508.065) 29: ( 1350, 1548.71)
        30: ( 1350, 1589.355) 31: ( 1350, 1630)
        Measure overall pressure p = p_0 + ... + p_L
        Memory Usage at start118
        Initialize Subproblems 118
        Starting the Loops with max_iter: 10 and num_problems 2
        Iteration Main Looop Counting Variable iter: 0
        iteration: 0 PROBLEM Number: 0
        FWISO problem 0: d(0)
        shot: 0: Solving forward problem...
        Initialization: 0.14 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.33 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 120
        state_comps =
        1
        Prä-Residuumnorm: 4904.15518766181
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 4904.15518717139 und m_max 1
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.26 seconds
        Initialization: 0.14 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Inner Loop: : InnerCG resNorm : 2110.6044825726
        Inner Loop: : Time needed for inner loop: 2.67 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen
        Inner Loop: : 2.67 seconds
        Residuumnorm 1: 2110.6044825726
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.13 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 0.98 seconds
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Intermezzo Residuum: 2046.08561937696
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 4904.15518717139 und m_max 1
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 0.99 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 0.99 seconds
        PhiAdjSO: : 2.25 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.03 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 0.98 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Inner Loop: : InnerCG resNorm : 1181.33327782573
        Inner Loop: : Time needed for inner loop: 6.67 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen
        Inner Loop: : 6.67 seconds
        FWISO Subproblem: 0: d(0): Finished first / second inner loop ( 1, 1 steps )
        *************************************
        Residuumnorm 2: 1181.33327782573
        iteration: 0 PROBLEM Number: 1
        FWISO problem 1: d(0)
        shot: 1: Solving forward problem...
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.04 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 234
        state_comps =
        1
        Prä-Residuumnorm: 1668.05746140048
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 1668.05746123367 und m_max 1
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.25 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Inner Loop: : InnerCG resNorm : 1333.73750171594
        Inner Loop: : Time needed for inner loop: 2.44 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen
        Inner Loop: : 2.44 seconds
        Residuumnorm 1: 1333.73750171594
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.15 seconds
        Intermezzo Residuum: 1334.47316004788
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 1668.05746123367 und m_max 1
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.16 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        PhiAdjSO: : 2.75 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.16 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.13 seconds
        Inner Loop: : InnerCG resNorm : 1115.45472260449
        Inner Loop: : Time needed for inner loop: 7.57 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen
        Inner Loop: : 7.57 seconds
        FWISO Subproblem: 1: d(0): Finished first / second inner loop ( 1, 1 steps )
        *************************************
        Residuumnorm 2: 1115.45472260449
        Iteration Main Looop Counting Variable iter: 1
        iteration: 1 PROBLEM Number: 0
        FWISO problem 0: d(1)
        shot: 0: Solving forward problem...
        Initialization: 0.10 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 237
        Prä-Residuumnorm: 1145.59953001318
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 267.609452178072 und m_max 2
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.28 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Inner Loop: : InnerCG resNorm : 857.395772382246
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.27 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 574.416797964639
        Inner Loop: : Time needed for inner loop: 4.95 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen
        Inner Loop: : 4.95 seconds
        Residuumnorm 1: 574.416797964639
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.15 seconds
        Intermezzo Residuum: 572.180016466027
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 267.609452178072 und m_max 2
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        PhiAdjSO: : 2.42 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.16 seconds
        Inner Loop: : InnerCG resNorm : 495.290814214081
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        PhiAdjSO: : 2.41 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.15 seconds
        Inner Loop: : InnerCG resNorm : 436.502527534886
        Inner Loop: : Time needed for inner loop: 14.17 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen
        Inner Loop: : 14.17 seconds
        FWISO Subproblem: 0: d(1): Finished first / second inner loop ( 2, 2 steps )
        *************************************
        Residuumnorm 2: 436.502527534886
        iteration: 1 PROBLEM Number: 1
        FWISO problem 1: d(1)
        shot: 1: Solving forward problem...
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 238
        Prä-Residuumnorm: 1113.8806047297
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 743.817302643343 und m_max 2
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.26 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.11 seconds
        Inner Loop: : InnerCG resNorm : 969.097609971411
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Inner Loop: : InnerCG resNorm : 530.312799141632
        Inner Loop: : Time needed for inner loop: 4.90 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen
        Inner Loop: : 4.90 seconds
        Residuumnorm 1: 530.312799141632
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.16 seconds
        Intermezzo Residuum: 528.964528988116
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 743.817302643343 und m_max 2
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        PhiAdjSO: : 2.42 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.13 seconds
        Inner Loop: : InnerCG resNorm : 434.696155580712
        Inner Loop: : Time needed for inner loop: 7.08 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen
        Inner Loop: : 7.08 seconds
        FWISO Subproblem: 1: d(1): Finished first / second inner loop ( 2, 1 steps )
        *************************************
        Residuumnorm 2: 434.696155580712
        Iteration Main Looop Counting Variable iter: 2
        iteration: 2 PROBLEM Number: 0
        FWISO problem 0: d(2)
        shot: 0: Solving forward problem...
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 240
        Prä-Residuumnorm: 549.514984615502
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 338.940219405633 und m_max 3
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        Inner Loop: : InnerCG resNorm : 428.371145096895
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 371.618869976951
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.25 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Inner Loop: : InnerCG resNorm : 327.92280625477
        Inner Loop: : Time needed for inner loop: 7.35 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen
        Inner Loop: : 7.35 seconds
        Residuumnorm 1: 327.92280625477
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.15 seconds
        Intermezzo Residuum: 327.917353103265
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 338.940219405633 und m_max 3
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        PhiAdjSO: : 2.39 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.17 seconds
        Inner Loop: : InnerCG resNorm : 302.527333463289
        Inner Loop: : Time needed for inner loop: 7.09 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen
        Inner Loop: : 7.09 seconds
        FWISO Subproblem: 0: d(2): Finished first / second inner loop ( 3, 1 steps )
        *************************************
        Residuumnorm 2: 302.527333463289
        iteration: 2 PROBLEM Number: 1
        FWISO problem 1: d(2)
        shot: 1: Solving forward problem...
        Initialization: 0.10 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 241
        Prä-Residuumnorm: 510.489736064627
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 425.690020275019 und m_max 3
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.26 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 440.059190513106
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.22 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 386.066574776876
        Inner Loop: : Time needed for inner loop: 4.89 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen
        Inner Loop: : 4.89 seconds
        Residuumnorm 1: 386.066574776876
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.04 seconds
        Initialization: 0.10 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Intermezzo Residuum: 386.146281956215
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 306.80127403687 und m_max 2
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        PhiAdjSO: : 2.41 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.13 seconds
        Inner Loop: : InnerCG resNorm : 349.433142006843
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        PhiAdjSO: : 2.41 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Inner Loop: : InnerCG resNorm : 318.969053538246
        Inner Loop: : Time needed for inner loop: 14.13 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen
        Inner Loop: : 14.13 seconds
        FWISO Subproblem: 1: d(2): Finished first / second inner loop ( 2, 2 steps )
        *************************************
        Residuumnorm 2: 318.969053538246
        Iteration Main Looop Counting Variable iter: 3
        iteration: 3 PROBLEM Number: 0
        FWISO problem 0: d(3)
        shot: 0: Solving forward problem...
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 242
        Prä-Residuumnorm: 373.034492500245
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 277.736332155707 und m_max 5
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.26 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.12 seconds
        Inner Loop: : InnerCG resNorm : 318.536689870581
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.26 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Inner Loop: : InnerCG resNorm : 278.954555012328
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.25 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.11 seconds
        Inner Loop: : InnerCG resNorm : 252.812842735491
        Inner Loop: : Time needed for inner loop: 7.42 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen
        Inner Loop: : 7.42 seconds
        Residuumnorm 1: 252.812842735491
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Intermezzo Residuum: 252.890793497662
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 207.078526785094 und m_max 3
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        PhiAdjSO: : 2.41 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.16 seconds
        Inner Loop: : InnerCG resNorm : 238.757504140639
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        PhiAdjSO: : 2.40 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.12 seconds
        Inner Loop: : InnerCG resNorm : 217.851800150853
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        PhiAdjSO: : 2.40 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.12 seconds
        Inner Loop: : InnerCG resNorm : 202.032183127449
        Inner Loop: : Time needed for inner loop: 21.24 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 3 = m innere Iterationen
        Inner Loop: : 21.24 seconds
        FWISO Subproblem: 0: d(3): Finished first / second inner loop ( 3, 3 steps )
        *************************************
        Residuumnorm 2: 202.032183127449
        iteration: 3 PROBLEM Number: 1
        FWISO problem 1: d(3)
        shot: 1: Solving forward problem...
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 244
        Prä-Residuumnorm: 386.086864831508
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 289.75703591328 und m_max 4
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.25 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Inner Loop: : InnerCG resNorm : 338.640751535985
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Inner Loop: : InnerCG resNorm : 317.503941773126
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Inner Loop: : InnerCG resNorm : 257.098318330168
        Inner Loop: : Time needed for inner loop: 7.28 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen
        Inner Loop: : 7.28 seconds
        Residuumnorm 1: 257.098318330168
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.13 seconds
        Intermezzo Residuum: 257.062277033859
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 309.061379154856 und m_max 3
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        PhiAdjSO: : 2.36 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Inner Loop: : InnerCG resNorm : 237.990580739104
        Inner Loop: : Time needed for inner loop: 7.02 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen
        Inner Loop: : 7.02 seconds
        FWISO Subproblem: 1: d(3): Finished first / second inner loop ( 3, 1 steps )
        *************************************
        Residuumnorm 2: 237.990580739104
        Iteration Main Looop Counting Variable iter: 4
        iteration: 4 PROBLEM Number: 0
        FWISO problem 0: d(4)
        shot: 0: Solving forward problem...
        Initialization: 0.10 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 245
        Prä-Residuumnorm: 323.139362051401
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 216.529003875182 und m_max 6
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.27 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.11 seconds
        Inner Loop: : InnerCG resNorm : 236.552196860995
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.26 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Inner Loop: : InnerCG resNorm : 211.849032461509
        Inner Loop: : Time needed for inner loop: 4.93 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen
        Inner Loop: : 4.93 seconds
        Residuumnorm 1: 211.849032461509
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.15 seconds
        Intermezzo Residuum: 211.792831065765
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 275.219838997481 und m_max 4
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        PhiAdjSO: : 2.39 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.13 seconds
        Inner Loop: : InnerCG resNorm : 204.271183116061
        Inner Loop: : Time needed for inner loop: 7.06 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen
        Inner Loop: : 7.06 seconds
        FWISO Subproblem: 0: d(4): Finished first / second inner loop ( 2, 1 steps )
        *************************************
        Residuumnorm 2: 204.271183116061
        iteration: 4 PROBLEM Number: 1
        FWISO problem 1: d(4)
        shot: 1: Solving forward problem...
        Initialization: 0.10 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 246
        Prä-Residuumnorm: 263.914281538076
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 220.016012512124 und m_max 5
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.27 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 250.626616241811
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        Inner Loop: : InnerCG resNorm : 220.767262923878
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Inner Loop: : InnerCG resNorm : 189.523920443087
        Inner Loop: : Time needed for inner loop: 7.43 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen
        Inner Loop: : 7.43 seconds
        Residuumnorm 1: 189.523920443087
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.13 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Intermezzo Residuum: 189.454315215716
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 190.136332868447 und m_max 3
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.15 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        PhiAdjSO: : 2.42 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.21 seconds
        Inner Loop: : InnerCG resNorm : 169.881286099091
        Inner Loop: : Time needed for inner loop: 7.24 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen
        Inner Loop: : 7.24 seconds
        FWISO Subproblem: 1: d(4): Finished first / second inner loop ( 3, 1 steps )
        *************************************
        Residuumnorm 2: 169.881286099091
        Iteration Main Looop Counting Variable iter: 5
        iteration: 5 PROBLEM Number: 0
        FWISO problem 0: d(5)
        shot: 0: Solving forward problem...
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 248
        Prä-Residuumnorm: 305.833298956507
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 184.439312001679 und m_max 5
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.25 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        Inner Loop: : InnerCG resNorm : 230.892791622352
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 208.321994469993
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.25 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.13 seconds
        Inner Loop: : InnerCG resNorm : 194.250875041791
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.26 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Inner Loop: : InnerCG resNorm : 178.727941351457
        Inner Loop: : Time needed for inner loop: 9.92 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen
        Inner Loop: : 9.92 seconds
        Residuumnorm 1: 178.727941351457
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Initialization: 0.14 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Intermezzo Residuum: 178.729496701306
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 234.432140015616 und m_max 4
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        PhiAdjSO: : 2.40 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Inner Loop: : InnerCG resNorm : 171.164230179785
        Inner Loop: : Time needed for inner loop: 7.04 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen
        Inner Loop: : 7.04 seconds
        FWISO Subproblem: 0: d(5): Finished first / second inner loop ( 4, 1 steps )
        *************************************
        Residuumnorm 2: 171.164230179785
        iteration: 5 PROBLEM Number: 1
        FWISO problem 1: d(5)
        shot: 1: Solving forward problem...
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.11 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 249
        Prä-Residuumnorm: 206.261266100883
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 154.757457364065 und m_max 6
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.30 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        Inner Loop: : InnerCG resNorm : 193.040892345105
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.11 seconds
        Inner Loop: : InnerCG resNorm : 179.754516933347
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Inner Loop: : InnerCG resNorm : 166.730816964363
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 154.132216110152
        Inner Loop: : Time needed for inner loop: 9.84 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen
        Inner Loop: : 9.84 seconds
        Residuumnorm 1: 154.132216110152
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Intermezzo Residuum: 154.071765892099
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 133.740335947715 und m_max 2
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        PhiAdjSO: : 2.40 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Inner Loop: : InnerCG resNorm : 145.62239316981
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.12 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        PhiAdjSO: : 2.39 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.15 seconds
        Inner Loop: : InnerCG resNorm : 138.935395217478
        Inner Loop: : Time needed for inner loop: 14.19 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen
        Inner Loop: : 14.19 seconds
        FWISO Subproblem: 1: d(5): Finished first / second inner loop ( 4, 2 steps )
        *************************************
        Residuumnorm 2: 138.935395217478
        Iteration Main Looop Counting Variable iter: 6
        iteration: 6 PROBLEM Number: 0
        FWISO problem 0: d(6)
        shot: 0: Solving forward problem...
        Initialization: 0.12 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 250
        Prä-Residuumnorm: 230.904137726489
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 185.077908243591 und m_max 6
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.25 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.13 seconds
        Inner Loop: : InnerCG resNorm : 187.34881216537
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.11 seconds
        Inner Loop: : InnerCG resNorm : 172.934892102654
        Inner Loop: : Time needed for inner loop: 4.97 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 2 = m innere Iterationen
        Inner Loop: : 4.97 seconds
        Residuumnorm 1: 172.934892102654
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Intermezzo Residuum: 172.899713768813
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 159.296637080848 und m_max 2
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.03 seconds
        PhiAdjSO: : 2.38 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.13 seconds
        Inner Loop: : InnerCG resNorm : 166.686029178543
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        PhiAdjSO: : 2.39 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.13 seconds
        Inner Loop: : InnerCG resNorm : 158.361339396057
        Inner Loop: : Time needed for inner loop: 14.04 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen
        Inner Loop: : 14.04 seconds
        FWISO Subproblem: 0: d(6): Finished first / second inner loop ( 2, 2 steps )
        *************************************
        Residuumnorm 2: 158.361339396057
        iteration: 6 PROBLEM Number: 1
        FWISO problem 1: d(6)
        shot: 1: Solving forward problem...
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 252
        Prä-Residuumnorm: 156.394160111639
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 127.105233030661 und m_max 7
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Inner Loop: : InnerCG resNorm : 149.220221063571
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.26 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.11 seconds
        Inner Loop: : InnerCG resNorm : 144.484978299713
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.25 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Inner Loop: : InnerCG resNorm : 137.06913248533
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.25 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 123.54261560923
        Inner Loop: : Time needed for inner loop: 9.79 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 4 = m innere Iterationen
        Inner Loop: : 9.79 seconds
        Residuumnorm 1: 123.54261560923
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.15 seconds
        Intermezzo Residuum: 123.538737937925
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 128.90026807795 und m_max 3
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        PhiAdjSO: : 2.42 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.20 seconds
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.28 seconds
        Inner Loop: : InnerCG resNorm : 116.549158766415
        Inner Loop: : Time needed for inner loop: 7.33 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen
        Inner Loop: : 7.33 seconds
        FWISO Subproblem: 1: d(6): Finished first / second inner loop ( 4, 1 steps )
        *************************************
        Residuumnorm 2: 116.549158766415
        Iteration Main Looop Counting Variable iter: 7
        iteration: 7 PROBLEM Number: 0
        FWISO problem 0: d(7)
        shot: 0: Solving forward problem...
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.12 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 253
        Prä-Residuumnorm: 224.231487862258
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 161.75658708441 und m_max 6
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        Inner Loop: : InnerCG resNorm : 179.137133697394
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.28 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 165.227641744942
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 155.064794486884
        Inner Loop: : Time needed for inner loop: 7.36 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen
        Inner Loop: : 7.36 seconds
        Residuumnorm 1: 155.064794486884
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Intermezzo Residuum: 155.038434485925
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 189.462391539503 und m_max 3
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        PhiAdjSO: : 2.38 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Inner Loop: : InnerCG resNorm : 150.678993955756
        Inner Loop: : Time needed for inner loop: 7.05 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen
        Inner Loop: : 7.05 seconds
        FWISO Subproblem: 0: d(7): Finished first / second inner loop ( 3, 1 steps )
        *************************************
        Residuumnorm 2: 150.678993955756
        iteration: 7 PROBLEM Number: 1
        FWISO problem 1: d(7)
        shot: 1: Solving forward problem...
        Initialization: 0.10 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.03 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 254
        Prä-Residuumnorm: 128.814334807691
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 94.2214110076765 und m_max 8
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 124.05435068289
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.10 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        Inner Loop: : InnerCG resNorm : 120.723693565467
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Inner Loop: : InnerCG resNorm : 116.203421469166
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.26 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Inner Loop: : InnerCG resNorm : 102.559024382893
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Inner Loop: : InnerCG resNorm : 93.25519573462
        Inner Loop: : Time needed for inner loop: 12.20 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen
        Inner Loop: : 12.20 seconds
        Residuumnorm 1: 93.25519573462
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.11 seconds
        Intermezzo Residuum: 93.2705943937637
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 95.5520465049809 und m_max 3
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        PhiAdjSO: : 2.37 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.13 seconds
        Inner Loop: : InnerCG resNorm : 89.0340906076049
        Inner Loop: : Time needed for inner loop: 7.01 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen
        Inner Loop: : 7.01 seconds
        FWISO Subproblem: 1: d(7): Finished first / second inner loop ( 5, 1 steps )
        *************************************
        Residuumnorm 2: 89.0340906076049
        Iteration Main Looop Counting Variable iter: 8
        iteration: 8 PROBLEM Number: 0
        FWISO problem 0: d(8)
        shot: 0: Solving forward problem...
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 256
        Prä-Residuumnorm: 248.104583107822
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 202.020335202633 und m_max 5
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.22 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 182.372056161549
        Inner Loop: : Time needed for inner loop: 2.43 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 1 = m innere Iterationen
        Inner Loop: : 2.43 seconds
        Residuumnorm 1: 182.372056161549
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        Intermezzo Residuum: 182.347810336916
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 188.670374995484 und m_max 3
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        PhiAdjSO: : 2.39 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Inner Loop: : InnerCG resNorm : 168.877729424012
        Inner Loop: : Time needed for inner loop: 7.02 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen
        Inner Loop: : 7.02 seconds
        FWISO Subproblem: 0: d(8): Finished first / second inner loop ( 1, 1 steps )
        *************************************
        Residuumnorm 2: 168.877729424012
        iteration: 8 PROBLEM Number: 1
        FWISO problem 1: d(8)
        shot: 1: Solving forward problem...
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.02 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 257
        Prä-Residuumnorm: 96.4076061387224
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 75.6954953142397 und m_max 9
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.26 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Inner Loop: : InnerCG resNorm : 89.8116522676763
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 87.7063811864888
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.25 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Inner Loop: : InnerCG resNorm : 85.8030037893987
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Inner Loop: : InnerCG resNorm : 83.6868865855584
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Inner Loop: : InnerCG resNorm : 75.165209772079
        Inner Loop: : Time needed for inner loop: 12.18 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 5 = m innere Iterationen
        Inner Loop: : 12.18 seconds
        Residuumnorm 1: 75.165209772079
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.15 seconds
        Intermezzo Residuum: 75.16369172744
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 64.3620111927632 und m_max 2
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        PhiAdjSO: : 2.36 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.16 seconds
        Inner Loop: : InnerCG resNorm : 70.9606190123436
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        PhiAdjSO: : 2.39 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.12 seconds
        Inner Loop: : InnerCG resNorm : 69.2311416268925
        Inner Loop: : Time needed for inner loop: 14.02 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen
        Inner Loop: : 14.02 seconds
        FWISO Subproblem: 1: d(8): Finished first / second inner loop ( 5, 2 steps )
        *************************************
        Residuumnorm 2: 69.2311416268925
        Iteration Main Looop Counting Variable iter: 9
        iteration: 9 PROBLEM Number: 0
        FWISO problem 0: d(9)
        shot: 0: Solving forward problem...
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 259
        Prä-Residuumnorm: 210.356319894804
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 154.155269331745 und m_max 4
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.25 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Inner Loop: : InnerCG resNorm : 175.972873741039
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Inner Loop: : InnerCG resNorm : 161.741684509335
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 151.276361647265
        Inner Loop: : Time needed for inner loop: 7.29 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 3 = m innere Iterationen
        Inner Loop: : 7.29 seconds
        Residuumnorm 1: 151.276361647265
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.16 seconds
        Intermezzo Residuum: 151.255892009384
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 143.968340826568 und m_max 2
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        PhiAdjSO: : 2.39 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.15 seconds
        Inner Loop: : InnerCG resNorm : 146.479556193603
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.04 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.04 seconds
        PhiAdjSO: : 2.36 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.10 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.13 seconds
        Inner Loop: : InnerCG resNorm : 140.853443912865
        Inner Loop: : Time needed for inner loop: 14.05 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 2 = m innere Iterationen
        Inner Loop: : 14.05 seconds
        FWISO Subproblem: 0: d(9): Finished first / second inner loop ( 3, 2 steps )
        *************************************
        Residuumnorm 2: 140.853443912865
        iteration: 9 PROBLEM Number: 1
        FWISO problem 1: d(9)
        shot: 1: Solving forward problem...
        Initialization: 0.11 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        Assembling Linearized Operators
        Assembling Linearized Operators
        Done!
        Done!
        after NonlinearEvaluation 260
        Prä-Residuumnorm: 92.7103527300989
        Inner Loop: : FIRST ORDER Inner Loop with Abbruchkriterium Residuum zu erreichen 65.5133004185196 und m_max 10
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Inner Loop: : InnerCG resNorm : 84.9448925781271
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        Inner Loop: : InnerCG resNorm : 78.0049523365484
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.22 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Inner Loop: : InnerCG resNorm : 75.3242507793421
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        Inner Loop: : InnerCG resNorm : 72.9170536035026
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.25 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 71.1113568510747
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.23 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 67.4232913627472
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.24 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.09 seconds
        Inner Loop: : InnerCG resNorm : 64.1350531436943
        Inner Loop: : Time needed for inner loop: 16.98 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 1 brauchte 7 = m innere Iterationen
        Inner Loop: : 16.98 seconds
        Residuumnorm 1: 64.1350531436943
        ----- Intermezzo: Change Operators and Recalculate Residuum -----
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.14 seconds
        Intermezzo Residuum: 64.1316270903377
        ----- Intermezzo Ende -----
        Inner Loop: : PSI Inner Loop with Abbruchkriterium Residuum zu erreichen 77.3020331489095 und m_max 3
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.08 seconds
        PhiAdjSO: : Starting ImplicitMidpointRule (Order=2)
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.05 seconds
        PhiAdjSO: : 2.36 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.07 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.06 seconds
        Initialization: 0.09 seconds
        TI: Starting ImplicitMidpointRule (Order=2)
        TI: 1.12 seconds
        Inner Loop: : InnerCG resNorm : 63.1938889397118
        Inner Loop: : Time needed for inner loop: 7.00 seconds
        Inner Loop: : Innere Schleife No. 0/1 : 0 brauchte 1 = m innere Iterationen
        Inner Loop: : 7.00 seconds
        FWISO Subproblem: 1: d(9): Finished first / second inner loop ( 7, 1 steps )
        *************************************
        Residuumnorm 2: 63.1938889397118
        FWISO: d(10)= 0

Generated by CLion on 5/8/23 12:20 PM